

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
401. |
Given figure is of filamentous. Blue green alga Nostoc. Identify the parts marked as A and B and select the correct option. A. `{:(,A,B),((a),"Heterocyst","Mucilaginous sheath"):}`B. `{:(,A,B),((b),"Vegetative cell","Mucilaginous sheath"):}`C. `{:(,A,B),((c),"Trichomes","Cell wall"):}`D. `{:(,A,B),((d),"Muclilaginous sheath","Heterocyst"):}` |
Answer» Correct Answer - A | |
402. |
Viruses areA. Bigger than fungi (yeast)B. Larger than bacteriaC. Smaller than viroidsD. Smaller than bacteria |
Answer» Correct Answer - D Viruses are smalleer than bacteria. |
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403. |
Refer to the given figure of Paramecium caudatum and select the option that correctly identifies A,B,C and D A. `{:(,A,B,C,D),((a),"Cell wall","Cilia","Contractile vacuole","Cytostome"):}`B. `{:(,A,B,C,D),((b),"Pellicle","Cilia","Contractile","Cytostome"):}`C. `{:(,A,B,C,D),((c),"Pellicle","Cilia","Marcronucleus","Cyostome"):}`D. |
Answer» Correct Answer - C | |
404. |
Which fungus does not consist a long, slender thread like structure called hyphae ?A. YeastB. MushroomC. ToadstoolD. Puffball |
Answer» Correct Answer - A Yeast do not consist of a long, slender thread like structure called hypae as it is unicellular. |
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405. |
Oxygen is not produced during photosynthesis byA. Green sulphur bacteriaB. NostocC. CycasD. Chara |
Answer» Correct Answer - A Oxygen is not produced during photosynthesis by green sulphur bacteria. |
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406. |
Select the wrong statementA. Cell wall is present in members of Fungi and Plantae.B. Mushrooms belong to Basidiomycetes.C. Pseudopodia are locomotory and feeding structures in Sporozoans.D. Mitochondria are the powerhouse of the cell in all kingdoms except Monera. |
Answer» Correct Answer - C Pseudopodia are locomotory and feeding strucutres in Amoeboid protozoans. |
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407. |
Which of the following explanation is best for not placing hydrogen in either the group of alkali metals or halogens?A. The ionisation energy of hydrogen is too high for group of alkali metals, but too low of halogen groupB. Hydrogen can form compounds with all other elements.C. Hydrogen is much lighter element than the alkali metals or the halongensD. None of the above |
Answer» Correct Answer - A The Ionisatin energy of hydrogen is too high for group of alkali metals, but too low for halogen group. |
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408. |
In comparison with alkali metals, the electron affinity of halogens isA. very highB. vergy lowC. nearly sameD. exactly same |
Answer» Correct Answer - A Because it can easily accept an `e^(-)` |
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409. |
The graph of `IE_(1)` or `Delta_(1)H_(1)^(ɵ)` versus atomic number `(Z)` is given below: Which of the following statement is correct ?A. Alkali metals are at the maxima and noble gases at the minima.B. Noble gases are at the maxima and alkali metals at the minima.C. Transition elements are at the maxima.D. Minima and maxima do not show any regular behaviour. |
Answer» Correct Answer - B Noble gases are at the maxima which have closed electron shells and very stable electronic configuration. On the other hand, minima occurs at the alkali metals and their low `IE_(1)` can be correlated with their high reactivity. |
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410. |
Assertion (A) : `IE_(1)` of `Mg` is greater than that of `Al`. Reason (R ) : It is easier to remove an electron fro `3s` orbital than from `3p` orbital.A. If both A and R are correct and R is the correct explanation for A.B. If both A and R are correct and R is not the correct explanation for A.C. If A is correct and R is incorrectD. If A is incorrect and R is correct |
Answer» Correct Answer - C `IE_(1)` of `Mg gt IE_(1)` of `Al`. Assertion is correct. Correct reason : It is easier to remove an electron from `3p` orbital than from `3s` orbital (due to pentration effect). |
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411. |
