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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
The specific conductivity of a saturated solution of AgCl is `3.40xx10^(-6) ohm^(-1) cm^(-1)` at `25^(@)C`. If `lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1)` and `lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1)`, the solubility of AgC at `25^(@)C` is:A. `2.6xx10^(-5)M`B. `4.5xx10^(-3)M`C. `3.6xx10^(-5)M`D. `3.6xx10^(-3)M` |
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Answer» Correct Answer - A |
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| 202. |
The solubiltiy product of silver iodide is `8.3 xx 10^(-17)` and the standard potential (reduction) of `Ag,Ag^(+)` electrode is `+0.800` volts at `25^(@)C`. The standard potential of `Ag,AgI//I^(-)` electrode (reduction) from these data isA. `-0.30V`B. `+0.15V`C. `+0.10V`D. `-0.15V` |
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Answer» Correct Answer - B |
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| 203. |
Standard reduction potential (volts) in acid solution is given by the Latimer diagram as shown: `CiO_(4)^(-)overset(1.19)rarrCIO_(3)^(-)overset(1.21)rarrCIOrarrCl_(2)rarrCl^(-)` What is standard reduction potential of `CIO_(3)^(-)rarr(1)/(2)Cl_(2)` In acidic medium is:A. 1.47VB. 4.47VC. 2.23VD. 0.894V |
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Answer» Correct Answer - A |
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| 204. |
The standard reduction potential `E^(@)` of the following systems are:- `{:(System,E^(@)("volts")),((i)MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O,1.51),((ii)Sn^(4+)+2e^(-)rarrSn^(2+)0.15,),((iii)Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr2Cr^(3+)+7H_(2)O,1.33),((iv)Ce^(4+)+e^(-)rarrCe^(3+)1.61,):}` The oxidising power of teh various species decreases in the orderA. `Ce^(4+) gt Cr_(2)O^(2-_(7)) gt Sn^(4+) gt MnO^(-_(4)`B. `Ce^(4+) gt MnO^(-_(4) gt Cr_(2)O^(2-_(7)) gt Sn^(4+)`C. `Cr_(2)O^(2-_(7) gt Sn^(4+) gt Ce^(4+) gt MnO^(-_(4))`D. `MnO^(-_(4) gt Ce^(4+) gt Sn^(4+) gt Cr_(2)O^(2-_(7)` |
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Answer» Correct Answer - B |
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| 205. |
Latimer diagram for Cu in an acidic solution is: `Cu^(+2) overset(+0.15V)toCu^(+) overset(+0.50)toCu,`A. `+0.65` voltB. `+0.325 volt`C. `-0.0325 volt`D. `-0.325 volt` |
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Answer» Correct Answer - B |
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| 206. |
Standard reduction potential (volts) in acid solution is given by the Latimer diagram as shown: `CiO_(4)^(-)overset(1.19)rarrCIO_(3)^(-)overset(1.21)rarrCIOrarrCl_(2)rarrCl^(-)` Which of the following cannot disproportionate in acid solution under standard conditions?A. `CIO_(3)^(-)`B. `CIO_(2)^(-)`C. `Cl_(2)`D. `CIO^(-)` |
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Answer» Correct Answer - C |
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| 207. |
Standard reduction potential (volts) in acid solution is given by the Latimer diagram as shown: `CiO_(4)^(-)overset(1.19)rarrCIO_(3)^(-)overset(1.21)rarrCIOrarrCl_(2)rarrCl^(-)` The pH at which `E_(CIO_(3)^(-)|CIO^(-))=1.31` volt is: [Given: `[CIO_(3)^(-)=1M,[CIO^(-)]=1M`, `(2.303RT)/(F)=0.06]` |
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Answer» Correct Answer - C |
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| 208. |
The overall reaction electrochemical cell at 298K. `Ag(s)|AgI(s)|I^(-)(aq)||Cl^(-)(aq)|Hg_(2)Cl_(2)|Hg(l)|Pt(s)` [Given: `E_(Cl^(-)|Hg_(2)Cl_(2)|Hg)^(@)=0.26V. E_(Ag^(+)|Ag)^(@)=0.8V`. `K_(sp)(Agl)=10^(-16)` and `(2.303RT)/(F)=0.06`] The overall reaction occuring in the above cell is:A. `(1)/(2)Hg_(2)Cl_(2)(s)+Ag(s)+I^(-)(aq)rarrHg(l)+Cl^(-)(aq)+Agl(s)`B. `Ag^(+)(aq)+I^(-)(aq)rarrAgl(s)`C. `Hg_(2)^(2+)(aq)+I 2Cl^(-)(aq)rarrHg_(2)Cl_(2)(s)`D. `Hg_(2)Cl_(2)(s)+2Agl(s)rarr2AgCl(s)+Hg_(2)I_(2)(s)` |
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Answer» Correct Answer - A |
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| 209. |
The overall reaction electrochemical cell at 298K. `Ag(s)|AgI(s)|I^(-)(aq)||Cl^(-)(aq)|Hg_(2)Cl_(2)|Hg(l)|Pt(s)` [Given: `E_(Cl^(-)|Hg_(2)Cl_(2)|Hg)^(@)=0.26V. E_(Ag^(+)|Ag)^(@)=0.8V`. `K_(sp)(Agl)=10^(-16)` and `(2.303RT)/(F)=0.06`] At equilibrium ratio of `([Cl^(-)])/([I^(-)])` in the above cell will be:A. `10^(7)`B. 200C. `10^(-7)`D. none of these |
