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451.

Citrus canker is aA. Bacterial diseaseB. Algal diseaseC. Viral diseaseD. Fungal disese

Answer» Correct Answer - A
Citrus canker is a bacterial disease.
452.

Fungus Albugo is a member ofA. PhycomycetesB. AscomycetesC. BasidiomycetesD. Deuteromycetes

Answer» Correct Answer - A
Fungus Albugo is a member of Phycomycetes.
453.

A qualitive measure of the ability of an atom in____to attract shared electrons to itself is called electronativity.A. an ionic compoundB. a covalent compoundC. gaseous stateD. condensed state

Answer» Correct Answer - B
Electronegativity measure has ability of an atom in a molecule to attract shared electrons in a convalent bond.
454.

Which of the following is a measure of the firmness or strength with which an extra electron is bound to the free atom?A. First ionization enthalpyB. Second ionization enthalpyC. Third ionization enthalpyD. Zeroth ionization enthalpy

Answer» Correct Answer - D
Zeroth ionization enthalpy is the energy required to remove an electron from an isolated gaseous anion to form free atom.
`X^(-)(g) rarr X(g) +e^(-)`
It is numerically equal to first electron gain enthalpy.
455.

Energy is_______when an electron is added to isolated gaseous atom to form an ion with a `1-`charge.A. releasedB. absorbedC. nither released nor absorbedD. either released or absorbed

Answer» Correct Answer - D
The process is either exothermic or endothermic depending upon the nature of the element.
456.

Why are alkali metals not found in a free state in nature.

Answer»

Alkali metals are not found in the free state in nature because they readily lose their valency electron to form M+ ion (a non-valent ion).

457.

Calculate the pH of 0.05 M NaOH solution.

Answer»

[OH] = 0.05 = 5 ×10–2

pOH = – log[OH]

= – log (5 × 10–2) = – 0.699 + 2

= 1.3010 pH = 14 – pOH

= 14 – 1.3010 = 12.699

458.

Why is carbon monoxide poisonous?

Answer»

'CO' is majorly released into atmosphere due to automobile (vehicles).

→ 'CO' reacts with hemoglobin of blood & forms carboxy haemoglobin complex (stable)

→ Due to formation of above complex, prevention of transportation of O2 to different parts of the body takes place. 

→ If CO concentration is increased upto 1000 ppm in atmosphere then it leads to death.

459.

Calculate kinetic energy of 5 moles of nitrogen at 27°C

Answer»

n = 5

R = 2 cal

T = 27° C = 300 k

K.E = 3/2 nRT

= 3/2 x 5 x 2 x 300

= 4500 cal

460.

What is allotropy? Give the crystalline allotropes of carbon.

Answer»

Allotropy : The phenomenon of existence of an element in different properties is called allotropy.

Crystalline allotropes of carbon are

(a) Diamond 

(b) Graphite 

(c) Fullerenes.

461.

Give the reason for bleaching action of Cl2?

Answer»

Bleaching action of chlorine is due to its oxidizing property. When chlorine reacts with water, it gives nascent oxygen which decoloures is the coloured substance.

Cl2 + H2O → 2HCl + [O]

Coloured substance + [O] → Colourless substance

Bleaching action of chlorine creates permanent effect. It bleaches the vegetable of organic matter in the presence of moisture.

462.

How does SO2 react with the following? (i) Na2SO3(aq) (ii) Cl2 (iii) Fe+3ions (iv) KMnO4

Answer»

(i) Sodium sulphite (aq) reacts with So2 to form sodium hydrogen sulphite.

Na2SO3 + H2O + SO2 → 2NaHSO3

(ii) SO2 gas reacts with chlorine gas in the presence of charcoal to form suphuryl chloride.

SO2(g) + Cl2(g) → SO2Cl2(l)

(iii) Fe+3ions are reduced to Fe+2 ions by SO2

2Fe+3+ SO2 + 2H2O → 2Fe+2 + SO–24 + 4H+

(iv) SO2 gas decolourises acidified potassium permanganate

5SO2 + 2MnO4 + 2H2O → 5SO–24 + 4H++ 2Mn+2

463.

