100 + Interview Questions in Edc Overview in Electronic Devices & Circuits Page 2 InterviewSolution

51.	An AM broadcast station operates at its maximum allowed total output of 50 kW with 80% modulation. The power in the intelligence part is(a) 12.12 kW(b) 31.12 kW(c) 6.42 kW(d) none of the mentionedI have been asked this question during an online interview.My enquiry is from Amplitde Modulation in chapter EDC Overview of Electronic Devices & Circuits
Answer» Right answer is (a) 12.12 kW Easiest explanation: PI = PT – PC = 50 – 37.88 kW or 12.12 kW.

Discussion

52.	What average operating noise figure results when the amplifier is used with an antenna of temperature 30 K?(a) 9.54 db(b) 10.96 db(c) 11.23 db(d) 12.96 dbI have been asked this question in an interview for internship.My doubt is from Noise topic in chapter EDC Overview of Electronic Devices & Circuits
Answer» RIGHT OPTION is (a) 9.54 DB The best I can explain: The REQUIRED ANSWER is 1 + 240/30 = 9 or 9.54 db.

Discussion

53.	In a receiver the input signal is 100 V, while the internal noise at the input is 10 V. With amplification the output signal is 2 V, while the output noise is 0.4 V. The noise figure of receiver is(a) 2(b) 0.5(c) 0.2(d) None of the mentionedI had been asked this question in an online quiz.Enquiry is from Noise topic in section EDC Overview of Electronic Devices & Circuits
Answer» Right CHOICE is (a) 2 For explanation: NF = (100/10)/(2/0.4) or 2.

Discussion

54.	How many weeds per year (average) can the Delhi expect the number of murders per week to equal or exceed the average number per week?(a) 15(b) 20(c) 25(d) 30This question was posed to me in my homework.Asked question is from Continous Time Signals in portion EDC Overview of Electronic Devices & Circuits
Answer» Right OPTION is (d) 30 To explain: P(3 or more) = 1 – P(0) – P (1) – P(2) = 0.5768. Therefore average number of weeks per year = 52 X 0.5768 or 29.994 weeks.

Discussion

55.	The probability that more than 3 cars will arrive during any 10 min period is(a) 0.249(b) 0.143(c) 0.346(d) 0.543The question was posed to me in quiz.This question is from Continous Time Signals topic in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct answer is (b) 0.143 The EXPLANATION: EVALUATE 1 – P(X = 0) – P(x = 1) – P(x = 2) – P(x = 3).

Discussion

56.	Rth = ? (in ohm)(a) 2(b) 3(c) 4(d) 5I have been asked this question in a national level competition.My question is from Network Theroms in chapter EDC Overview of Electronic Devices & Circuits
Answer» Correct ANSWER is (C) 4 Easiest EXPLANATION: Rth = (3\|\|6) + 2 or 4 ohm.

Discussion

57.	Analog data having highest harmonic at 30 kHz generated by a sensor has been digitized using 6 level PCM. What will be the rate of digital signal generated?(a) 120 kbps(b) 200 kbps(c) 240 kbps(d) 180 kbpsThe question was asked in examination.My enquiry is from Digital Transmission topic in division EDC Overview of Electronic Devices & Circuits
Answer» Correct ANSWER is (d) 180 kbps Explanation: Nyquist RATE = 2 x 30k = 60 KHZ 2^n should be GREATER than or equal to 6. Thus n 3, Bit Rate = 60×3 = 18 kHz.

Discussion

58.	If the amplifier is sold to engineering public, the noise figure that would be quoted in a catalog is(a) 0.46(b) 0.94(c) 1.83(d) 2.93This question was addressed to me by my college director while I was bunking the class.This intriguing question originated from Noise in portion EDC Overview of Electronic Devices & Circuits
Answer» Right answer is (C) 1.83 For EXPLANATION: The REQUIRED answer is 1 + (240/290).

Discussion

59.	On the average, how many weeks a year can Delhi expect to have no murders ?(a) 1.4(b) 1.9(c) 2.6(d) 3.4I had been asked this question in quiz.The query is from Continous Time Signals in portion EDC Overview of Electronic Devices & Circuits
Answer» Right answer is (c) 2.6 Explanation: P(0) = 0.0498. Hence average NUMBER of weeks per YEAR with no murder is 52 x P(0) = 2.5889 WEEK.

