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101.

The formula for SEP is given by ___________(a) [FN-D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}\)(b) [FN+D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}\)(c) [FN-D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H-\frac{V^2}{2g}\Big\}\)(d) [FN+D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H-\frac{V^2}{2g}\Big\}\)I had been asked this question by my college director while I was bunking the class.The above asked question is from High Performance Climb in section Climb and Descent Performance of Aircraft Performance

Answer»

Right choice is (a) [FN-D]\(\frac{V}{W}=\frac{d}{DT}\Big\{H+\frac{V^2}{2G}\Big\}\)

Explanation: The formula for SEP is given by [FN-D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}\) where FN is force, D is drag, H is height, V is velocity, g is acceleration due to gravitation. SEP stands for specific EXCESS power. It is equal to the rate of change of specific total energy (STE) and is used to increase the total energy of the aircraft which is in a combination with climb and acceleration.
Discussion
102.

What are the methods followed to gain advantage in air to air combat mission?(a) Accelerate to the operational height in a short time(b) Decelerate to the operational height in a short time(c) Accelerate to the operational height in a long time(d) Decelerate to the operational height in a long timeI have been asked this question in an interview for internship.I'd like to ask this question from High Performance Climb in section Climb and Descent Performance of Aircraft Performance

Answer» RIGHT answer is (a) Accelerate to the operational height in a short time

Explanation: The gain in advantage of AIR to air combat MISSION is gained by accelerating to the operational height in a short time and obtaining an optimum mach number in that short SPAN of time.
Discussion
103.

What is the operational technique in combat mission aircraft?(a) Minimizing the time required to increase the total energy of the aircraft to its combat height(b) Maximizing the time required to decrease the total energy of the aircraft to its combat height(c) Minimizing the time required to decrease the total energy of the aircraft to its combat height(d) Minimizing the time required to increase the total energy of the aircraft to its combat heightThe question was posed to me in unit test.I'm obligated to ask this question of High Performance Climb topic in section Climb and Descent Performance of Aircraft Performance

Answer»

The correct choice is (a) Minimizing the time required to increase the TOTAL energy of the aircraft to its combat height

The EXPLANATION is: The operational technique in combat MISSION aircraft is to MINIMIZE the time required to increase the total energy of the aircraft to its combat height. The gain in advantage of air to air combat mission is gained by accelerating to the operational height in a short time and OBTAINING an optimum mach number in that short span of time.
Discussion
104.

The time taken to increase the specific total energy will be minimized by maximizing the SEP.(a) True(b) FalseI have been asked this question by my school principal while I was bunking the class.Asked question is from High Performance Climb in division Climb and Descent Performance of Aircraft Performance

Answer»

The CORRECT choice is (a) True

Explanation: The time taken to INCREASE the SPECIFIC total energy will be minimized by maximizing the SEP. The formula for SEP is given by [FN-D]\(\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}\) where FN is force, D is drag, H is height, V is velocity, g is acceleration due to gravitation. SEP STANDS for specific EXCESS power. It is equal to the rate of change of specific total energy (STE) and is used to increase the total energy of the aircraft which is in a combination with climb and acceleration.
Discussion
105.

In transonic region the thrust is inversely proportional to drag.(a) True(b) FalseI had been asked this question in class test.The above asked question is from High Performance Climb topic in chapter Climb and Descent Performance of Aircraft Performance

Answer»

Correct answer is (a) True

Best explanation: In transonic region the thrust is INVERSELY PROPORTIONAL to drag. Acceleration across the transonic region can be assisted by reducing rate of climb of the aircraft but the priority is given to increase in KINETIC energy of the aircraft.
Discussion