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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
According to the half-reaction table, `Sn^(2+) + 2e^(-) rightarrow Sn` `E_(@) = -0.14V` `Mn^(2+) + 2e^(-) rightarrow Mn` `E^(@) = -1.03V` Which species in the better oxidizing agent?A. `Mn^(2+)`B. `Sn^(2+)`C. MnD. Sn |
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Answer» Correct Answer - B |
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| 102. |
What is the approximate value of the equilibrium constant, `K_(eq)`, at `25^(@)`C for the reaction, `3Ag^(+)(aq) + Cr(s) rightarrow Cr^(3+)(aq) + 3Ag(s)` A. `10^(22)`B. `10^(26)`C. `10^(33)`D. `2*10^(78)` |
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Answer» Correct Answer - D |
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| 103. |
The conductivity of 0.2M methanoic acid is `8Sm^(-1)`. Then, degree of dissociation for methanoic acid is: [Given : `lambda_((H^(+)))^(@)=350 Scm^(2)"mol"^(-1),lambda_(HCOO^(-))^(@)=50 Scm^(2) "mol"^(-1)`]A. `10^(-1)`B. `10^(-3)`C. `10^(-5)`D. `10^(-7)` |
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Answer» Correct Answer - A |
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| 104. |
Conductivity k, is equal to ....A. `R.((l)/(A))`B. `(G^(o+))/(R)`C. `A_(m)`D. `(l)/(A)` |
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Answer» Correct Answer - B |
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| 105. |
Match matrix `(E_(Ag^(+)//Ag)^(@)=0.8K_(sp)(AgCl)=10^(-10))` |
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Answer» Correct Answer - (a-p,q,r);(b-q);(c-p,s);(d-p,s) |
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| 106. |
Which has maximum vlaue of `A_(eq)` at constant temperature assuming 100% ionisation of each electrolyte?A. 0.1M HClB. 0.1M NaClC. 0.1 M KClD. Equal |
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Answer» Correct Answer - A |
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| 107. |
`A_(AgCl)^(oo)` can be obtained:A. by extrapolation of the graph A and `sqrt(C)` to zero concentration.B. by known values of `A^(oo)` of `AgNO_(3)`,HCl and `HNO_(3)`C. both a and bD. None of these |
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Answer» Correct Answer - C |
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| 108. |
Which of the statements about solution of electrolytes is not correct?A. conductivity of solution depends upon size of ions.B. Conductivity depends upon viscosity of solution.C. Conductivity does not depend upon solvation of ions present in solution.D. Conductivity of solution increases with temperature. |
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Answer» Correct Answer - C |
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| 109. |
A cell `Cu| Cu^(2+) || Ag^(+) | Ag` initially contains 2 M `Ag^(+)` and 2 M `Cu^(2+)` ions in 1 L electrolyte. The magnitude of change in potential after charging the cell by passage of 10 amp current for 4825 sec at 298 K is:A. 0.0074 VB. 1.0074 VC. 0.0038 VD. 0.0089 V |
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Answer» Correct Answer - A |
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| 110. |
At 298 K, the standard reduction potential are: `1.33 V` for `Cr_(2)O_(7)^(2-) | Cr^(3+)`, `1.36 V` for `Br_(2)|Br^(-)` and 0.54V for `I_(2)|I^(-)`. At pH = 4, `Cr_(2)O_(7)^(2-)` is expected to oxidise? Assume `[Cr^(3+)]` = `[Cr_(2)O_(7)^(2-)]`= 1M.A. `Cl^(-) and Br^(-)`B. `Cl^(-), Br, I^(-)`C. `Br^(-), I^(-)`D. `I^(-) only` |
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Answer» Correct Answer - D |
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| 111. |
`2Ga(s) + 6H^(+)(aq) rightarrow 2Ga^(3+)(aq) + 3H_(2)(g)` , The potential of the cell for the reaction given is 0.54V. If the concentrations of the ions are 1.0M and the pressure of `H_(2)(g)` is 1atm, what is `E^(@)` for the half-reaction `Ga^(3+)(aq) + 3e^(-) rightarrow Ga(s)`A. `-0.54V`B. `-0.27V`C. 0.27 VD. 0.54 V |
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Answer» Correct Answer - A |