Discussion

60.	What will be the value of i1 in the following circuit?(a) 1 mA(b) 1.5 mA(c) 2 mA(d) 2.5 mAThe question was asked in a national level competition.My question is from Method of Analysis in chapter EDC Overview of Electronic Devices & Circuits
Answer»

Discussion

61.	What will be the value of Va in the following circuit?(a) -11 V(b) 11 V(c) 3 V(d) -3 VThe question was posed to me by my college professor while I was bunking the class.The doubt is from Method of Analysis topic in chapter EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT choice is (b) 11 V The best I can explain: By current division, we get 4A and 1A in resistors 2ohm and 3ohm respectively, APPLYING KVL in the bottom loop, we have Va = 2(4) + 3(1) = 11V.

Discussion

62.	If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is _________(a) 0.5 A(b) 2 A(c) 3.33 mA(d) 0.3 mAThis question was addressed to me in an interview.This interesting question is from Basic Concepts in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct ANSWER is (B) 2 A Best explanation: i = dQ/dt = 120/60 = 2A.

Discussion

63.	If i1 = 3 cos(4t) and and i2 = 0. Find v2.(a) -24 sin(4t) V(b) -36 sin(4t) V(c) sin(4t) V(d) -sin(4t) VI had been asked this question during an online interview.The origin of the question is Magneticaly coupled circuits topic in division EDC Overview of Electronic Devices & Circuits
Answer» CORRECT ANSWER is (a) -24 sin(4t) V For EXPLANATION I would say: v2 = -3 d(i1)/dt + 2 d(I2)/dt.

Discussion

64.	A speech signal has a total duration of 20 sec. It is sampled at the rate of 8 kHz and then PCM encoded. The signal-to-quantization noise ratio is required to be 40 dB. The minimum storage capacity needed to accommodate this signal is(a) 1.12 KBytes(b) 140 KBytes(c) 168 KBytes(d) None of the mentionedThis question was posed to me by my school teacher while I was bunking the class.This key question is from Digital Transmission in portion EDC Overview of Electronic Devices & Circuits
Answer» The correct option is (b) 140 KBYTES Explanation: (SNR)q = 1.76 + 6.02(n) = 40 dB, n = 6.35 We TAKE the n = 7. Capacity = 20 X 8k x 7 = 1.12 Mbits = 140 Kbytes.

Discussion

65.	Total sideband power is(a) 4 W(b) 8 W(c) 16 W(d) 2 WThe question was posed to me in an online interview.Origin of the question is Amplitde Modulation in division EDC Overview of Electronic Devices & Circuits
Answer» RIGHT CHOICE is (a) 4 W For explanation I would SAY: Pt – Pc = 204 – 200 = 4W.

Discussion

66.	The variance is(a) 20(b) 50(c) 70(d) 30The question was asked in an online quiz.Asked question is from Random Process in section EDC Overview of Electronic Devices & Circuits
Answer» The correct answer is (d) 30 Easy EXPLANATION: Here X = 0, y = 0, Rxx(0) = 5, Ryy(0) = 10. The only VALUE that satisfies all the given conditions is 30.

Discussion

67.	The modulation index is(a) 20(b) 4(c) 0.2(d) 10The question was posed to me by my college professor while I was bunking the class.This intriguing question comes from Amplitde Modulation topic in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct option is (C) 0.2 Explanation: 20 + 4SIN(500πt) = 20(1 + 0.2sin(500πt)), hence the MODULATION index is 0.2.

Discussion

68.	The E[X^2(t)] is(a) 10(b) sqrt(10)(c) 50(d) sqrt(50)This question was addressed to me during an online interview.My doubt stems from Random Process topic in section EDC Overview of Electronic Devices & Circuits
Answer» RIGHT choice is (C) 50 Easiest explanation: RXX(0) = X^2 = 50.

