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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

A modulating signal is amplified by a 80% efficiency amplifier before being combined with a 20 kW carrier to generate an AM signal. The required DC input power to the amplifier, for the system to operate at 100% modulation, would be(a) 5 kW(b) 8.46 kW(c) 12.5 kW(d) 6.25 kWI had been asked this question by my school principal while I was bunking the class.My doubt stems from Amplitde Modulation topic in section EDC Overview of Electronic Devices & Circuits

Answer» CORRECT answer is (c) 12.5 KW

The best I can explain: Pi = PT -Pc = 30 – 20 = 10 kW. DC input = 10/0.8 or 12.5 kW.
2.

A battery has a short-circuit current of 30 A and an open circuit voltage of 24 V. If the battery is connected to an electric bulb of resistance 2 ohm^-1, the power dissipated by the bulb is(a) 80 W(b) 1800 W(c) 112.5 W(d) 228 WThe question was asked in an international level competition.This is a very interesting question from Network Theroms topic in division EDC Overview of Electronic Devices & Circuits

Answer» RIGHT option is (C) 112.5 W

Easy explanation: r = Voc/Isc = 1.2 ohm

Power USED by BULB = (24 x 24) x 2/(1.2 + 2) x (1.2 + 2) or 11.5 Watt.
3.

The network function (s^2 + 8s +15)/(s^2 + 6s + 8) is(a) RL admittance(b) RC admittance(c) LC admittance(d) All of the mentionedI got this question during an interview.The above asked question is from Circuit analysis in S domain in chapter EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT CHOICE is (a) RL admittance

To elaborate: The singularity nearest to origin is a POLE. So it may be a RL admittance or RC IMPEDANCE function.

4.

The mean value E[X(t)] is(a) 50(b) sqrt(50)(c) 20(d) sqrt(20)This question was posed to me in an international level competition.I'm obligated to ask this question of Random Process in portion EDC Overview of Electronic Devices & Circuits

Answer»

The correct answer is (d) sqrt(20)

EXPLANATION: LIM |t| TENDS to INFINITY, Rxx(t) = 20 = X^2. HENCE X is sqrt(20).

5.

Theprobability of the event that X is less than three is(a) 0.45(b) 0.50(c) 0.55(d) 0.60This question was posed to me during an interview.The above asked question is from Continous Time Signals in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Correct option is (b) 0.50

For EXPLANATION I WOULD say: The required answer is given by Fx(3.0) = FXY(3.0, infinity) =0.1 + 0.35 + 0.05 = 0.50.

6.

The probability of the event{X2.5, Y6} is(a) 0.45(b) 0.50(c) 0.55(d) 0.60I have been asked this question in quiz.My question comes from Continous Time Signals in portion EDC Overview of Electronic Devices & Circuits

Answer» RIGHT choice is (a) 0.45

To EXPLAIN: The required ANSWER is given by FXY(2.5, 6.0) = 0.1 + 0.35 = 0.45.
7.

What will be the value of i1 in the following circuit?(a) 20 mA(b) 15 mA(c) 10 mA(d) 5 mAThe question was asked by my college professor while I was bunking the class.The query is from Method of Analysis topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

The correct choice is (B) 15 mA

The best explanation: 45 = 2ki1 + 500(i1 + 15m) => i1 = 15 mA.

8.

The expect value of g(x) = X^3 is(a) 48(b) 192(c) 36(d) 72This question was addressed to me in an international level competition.This interesting question is from Continous Time Signals topic in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Correct ANSWER is (a) 48

Easy EXPLANATION: Solve E[G(X)] = E[X^3].

9.

If i1 = e^(-2t) and i2 = 0, the voltage v1 is(a) -6e^(-2t) V(b) 6e^(-2t) V(c) 1.5e^(-2t) V(d) -1.5e^(-2t) VThe question was asked during a job interview.I'd like to ask this question from Magneticaly coupled circuits in chapter EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT answer is (C) 1.5e^(-2t) V

Easiest explanation: v1 = 4 d(i1)/DT – 3 d(i2)/dt.

10.

The [y] parameter of a two port network is given byI had been asked this question in semester exam.This interesting question is from Two Port Network in section EDC Overview of Electronic Devices & Circuits

Answer»
11.

The voltage response of a network to a unit step input is Vo(s) = 10/s(s^2 + 8s + 16). The response is(a) under damped(b) over damped(c) critically damped(d) can’t be determinedI had been asked this question in an internship interview.This interesting question is from Circuit analysis in S domain in division EDC Overview of Electronic Devices & Circuits

Answer» CORRECT option is (C) CRITICALLY damped

The best EXPLANATION: The characteristic EQUATION has real and repeated roots (-4, -4). Hence it is critically damped.
12.

