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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the folloeing statement is (are) incorrect?A. 0.1 M KCl solution will have the same osmotic pressure as 0.1 M glucose solutionB. 0.1 M KCl solution will have the same boiling point as 0.1 M urea solutionC. 0.1 m glucose and 0.1 m urea are ismoticD. 0.1 m `MgCl_(2)` solution will have less relative lowering of vapour pressure than 0.1 m NaCl |
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Answer» Correct Answer - a,b,d |
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| 2. |
A complex is represented as `CoCl_(3) . XNH_(3)`. Its `0.1` molal solution in aqueous solution shows `Delta T_(f) = 0.558^(circ). (K_(f)` for `H_(2)O` is `1.86 K "molality"^(-1))` Assuming `100%` ionisation of complex and co-ordination number of `Co` as six, calculate formula of complex.A. `[Co(NH_(3)_(4)CL_(2)]Cl`B. `[Co(NH_(3))_(5)Cl]Cl_(2)`C. `[Co(NH_(3))_(4)CL_(2)]Cl`D. none of these |
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Answer» Correct Answer - b |
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| 3. |
Calculate the molecular weight of a substance whose `7.0%` (by weight) solution in water freezes at `-0.89^(@)C`. `(k_(f) "for" H_(2)O=1.86K"molality"^(-1)`). |
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Answer» `DeltaT_(f)=K_(f)xx"Molality"=K_(f)xx(wxx1000)/(mxxW)` w=7 g, W=100-7=93g, `DeltaT_(f)=0.89, K_(f)=1.86` `:.` Molecular wt., `m=(K_(f)xxwxx1000)/(WxxDeltaT_(f))=(1.86xx7xx1000)/(93xx0.89)` `=157.30` |
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| 4. |
A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05 M `BaCl_(2)`solution at 300 K ?A. 1.23 atmB. 3.69 atmC. 6.15 atmD. None of these |
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Answer» Correct Answer - a |
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| 5. |
When `250 mg` of eugenol is added to `100 g` of camphor `(K_(f) = 39.7K "molality"^(-1))`, it lowered the freezing point by `0.62^(@)C`. The molar mass of eugenol is:A. (a) `160g mol^(-1)`B. (b) `165g mol^(-1)`C. (c ) `200g mol^(-1)`D. (d) `250g mol^(-1)` |
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Answer» Correct Answer - A `m = (1000 xx K_(f) xx w)/(W xx Delta T)` `= (1000 xx 39.7 xx 250 xx 10^(-3))/(100 xx 0.62)` `= 160 g mol^(-1)` |
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| 6. |
Two liquid A and B have vapour pressure in the ratio ` P_A^(@) : P_B^(@)`=1.3 at a certain temperature.Assume A and B from an ideal solution and the ratio of mole fractions of A to B in the vapour phase is 4 : 3, then the mole fraction of B in the solution at the same tempreature is :A. `1/5`B. `2/3`C. `4/5`D. `1/4` |
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Answer» Correct Answer - a |
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| 7. |
For a ideal liquid solution with `P_A^(@)gtP_A^(@)`, which relation between` X_(A)` ((mole fraction of A in liquid phase) and `Y_(A)`(mole fraction of A in vapour phese) is correct ?A. `Y_(a) lt Y_(b)`B. `X_(A) gtX_(B)`C. `(Y_(A))/(Y_(B)) gt( X_(A))/(X_(B))`D. `(Y_(A))/(Y_(B)) lt( X_(A))/(X_(B))` |
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Answer» Correct Answer - c |
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| 8. |
1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is (`K_(f) of H_(2)O = 1.86 K kg "mol"^(-1)`):A. 0.2B. 0.25C. 0.4D. 0.5 |
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Answer» Correct Answer - b |
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| 9. |
An ideal solution has two components A is more volatile than B, i.e.`P_A^(@)gtP_B^(@)` and also` p_A^(@) gt P_("total")`. If `X_(A) andY_(A)` are mole fraction of components A in liquid and vapour phases, than :A. `X_(A) = Y_(A)`B. `X_(A) gt Y_(A)`C. `X_(A) lt Y_(A)`D. Data insuffcient |
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Answer» Correct Answer - c |
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| 10. |
100 g of `C_(6)H_(12)O_(6)` (aq.) solution has vapour pressure is equal to 40 torr at certain temperature. Vapour pressure of `H_(2)O`(l) is 40.18 torr at same temperature. If this solution is cooled to `-0.93^(@)C`, what mass of ice will be separated out? (`K_(f) = 1.86 kg "mol"^(-1)`):A. 95.5 gB. 4.5 gC. 45.5 gD. 47.8 g |
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Answer» Correct Answer - d |
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| 11. |