Discussion

69.	White noise with power density No/2 = 6 microW/Hz is applied to an ideal filter of gain 1 and bandwidth W rad/s. If the output’s average noise power is 15 watts, the bandwidth W is(a) 2.5 x 10 ^ (-6)(b) 2.5p x 10^(-6)(c) 5 x 10^(-6)(d) p5 x 10^(-6)I have been asked this question in quiz.I want to ask this question from Random Process in chapter EDC Overview of Electronic Devices & Circuits
Answer» RIGHT choice is (b) 2.5p x 10^(-6) The best I can explain: Pyy = 1/2p Integral(?xx(W) \|H(w)\|^2 dw ) from PLUS infinity to minus infinity. Hence solve for W.

Discussion

70.	Find V1 and V2.(a) -68.6 V, 114.3 V(b) 68.6 V, -114.3 V(c) 114.3 V, -68.6 V(d) -114.3 V, 68.6 VI got this question during an internship interview.I need to ask this question from Two Port Network in division EDC Overview of Electronic Devices & Circuits
Answer» Correct CHOICE is (B) 68.6 V, -114.3 V Best EXPLANATION: 800 = 10V1 – V2 and 3V2 = 5V1 = 0.

Discussion

71.	What will be the value of I1 in the following circuit?(a) 0.6 A(b) 0.5 A(c) 0.4 A(d) 0.1 AI have been asked this question during an interview.My enquiry is from Method of Analysis in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct OPTION is (d) 0.1 A For explanation: By NODAL analysis, 0.5=V1/30 + (V1-10)/20 i.e.V1=12V. So i1 = (v1-v2)/20, which GIVES i1=0.1A.

Discussion

72.	What will be the value of V2 in the following circuit?(a) 0.5 V(b) 1.0 V(c) 1.5 V(d) 2.0 VThis question was posed to me during an interview.The query is from Method of Analysis in section EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT CHOICE is (d) 2.0 V Easy EXPLANATION: V2/20 + V2+10/30 = 0.5 V or V2 = 2.0 V.

Discussion

73.	The network function s^2 + 10s + 24/s^2 + 8s + 15 represents(a) RC impedance(b) RL impedance(c) LC impedance(d) None of the mentionedThe question was asked in a job interview.This key question is from Circuit analysis in S domain topic in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct answer is (d) None of the mentioned To explain I would say: The singularity is NEAR to origin is pole. So it MAY be RC impedance or RL ADMITTANCE function.

Discussion

74.	In = ?(a) 1.5 A(b) 3 A(c) 6 A(d) 10 AThis question was posed to me in semester exam.This intriguing question comes from Network Theroms topic in portion EDC Overview of Electronic Devices & Circuits
Answer» RIGHT option is (B) 3 A Explanation: V1 = (15/2)/(1/4 + 1/2 + 1/2) In = ISC = V1/2 = 3 A.

Discussion

75.	Four signals each band limited to 5 kHz are sampled at twice the Nyquist rate. The resulting PAM samples are transmitted over a single channel after time division multiplexing. The theoretical minimum transmissions bandwidth of the channel should be equal to(a) 5 kHz(b) 20 kHz(c) 40 kHz(d) 80 kHzThe question was posed to me by my school principal while I was bunking the class.This key question is from Digital Transmission topic in portion EDC Overview of Electronic Devices & Circuits
Answer»

Discussion

76.	A carrier is simultaneously modulated by two sine waves with modulation indices of 0.4 and 0.3. The resultant modulation index will be(a) 1.0(b) 0.7(c) 0.5(d) 0.35I got this question in my homework.My question is from Amplitde Modulation topic in chapter EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT OPTION is (C) 0.5 Best EXPLANATION: α^2 = 0.3^2 + 0.4^2 = 0.5^2 or α = 0.5.

Discussion

77.	The aerial current of an AM transmitter is 18 A when unmodulated but increases to 20 A when modulated.The modulation index is(a) 0.68(b) 0.73(c) 0.89(d) 0.95I have been asked this question in unit test.The doubt is from Amplitde Modulation topic in division EDC Overview of Electronic Devices & Circuits
Answer» The correct OPTION is (a) 0.68 To explain I would say: 400/326 = 1 + (α^2)/2, therefore α is 0.68.

Discussion

78.	A system has three stage cascaded amplifier each stage having a power gain of 10 dB and noise figure of 6 dB. the overall noise figure is(a) 1.38(b) 6.8(c) 4.33(d) 10.43I got this question in an international level competition.I'd like to ask this question from Noise topic in portion EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT option is (c) 4.33 The explanation is: The gain at each stage is 10DB, HENCE the REQUIRED answer is 4 + (4-1)/10 + (4-1)/100 or 4.33.