For a reaction, A + B → Product : the rate law is given by r = k [A]1/2 [B]2 What is the order of the reaction?

Answer»

A + B → product; r = k [A]1/2 [B]2

Rate of the reaction r = 1/2  + 2 = 2.5

464.

What is rate law? Illustrate with an example.

Answer»

The equation that describes mathematically the dependence of the rate of a reaction on the concentration terms of the reactions is known as the rate equation (or) rate law.

Eg : 2A + 3B → 3C

Rate of the given reaction ∝ [A]2 [B]3

465.

Describe lake as an ecosystem giving examples for the various zones and the biotic components in it.

Answer»

Deep water lakes contain three distinct zones namely 

(i) Littoral zone 

(ii) Limnetic zone 

(iii) Profundal zone.

(i) Littoral Zone : It is the shallow part of the lake closer to the shore. Light penetrates up to the bottom. It is 'euphotic' (having good light) has rich vegetation and higher rate of photosynthesis, hence rich in oxygen.

(ii) Limnetic Zone : It is the open water zone away from the shore. It extends up to the effective light penetration level, vertically. The imaginary line that separates the limntic zone from the profundal zone is known as 'zone of compensation/compensation point' light compensation level. It is the zone of effective light penetration. Here the rate of photosynthesis is equal to the rate of respiration. Limnetic zone has no contact with the bottom of the lake.

(iii) Profundal Zone : It is the deep water area present below the limnetic zone and beyond the depth of effective light penetration. Light is absent. Photosynthetic organisms are absent and so the water is poor in oxygen content. It includes mostly the anaerobic organisms which feed on detritus.

The organisms living in lentic habitat are classified into pedonic forms. Which live at the bottom of the lake and those living in the open waters of lakes, away from the shore vegetation are known as limnetic forms.

Biota (animal and plant life of a particular region) of the littoral zone :

 Littoral zone is rich with pedonic flora (especially up to the depth of the effective light penetration). At the shore proper emergent vegetation is abundant with firmly fixed roots in the bottom of the lake and shoots and leaves are exposed above the level of water. These are amphibious plants. Certain emergent rooted plants of littoral zone are the cattails (Typha) bulrushes (scripus) arrowheads (sagitlaria). Slightly deeper are the rooted plants with floating leaves, such as the water lilies (Nymphaea) Nelumbo, Trapa etc., still deeper are the submerged plants such as Hydrilla - Chasa, potamogeton etc. The free floating vegetation includes pista, wolffia, Lemna (duck weed), Azolla, Eichhornia etc.

The phytoplankton of the littoral zone composed of diatoms (coscinodiscus), Nitzschia etc) green algae (volvax spirogyra etc), euglenoids (Euglena, phacus etc) and dinoflagellates (Gymnodinium, cystodinium etc.) 

Animals the consumers of the littoral zone, are abundant in this zone of the lake, these are categorized into zooplankton, neuston, nekton, periphyton and benthos. The Zoo-plankton of the littoral zone consists of 'water fleas' such as Daphnia, rotizers and ostracods.

The animals living at the air-water interface constitute the neuston.They are of two types. The epineuston and hyponeuston. Water striders (Gerris), beetles, water bugs (Dineustes) from the epineustan/supraneuston and the hydoneustan/infraneuston includes the larvae of mosquitoes.

The animals such as fishes amphibians, water-snakes, terrapins, insects like water scorpion (Ranatra) back swimmer (Notonecta), driving beetley (Dytiscus), capable of swimming constitute the nekton.

The animals that are attached to / creeping on the aquatic plants, such as the 'water snails' nymphs of insects, bryozoauns, turbellarians, hydras etc., constitute the periphyton.

The animals that rest on or move on the bottom of the lake constitute the benthos  e.g: red anielids, chironomid, larvae, cray fishes, some isopods amphipods clams etc.