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| 112. |
The voltage for the cell `Fe | Fe^(2+)(0.0010 M)` || Cu^(2+)(0.10 M) | Cu` is 0.807 V at `25^(@)`C. What is the value of E^(@)`?A. 0.51B. 1.01C. 2.5D. 3.21 |
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Answer» Correct Answer - C |
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| 113. |
For the cell `Zn(s) + 2H^(+)(aq) rightarow Zn^(2+)(aq) + H_(2)(g)`, `E^(@) = 0.76`V Which change will increase the voltage of the cell?A. increasing the size of the Zn electrodeB. increasing the `[Zn^(2+)]`C. Increasing the `[H^(+)]`D. increasing the pressure of the `H_(2)(g)` |
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Answer» Correct Answer - C |
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| 114. |
Which statement is correct?A. In SHE, the pressure of dihydrogen gas should be low and pH of solution should be zero.B. In the reaction `H^(2)O_(2) + O(3) rightarrow 2H_(2)O + 2O_(2)`, `H_(2)O_(2)` is oxidised to `H_(2)O`.C. The absolute value of electrode potential cannot be determined.D. According to IUPAC covention, the standard electrode potential pertains to oxdidation reactioin only. |
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Answer» Correct Answer - C |
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| 115. |
Which of the following facts is not truegtA. if `E^(@) (M^(n+ //M)` is negative, `H^(+)` will be reduced to `H^(2)` by the metal M.B. If `E^(@)(M^(n+)//m)` is positive, `M^(n+)` will be reduced to M by `H_(2)`C. In a cell `M^(n+) // M` electrode is attached to hydrogen-half cell. To produce spontaneous cell reaction, metal M generally acts as negative electrode.D. Compounds of active metals (Zn, Na, Mg) are reducible by `H_(2)` whereas those of noble metals (Cu, Ag, Au) are not reducible. |
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Answer» Correct Answer - D |
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| 116. |
For `Zn^(2+) //Zn, E^(@) =- 0.76`, for `Ag^(+)//Ag, E^(@) = +0.799V`. The correct statement isA. The reactioin `rightarrow` Zn getting reduced Ag getting oxidized is spontaneous.B. Zn undergoes reduction and Ag is oxidized.C. Zn undergoes oxidatioin and `Ag^(+)` gets reduced.D. No suitable answer. |
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Answer» Correct Answer - C |
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| 117. |
`Al^(3+)(aq) + 3e^(-) rightarrow Al(s)` `E^(@) = -1.66V` `Cu^(2+)(aq) + 2e^(-) rightarrow Cu(s)` `E^(@) = +0.34V` What voltage is produced under standard conditions by combining the half-reactions witih these standard Electrode Potential?A. 1.32VB. 2.00VC. 2.30VD. 4.34V |
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Answer» Correct Answer - B |
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| 118. |
Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential `(E^(@))` of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. `E^(@)(SRP)` of different half cells are given below: `E_(Cu^(2+)|Cu)^(@)=0.34V, E_(Zn^(2+)|Zn)^(@)=-0.76V` `E_(Ag^(+)|Ag=0.8V, E_(Mg^(2+)|Mg))=-2.37V` In which cell, `DeltaG^(@)` per "mole" of electron is most negative?A. `Zn(s)|Zn^(2+)(1M)||Mg^(2+)(1M)|Mg(s)`B. `Zn(s)|Zn^(2+)(1M)||Ag^(+)(1M)|Ag(s)`C. `Cu(s)|Cu^(2+)(1M)||Ag^(+)(1M)|Ag(s)`D. `Ag(s)|Ag^(+)(1M)||Mg^(2+)(1M)|Mg(s)` |
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Answer» Correct Answer - B |
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| 119. |
Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential `(E^(@))` of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. For the cell: Pt `|H_(2)(0.4"atm")H^(+)(pH=1)||H^(+)(pH=2)|H_(2)(0.1"atm")|` Pt, the measured potential at `25^(@)C` is: [Given: 2.303RT/F=0.06V, log 2=0.3]A. `-0.1V`B. `-0.5V`C. `-0.042V`D. `-0.035V` |
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Answer» Correct Answer - C |
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| 120. |