Discussion

79.	A stationary random process X(t) is applied to the input of a system for which h(t) = u(t) t^2 e^(-8t). If E[X(t)] = 2, the mean value of the system’s response Y(t)is(a) 1/128(b) 1/64(c) 3/128(d) 1/32I had been asked this question during a job interview.Query is from Random Process in division EDC Overview of Electronic Devices & Circuits
Answer» CORRECT option is (C) 3/128 Easiest explanation: The mean VALUE of Y(t) is integral of h(t)dt over NEGATIVE infinity to POSITIVE infinity which gives the value equal to 3/128.

Discussion

80.	A capacitor is charged by a constant current of 2 mA and results in a voltage increase of 12 V in a 10 sec interval. The value of capacitance is ________(a) 0.75 mF(b) 1.33 mF(c) 0.6 mF(d) 1.67 mFI had been asked this question in an interview.This intriguing question originated from Basic Concepts in portion EDC Overview of Electronic Devices & Circuits
Answer» The correct answer is (d) 1.67 mF The explanation is: The capacitor current is given as i=C*(dv/dt), where dv/dt is the DERIVATIVE of voltage, dt=t2-t1given as 10 SEC and dv is the change in voltage which is given as 12V. So, we have C=i/(dv/dt) => C = 2mA/(12/10) = 2mA/(1.2). Hence C = 1.67mF.

Discussion

81.	Twelve 6 ohm resistors are used to form an edge of a cube. The resistance between two diagonally opposite corner of the cube (in ohm) is ________(a) 5/6(b) 6/5(c) 5(d) 6This question was posed to me in quiz.My question is based upon Basic Concepts in division EDC Overview of Electronic Devices & Circuits
Answer» Correct choice is (c) 5 The BEST explanation: The current I will be DISTRIBUTED to the cube branches symmetrically. Connecting a VOLTAGE source Vab across the TERMINALS and applying kvl in the outer loop, we have => -Vab + (i/3+i/6+i/3)*R = 0(where R is given as 6ohm) => Vab = 5i => Req=Vab/i, which gives Req = 5OHM.

Discussion

82.	[y] = ?I had been asked this question in an international level competition.The question is from Two Port Network in portion EDC Overview of Electronic Devices & Circuits
Answer»

Discussion

83.	The value of inductor is(a) 4.3 mH(b) 43 mH(c) 0.16 mH(d) 1.6 mHI have been asked this question in an internship interview.Query is from Frequency Response in portion EDC Overview of Electronic Devices & Circuits
Answer» The correct ANSWER is (c) 0.16 mH The EXPLANATION: w = (86 + 90)k/2 = 88 = (1/LC)^(0.5) or L = 0.16 mH.

Discussion

84.	The equivalent to the given circuit isI got this question by my school principal while I was bunking the class.I'd like to ask this question from Network Theroms topic in chapter EDC Overview of Electronic Devices & Circuits
Answer»

Discussion

85.	A 2 MHz carrier is amplitude modulated by a 500 Hz modulating signal to a depth of 70%. If the unmodulated carrier power is 2 kW, the power of the modulated signal is(a) 2.23 kW(b) 2.36 Kw(c) 1.18 kW(d) 1.26 kWI got this question during an interview.Query is from Amplitde Modulation in section EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT answer is (a) 2.23 kW To explain: PT = Pc (1 + 0.49/2).

Discussion

86.	A receiver is operated at a temperature of 300 K. The transistor used in the receiver have an average output resistance of 1 k. The Johnson noise voltage for a receiver with a bandwidth of 200 kHz is(a) 1.8 µV(b) 8.4 µV(c) 4.3 µV(d) 12.6 µVI have been asked this question in an online quiz.The origin of the question is Noise in chapter EDC Overview of Electronic Devices & Circuits
Answer» CORRECT CHOICE is (a) 1.8 µV To explain: v^2 = 4kBTR where SYMBOLS have their USUAL MEANINGS, hence v = 1.8 µV.