Biota of the Limnetic Zone : Limnetic zone is the largest zone of a lake. It is the region of rapid variations of the level of the water, temperature, oxygen availability, etc., from time to time. The limnetic zone has autotrophs (photosynthetic plants) in abundance. The chief autotrophs of this region are the phytoplankton such as the euglenoids, diatoms, cyanobacteria, dinoflagellates and green algae.

consumers of the limnetic zone are the zooplanktonic organisms such as the copepods, Fisher frogs, water snakes etc., form the limnetic nekton.

Biota of the Profundal Zone : It includes the organisms such as decomposers (bacteria),chironomid larvae, Chaoborus (phantom larva), red annelids, clams etc., that are capable of living in low oxygen levels. The decomposers of this zone decompose the dead plants and animals and release nutrients which are used by the biotic communities of both littoral and limnetic zones.

The lake ecosystem performs all the functions of any ecosystem and of the biosphere as a whole. i.e., conversation of inorganic substances into organic material, with the help of the radiant solar energy by the autotrophs, consumption of the autotrophs by the heterotrophs; decomposition and mineralization of the dead matter to release them back for reuse by the autotrophs (recycling of minerals).

466.

Write a short note on Cannabinoids.

Answer»

Cannabinoids : These are a group of chemicals obtained from Indian temp. plant cannabis sativa (varnacular name Ganjai mokka). They interact with cannabinoid receptors present in the brain. The flower tops, leaves and the resin of this plant are used in various combinations to produce marijuna, hashish, charas and ganja. These daufs, cannabinoids are being abused by even some sports - persons (doping). 

Mode of abuse : These are genarally taken by inhalation and oral ingestion. 

Effect : Show their effects on cardiovascular system of the body.

467.

Distinguish between nuclear fission and nuclear fusion. 

Answer»
Nuclear fissionNuclear fusion
1. In this process heavy nucleus is divided into two fragments along with few neutrons.1.In this process lighter nuclei will join together to produce heavy nucleus.
2. These reactions will takes place even at room temperature.2. These reactions will takes place at very high temperature such as 106 °C
3. To start fission at least one thermal neutron from out side3. No necessary of external neutrons.
4. Energy released per unit mass of participants is less.4. Energy released per unit mass of participants is high. Nearly seven time more than fission reaction.
5. In this process neutrons are liberated.5. In this process positrons are liberated.
6. This reaction can be controlled.
Ex : Nuclear reactor.
6. There is no control on fusion reaction.
7. Atom bomb works on principle of fission reaction.7. Hydrogen bomb works on the principle of fusion reaction.
8. The energy released in fission can be used for peaceful pur– pose.
Ex : Nuclear reactor and Atomic power stations.
8. The energy released in fusion cannot be used for peaceful purpose.
468.

Which of the following statements is incorrect about the class Deuteromycetes?A. They reporduce only by asexual spores (conidia).B. Mycelium in these fungi is branched and septate.C. They have only parasitic forms.D. Examples of these fungi are Altermaria, Colletotrichum and Trichoderma.

Answer» Correct Answer - C
Some mambers of Class Deuteromucetes are saprophytes or parasites while a larger number of them are decomposeres of litter and help in mineral cycling. Some examples are Collectotrichum and Trichoderma.
469.

Read the following statements and select the correct statement.A. Members of kingdom fungi show a great diversity in structures and habitatB. Most fungi are saprophytic in their mode of nutritionC. There are four classes under kingdom fungiD. All of the above

Answer» Correct Answer - D
`**` Members of kingdom fungi show a great diversity in structures and habitat.
`**` Most fungi are saprophytic in their mode of nutrition.
`**` There are four classes under kingdom fungi.
470.