What is correct for working Galvanic cell?A. Anode is negative electrodeB. Current flows from anode to cathode in outer circuitC. Electrons flow from anode to cathode through solutionD. `E_(cell) = -ve` |
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Answer» Correct Answer - A |
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| 121. |
Which of the following is not true about emf of a cell?A. Work calcualted from it is not the maximum work obtainable from the cellB. It is maximum voltage obtainable from the cellC. It is potential difference between two electrodes when no current is flowing in circuitD. It is responsible for the flow of steady current in the cell |
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Answer» Correct Answer - A |
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| 122. |
Statement-1: On increasing dilution, the specific conductance keeps on increasing. Statement-2: On increasing dilution. Degree of ionization of weak electrolyte ncreases and mobility of ions also increases.A. Statement-1 is True, Statement-2 is True : Statement-2 is a correct explanation for Statement-23B. Statement-1 is True, Statement-2 is True : Statement-2 is `NOT` a correct explanation for Statement-23C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - B |
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| 123. |
Assertion `(A) :` Galvanized iron does not rust. Reason `(R): Zn` has a more negative electrode potential than `Fe`.A. Statement-1 is True, Statement-2 is True : Statement-2 is a correct explanation for Statement-22B. Statement-1 is True, Statement-2 is True : Statement-2 is `NOT` a correct explanation for Statement-22C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - A |
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| 124. |
The standard electrode potentials, `E^(@)` of `Fe^(3+)//Fe^(2+)` and `Fe^(2+)//Fe` at 300 K are +0.77 V and `-0.44V`, respectively, The `E^(@)` of `Fe^(3+)//Fe)` at the same temperature is:A. 1.21 VB. 0.33 VC. `-0.036 V`D. 0.036 V |
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Answer» Correct Answer - C |
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| 125. |
The EMF of a concentration cell consisting of two zinc electrodes, one dipping into `M/4` sol. Of zinc sulphate and the other into `M/6` sol. Of the same salt at `25^(@)`C. is:A. `0.0125V`B. `0.0250V`C. `0.0052V`D. `0.9178V` |
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Answer» Correct Answer - C |
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| 126. |
A current of 4.0 A is passed for 5 hours through 1 L of 2 M solution of nickel nitrate using two nickel electrodes. The molarity of the solution at the end of the elelctrolysis will be:A. 1.5 MB. 1.2 MC. 2.5 MD. 2.0 M |
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Answer» Correct Answer - D |
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| 127. |
Based on the standard reduction potentials above, which reaction(s) is (are) spontaneous? (P) `Cr^(2+)(aq)+Fe^(3+)(aq)rarrCr^(2+)(aq)+Fe^(2+)(aq)` (Q) `Cu^(2+)(aq)+Fe^(2+)(aq)rarrCu^(2+)(aq)+Fe^(3+)(aq)`A. P onlyB. Q onlyC. Both P and QD. Neither P nor Q |
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Answer» Correct Answer - A |
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| 128. |
What happens to a certain during the electrolysis of a molten salt? The cation moves towards the:A. Anode and undergoes reductionB. anode and undergoes oxidationC. cathode and undergoes reductionD. cathode and undergoes oxidation |
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Answer» Correct Answer - C |
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| 129. |
Match the following columns: |
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Answer» Correct Answer - (a-s);(b-p);(c-q);(d-t);(e-r) |
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| 130. |
Match the terms given in Column I with the items given in Column II. (One to one match only) |
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Answer» Correct Answer - (a-s)(b-p)(c-q)(d-r) |