A simple of thliqid `H_(2)O` at 18.0 g is inlected into an evacuated 7.6 L flask maintained at `27.0^(@)C`. If vapour pressure of `H_(0)O` at `27.0^(@)C` is 24.63 mm Hg, what wight percentage of the water will be vaproueied when the ssystem comes to equilibrium? Assume water vapours behaves as an ideal gas. The volume occupied by the liquid water is negligible compared to the volume of the container:A. 0.01B. 0.1C. 0.18D. 0.2 |
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Answer» Correct Answer - a |
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| 12. |
When `20g` of naphthoic acid `(C_(11)H_(8)O_(2))` is dissolved in `50g` of benzene `(K_(f) = 1.72 K kg mol^(-1))`, a freezing point depression of `2K` is observed of `2K` is observed. The van,t Hoff factor `(i)` is:A. `0.5`B. `1.0`C. `2.0`D. `3.0` |
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Answer» Correct Answer - A `Delta T_(f) = K_(f) xx "molality" xx i` `2 = 1.72 xx (20)/(172) xx (1000)/(50) xx i` `i = 0.5` |
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| 13. |
The depression in freezing point of `0.01 m` aqueous `CH_(3)CooH` solution is `0.02046^(@)`, `1 m` urea solution freezes at `-1.86^(@)C`. Assuming molality equal to molarity, `pH` of `CH_(3)COOH` solution isA. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - b |
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| 14. |
An aqueous solution contain 3% and 1.8% by mass. Urea and glucose respectively. What is the freezing point of solution ? (`K_(f)=1.86^(@)C//m`)A. `-1.172^(@)C`B. `-2.27^(@)C`C. `-1.5^(@)C`D. none of these |
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Answer» Correct Answer - a |
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| 15. |
An aqueous solution of urea has a freezing point of `-0.515^(@)C`. Predict the osmotic pressure (in atm) of the same solution at `37^(@)C`. |
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Answer» Correct Answer - 7 |
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| 16. |
The total vapour pressure of a binary solution is gives byP = (`100X_(A) + 260 X_(B)`)mm Hg where,`X_(A)and X_(B)`are the molefractions of components A and B. This indicates that the:A. vapour pressure of solution is less than the pure B componentB. vapour pressure of solution is less than the pure A componentC. vapour pressure of pure A is 100 mm Hg and that of pure B is 260 mm HgD. the vapour pressure of pure A and B are 260 mm Hg and 100 mm hg respectively |
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Answer» Correct Answer - a,b,c |
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| 17. |
The lubricating action of an oil is more if it possess:A. (a) High vapour pressureB. (b) Low vapour pressureC. ( c) High surface tensionD. (d) High density |
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Answer» Correct Answer - B Substances of high vapour pressure (e.g., gasoline) evaporates more quickly than substance of low vapour pressure (e.g., motor oil). |
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| 18. |
The natural semipermeable membrane is:A. (a) Gelatinous `Cu_(2)Fe(CN)_(5)`B. (b) Gelatinous `Ca_(3)(PO_(4))_(2)`C. (c ) Plant cellD. (d) Phenol layer |
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Answer» Correct Answer - C A natural semipermeable membrane is one which exists in nature. |
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| 19. |
Equimolar solutions of two non-electroytes in the same solvent have:A. Same `b.pt.` but different `f.pt.`B. Same `f.pt.` but different `b.pt.`C. Same `b.pt.` and same `f.pt.`D. Different `b.pt.` and different `f.pt.` |
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Answer» Correct Answer - C `Delta T_(f) = K_(f) xx "molality"` `Delta T_(b) = K_(b) xx "molality"` Thus `Delta T` and `Delta T_(b)` for different non electronlytes is same as `K_(f)` and `K_(b)` constant. |
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| 20. |
The osmotic pressures of equimolar solutions of urea,`BaCl_(2)" and "AlCl_(3)`willl be in the order :A. `AlCl_(3) gt BaCl_(2)` gt ureaB. `BaCl_(2) gt AlCl_(3)` gtureaC. urea gt`BaCl_(2) gt AlCl_(3)`D. `BaCl_(2) gt "urea" gtAlCl_(3)` |
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Answer» Correct Answer - a |
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| 21. |
What is the composition of last droplet of liquid remaining in equilibrium with vapour?A. `x_(A) = 0.6,x_(B) = 0.4`B. `x_(A) = 0.5,x_(B) = 0.5`C. `x_(A) = 0.7,x_(B) = 0.3`D. `x_(A) = 0.3,x_(B) = 0.7` |
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Answer» Correct Answer - c |