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Answer» Correct Answer - A |
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| 210. |
The overall reaction electrochemical cell at 298K. `Ag(s)|AgI(s)|I^(-)(aq)||Cl^(-)(aq)|Hg_(2)Cl_(2)|Hg(l)|Pt(s)` [Given: `E_(Cl^(-)|Hg_(2)Cl_(2)|Hg)^(@)=0.26V. E_(Ag^(+)|Ag)^(@)=0.8V`. `K_(sp)(Agl)=10^(-16)` and `(2.303RT)/(F)=0.06`] `E_("cell")^(@)` of the above cell is:A. 0.42 voltB. 0.44 voltC. 0.10voltD. `-0.06 V` |
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Answer» Correct Answer - A |
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| 211. |
Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together thenA. `Fe^(3+_` increasesB. `Fe^(3+)` decreasesC.D. `Fe^(2+)//Fe^(3+)` remains unchanged |
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Answer» Correct Answer - A |
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| 212. |
Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together thenA. `Fe^(3+)` increasesB. `Fe^(3+)` decreasesC. `Fe^(2+)` increasesD. `Fe^(2+)` decreases |
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Answer» Correct Answer - B::C |
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| 213. |
Assertion (A): Sodium ions are discharged in preference to hydrogen ions at a mercury cathode. Reason (R ): The nature of cathode can affect the order of discharge of cations.A. Statement-1 is True, Statement-2 is True : Statement-2 is a correct explanation for Statement-18B. Statement-1 is True, Statement-2 is True : Statement-2 is `NOT` a correct explanation for Statement-18C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - A |
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| 214. |
When the electric current is passed through a cell having an electrolyte, the positive ions move towards cathode and negative ions toqards the anode. If the cathode is pulled out of the solution .A. the positive and negative ions will move towards anodeB. the positivie ions will start moving towards the anode while negative ions will stop moving.C. the negative ions will continue to move towards anode whie positive ions will stop movingD. the positive and negative ions will start moving randomly |
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Answer» Correct Answer - D |
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| 215. |
With t taken in seconds and I taken in amp, the variation of I follows the equation `t^(2) + I^(2) = 25` What amount of Ag will be electrodeposited with this current flowing in the interval 0-5 second? (Ag=108)A. 22 mgB. 66 mgC. 77 mgD. 88 mg |
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Answer» Correct Answer - A |
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| 216. |
One g equivalent of Na metal is formed from electrolyis of fused NaCl. No of "mole" of Al from the fused `Na_(3)AlF-(6)` with the same current passed is:A. 1B. 3C. `1/3`D. 2 |
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Answer» Correct Answer - C |
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| 217. |
A current of `2` A was passed for `1 h` through a solution of `CuSO_4. 0.237g` of `Cu^(2+)` ions was discharged at cathode . The current efficiency is .A. `42.24%`B. `26.1%`C. `10%`D. `40.01%` |
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Answer» Correct Answer - C |
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| 218. |
At `25^(@)C, {:(Ag+I^(-)rarr,AgI+e,,E^(@) =0.152V),(Agrarr,Ag.^(+)+e,,E^(@) =- 0.80V):}` The `log K_(sp)` of `AgI` is: `((2.303RT)/(F)=0.059)`A. `-8.12`B. `+8.612`C. `-37.83`D. `16.13` |
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Answer» Correct Answer - D |
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| 219. |
`Al^(3+)(aq)+3e^(-)rarrAl(s) E^(@)=-1.66V` `Mn^(2+)(aq)+2e^(-)rarrMn(s) E^(@)=-1.18V` What is the standard potential of a volaic cell produced by using these two half-reactions?A. 0.04VB. 0.48VC. 2.84VD. 6.68V |
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Answer» Correct Answer - B |
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| 220. |
In a cell that utilizes the reactions. `Zn(s) + 2H^(+) (aq) rightarrow Zn^(2+)(aq) + H_(2)(g)` addition of `H_(2)SO_(4)` to cathode compartment, willA. lower the E and shift equilibrium to the leftB. lower the E and shift the equilibrium to the rightC. increase the E and shift the equilibrium to the rightD. increase the E and shift the equilibrium to the left |