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| 131. |
E.m.f of the cell `2Ag^(+) + Cu rightarrow Cu^(+2) = 2Ag` [Given : `E^(@)`= -0.8V , `E_(Cu^(+2))^@` Cu = 0.3V]`A. `-0.5V`B. `0.5V`C. `-1.1V`D. `1.1V` |
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Answer» Correct Answer - B |
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| 132. |
Consider the cell potentials `E_(Mg^(2+)|Mg)^(0)=-2.37V` and `E_(Fe^(3+)|Fe)^(0)=-0.04V` The best reducing agent would beA. `Mg^(2+)`B. `Fe^(3+)`C. MgD. Fe |
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Answer» Correct Answer - C |
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| 133. |
Consider the cell potentials `E_(Mg^(2+)|Mg)^(0)=-2.37V` and `E_(Fe^(3+)|Fe)^(0)=-0.04V` The best reducing agent would beA. `Mg^(2+`B. `Fe^(3+`C. MgD. Fe |
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Answer» Correct Answer - C |
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| 134. |
What is the standard cell potential for the reaction, `2Cr(s) + 3Sn^(2+)(aq) rightarrow 3Sn(s) + 2Cr^(3+)(aq)` given the `E^(@)` values shown? A. 0.945VB. 0.603VC. `-0.603V`D. `-0.945V` |
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Answer» Correct Answer - B |
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| 135. |
Consider the following `E^(@)` values. `E^(@)underset(M^(3+)//M^(2-))` values for Cr, Mn, Fe and Co are `-0.41 Under standard condition, the potential for the reaction : `Sn(s) + 2Fe^(3+)(aq) rightarrow2Fe^(2+)(aq) + Sn^(2+)(aq)`A. 1.68VB. 1.40VC. 0.91VD. 0.63V |
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Answer» Correct Answer - A |
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| 136. |
Match the items of Column I and Column II on the basis of data given below: (One to one match only) `E_(F_(2)|F^(-))^(@)` = 2.87 V, `E_(Li^(+)|(Li)` = -3.5 V, `E_(Au^(3+)|Au)^(@)` = 1.4 V, `E_(Br_(2)|Br^(-))^(@)` = 1.09V |
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Answer» Correct Answer - (a-r)(b-p)(c-v)(d-t)(e-s)(f-q)(g-u) |
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| 137. |
If AgCl `hArr` `Ag^(+) + Cl^(-)` `K_(eq) = 10^(-10)` `AgBr hArr Ag6(+) + Br(-)` `K_(eq) = 10^(-12)` `Ag(NH_(3))_(2)^(+) hArr Ag6(+) + 2NH-(3)` `K_(eq) = 10^)(-8)` (At `25^(@)`C assume `(RT)/(F)` = 0.06) Match the following columns: |
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Answer» Correct Answer - (a-r)(b-s)(c-q)(d-p) |
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| 138. |
A gas `Cl^(2)` at atm is bubbled through a solution containing a mixture of `1M Br^(-)` and `1M F^(-)` at `25^(@)`C. If the reductioni potential order is F gt Cl gtBr, then:A. Cl will oxidise Br and not FB. Cl will oxidise F and not BrC. Cl will oxidise both Br and FD. Cl will reduce both Br and F |
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Answer» Correct Answer - A |
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| 139. |
The `E^(@)_(M^(3+)/M^(2-))` values for Cr, Mn, Fe and Co are `-0.41, +1.567, 0.77 and +1.97V` respectively. For which one of these metals the change in oxidation state from `+2` to `+3` is easiest?A. CrB. MnC. FeD. Co |
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Answer» Correct Answer - A |
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| 140. |
Use the `E^(@)` values in the table above to the determining which of the following reactions will give the highest potential in a voltaic cell?A. `3Zn^(2+)(aq) + 2Cr(s) rightarrow 3Zn(s) + 2Cr^(3+)(aq)`B. `3Zn(s) + 2Cr^(3+)(aq) rightarrow 3Zn^(2+)(aq) + 2Cr(s)`C. `Zn^(2+)(aq) + Fe(s) rightarrow Zn(s) + Fe^(2+)(aq)`D. `Zn(s) + Fe^(2+)(s) rightarrow Zn^(2+)(aq) + Fe(s)` |
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Answer» Correct Answer - D |
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| 141. |
The standard reduction potentials of three metals `A,B,` and `C` are `+0.5 V , -3.0V,` and `-1.2V`, respectively. The order of reducing power of these metals isA. B gtCgtAB. AgtBgtCC. CgtBgtAD. AgtCgtB |