A mixer stage has a noise figure of 20 dB. This mixer stage is preceded by an amplifier which has a noise figure of 9 dB and an available power gain of 15 dB. The overall noise figure referred to the input is(a) 11.07(b) 18.23(c) 56.43(d) 97.38I have been asked this question in final exam.Origin of the question is Noise topic in section EDC Overview of Electronic Devices & Circuits

Answer» RIGHT CHOICE is (a) 11.07

Best EXPLANATION: The REQUIRED ANSWER is 7.94 + (100-1)/31.62 = 11.07.
13.

In silicon at T = 300 K the thermal-equilibrium concentration of electron is n0 = 5 x 10^4 cc. The hole concentration is(a) 4.5 x 10^15 cc(b) 4.5 x 10^15 m^3(c) 0.3 x 10^-6 cc(d) 0.3 x 10^-6 m^3This question was posed to me during an interview.This is a very interesting question from Semiconductor Physics topic in chapter EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT option is (a) 4.5 x 10^15 cc

The best I can EXPLAIN: NI x ni = no x PO.

14.

A parallel RLC circuit has R 1 k and C1 F. The quality factor at resonance is 200. The value of inductor is(a) 35.4 H(b) 25 H(c) 17.7 H(d) 50 HI had been asked this question during an online interview.Query is from Frequency Response in division EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT ANSWER is (b) 25 H

The EXPLANATION: Use Q = R (L/C)^0.5.

15.

Vth = ?(a) -2 V(b) -1 V(c) 1 v(d) 2 VI have been asked this question in an interview for internship.I'd like to ask this question from Network Theroms in division EDC Overview of Electronic Devices & Circuits

Answer»

Correct option is (C) 1 v

The best I can EXPLAIN: Vth = (2)(3)(1)/3+3 = 1V.

16.

A resistor R1 k is maintained at 17C. The rms noise voltage generated in a bandwidth of 10 kHz is(a) 16 x 10^(-14) V(b) 0.4 µV(c) 4 µV(d) 16 x 10^(-18) VThe question was posed to me during an online interview.My doubt stems from Noise in portion EDC Overview of Electronic Devices & Circuits

Answer» RIGHT ANSWER is (b) 0.4 µV

Explanation: v^2 = 4kBTR where symbols have their usual MEANINGS, HENCE v = 0.4 µV.
17.

A parallel circuit has R = 1k ohm , C = 50 µF and L = 10mH. The quality factor at resonance is(a) 100(b) 90.86(c) 70.7(d) None of the aboveI had been asked this question in an interview for job.The origin of the question is Frequency Response topic in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Correct OPTION is (c) 70.7

Best explanation: USE Q = R (L/C)^0.5.

18.

A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload is(a) 2.04 V(b) 1.08 V(c) 4.08 V(d) 2.16 VI had been asked this question at a job interview.The query is from Digital Transmission topic in section EDC Overview of Electronic Devices & Circuits

Answer»

Right CHOICE is (b) 1.08 V

Easiest EXPLANATION: Amax = (0.1 X 68K)/(2000p) or 1.08V.

19.

Four voice signals. each limited to 4 kHz and sampled at Nyquist rate are converted into binary PCM signal using 256 quantization levels. The bit transmission rate for the time-division multiplexed signal will be(a) 8 kbps(b) 64 kbps(c) 256 kbps(d) 512 kbpsI got this question during an online exam.Origin of the question is Digital Transmission in division EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT ANSWER is (c) 256 kbps

To elaborate: NYQUIST RATE2 x 4k = 8 kHz

Total SAMPLE 4 x 8 = 32 k sample/sec

256 = 2^8, so that 8 bits are required

Bit Rate32k x 8 = 256 kbps.

20.

A 10 kW carrier is sinusoidally modulated by two carriers corresponding to a modulation index of 30% and 40% respectively. The total radiated power is(a) 11.25 kW(b) 12.5 kW(c) 15 kW(d) 17 kWThe question was posed to me by my school teacher while I was bunking the class.This is a very interesting question from Amplitde Modulation topic in division EDC Overview of Electronic Devices & Circuits

Answer» CORRECT ANSWER is (a) 11.25 kW

The BEST EXPLANATION: The REQUIRED answer is 1 (1 + 0.4^2 + 0.3^2) or 11.25 kW.
21.