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| 22. |
Boiling point composition diagram of the liqid-vapour equilibrium for A and B is shown in the figure. If a binary liquid mixture of A and B is distilled fractionally, which of the following would be correct observation ? A. Composition of the still (residus) will approach pure liquid B onlyB. composition of the distillate will approach pure A onlyC. Composition of distillate and residus will approach pure A and B respectivelyD. Neither of the componement can be obtained in pure state |
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Answer» Correct Answer - c |
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| 23. |
In mixture A and B ,components show -ve deviations as:A. `Delta V_(mix)` is `+ve`B. `A-B` interaction is weaker than `A-A` and `B-B` interactionC. `Delta H_(mix)` is `+ve`D. `A-B` interaction is stronger than `A-A` and `B-B` interaction |
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Answer» Correct Answer - D It is a required condition along with `Delta V = -ve` and `Delta H = -ve` |
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| 24. |
The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:A. `0.16`B. `0.05`C. `0.1`D. ` 0.2` |
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Answer» Correct Answer - A `Delta T_(b) = (1000 xx 0.52 xx 13.44)/(13.44 xx 1000) xx (1+2 alpha) (because alpha = 1)` `= 0.052 xx 3 = 0.156` |
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| 25. |
Elevation in boiling point of an aqueous solution of urea is `0.52 ( k_(b) "for water"=0.52K"molality"^(-1))`. The mole fraction is urea in this solution is :A. `0.98`B. `0.0567`C. `0.943`D. `0.02` |
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Answer» Correct Answer - D `Delta T = K_(b) xx "molality"` `0.52 = 0.52 xx "molality"` `:. (n)/(W) xx 1000 = 1` `(nxx1000)/((W)/(M) xx M) = 1` or `(n)/(N) = (18)/(1000)` or `(N+n)/(N) = (1018)/(1000) = 1.018` `:. (N)/(n+N) = 0.98`, `:. (n)/(n+N) = 0.02` |
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| 26. |
`0.75 g` of a non-electrolyte was dissolved in `87.9 g` of benzene. This raised the boiling point of benzene by `0.25^(@)C`. If the molecular mass of non-electrolyte is `103`, calculate the molal elevation constant for bezene. |
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Answer» Correct Answer - 3 `K_(b) = (Delta T_(b) xx m xx W)/(w xx 1000)` Given, `Delta T_(b) = 0.25 K, m = 103, w= 0.75g`, `W = 87.9g` `:. K_(b) = (0.25 xx 103 xx 87.9)/(0.75 xx 1000) ~~ 3.0 K log mol^(-1)` |
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| 27. |
cansider 0.1 M solutions of two solutesX and Y. The behaves as a univalent electrolyte while the solute Y dimerises in solution. Which of the following statement are correct regarding these solutions?(1) The boiling point of the solution of X will be higher than that of Y (2) The osmotic pressure of the solution of Y will be lower than that of X (3) The freezing point of the solition of X will be lower than that of Y (4) The relative lowering of vapour pressure of both the solutions will be the same lt brgt Select the correct answer from the option given belowA. 1, 2 and 3B. 2, 3 and 4C. 1, 2 and 4D. 1, 3 and 4 |
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Answer» Correct Answer - a |
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| 28. |
The relationship between osmotic pressure at `273 K` when `10 g` glucose `(P_(1)), 10 g` urea `(P_(2))` and `10 g` sucrose `(P_(3))` are dissolved in `250 mL` of water is:A. (a) `P_(1) gt P_(2) gt P_(3)`B. (b) `P_(3) gt P_(1) gtP_(2)`C. ( c) `P_(2) gt P_(1) gt P_(3)`D. (d) `P_(2) gt P_(3) gt P_(1)` |
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Answer» Correct Answer - C `P = (w)/(m.V)ST`, since `w, V,T` are constant Thus `P prop (1)/(m)` |
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| 29. |
A saturated solution of `XCl_(3)` has a vapour pressure 17.20 mm Hg at `20^(@)C`, while pure water vapour pressure is 17.25 mm Hg. Solubility product (`K_(sp)`) of `XCl_(3)` at `20^(@)`C is :A. `9.8 xx 10^(-2)`B. `10^(-5)`C. 2.56x`10^(-6)`D. 7x`10^(-5)` |
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Answer» Correct Answer - d |
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| 30. |
Moles of` Na_(2)SO_(4)` to be dissoved in 12 mole water to lower its vapour pressure by 10 mm Hg at a temperature at which vapour pressure of pure water is 50 mm is:A. 1.5 moleB. 2 moleC. 1 moleD. 3 mole |
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Answer» Correct Answer - c |