Discussion

87.	A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is _________(a) 160.2 C(b) -160.2 C(c) 16.02 C(d) -16.02 CI have been asked this question during an interview for a job.The above asked question is from Basic Concepts topic in section EDC Overview of Electronic Devices & Circuits
Answer» Correct ANSWER is (C) 16.02 C The explanation: n10^20, Q = ne = e 10^20 = 16.02 C. Charge on sphere will be POSITIVE.

Discussion

88.	A series resonant circuit has an inductor L = 10 mH. The resonant frequency w = 10^6 rad/s and bandwidth is BW = 10^3 rad/s. The value of R and C will be(a) 100 F, 10 ohm(b) 100 pF, 10 ohm(c) 100 pF, 10 Mega-ohm(d) 100 µF, 10 Meg-ohmThe question was asked in an online quiz.My question comes from Frequency Response in chapter EDC Overview of Electronic Devices & Circuits
Answer» The correct choice is (B) 100 PF, 10 ohm Easy explanation: Use WXW = 1/LC and BW = R/L.

Discussion

89.	The network function (3s^2 + 8s)/(s + 1)(s + 3) represents(a) RC impedance(b) RL impedance(c) LC impedance(d) None of the mentionedI had been asked this question in my homework.This is a very interesting question from Circuit analysis in S domain topic in chapter EDC Overview of Electronic Devices & Circuits
Answer» The correct OPTION is (c) LC IMPEDANCE To explain: The singularity nearest to ORIGIN is a zero. So it may be RL impedance or RC admittance function. Because of (D) option it is required to CHECK that it is a valid RC admittance function. The poles and ZEROS interlace along the negative real axis. The residue of Yrc(s)/s is positive.

Discussion

90.	The probability that there will be five or more murder in a given week is(a) 0.1847(b) 0.2461(c) 0.3927(d) 0.4167The question was asked in quiz.My enquiry is from Continous Time Signals topic in division EDC Overview of Electronic Devices & Circuits
Answer» The correct choice is (a) 0.1847 For EXPLANATION I would SAY: P(5 or more) = 1 – P(0) – P(1) – P(2) – P(3) – P(4) = 0.1847.

Discussion

91.	The network function (s^2 + 4s)/(s + 1)(s + 2)(s + 3) represents(a) RC impedance(b) RL impedance(c) LC impedance(d) None of the mentionedThis question was addressed to me in homework.I need to ask this question from Circuit analysis in S domain in portion EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT CHOICE is (d) None of the mentioned The best EXPLANATION: POLES and zero does not interlace on negative REAL axis so it is not a immittance function.

Discussion

92.	The energy required to move 120 coulomb through 3 V is _________(a) 25 mJ(b) 360 J(c) 40 J(d) 2.78 mJI have been asked this question in an international level competition.The query is from Basic Concepts in section EDC Overview of Electronic Devices & Circuits
Answer» Right choice is (b) 360 J For EXPLANATION: W = QV = 360 J.

Discussion

93.	A series resonant circuit has L = 1 mH and C = 10 F. The required R (in ohm) for the BW = 15 9 . Hz is(a) 0.1(b) 0.2(c) 0.0159(d) 500I got this question in a national level competition.Asked question is from Frequency Response topic in portion EDC Overview of Electronic Devices & Circuits
Answer» CORRECT CHOICE is (a) 0.1 To EXPLAIN: USE BW = R/L.

Discussion

94.	The quality factor is(a) 22(b) 100(c) 48(d) 200I got this question in an online quiz.I would like to ask this question from Frequency Response in portion EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT OPTION is (a) 22 The best EXPLANATION: Q = w/BW = 176pK/8pk = 22.

Discussion

95.	What will be the value of Req in the following Circuit?(a) 11.86 ohm(b) 10 ohm(c) 25 ohm(d) 11.18 ohmI got this question by my school teacher while I was bunking the class.My question is from Basic Concepts in section EDC Overview of Electronic Devices & Circuits
Answer» Correct choice is (d) 11.18 ohm The explanation: We infer from the given DIAGRAM that the same pattern is followed after every 10ohm resistor. The infinite pattern in PARALLEL as a whole is considered as to be RX. Thus, Rx = R + (R\|\|Rx) Solving for Rx, we get Rx = 1.62R, where R=10ohm. So we have Rx = (1.62ohm)(10ohm), which gives Rx=16.2ohm Therefore, Req = 5 + (10\|\|16.2) => 5 + [(1016.2)/(10+16.2)] => Req = 5 + (162/26.2) which gives Req=11.18 ohm.