Which one is an incorrectly mathc pair?A. Phycomycetes-Mucor, AlbugoB. Ascomycetes-Penicilium, AspergiliusC. Basicdomycetes-Puccinia,AgaricusD. Deuteromycetes-Ustiliago, Collectorichum

Answer» Correct Answer - D
Deuteromycetes is an artificial class of fungi which has been created to include all those fuggi in which sexual stage in either absent or not known. Ustilago is the member of Basidiomycetes.
471.

Select the incorrect math.A. Morels and truffles - phycomycetesB. puffbalss and toad stools-BasidiomycetesC. Early blight of potato-Altermaria solaniD. Late blight of potato-Phytophthora infestans

Answer» Correct Answer - A
Morels are Ascomycetes with edible ascocarps that have fleshy songe-like conical cap or pilus and a strik like stipe, e.g., Morchella esculenta (vern. Gucchi), M. crassipes, M. deliciosia. Truffles are edible Ascomycetes with tuber-like substerranean ascocarps that are often dug out with the help of trained dogs and pigs, e.g., Tuber uncinatum, T.aestivum.
472.

What is common among Agaricus, rust and smut ?A. All are parasitesB. All are the members of basidiomycetes and bears basidiocarpsC. All are not reproduced sexuallyD. Both B and C

Answer» Correct Answer - B
Agaricus, rust and smut all are the members of basidiomycetes and bears basidiocarps.
473.

What do you understand by self inductance?

Answer»

Self inductance of a coil is defined as the induced e.m.f produced in the coil through which the rate of change of current is unity.

ε  = - L(dI/dt); ε = - L if dI/dt = 1A/s.

474.

Define magnetic inclination (or) angle of dip. Define magnetic inclination (or) angle of dip.

Answer»

Inclination or Dip (I) : The angle which the total intensity of earth's magnetic field makes with the horizontal at any place is called inclination (I).

475.

A current carrying circular loop is placed in a uniform external magnetic field. If the loop is free to turn, what is its orientation when it is achieves stable equilibrium ?

Answer»

The plane of the loop is perpendicular to the direction of magnetic field because the torque on the loop in this orientation is zero.

476.

Which of the following processes was discovered by Lederberg and Tatum (1946) ?A. TransductionB. TransformationC. Asexual reproductionD. Conjugation

Answer» Correct Answer - D
Conjugation processes was discovered by Lederberg and Tatum (1946).
477.

Expand PPLO. What is its other name ?

Answer» Pleuropneumonia-like organisms, Mycoplasmas.
478.

Which of the following is incorrect?A. `IE_(1)` of `Li lt IE_(1)` of `Be`B. `IE_(1)` of `Be lt IE_(1)` of `B`C. `IE_(1)` of `Li lt IE_(1)` of `Na`D. `IE_(1)` of `He lt IE_(1)` of `Ne`

Answer» Correct Answer - B
`IE_(1)` of `Be gt IE_(1)` of `B` , In `Be`, removal occurs from `2s,` in `B` , it occurs from `2p`. The more closer are subshell to nucleus the more is `IE`.
479.

Identify the incorrect statement among the following:A. Lanthanoids contraction is the accumlation of successive linkages.B. as a result of lanthanoids contraction the properties of `4d` series of the transition elements have no similarities with the `5d` series of transition elements.C. shielding power of `4f` electrons is quite weakD. there is a decreases in the radii of the atoms or ions as one proceeds from `La` to `Lu`

Answer» Correct Answer - B
In each vertical column of transition element, the elemints of second and third transition series resemble each other more colsely than the elements of first and second transition series on account of lanthanoids contraction. Hence, the properties of elements resemble with the properties of the elements of `5d` of the transition elements.
480.

Which of the following is the most metallic element in the periodic table?A. `Fr`B. `Ba`C. `Ra`D. `Cs`

Answer» Correct Answer - D
`Fr` and `Ra` are radioactive elements, thus, they are not included in the disussion. In general, the metallic character of the elements decreases from left to right across a period in the periodic table and within each ground, the metallic character increases with increase of atomic number. Thus, `Cs` is the most metallic element in the periodic table.
481.