The current response of a network to a unit step input is Io(s) = 10(s + 2)/s(s^2 + 11s + 30). The response is(a) Under damped(b) Over damped(c) Critically damped(d) None of the mentionedThe question was asked in an interview.The above asked question is from Circuit analysis in S domain in portion EDC Overview of Electronic Devices & Circuits

Answer»

The correct answer is (b) Over DAMPED

For explanation I WOULD say: The ROOTS are real and unequal (-6, -5) for the characteristic equation. HENCE it is over damped.

22.

The variance of the random variable x is(a) 1/10(b) 3/80(c) 5/16(d) 3/16This question was posed to me by my college director while I was bunking the class.The origin of the question is Continous Time Signals topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

Right choice is (B) 3/80

To explain I WOULD SAY: VARIANCE is given by E[X^230] – 1/16.

23.

What will be the value of i1 in the following circuit?(a) 4 A(b) 3 A(c) 6 A(d) 5 AI got this question in class test.My doubt is from Method of Analysis in section EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT option is (b) 3 A

Easy EXPLANATION: 3 – 5i1 – 12 => i1 = 3A.

24.

The energy required to charge a 10 µF capacitor to 100 V is ________(a) 0.1 J(b) 0.05 J(c) 5 x 10^(-9) J(d) 10 x 10^(-9) JThe question was asked by my college professor while I was bunking the class.The origin of the question is Basic Concepts in chapter EDC Overview of Electronic Devices & Circuits

Answer»

The correct option is (B) 0.05 J

To ELABORATE: Energy provided is equal to 0.5 CVxV.

25.

In the circuit the dependent source __________(a) supplies 16 W(b) absorbs 16 W(c) supplies 32 W(d) absorbs 32 WThis question was addressed to me in an online interview.My question is from Basic Concepts topic in section EDC Overview of Electronic Devices & Circuits

Answer»

Correct choice is (d) absorbs 32 W

To EXPLAIN I would say: P = VIx = 2IxIx = 2 x 16 or 32 watt (absorb).

26.

Leq = ?(a) 2 H(b) 4 H(c) 6 H(d) 8 HI have been asked this question during an interview.I'd like to ask this question from Magneticaly coupled circuits topic in section EDC Overview of Electronic Devices & Circuits

Answer» RIGHT OPTION is (a) 2 H

Explanation: LEQ = L1 + L2 – 2M.
27.

If i2 = 4 cos(3t) and and i1 = 0. Find v2.(a) -12 cos(3t) V(b) -24 cos(3t) V(c) -36 cos(3t) V(d) -48 cos(3t) VI have been asked this question by my college director while I was bunking the class.Origin of the question is Magneticaly coupled circuits topic in section EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT OPTION is (c) -36 COS(3t) V

Easiest explanation: v2 = 3 d(I1)/DT + 2 d(i2)/dt.

28.

The probability that no car will arrive is(a) 0.516(b) 0.459(c) 0.246(d) 0.135I had been asked this question by my school teacher while I was bunking the class.My query is from Continous Time Signals in chapter EDC Overview of Electronic Devices & Circuits

Answer» RIGHT answer is (d) 0.135

For explanation: Evaluate P(X = 0).
29.

The response is(a) Over damped(b) Under damped(c) Critically damped(d) can’t be determinedThis question was posed to me by my college professor while I was bunking the class.Enquiry is from Circuit analysis in S domain topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

Right answer is (a) Over damped

The BEST I can EXPLAIN: The characteristic roots are real and unequal (-1, -3), therefore it is over damped.

30.

A sinusoidal massage signal m(t) is transmitted by binary PCM without compression. If the signal to-quantization-noise ratio is required to be at least 48 dB, the minimum number of bits per sample will be(a) 8(b) 10(c) 12(d) 14The question was asked during an interview for a job.My question is from Digital Transmission topic in division EDC Overview of Electronic Devices & Circuits

Answer» RIGHT CHOICE is (a) 8

The BEST explanation: 3(L^2)/2 = 48 db or L = 205.09. Since L is power of 2, so we SELECT L = 256 HENCE 256 = 2^8, So 8 bits per sample is required.
31.

A valid immittance function is(a) (s + 4)(s + 8)/(s + 2)(s – 5)(b) s(s + 1)/(s + 2)(s + 5)(c) s(s + 2)(s + 3)/(s + 1)(s + 4)(d) s(s + 2)(s + 6)/(s + 1)(s + 4)I got this question in an online interview.I need to ask this question from Circuit analysis in S domain in portion EDC Overview of Electronic Devices & Circuits

Answer»

The correct CHOICE is (d) s(s + 2)(s + 6)/(s + 1)(s + 4)

The best explanation: a) pole lie on positive real axis

b) poles and zero does not interlace on axis.

c) poles and zero does not interlace on axis.

d) is a valid immittance FUNCTION.