Discussion

96.	Assuming that the signal is quantized to satisfy the condition of previous question and assuming the approximate bandwidth of the signal is W. The minimum required bandwidth for transmission of a binary PCM signal based on this quantization scheme will be(a) 5 W(b) 10 W(c) 20 W(d) None of the mentionedThe question was asked in homework.My question is from Digital Transmission in portion EDC Overview of Electronic Devices & Circuits
Answer» Right ANSWER is (b) 10 W To elaborate: The minimum bandwidth requirement for TRANSMISSION of a binary PCM SIGNAL is BW= vW. Since v10, we have BW = 10 W.

Discussion

97.	The Te is(a) 70 K(b) 110 K(c) 149 K(d) 240 KThe question was posed to me in an online interview.I would like to ask this question from Noise in section EDC Overview of Electronic Devices & Circuits
Answer» The CORRECT option is (d) 240 K To EXPLAIN I would say: The REQUIRED ANSWER is 60 (5-1) or 240K.

Discussion

98.	What is the maximum average effective input noise temperature that an amplifier can have if its average standard noise figure is to not exceed 1.7?(a) 203 K(b) 215 K(c) 235 K(d) 255 KI had been asked this question in a job interview.The above asked question is from Noise in portion EDC Overview of Electronic Devices & Circuits
Answer» Right ANSWER is (a) 203 K Explanation: The required answer is 290 x (1.7-1) or 203K.

Discussion

99.	The value of R (in ohm) is(a) 40(b) 56.57(c) 80(d) 28.28This question was posed to me in an interview.I need to ask this question from Frequency Response topic in chapter EDC Overview of Electronic Devices & Circuits
Answer» Correct option is (a) 40 To elaborate: At mid-band FREQUENCY Y = 1/R or R = 1000/25 or 40 OHM.

Discussion

100.	The mean of the random variable x is(a) 1/4(b) 1/6(c) 1/3(d) 1/5I have been asked this question in examination.The question is from Continous Time Signals topic in portion EDC Overview of Electronic Devices & Circuits
Answer» Correct option is (a) 1/4 The best I can explain: Solve integral (X F(x) dx) from NEGATIVE infinity to x.

Discussion

Explore topic-wise InterviewSolutions in .

The probability that more than 3 cars will arrive during any 10 min period is(a) 0.249(b) 0.143(c) 0.346(d) 0.543The question was posed to me in quiz.This question is from Continous Time Signals topic in portion EDC Overview of Electronic Devices & Circuits

Rth = ? (in ohm)(a) 2(b) 3(c) 4(d) 5I have been asked this question in a national level competition.My question is from Network Theroms in chapter EDC Overview of Electronic Devices & Circuits

On the average, how many weeks a year can Delhi expect to have no murders ?(a) 1.4(b) 1.9(c) 2.6(d) 3.4I had been asked this question in quiz.The query is from Continous Time Signals in portion EDC Overview of Electronic Devices & Circuits

What will be the value of i1 in the following circuit?(a) 1 mA(b) 1.5 mA(c) 2 mA(d) 2.5 mAThe question was asked in a national level competition.My question is from Method of Analysis in chapter EDC Overview of Electronic Devices & Circuits

What will be the value of Va in the following circuit?(a) -11 V(b) 11 V(c) 3 V(d) -3 VThe question was posed to me by my college professor while I was bunking the class.The doubt is from Method of Analysis topic in chapter EDC Overview of Electronic Devices & Circuits

If i1 = 3 cos(4t) and and i2 = 0. Find v2.(a) -24 sin(4t) V(b) -36 sin(4t) V(c) sin(4t) V(d) -sin(4t) VI had been asked this question during an online interview.The origin of the question is Magneticaly coupled circuits topic in division EDC Overview of Electronic Devices & Circuits

Total sideband power is(a) 4 W(b) 8 W(c) 16 W(d) 2 WThe question was posed to me in an online interview.Origin of the question is Amplitde Modulation in division EDC Overview of Electronic Devices & Circuits

The variance is(a) 20(b) 50(c) 70(d) 30The question was asked in an online quiz.Asked question is from Random Process in section EDC Overview of Electronic Devices & Circuits