Which of the metals are usually referred to as lighter metals?A. `f`-block metalsB. `d`-block metalsC. `p`-block metalsD. `s`-block metals

Answer» Correct Answer - D
By definition, lighter metals have densities less than `5 g cm^(-3)`. All `s-`block metals except `Ra(5.5g cm^(-3))` have densities less than `5gm cm^(-3)`. In `d-`block metals, only `Sc(3.0g cm^(-3)), Ti(4.5 g cm^(-3))`, and `(4.5g cm^(-3))` have densities less than `5 g cm^(-3)`.
482.

Finding the size of an atom is a lot more complicated than measuring the radius of a ball because ltbrlt (i) the size of an atom is very small (ii) the electron cloub sorrounding the nucleus does not have a sharp boundary. (iii) we cannot isolate a single and measure its diameter the way we can measure the diameter of a ball (iv) atomic radius charges as atom moves from one environment to the other and also when the atom is present in different bonded states.A. `(i),(ii)`B. `(ii),(iii)`C. `(i),(ii),(iii),(iv)`D. `(ii),(iii),(iv)`

Answer» Correct Answer - C
`(a)` Atomic radii are so small that they are often stated in Angustoms `(1Å = 10^(-10)m)` or in the `SI` units, nanometers `(1nm = 10^(-9)m)` or picometers `(1"pm" = 10^(-12)m)`. To convert form `Å` to `nm`, move the decimal point one place to the left `(1Å =0.1 nm`). for example, the atomic radius of `Li` is `1.52Å` or `0.512 nm`.
`(2)` Atomic orbitals described in terms of probability desctributions of electrons over certain region in space are somewhat indefinite because the probability of finding an electron never becomes zero even at great distance form the nucleus, i.e., the size of an atom cannot be defined and determined precisely.
`(4)` If we are measuring the size of an atom when it is occupying a lattice site in the crystal, the value will be different from the one when it is colliding with another atom in the gaseous state. Furthermore, the size of the neutral atom will be different from the one when it is present as a cation or anion. Consequently, we cannot have one set of atomic radii applicable under all conditions.
483.

The electron density in an atom extends far beyond the nucleus. In practice, we normally think of atomic size as the volume containing about____percent of the total electron density around the nucleus.A. `100`B. `80`C. `70`D. `90`

Answer» Correct Answer - D
The probability density `|psi|^(2)` has always some value, howsoever small it may be, at any finite distance form the necleus. It is, therefore, not possible to draw a boundary surface diagram of a rigid size in which the probability of finding the electorn is `100%`
484.

The magnitude of the ______does not depend upon the packing of the particles when the substance is in the solid state.A. covalent radiusB. van der Waals radiusC. metallic radiusD. ionic radius

Answer» Correct Answer - A
Because it is one-half the distance between the nuclei of two convalently bonded atoms o fthe homonuclear diatomic molecule, its value depends only upon the bond length.
485.

There is no real boundary to an atom because the electrons can be defined only in terms of________.A. orbitalsB. orbitsC. shellsD. subshells

Answer» Correct Answer - A
Orbitals are defined in terms of probability.
486.

For all practical purposes, the size of an individual atom cannot be uniquely defined. An indirect approach is required. The size of an atom is determined by its immediate environment, especially its interaction with surrounding atoms. Pertaining to the types of bonding how many types of atomic radii are employed?A. TwoB. FourC. FiveD. Three

Answer» Correct Answer - B
Pertaining to four major types of bonding, atomic radii are of the following four types: covalent raidus, van der Walls radius, metallic raidus, and ionic radius.
487.

The covalent radius `(r_(cov))` is defined as the half-distance between the nuclei of two atoms of the same elecment joined in a________covalent bondA. multipleB. doubleC. singleD. triple

Answer» Correct Answer - C
The covalent radius of an atom is taken as half of the distance between nuclei in homonuclear diatomic molecules such as `C1_(2)`.
488.