Loundess of sound is transferred toA. Increased movement of basilar fibres of cochleaB. Increased vibration of semicircular canalsC. Vibrations of endolymphatic sacD. Vibrations of typmpanic bulla |
Answer» Correct Answer - A Loudness of sound is transferred to increased movement of basilar fibres of cochlea. |
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412. |
Lichen is an association betweenA. Fungi and bryophytesB. Fungi and algaeC. Algae and pteridophyteD. Algae and bacteria |
Answer» Correct Answer - B Lichen is an association between Fungi and algae. |
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413. |
All sensory pathways to the correct cortex synapse at theA. ThalamusB. PonsC. HypothalamusD. Cerebellum |
Answer» Correct Answer - B All sensory pathways to cerebral cortex synapse at pons. |
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414. |
The genetic material of a viroid isA. DNAB. RNAC. ProteinD. Carbohydrate |
Answer» Correct Answer - B The genetic material of a viroid is RNA. |
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415. |
The amount of CSF in the cranial cavity isA. 50 mlB. 140 mlC. 1 litreD. 1.5 ml |
Answer» Correct Answer - B Amount of CSF in cranial cavities is 140 ml. |
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416. |
A virus like naked pathogenic particle of single-stranded circular RNA filament without a protein covering is known asA. Potato Spindle Tuber Viriod (PSTVd)B. Mumps virusC. Polyoma virusD. Tobacco mosaic virus. |
Answer» Correct Answer - A A virus like naked pathogenic particle of single-stranded circular RNA filament without a protein covering is known as Potato Spindle Tuber Virus (PSTV) viriod. |
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417. |
Cellulose is made ofA. Unbranched chain of glucose molecules linked by `alpha-1,6` glycosidic bondsB. Unbranched chain of glucose molecules linked by `beta-1,4` glycosidic bondsC. Branched chain of glucose molecules having `alpha-1,6` glycosidic bonds at the site of branchingD. Branched chain of glucose molecules with `alpha-1` and `beta-1,4` linked bonds at the site of branching |
Answer» Correct Answer - B Cellulose is made of unbranched chain of glucose molecules linked by `beta-1,4` glycosidic bonds. |
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418. |
The fungus which grows on dungs is calledA. HemicolousB. LignicolousC. CoprophilousD. Fungicolous |
Answer» Correct Answer - C The fungus, which grows on dung is called Coprophilous. |
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419. |
What are molecular scissors ? Where are they obtained from ? |
Answer» Molecular scissors are the restriction enzymes which cut the DNA at specific locations usually they are obtained from Bacteria. |
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420. |
What are virulent phages ? Give an example. |
Answer» T-even phages that attack the bacterium E.coli cause lysis of the cells and are called virulent phages Eg : Bacteriophage. Bacteriophage. |
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421. |
The five kingdom classification was proposed byA. R. H. WhittakerB. C. LinnaeusC. A. RoxbergD. Virchow |
Answer» Correct Answer - A | |
422. |
What are the characteristic features of Euglenoids? |
Answer» Some characteristic features of Euglenoids are as follows. `implies` Euglenoids (such as Euglena) are unicellular protists commonly found in fresh water. `implies` Instead of cell wall, a protein-rich cell membrane known as pellicle is present. `implies` They bear two flagella on the anterior end of the body. `implies` A small light sensitive eye spot is present. `implies` They contain photosynthetic pigments such as chlorophyll and can thus prepare their own food. However, in absence of light, they behave similar to heterotrophs by capturing other small aquatic organisms. `implies` They have both plant and animal-like features, which makes them difficult to classify |
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423. |
What property did Mendelev use to classify the elements in his perodic table. |
Answer» Correct Answer - Atomic masses atomic masses (i.e. mass numbers). |
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424. |
Which one of the following statements is wrong ?A. Cyanobacteria are also called blue-green-algae.B. Golden algae are also called desmids.C. Eubacteria are also called false bacteria.D. Phycomycetes are also called algal fungi. |