The modulation index is(a) 20(b) 4(c) 0.2(d) 10The question was posed to me by my college professor while I was bunking the class.This intriguing question comes from Amplitde Modulation topic in portion EDC Overview of Electronic Devices & Circuits

The E[X^2(t)] is(a) 10(b) sqrt(10)(c) 50(d) sqrt(50)This question was addressed to me during an online interview.My doubt stems from Random Process topic in section EDC Overview of Electronic Devices & Circuits

Find V1 and V2.(a) -68.6 V, 114.3 V(b) 68.6 V, -114.3 V(c) 114.3 V, -68.6 V(d) -114.3 V, 68.6 VI got this question during an internship interview.I need to ask this question from Two Port Network in division EDC Overview of Electronic Devices & Circuits

What will be the value of I1 in the following circuit?(a) 0.6 A(b) 0.5 A(c) 0.4 A(d) 0.1 AI have been asked this question during an interview.My enquiry is from Method of Analysis in portion EDC Overview of Electronic Devices & Circuits

What will be the value of V2 in the following circuit?(a) 0.5 V(b) 1.0 V(c) 1.5 V(d) 2.0 VThis question was posed to me during an interview.The query is from Method of Analysis in section EDC Overview of Electronic Devices & Circuits

The network function s^2 + 10s + 24/s^2 + 8s + 15 represents(a) RC impedance(b) RL impedance(c) LC impedance(d) None of the mentionedThe question was asked in a job interview.This key question is from Circuit analysis in S domain topic in portion EDC Overview of Electronic Devices & Circuits

In = ?(a) 1.5 A(b) 3 A(c) 6 A(d) 10 AThis question was posed to me in semester exam.This intriguing question comes from Network Theroms topic in portion EDC Overview of Electronic Devices & Circuits

[y] = ?I had been asked this question in an international level competition.The question is from Two Port Network in portion EDC Overview of Electronic Devices & Circuits

The value of inductor is(a) 4.3 mH(b) 43 mH(c) 0.16 mH(d) 1.6 mHI have been asked this question in an internship interview.Query is from Frequency Response in portion EDC Overview of Electronic Devices & Circuits

The equivalent to the given circuit isI got this question by my school principal while I was bunking the class.I'd like to ask this question from Network Theroms topic in chapter EDC Overview of Electronic Devices & Circuits

The probability that there will be five or more murder in a given week is(a) 0.1847(b) 0.2461(c) 0.3927(d) 0.4167The question was asked in quiz.My enquiry is from Continous Time Signals topic in division EDC Overview of Electronic Devices & Circuits

The energy required to move 120 coulomb through 3 V is _________(a) 25 mJ(b) 360 J(c) 40 J(d) 2.78 mJI have been asked this question in an international level competition.The query is from Basic Concepts in section EDC Overview of Electronic Devices & Circuits

A series resonant circuit has L = 1 mH and C = 10 F. The required R (in ohm) for the BW = 15 9 . Hz is(a) 0.1(b) 0.2(c) 0.0159(d) 500I got this question in a national level competition.Asked question is from Frequency Response topic in portion EDC Overview of Electronic Devices & Circuits

The quality factor is(a) 22(b) 100(c) 48(d) 200I got this question in an online quiz.I would like to ask this question from Frequency Response in portion EDC Overview of Electronic Devices & Circuits

What will be the value of Req in the following Circuit?(a) 11.86 ohm(b) 10 ohm(c) 25 ohm(d) 11.18 ohmI got this question by my school teacher while I was bunking the class.My question is from Basic Concepts in section EDC Overview of Electronic Devices & Circuits

The Te is(a) 70 K(b) 110 K(c) 149 K(d) 240 KThe question was posed to me in an online interview.I would like to ask this question from Noise in section EDC Overview of Electronic Devices & Circuits

The value of R (in ohm) is(a) 40(b) 56.57(c) 80(d) 28.28This question was posed to me in an interview.I need to ask this question from Frequency Response topic in chapter EDC Overview of Electronic Devices & Circuits

The mean of the random variable x is(a) 1/4(b) 1/6(c) 1/3(d) 1/5I have been asked this question in examination.The question is from Continous Time Signals topic in portion EDC Overview of Electronic Devices & Circuits