Which of the following radius is not described for the element chlorine?A. Covalent radiusB. van der Waals radiusC. Metallic radiusD. Ionic radius

Answer» Correct Answer - C
Metallic radius is described for metals only while chlorine is a typical nonemtals.
489.

While dealing with multielectron atoms or ions, we must use the concept of effective nuclear charged, `Z_(eff)` which is calculated by the formulaA. `Z_(eff) = Z + sigma`B. `Z_(eff) = Z//sigma`C. `Z_(eff) = Z - sigma`D. `Z_(eff) = Zsigma^(2)`

Answer» Correct Answer - C
`Z_(eff)` is taken to be equal to the actual nuclear charge `(Z)` minus the screening or shielding) constant, `sigma`, of the inner screening electrons. The attraction of the outermost electrons by the nucleus is partly counterbalanced by the repulsion of teh outermost electrons by the electrons in the inner shell.
490.

Atomic radii can be measured byA. `X`-ray diffractionB. spectroscopic methodsC. both `(1)` and `(2)`D. photoelectric effect

Answer» Correct Answer - B
Wavelength of `X`rays metches with the size of atoms.
491.

For the transition elements, the variations in atomic radii are not so regular because electrons are being added to the __________subshell.A. `(n+1)d`B. `(n - 1)d`C. `nd`D. `(n+2)d`

Answer» Correct Answer - B
Electrons are being added to the inner shell.
492.

In the periodic table, going down in fluorine groupA. Ionic radius will increaseB. Electronegativity will increaseC. Reactivity will increaseD. Ionisation patential will increase

Answer» Correct Answer - A
Ionic radius will increase as number of shells increases.
493.

In the modern periodic table, elements are arranged inA. increasing massB. increasing volumeC. increasing atomic numberD. Alphabetically

Answer» Correct Answer - C
Increasing atomic number. Mosley found that atomic no. Was better fundamental properly than atomic weight.
494.

In `p`-block elements, the_________orbitals are successively filled.A. `(n +1)p`B. `(n - 1)p`C. `np`D. `(n +2)p`

Answer» Correct Answer - C
In the atoms of `p`-block elements, the differentiating electron enters the `p`-subshell of their respective outermost shells.
495.

Total number of `3^(@)` carbon atoms present in compound given below:

Answer» Correct Answer - 8
496.

`d-`blcok elements are the elements in which the differentiating electron enters the_____orbitals.A. `(n +1)d`B. `(n-1)d`C. `nd`D. `(n+2)d`

Answer» Correct Answer - B
In `d-`block elements, the last electron enters the `d`-subshell of their respective penultimate shells.
497.

Groups corresponding to the progressive filling of the `ns` and `np` orbitals represent the main group elements (also called representative elements). The total number of such groups in the periodic table isA. `8`B. `7`C. `6`D. `5`

Answer» Correct Answer - A
Elements in groups `1` and `2` and `13` through `18`, i.e., `A`-group elements in the periodic table are called representative elements. Their last electron is assigned to an outermost `s-`or `p`-orbital. These elements show distinct and fairly regular variations in their properties with changes in atomic number. The discussion of these elements takes up the majority of space in the texts because it is these elements that cover the widest range of chemical and physical properties.
498.

Which of the `d`-block elements has zero electrons in the `ns` subshell?A. `Pt`B. `Pb`C. `Ds`D. `Mt`

Answer» Correct Answer - B
It is palladium: `[Kr] 4d^(10)5s^(0)`
499.

What are complex reactions ? Name one Complex reaction.

Answer»

A sequence of elementary reactions, reactants give the products, the reactions are called complex reactions.

Eg : Oxidation of Ethane to CO2 and H2O passes through a series of intermediate steps in which alcohol, aldehyde and acid are formed.

500.

The highest Mn fluoride is MnF4 where as the highest oxide is Mn2O7. Why?

Answer»

The ability of oxygen to stabilize the high oxidation states exceeds that of fluoride. Thus the highest Mn fluoride is MnF4 where as highest oxide is Mn2O7.