32.

In PCM system, if the quantization levels are increased form 2 to 8, the relative bandwidth requirement will(a) Remain same(b) Be doubled(c) Be tripled(d) Become four timesI have been asked this question during an online exam.My question is based upon Digital Transmission in portion EDC Overview of Electronic Devices & Circuits

Answer»

Right OPTION is (c) Be tripled

The explanation: If L = 2, then 2 = 2^n or n = 1 ND. If L = 8, then 8 = 2^n or n = 3. So RELATIVE bandwidth will be tripled.

33.

Total signal power is(a) 208 W(b) 204 W(c) 408 W(d) 416 WThe question was posed to me by my college director while I was bunking the class.This intriguing question originated from Amplitde Modulation topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT answer is (b) 204 W

For explanation: PC = 20×20/2 or 200 W. PT = Pc(1 + 0.2×0.2/4) or 204 W.

34.

[h] = ?I had been asked this question in a job interview.My question is based upon Two Port Network in section EDC Overview of Electronic Devices & Circuits

Answer»
35.

Air craft of Jet Airways at Ahmedabad airport arrive according to a Poisson process at a rate of 12 per hour. All aircraft are handled by one air traffic controller. If the controller takes a 2 – minute coffee break, what is the probability that he will miss one or more arriving aircraft?(a) 0.33(b) 0.44(c) 0.55(d) 0.66I have been asked this question during an interview.This question is from Random Process in section EDC Overview of Electronic Devices & Circuits

Answer» RIGHT answer is (a) 0.33

The best explanation: P (miss/or more AIRCRAFT) = 1 – P(miss 0) = 1 – P(0 ARRIVE).
36.

The network function (s + 1)(s + 4)/s(s + 2)(s + 5) represents(a) RC impedance(b) RL impedance(c) LC impedance(d) All of the mentionedThe question was posed to me by my college director while I was bunking the class.Query is from Circuit analysis in S domain topic in portion EDC Overview of Electronic Devices & Circuits

Answer»
37.

If a matched attenuator with a loss of 3.2 dB is placed between the source and the amplifier’s input, what is the operating spot noise figure of the attenuator amplifier cascade if the attenuator’s physical temperature is 290 K?(a) 9 db(b) 11.3 db(c) 10.4 db(d) 13.3 dbThis question was posed to me during an interview.Question is from Noise topic in division EDC Overview of Electronic Devices & Circuits

Answer»

Right answer is (d) 13.3 DB

Best explanation: Here TE is 290[(20.89-1) + (2.089)(7.98-1)] or 4544.4K. HENCE the required answer is 1 + 4544.4/290 = 212 or 13.3 db.

38.

Rn = ? (in ohm)(a) 10/3(b) 4(c) 6(d) 10This question was posed to me in unit test.This intriguing question originated from Network Theroms topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

Right answer is (a) 10/3

The BEST I can EXPLAIN: RN = (2||4) + 2.

39.

A 2-port resistive network satisfy the condition A = D = 3/2B = 4/3C. The z11 of the network is(a) 4/3(b) 3/4(c) 2/3(d) 3/2The question was posed to me in unit test.I want to ask this question from Two Port Network topic in section EDC Overview of Electronic Devices & Circuits

Answer» RIGHT OPTION is (a) 4/3

Easy EXPLANATION: Z11 = A/C = 4/3.
40.

The value of C is(a) 2 µF(b) 28.1 µF(c) 10 µF(d) 14.14 µFI had been asked this question in homework.Question is from Frequency Response topic in portion EDC Overview of Electronic Devices & Circuits

Answer» CORRECT CHOICE is (c) 10 µF

The EXPLANATION: Q = wRC or C = 80/(200 x 1000 x 40) or 10 µF.
41.

What will be the value of i1 in the following circuit?(a) 0.6 A(b) 2.1 A(c) 1.3 A(d) 1.7 AI have been asked this question during a job interview.My question is from Method of Analysis in section EDC Overview of Electronic Devices & Circuits

Answer»

The correct choice is (c) 1.3 A

To explain I would say: By NODAL analysis computing v1 and v2 where

(V1-75)/8 + V1/4 + (V1-V2)/2=0— (1)

(V1-V2)/2 + [V1-(10*6)]*/(10+5) + V2/3=0— (2)

*converting current source to voltage source (source transformation)

Hence, I1 = (v1-v2)/2 which gives i1 = 1.3A.

42.