Answer» Correct Answer - C `**` Eubacteria are also called true bacteria. `**` Phycomycetes are also called algal fungi. |
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425. |
In the long form of the perodic table, physical and chemical properties of the elements are a periodic function of their `"_______"` . |
Answer» Correct Answer - Atomic numbers Atomic numbers |
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426. |
Solve sin–1 [dy/dx] = x + y. |
Answer» dy/dx = sin (x + y) x + y = t 1 + (dy/dx) = dt/dx (dt/dx) – 1 = sin t dt/dx = 1 + sin t dt/(1 + sin t) = dx Integrating both sides we get ∫ dt/(1 + sin t) = ∫ dx ∫ (1 − sin t/(cos2 t)) dt = x + c ∫ sec2 t dt – ∫ tan t.sec t dt = x + c tan t – sec t = x + c ⇒ tan (x + y) – sec (x + y) = x + c |
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427. |
Electronic configuration of chalcogens in their outermost orbit isA. `s^(2)p^(3)`B. `s^(2)p^(5)`C. `s^(2)p^(4)`D. `p^(6)` |
Answer» Correct Answer - C Chalcogens are oxygen family. |
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428. |
Phospholipids areA. AmphibolicB. AmphipathicC. HydrophobicD. Hydrophilic |
Answer» Correct Answer - B Phospholipids are amphipathic. |
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429. |
The fungus, commonly known as bread mould isA. AlternariaB. RhizopusC. PenicillumD. Aspergillus |
Answer» Correct Answer - B The fungus, commonly known as bread mould is Rhizopus. |
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430. |
Which is associated with asexual reproduction in fungiA. AscosporesB. BasidiosporesC. ZygosporesD. Conidiospores |
Answer» Correct Answer - D Conidiospores is associated with asexual reproduction in fungi. |
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431. |
Asexual spores are generally absent inA. UstilagoB. TrichodermaC. NeurosporaD. Yeast |
Answer» Correct Answer - A Asexual spore are generally absent in Ustilago |
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432. |
Dinoflagellates are mostlyA. TerrestrialB. MarineC. ThermohalineD. Fresh water |
Answer» Correct Answer - B Dinoflagellates are mostly Marine. |
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433. |
Fungi show asexual reproduction by all of the following kinds of spores exceptA. conidiaB. oosporesC. zoosporesD. basidiospores. |
Answer» Correct Answer - B Asexual reproduction in fungi occurs through the fomation of spores. Spores are single-celled propagules which separate from the parent organism and can get dispersed. E.g., zoospores, sproangiospores, chlamydospores, oidia, conidia, etc. Oospore is the product of sexual reproduction. |
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434. |
Chief producers in the oceasns areA. ChrysophytesB. EuglenoidsC. DesmidsD. Diatoms |
Answer» Correct Answer - D Chief producers in the occeans are Diatoms. |
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435. |
True or False type questions : (i) Two-kingdom classification is the oldest and was proposed by Robert H. Whittaker in 1969. (ii) Euglena is a unicellular organism which has both animal and plant features. (iii) Bacteria and fungi are called decomposers or reducers. (iv) Liverworts and masses belong to the kingdom plantae. (v) Genetic material in eukaryotes is circular, double-stranded, helical DNA, not enclosed by a nuclear envelope. (vi) Blue-green algae (cyanobacteria) are the photosynthetic monerans. |
Answer» (i) False (ii) True (iii) True (iv) True (v) False (vi) True. | |
436. |
Beggiotoa is aA. ChemoautotrophB. PhotoautotrophC. PhotoheterotrophD. Chemoheterotroph |
Answer» Correct Answer - A Beggiotoa is a Chemoautotroph. |
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437. |
Trichodesmium erythraeum which gives colour to Red Sea isA. Green algaB. Blue-green algaeC. Red algaD. Brown alga |
Answer» Correct Answer - B Trichodesmiumerythreum which gives colour to red sea is Blue-green alga. |
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438. |
Which of the following is/are partially heterotrophic ?A. Parasites like CuscutaB. Insectivorous plants like Bladderwort and Venus fly trapC. Both A and BD. None of the above |