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Answer» Correct Answer - C |
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| 221. |
A current is passed through 2 voltmeters connected in series. The first voltmeter contians `XSO-94)(aq)` and second has `Y_(2)SO_(4)`(aq). The relative atomic masses of X and Y are in the ratio `2:1`. The ratio of the mass of X liberated to the mass of Y liberated is:A. `1:1`B. `1:2`C. `2:1`D. none of these |
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Answer» Correct Answer - A |
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| 222. |
Which of the following is //are function (s) of salt bredge ?A. It completes the electrical circuit with electrons flowing from one electrode to the other through external wires and a flow of ions between the two compartments through salt-bridge.B. It minimizes the liquid-liquid junctioni potential.C. Both are correct.D. None of the above. |
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Answer» Correct Answer - C |
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| 223. |
During the electrolysis of an aqueous solution of `AgNO_(3)`. What would happen to the mass of silver metal deposited if the current is doubled and the electrolysis time is decreased to `(1)/(2)` of its initial value?A. It would stay the same.B. It would increase to twice its initial value.C. It would decrease to `(1)/(4)` of its initial value.D. It would decrease to `(1)/(2)` of its initial value. |
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Answer» Correct Answer - A |
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| 224. |
In given galvanic cell, `Pt|H-(2)(g) | NaCl(aq)|| AgNO_(3)(aq)| Ag` on adding water into L.H.S compartment, e.m.f of the cell:A. increasesB. decreasesC. remains unchangedD. none of these. |
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Answer» Correct Answer - C |
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| 225. |
A certain metal salt solution is electrolysed in series with a silver coulometer. The weights of silver and the metal deposited are 0.5094 g and 0.2653 g. Calculate the valency of the metal if its atomic weight is nearly that of silver. |
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Answer» Correct Answer - 2 |
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| 226. |
Using the data given below: `E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V` `E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V` Mark the strongest oxidising agent.A. `Cl^(-)`B. `Mn^(2+)`C. `MnO_(4)^(-)`D. `Cr^(3+)` |
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Answer» Correct Answer - C |
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| 227. |
How many Faradays are required to reduce all the chromium in 0.150L of 0.115 M of `Cr_(2)O_(7)^(2-)` to `Cr^(2+)`?A. 0.920FB. 0.690FC. 0.138FD. 0.069F |
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Answer» Correct Answer - C |
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| 228. |
Which expression gives the correct value of the standard potential for a gold-rhodium voltaic cell? `{:("Half-reaction",E^(@)V), (Rh^(3+)(aq) +_ 3e^(-) rightarrow Rh(s), 0.76), (Au^(+)(aq) + e^(-) rightarrow Au(s), 1.69):}`A. `1.69 + 0.76`B. `1.69 = 0.76`C. `3(1.69) + 0.76`D. `3(1.69) - 0.76` |
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Answer» Correct Answer - B |
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| 229. |
`Rh^(03+)(aq)+3e^(-)rarrRh(s) E^(@)=0.80V` `Cu^(+)(aq)+e^(-)rarrCu(s) E^(@)=0.52V` What is the direction of electronflow in the external circuit if the concentrations of `Cu^(+)` and `Rh^(3+)` are each 1M?A. From the Rh anode to the Cu cathodeB. From the Rh cathode to the Cu anodeC. From the Cu anode to the Rh cathodeD. From the Cu cathode to the Rh anode |
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Answer» Correct Answer - C |
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| 230. |
During an electrolysis of conc `H_(2)SO_(4)` , perdisulphuric acid `(H_(2)S_(2)0_(8))` and `O_(2)` are formed in equimolar amount. The moles of `H_(2)` that will be formed simultaneously will be `a. `Thrice that of `O_(2)" "b.` Twice that of `O_(2)` `c.` Equal to that of `O_(2)." "d.` Half of that of `O_(2)`A. Thrice that of `O_(2)` in "mole"sB. Twice that of `O_(2)` in "mole"sC. Equal to that of `O_(2)` in "mole"sD. Half that of `O_(2)` in "mole"s |
