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The answer is (B) MET²

Electrostatic potential energy of a system of charges is defined as the work done to move the charges from infinity to their present configuration. 

SI Unit of Electric Potential is J C^-1 = volt (V)

(i) The potential due to a dipole depends not just on r but also on the angle between the position vector r and the dipole moment vector p. 

(ii) The electric dipole potential falls off, at large distance, as 1/r², not as 1/r, characteristic of the potential due to a single charge.

Because the Electric field inside the conductor is zero, therefore no work is done to move a charge against field and there is no potential difference between any two points. This means Electrostatic potential is constant throughout the volume. 

Because, If there are static charges inside the conductor, Electric field can be present inside it which is not true. 

No, Potential is continuous there.

Yes. The steady discharging current in the atmosphere charges up the aluminium sheet gradually and raises its voltage to an extent depending on the capacitance of the capacitor.

Light energy involved in lightning, heat and sound energy in the accompanying thunder.

The atmosphere is continually being charged by thunderstorms and lightning all over the globe and discharged through regions of ordinary weather. The two opposing currents are, on an average, in equilibrium.

A is at a higher potential. 

PD = V_final - V_initial = Work done/q 

= 10/200 

= 0.05V

Dielectrics are non-conducting substances. They have no charge carriers. There are two types of Dielectrics, polar Dielectrics and non-polar Dielectrics. 

Both polar and non-polar dielectrics develop a net dipole moment along the external field when placed in it. 

When Dielectric is placed in an external electric field, a net dipole moment is developed along it. The dielectric is now said to be polarised. The dipole moment acquired per unit volume is known as polarisation vector p. 

(i) Team work, concern, respect to teacher and responsibility. 

(ii) Electrical energy in the dielectric of the capacitor

(a) (i) Ability to take prompt decision.

(ii) Knowledge of subject matter.

(iii) Proper responsibility. 2

(b) If there is no current in the circuit, the capacitor may have charge. So, by handling a charged capacitor a person may get a severe shock. Thus, the circuit containing a capacitor must be handled carefully

(1) An equipotential surface is defined as the surface over which the total potential is zero. In the given question the plane is normal to line AB. The plane is located at the mid – point of the line AB as the magnitude of the charges are same.

(2) At every point on this surface the direction of the electric field is normal to the plane in the direction of AB.

Let centre of the hollow sphere(of radius r) is O and potential at centre is V_{​​​​​​o}​​​​​.

Let point is P from where centre is at fistance 2r and potential at this point is V_​​​​​​p.

According to the question    V_{​​​​​​o}​​​​​-Vp=V

Now V_{​​​​​​o} =kq/r ,where q is the charge on hollow sphere.

V_P=kq/2r

Vo-Vp=(kq/2r)=V        q=(2rV/k)

Electric field at distance 3r from centre is  kq/r² 

Putting value of q here we get 

E=2V/r This is the final answer.

I hope it helps     

Let centre of the hollow sphere(of radius r) is O and potential at centre is V_{​​​​​​o}​​​​​.

Let point is P from where centre is at fistance 2r and potential at this point is V_​​​​​​p.

According to the question    V_{​​​​​​o}​​​​​-Vp=V

Now V_{​​​​​​o} =kq/r ,where q is the charge on hollow sphere.

V_P=kq/2r

Vo-Vp=(kq/2r)=V        q=(2rV/k)

Electric field at distance 3r from centre is  kq/r² 

Putting value of q here we get 

E=2V/r This is the final answer.

I hope it helps     

(a) Capacitances of the given capacitors are C1 = 2 pF, C2= 3 pF and 4 pF 

For the parallel combination of the capacitors, equivalent capacitor CT is given by the algebraic sum, 

C' = 2 + 3 + 4 = 9 pF

Therefore, total capacitance of the combination is 9 pF. 

(b) Supply voltage, V = 100 V 

The voltage through all the three capacitors is same = V = 100 V 

Charge on a capacitor of capacitance C and potential difference V is given by the relation, q = VC … (i) 

For C = 2 pF, 

Charge = VC = 100 x 2 = 200 pC = 2 x 10^-10 C

For C = 3 pF, 

Charge = VC = 100 x 3 = 300 pC = 3 x 10^-10 C

For C = 4 pF, 

Charge = VC = 100 x 4 = 400 pC = 4 x 10^-10 C

The answer is (D) 2.24 × 10^-16J

The answer is (B) (1/2CV²)n

(i) Dr. Kapoor : Helpful and Considerate 

Bimla's Parents : Gratefulness 

(ii) It is considered safe to be inside a car during lightening and thunderstorm as the electric field inside a conductor is zero. 

(iii) Dielectric strength of a dielectric indicates the strength of the electric field that a dielectric can withstand without breaking down. This signifies the maximum electric field up to which the dielectric can safely play its role.

(a) (i) Ability to take prompt decision.

(ii) Presence of mind.

(iii) Knowledge of subject matter. 

(b) When we supply charge to a capacitor continuously, the potential difference between its plates goes on increasing, consequently a stage will come when the electric field between the plates will exceed the dielectric strength of medium, puncturing the dielectric. Thus, it will break the dielectric into positive and negative charges and so the capacitor will be discharged showing sparking.