Answer» Correct Answer - C Parasites like Cuscuta and Isectivorous plants like Bladderwort and Venus fly trap are partially heterotrophic. |
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439. |
Partially independent sporophyte is found inA. RicciaB. LycopodiumC. FunariaD. Cycas |
Answer» Correct Answer - C Partially independent sporophyte is found in Funaria. |
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440. |
Viroids haveA. ssRNA enclosed in capsidB. ssDNA enclosed in capsidC. ssRNA without capsidD. ssDNA without capsid |
Answer» Correct Answer - C Viroids have ssRNA without capsid. |
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441. |
Organism which obtains their nutrition from dead and decaying matter (detritus) is calledA. ParasiticB. HolophyticC. SaprophyticD. Holozoic |
Answer» Correct Answer - C Organism which obtains their nutrition from dead and decaying matter (detritus) are called saprophytic. |
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442. |
Similarity between fungi and bacteriophage lies inA. Cell membraneB. Cell wallC. DNAD. Organelles |
Answer» Correct Answer - C DNA is present in both bacteriophage and fungi. |
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443. |
Edible part of mushroom isA. BasidicarpB. Fungal hyphaeC. Primary myceliumD. Basidiospore |
Answer» Correct Answer - A Edible part of mushroom is Basidicarp. |
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444. |
Give the botanical name of an edible mushroom. |
Answer» Agaricus campestris. | |
445. |
The IUPAC name of compound `H_(3)COOC-underset(CH_(2)OH)underset("| " )(CH)-COOCH_(3)` is:A. 2-(hydroxy methyl)methyl propanedioateB. dimethyl-2-(hydroxy methyl) propanedioateC. 2-(hydroxy methyl)dimethyl propanedioateD. none of the above |
Answer» Correct Answer - B |
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446. |
Which of the following is not correct?A. Ionic radius does not after the physical and chemical properties of an ionic compound.B. For ions derived from elements in different groups, the comparison in size is meaningfual only if the ions are isolectronic.C. Among isolectronic cations, the size decreases as the charge on cation increases.D. Among isolectronic anious, the size increases as the charge on anion increases. |
Answer» Correct Answer - A The three-dimensional structure and hence, the properties of an ionic compounds depend on the relative sizes of its cations and anions. Isoelectronic cations are smaller than anions: `r_(Na+)lt r_(F^(-)),r_(A1^(3+))lt r_(Mg^(2+)) lt_(Na^(+)), r_(O^(2)) gt r_(F^(-))` |
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447. |
Consider the following species: `N^(3-)`,`O^(2-)`,`F^(ө)`,`Na^(o+)`,`Mg^(2+)` and `Al^(3+)` a. What is common in them? b. Arrange them in the order of increasing ionic radii.A. All have same ionic radii.B. All are isoelectronic species having 10 electrons.C. All of them belong to the third period.D. The nature of oxides of all the ions is basic. |
Answer» Correct Answer - B | |
448. |
Between C and CO, which is a better reducing agent for ZnO? |
Answer» Case – I : [Coke as reducing agent] ZnO + C → Zn + CO, ∆G° becomes lesser as the T is more then 1120K. Case – II : [CO as reducing agent] ZnO + CO2 → Zn + CO, ∆G° becomes lesser when the T is more then 1323K. → The value of ∆G° is negative for a reaction to occur. → In the equation (1) ∆G° becomes negative at low temperature- so equation (1) is feasible i.r. C is a better reducing agent for ZnO. |
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449. |
What is rate determining step in a complex reaction? |
Answer» The overall rate of a reaction is controlled by the slowest step in a reaction is called the rate determining step in a complex reaction. |
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450. |
How is molar mass related to the elevation in boiling point of a solution? |
Answer» The expression for elevation of boiling point is ∆Tb = (Kb x 1000 x w)/(m x w) = Kb = molal elevation constant w = Weight of solute W = Weight of solvent m = molar mass of solute Molar mass of solute m = (Kb x 1000 x w)/(∆Tb x w) ∴ Molar mass of solute (m) and elevation of boiling point (∆Tb) are inversely related. |
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