A lightning bolt carrying 15,000 A lasts for 100 s. If the lightning strikes an airplane flying at 2 km, the charge deposited on the plane is _________(a) 13.33 C(b) 75 C(c) 1500 C(d) 1.5 CThis question was posed to me in a job interview.My query is from Basic Concepts in portion EDC Overview of Electronic Devices & Circuits

Answer» RIGHT option is (d) 1.5 C

Easy EXPLANATION: DQ = i dt = 15000 X 100µ = 1.5 C.
43.

The auto correlation Rxx(t1 = 0.5T, t2 = 0.7T) will be(a) 1(b) 0(c) A x A(d) 0.5 (A x A)I have been asked this question at a job interview.I'd like to ask this question from Random Process in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Right choice is (c) A X A

The explanation is: Here Rxx is AXA if both t1 and T2 are different and zero if they are same. Hence the answer is AxA.

44.

What will be the value of V1 in the following circuit?(a) 120 V(b) -120 V(c) 90 V(d) -90 VThis question was addressed to me in a job interview.My question is based upon Method of Analysis in division EDC Overview of Electronic Devices & Circuits

Answer»
45.

Consider the circuit graph shown in figure below. Each branch of circuit graph represent a circuit element. The value of voltage V1 is:(a) 30 V(b) 25 V(c) 20 V(d) 15 VI got this question in quiz.My enquiry is from Basic Concepts topic in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Right OPTION is (d) 15 V

The explanation: 100 = 65 + V2 => V2 = 35 V

V3 – 30 = V2 => V3 = 65 V

105 – V3 + V4 – 65 = 0 => V4 = 25 V

V4 + 15 – 55 + V1 = 0 => V1 = 15 V.

46.

If i1 = 4 cos(3t) and and i1 = 0. Find v2.(a) 12 cos(3t) V(b) -12 cos(3t) V(c) -24 cos(3t) V(d) 24 cos(3t) VThis question was addressed to me in an internship interview.The doubt is from Magneticaly coupled circuits topic in chapter EDC Overview of Electronic Devices & Circuits

Answer»

Right OPTION is (c) -24 cos(3T) V

For explanation I would say: V1 = 2 d(i1)/dt – 2 d(i2)/dt.

47.

The ratio of the transfer function Io/Is is(a) s(s + 4)/(s^2 + 3s + 4)(b) s(s + 4)/(s + 1)(s + 3)(c) (s^2 + 3s + 4)/s(s + 4)(d) (s + 1)(s + 3)/s(s + 4)I have been asked this question in an interview for job.This interesting question is from Circuit analysis in S domain in portion EDC Overview of Electronic Devices & Circuits

Answer»

The CORRECT OPTION is (b) s(s + 4)/(s + 1)(s + 3)

Explanation: Io/Is = (s + 4)/ (s + 4 + 3/s) = s(s + 4)/(s + 1)(s + 3).

48.

A TDM link has 20 signal channels and each channel is sampled 8000 times/sec. Each sample is represented by seven binary bits and contains an additional bit for synchronization. The total bit rate for the TDM link is(a) 1180 K bits/sec(b) 1280 K bits/sec(c) 1180 M bits/sec(d) 1280 M bits/secThis question was addressed to me in unit test.My question is based upon Digital Transmission topic in division EDC Overview of Electronic Devices & Circuits

Answer»

Correct ANSWER is (b) 1280 K bits/sec

To explain I would say: TOTAL sample8000 X 20 = 160 k sample/sec

Bit for each sample7 + 1 = 8

Bit RATE = 160k x 8 = 1280kilobits/sec.

49.

A speech signal occupying the bandwidth of 300 Hz to 3 kHz is converted into PCM format for use in digital communication. If the sampling frequency is8 kHz and each sample is quantized into 256 levels, then the output bit the rate will be(a) 3 kb/s(b) 8 kb/s(c) 64 kb/s(d) 256 kb/sI have been asked this question in an online quiz.Enquiry is from Digital Transmission in chapter EDC Overview of Electronic Devices & Circuits

Answer»

The correct answer is (c) 64 kb/s

The explanation: FS = 8 kHz, 2^n = 256 or n = 8. Bit RATE = 8 X 8k = 64 kb/s.

50.

In a DSB-SC system with 100% modulation, the power saving is(a) 100%(b) 55%(c) 75%(d) 100%I had been asked this question in quiz.I want to ask this question from Amplitde Modulation topic in portion EDC Overview of Electronic Devices & Circuits

Answer»

The correct choice is (B) 55%

The best I can explain: This is so because the POWER is suppressed by two thirds of the total. hence the power saving is 66%.