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Answer» Correct Answer - A |
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| 231. |
Electrolysis of a solution of `HSO_(4)^(-1)` ions produces `S_(2)O_(8)^(2-)`. Assuming `75%` current efficiency, what current should be employed to achieve a production rate of 1 "mole" of `S_(2)O_(8)^(2-)` per hour?A. `+71.5` ampB. 35.7 ampC. 142.96 ampD. 285.93 amp |
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Answer» Correct Answer - A |
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| 232. |
`Rh^(03+)(aq)+3e^(-)rarrRh(s) E^(@)=0.80V` `Cu^(+)(aq)+e^(-)rarrCu(s) E^(@)=0.52V` What is the voltage of this cell if the concentrations of `Cu^(+)` and `Rh^(3+)` are each 1 M?A. 0.28VB. 0.76VC. 1.32VD. 2.36V |
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Answer» Correct Answer - A |
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| 233. |
Statement-1: During electrolysis of `H_(2)SO_(4),H_(2)` and `O_(2)` are liberated under normal concentrations and `H_(2)S_(2)O_(8)` at higher concentrations and lower temperature. Statement-2: Liberation of `H_(2)` and `O_(2)` at elecrode requires some potential drop known as overvoltage.A. Statement-1 is True, Statement-2 is True : Statement-2 is a correct explanation for Statement-24B. Statement-1 is True, Statement-2 is True : Statement-2 is `NOT` a correct explanation for Statement-24C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - B |
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| 234. |
Which statement is not true about the electrolysis of a 1 M solution of Kl to which phenolphthalein has been added?A. Potassium metal is formed.B. A yellow colour appears at the anodeC. A pink colour appears at the cathode.D. A gas is produced at the cathode. |
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Answer» Correct Answer - A |
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| 235. |
When water is electrolysed, hydrogen and oxygen gas are produced. If 1.008 g of `H_(2)` is liberated at the cathode. What mass of `O_(2)` is formed at the anode?A. 32.0gB. 16.0gC. 8.00gD. 4.00g |
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Answer» Correct Answer - C |
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| 236. |
If a spoon of copper metal is placed in a solution of ferrous sulphate .A. Cu will precipitateB. iron will precipitateC. Cu and Fe will precipitateD. no reaction will take place |
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Answer» Correct Answer - D |
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| 237. |
An electrochemical cell constructed for the reaction : `Cu^(2+)(aq) + M(s) rightarrow Cu(s) + M^(2+) (aq)` has an `E^(@) = 0.75V`. The standard reduction potential for `Cu^(2+)(aq)` is 0.34V. What is the standard reduction potential for `M^(2+)` (aq)?A. 1.09VB. `1.09V`C. `0.410V`D. `-0.410V` |
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Answer» Correct Answer - C |
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| 238. |
A hydrogen electrode is immersed in a solution with pH = 0 (HCl). By how much will the potential (reduction) change if an equivalent amount of NaOH is added to this solution? (Take `p_(H_(2) = 1atm)` T=298KA. Increase by 0.41VB. increase by 59 mVC. Decrease by 0.41VD. Decrease by 59mV |
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Answer» Correct Answer - C |
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| 239. |
Statement-1: Gold chloride `(AuCl_(3))` solution cannot be stored in a vessel made of copper, iron, nickel, chromium, zinc or tin. Statement-2 Gold is a very precious metal.A. Statement-1 is True, Statement-2 is True : Statement-2 is a correct explanation for Statement-7B. Statement-1 is True, Statement-2 is True : Statement-2 is `NOT` a correct explanation for Statement-7C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - B |
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| 240. |
The two aqueous solutions, `A (AgNO_3)` and `B (LiCI)`, were electrolysed using Pt electrodes. The `pH` of the resulting solutions will.A. increase in A and decrease in BB. decrease in bothC. increase in bothD. decrease in A and increase in B |
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Answer» Correct Answer - D |