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| 31. |
The partial pressure of ethane over a saturated solution containing `6.56 xx 10^(-2) g` of ethane is 1 bar. If the solution contains `5.00 xx 10^(-2) g` of ethane, then what shall be the partial pressure of the gas? |
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Answer» `a prop P` `6.56 xx 10^(-2) prop 1` , `(P = 1 "bar")` `5.00 xx 10^(-2) prop P` `:. P = (1 xx 5.00 xx 10^(-2))/(6.56 xx 10^(-2)) = 0.762 "bar"` |
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| 32. |
In a mixture of A and B, components show positive deviation when:A. A-B interaction is stronger than A -A and B-B interactionB. A-B interaction is weaker than A-A and B-B interactionC. `/_V"mix" lt0, /_Smix gt0`D. `/_V"mix" = 0, /_Smix gt0` |
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Answer» Correct Answer - b |
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| 33. |
If 30 g a solute of molecular mass 154 is dissolved in 250 g of benzene. What will be the elevation in boiling point of the resuling solution ? (Given : `K_B(C_(6)H_(6)) =2.6 K kg mol^(-1)`) |
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Answer» Correct Answer - 2 |
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| 34. |
The composition of vapour when first bubble formed is:A. `y_(A) = 0.6,y_(b) = 04`B. `y_(A) = 0.48,y_(b) = 0.52`C. `y_(A) = 0.52,y_(b) = 0.48`D. `y_(A) = 0.5,y_(b) = 0.5` |
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Answer» Correct Answer - b |
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| 35. |
A liquid mixture ohaving composition corresponding to point Z in the figure shown is subjected to distillation at constant pressure. Which of the following statements is correct about the process? A. The composition of distillate differs from the mixtureB. The boiling point goes on changingC. The mixyure has highest vapour pressure than for any other compositionD. Composition of an azeotrope alters on changing the exernal pressure |
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Answer» Correct Answer - d |
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| 36. |
The vapour pressure of a liqid solution containing A and B is 99 torr. Colvulate mole % of in vapour phese. (Given : `P_(A^(@)) = 100 torr , P_(B^(@)) =80 torr)` |
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Answer» Correct Answer - 4 |
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| 37. |
In a 2.0 molal aqueus solution of a weak acid HX the degree of disssociation is 0.25. The freezing point of the solution will be nearest to: (`K_(f)=1.86 K kg "mol"^(-1)`)A. `-0.26^(@)C`B. `0.465^(@)C`C. `-0.48^(@)C`D. `-0.465^(@)C` |
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Answer» Correct Answer - d |
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| 38. |
An aqueous solution of 0.01 M KCl cause the same elevation in boiling point as an aqueous solution of urea. The concetration of urea solution is :A. 0.01 mB. 0.005 MC. 0.02 MD. 0.04 M |
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Answer» Correct Answer - c |
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| 39. |
During depression of freezing point in a solution, the following are in equilibrium:A. liquid solvent, solid solventB. liquid solvent, solid soluteC. liquid solute, solid soluteD. liquid solute, solid solvent |
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Answer» Correct Answer - A Only liquid freezes at freezing point. Thus equilibrium between solid and liquid forms exist at freezing point. |
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| 40. |
An experimenter tries to determine the molecular weight to glucose by observing the depression in freezing point. He carries out his experiment in duplicates. In one he uses pure water as the solvent and in the other independent experiment by mistake, he uses a `0.1 N` aqueous `NaCl` as the solvent. It is expected that he will report:A. (a) Same results in both the casesB. (b) A higher value of molecular weight of glucose in the second caseC. ( c) A lower value of molecular weight of glucose in the second caseD. (d) An average of the molecular weights of glucose and sodium chlorise in the second case |
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Answer» Correct Answer - A The molecular weight of non-volatile solute will remain same. |
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| 41. |