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Answer» Correct Answer - A |
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| 142. |
Which is the weakest oxidizing agent in a 1 M aqueous solution?A. `Ag^(+) (aq)`B. `Cu^(2+)(aq)`C. `H^(+)(aq)`D. `Zn^(2+)(aq)` |
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Answer» Correct Answer - D |
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| 143. |
0.1 "mole" `AgNO_(3)` is added in 250 mL of saturated solution of AgCl at `25^(@)C` without changing volume. Given: `K_(sp)` of `AgCl=1.0xx10^(-10)M^(2)` Ionic conductance of `Ag^(+)"ion"=60Omega^(-1)cm^(2) "mol"^(-1)` Ionic conductance of `Cl^(-)` ion =`75Omega^(-1)cm^(2) "mol"^(-1)` Ionic conductance of `NO_(3)^(-) "ion"=75 Omega^(-1)` `[Cl^(-)]`in the final solution is equal to :A. `10^(9)M`B. `2.5xx10^(-10)M`C. `10^(-5)M`D. `2.5xx10^(-7)M` |
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Answer» Correct Answer - B |
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| 144. |
Choose the correct satement(s).A. At the anode, the species having minimum reduction potential is formed from the oxidation of corresponding oxidizable species.B. In highly alkaline medium, the anodic process during the electrolysis process is: `4OH^(-)rarrO_(2)+2H_(2)O+4e^(-)`C. The standard potential of `Cl^(-)|AgCl|Ag` half cell is related to that of `Ag^(+)|Ag` through the expression `E_(Ag^(+)|Ag)^(@)=E_(Cl^(-)|AgCl|Ag)^(@)=+0.059` in `[K_(sp)(AgCl)]` at `25^(@)C`D. Compounds of active metals `(Zn,Na,Mg)` are reducible by `H_(2)` whereas those of noble metals `(Cu,Ag,Au)` are not reducible. |
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Answer» Correct Answer - A::B |
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| 145. |
`M(s)rarrM^(n+)(aq)+ne^(-)` Choose the correct statement(s).A. `E_(M|M^(n+))^(@)`decreases on increasing in `[M^(n+)]`B. `E_(M^(m+)|M)^(@)` increases on increasing temperatureC. `E_(M^(n+)|M)^(@)` increases on increasing `[M^(n+)]`D. `E_(M|M^(n+))^(@)` increases on increasing temperature |
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Answer» Correct Answer - A::B::C |
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| 146. |
`2Ag^(+)(aq)+M(s)rarrM^(2+)(aq)+2Ag,E^(@)=0.940V` Which change will cause the largest increase in the voltage of a cell based on the reaction above?A. Doubling the `[Ag^(+)]` from 1M to 2MB. Doubling the amount of M(s)C. Doubling the volume of the 1M `Ag^(+)` solutionD. Reducing the `[M^(2+)]` from 1 M to 0.5M |
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Answer» Correct Answer - A |
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| 147. |
`2Ag^(+)(aq)+M(s)rarrM^(2+)(aq)+2Ag,E^(@)=0.940V` What is the value of `E^(@)` for the half reaction, `M^(2+)(aq)+2e^(-)rarrM(s)`? `{:(E^(@)//V),(Ag^(+)(aq)+e^(-)rarrAg(s)0.99):}`A. 0.658VB. 0.141VC. `-0.141V`D. `-0.658V` |
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Answer» Correct Answer - C |
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| 148. |
According to the equations and data in the table above, which species is the strongest reducing agent of the following choices?A. `H^(+)`B. `H_(2)`C. `H_(2)O`D. `Pd^(2+)` |
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Answer» Correct Answer - B |
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| 149. |
According to the standard reduction potentials above, cathodic protection of iron can be achieved by:A. Cu(s) onlyB. Cu(s) and Sn(s) onlyC. Mg(s) onlyD. Mg(s)_ and Zn(s) only |
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Answer» Correct Answer - D |
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| 150. |
If the pressure of hydrogen gas is increased from 1atm to 100atm, keepimng the hydrogen ion concentratioin constant at 1M, the new reduction potential of the hydrogen half cell is at `25^(@)C` will be:A. `0.059V`B. `-0.059V`C. `0.295V`D. `0.118V` |
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Answer» Correct Answer - B |
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