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| 241. |
Given: `E_(Zn^(+2)//Zn)^(@) =- 0.76V` `E_(Cu^(+2)//Cu)^(@) = +0.34V` `K_(f)[Cu(NH_(3))_(4)]^(2+) = 4 xx 10^(11)` `(2.303R)/(F) = 2 xx 10^(-4)` At what concentration of `Cu^(+2)` emf of the cell will be zero (at 298K) and concentration of `Zn^(+2)` is remains same:A. 0.81VB. 1.91VC. 1.1VD. 0.72V |
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Answer» Correct Answer - A |
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| 242. |
For the voltaic cell respresents below `Ni(s) | Ni^(2+)(aq) || Ag^(+)(aq) | Ag(s)` Which change will increase the cell potential?A. increasing the `[Ag^(+)]`B. increasing the `[Ni^(2+)]`C. Adding Ni(s)D. Removing Ag(s) |
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Answer» Correct Answer - A |
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| 243. |
Calculate the cell potential E at `25^(@)` C for the reactioni : `2Al(s) + 3Fe^(2+)(aq) rightarrow 2Al^(3+)(aq) + 3Fe(s)` [Given : `[Fe^(2+)] = 0.01M, [Al^(3+)] = 0.10M,` `E^_(Fe^(+2)//Fe)^(@) = -0.45V and ((2.303Rt)/(F) = 0.06)`A. `+1.20V`B. `+1.16V`C. `+1.24V`D. `+1.12V` |
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Answer» Correct Answer - B |
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| 244. |
A standard voltaic cell is constructed using Cu metal in 1.0 M `Cu(NO_(3))_(2)`(aq) and an unknown metal in a 1.0 M solution of its nitrate salt. The cell voltage is 0.47 V when the Cu half-cell is the cathode. What is the standard reduction potential of the unknown metal ? `[E_(Cu)^(@) = 0.34 V]`A. `-0.81V`B. `-0.13 V`C. `0.13V`D. `0.81V` |
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Answer» Correct Answer - B |
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| 245. |
What is the `[Fe^(2+)]` in a cell at `25^(@)C` for which E = `-0.458`V with a standard hydrogen electrode? `Fe^(2+)(aq) + 2e^(-) rightarrow Fe(s)` `E^(@) = -0.440V`A. 0.246 MB. 0.496 MC. 2.01 MD. 4.06 M |
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Answer» Correct Answer - A |
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| 246. |
The cell potential for the voltaic cell depicted (according to IUPAC) below is 0.109 V under standard conditions, `1 M Ni^(2+)(aq)` and `1 M Pb^(2+)(aq)` Which change will increase the voltage?A. The `1 M Ni^(2+)` solution is diluted with `H_(2)O`.B. A larger Ni electrode is used.C. 50 ml of 1M NaCl solution is added to precipitate of `PbCl_(2)`.D. More 1 M `Pb^(2+)` solution is added to the half-cell. |
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Answer» Correct Answer - A |
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| 247. |
`Ni(s) + Cu^(2+)(aq) rightarrow Ni^(2+)(aq) + Cu(s)` The voltaic cell based on this reaction has a voltage of 0.59 V under standard conditions. Which of these changes will produce a higher voltage? (P) Increasing `[Cu^(2+)]` (Q) Increasing the size of the `Ni(s)` electrode.A. P onlyB. Q onlyC. Both P and QD. Neither P nor Q |
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Answer» Correct Answer - A |
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| 248. |
The electrode potential of electrode `M(s) rightarrow M^(n+) (aq) (2M) + ne^(-)` at 298 K is E_(1). When temperature is doubled and concentration is made half, then the electrode potential becomes `E_(2)`. Which of the following represents the correct relationship between `E_(1)` and `E_(2)`?A. `E_(1) gt E_(2)`B. `E_(1) lt E_(2)`C. `E_(1) = E_(2)`D. Cannot be predicted |
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Answer» Correct Answer - B |
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| 249. |
`E^(@) = 0.93V` for the reactions: `Fe(s) + 2M^(+)(aq) rightarrow Fe^(2+)(aq) + 2M(s)` What is the standard potential for `M^(+) + e^(-) rightarrow M`, if `E_(Fe^(2+//Fe)^(@) = -0.44 V`?A. 0.26VB. 0.49VC. 0.67VD. 1.34V |
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Answer» Correct Answer - B |
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| 250. |
What is the standard cell potential for the voltaic cell? `Cr || Cr^(3+) || Pb^(2+)|| Pb` `{: ("Reaction", E_(red)^(@)//V), (Pb^(2+) + 2e^(-) rightarrow Pb, -0.13), (Cr^(3+) + 3e^(-) rightarow Cr, -0.74):}`A. 1.09VB. 0.61VC. `-0.61V`D. `-1.09V` |
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Answer» Correct Answer - B |
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