Study the following figure, and select the correct statements. A. There will be no mevement of any solution across the membraneB. Water from `BaCl_(2)` will flow towards the `NaCl` solutionC. Water from `NACl` will flow towards the `BaCl_(2)`D. The osmotic pressure of `0.1 M NaCl` is higher than the osmotic pressure of `0.05 M BaCl_(2)`, assuming complete dissociation of the electrolyte |
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Answer» Correct Answer - B::D `pi = I CRT` Assuming complete dissociation `pi_(NaCl) = 2 xx 0.1 RT = 0.2 RT` `pi_(BaCl_(2)) = 3 xx 0.05 xx RT = 0.15 RT` `:. pi_(NaCl) gt pi_(BaCl_(2))` `rArr` Water (solvent) will move from `BaCl_(2)` towards `NaCl` solution. |
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| 42. |
The depression in f.pt. of `0.01m` aqueous solution of urea, soldium chloride and soldium sulphate is in the ration:A. (a) `1:1:1:`B. (b) `1:2:3`C. ( c) `1:2:4`D. (d) `2:2:3` |
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Answer» Correct Answer - B `1` mole urea gives `1` mole. `1` mole `NaCl` gives `2` moles. `1` mole `Na_(2)SO_(4)` gives `3` moles. `:. Delta T` ratio `1:2:3` |
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| 43. |
The most likely an ideal solution is:A. (a) `NaCl-H_(2)O`B. (b) `C_(2)H_(5)OH-C_(6)H_(6)`C. ( c) `C_(7)H_(16(l))-H_(2)O`D. (d) `C_(7)H_(16(l))-C_(8)H_(18(l))` |
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Answer» Correct Answer - D Both are non-polar liquids and do not alter the forces of attraction among molecules. |
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| 44. |
When mercuric iodide is added to the aqueous solution of potassium iodide, then:A. freezing point is raisedB. Freezing point is loweredC. freezing point does not changeD. boilingpoint does not change |
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Answer» Correct Answer - a |
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| 45. |
Each pair forms ideal solution except:A. `C_(2)H_(5)Br` and `C_(2)H_(5)I`B. `C_(6)H_(5)Cl` and `C_(6)H_(5)Br`C. `C_(6)H_(6)` and `C_(6)H_(5).CH_(3)`D. `C_(2)H_(5)I` and `C_(2)H_(5)OH` |
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Answer» Correct Answer - D `C_(2)H_(5)OH` shows `H`-bonding as wll as both have polarity. |
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| 46. |
When mercuric iodide is added to the aqueous solution of potassium iodide, then:A. Freezing point is raisedB. Freezing point is loweredC. Freezing point does not changeD. Boiling point does not change |
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Answer» Correct Answer - A `HgI_(2)` although isoluble in water but shows complex formation with `KI` as: `2KI+HgI_(2)rarrK_(2)HgI_(4)` and this number of particles decreases in solution. |
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| 47. |
The correct relationship between the boiling points of very dilute solutions of `AlCl_(3)(t_(1))` and `CaCl_(2)(t_(2))` having the same molar concentration is:A. `t_(1)=t_(2)`B. `t_(1) gt t_(2)`C. `t_(2) gt t_(1)`D. `t_(2) get_(1)` |
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Answer» Correct Answer - B `AlCl_(3)` furnishes more ions than `CaCl_(2)` and thus shows higher `b.pt`. |
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| 48. |
Equal weights of methane and oxygen are mixed in an empty container at `25^(@)C`. The fraction of the total pressure exerted by oxygen isA. `(2)/(3)`B. `(1)/(3) xx (273)/(298)`C. `(1)/(3)`D. `(1)/(2)` |
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Answer» Correct Answer - C Let the masses of methane and oxygen are `w g` each. Mole fraction of oxygen `= ((w)/(32))/((w)/(32) + (w)/(16)) = ((1)/(32))/((1)/(32) + (1)/(16)) = ((1)/(32))/((3)/(32)) = (1)/(3)` Let the total pressure be `P`. The pressure exterted by oxygen (partial pressure) `= X_(O_(2)) xx P_("total") = P xx(1)/(3)` |
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| 49. |
0.1 M KI and 0.2 M `AgNO_(3)` are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [`K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1)`]:A. 3.72 KB. 1.86 KC. 0.93 KD. 0.279 K |
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Answer» Correct Answer - d |
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| 50. |
An aqueous solution is 1.00 molalin KI. Which change will cause the vapour pressure of the solution to increase ?A. addition of waterB. addtion of NaClC. addtion of `Na_(2)So_(4)`D. Addition of 1.0 molal KI |
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Answer» Correct Answer - a |
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