This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Mary bought 3 1/2 m of lace. She used 1 34 m of lace for her new dress. How much lace is left with her? |
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Answer» The correct answer is 1 3/4 m |
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| 2. |
How does the nature invite the poet to come into its contact?प्रकृति कवि को अपने सम्पर्क में आने के लिए कैसे निमन्त्रण देती है? |
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Answer» The nature invites the poet to come into its contact having shown its modified form. The ocean which remains full of waves becomes still and produces foam on its surface as if it is spreading flowers on the way of the poet. Setting of the sun and arrival of the evening stars are the symbol of new life and the clear call of the God invites the poet to come into the contact of nature and stay with it forever. प्रकृति अपना बदला हुआ स्वरूप पेश करके कवि को निमन्त्रण देती है। महासागर जो कि हमेशा लहरों से भरा होता है शांत हो जाता है तथा अपनी सतह पर झाग उत्पन्न करता है जैसे कि यह कवि के मार्ग में फूल बिछा रहा हो। सूर्य का अस्त होना तथा संध्या का आगमन और तारों का चमकना ये सब नए जीवन के संकेत हैं तथा भगवान की स्पष्ट आवाज कवि को प्रकृति के सम्पर्क में आने तथा हमेशा के लिए उसके साथ रहने का प्रस्ताव है। |
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| 3. |
Why is the poet confident to cross the sea easily?कवि को महासागर पार करने को विश्वास क्यों है? |
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Answer» The poet is confident to cross the sea easily because he realises that the God is the pilot of his ship and He will lead him to the right way to achieve the gospel of his life and the ocean has also became still to make his way easy to arrive at the destination. The aim of his life is to approach the heaven. कवि को इस महासागर को आसानी से पार करने का विश्वास है क्योंकि वह महसूस करता है कि उसके जहाज को चलाने वाला स्वयं भगवान है जो कि उसे उसके जीवन के लक्ष्य को प्राप्त करने के लिए सही दिशा में ले जाएगा तथा समुद्र भी उसके मार्ग को आसान बनाने के लिए शान्त है जिससे कि वह अपने जीवन का लक्ष्य आसानी से प्राप्त कर सके जो कि स्वर्ग प्राप्त करना है। |
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| 4. |
Describe the mental condition of the poet at the time of farewell?विदाई के समय कवि की मनोदशा के बारे में विवेचन कीजिए। |
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Answer» The poet is not sad at the time of farewell because he is very excited to go to see his maker and he is busy in the worship of God and believes in immortality of soul. He feels that it is the time to get rid of this mortal world in which he has to live a limited life in complete boundation. कवि विदाई के समय दु:खी नहीं है क्योंकि वह अपने निर्माता से मिलने के लिए बहुत ज्यादा उत्सुक है। वह भगवान की पूजा में व्यस्त है तथा आत्मा की अमरता में विश्वास करता है। वह महसूस करता है कि यह समय इस नश्वर संसार से छुटकारा पाने का अवसर है जिसमें वह एक सीमित जीवन जीता है जो कि पूर्ण बन्धनों से भरा हुआ है। |
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| 5. |
What does “the bar” symbolise in the poem?इस कविता में ‘the bar’ किसका प्रतीक है? |
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Answer» The bar is the symbol of the ocean which is the world to which we have to cross to see our maker face to face. The bar महासागर का प्रतीक है जो कि यह संसार है जिसे हमें पार करना पड़ता है, अपने निर्माता से आमने-सामने मिलने के लिए। |
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| 6. |
“I hope to see my Pilot face to face”. Whom does the word “Pilot” here refer to?“मैं अपने सारथी को आमने-सामने देखना चाहता हूँ।” यहाँ ‘पायलट’ शब्द किसके लिए प्रयुक्त किया गया है? |
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Answer» The word “Pilot refers to God with whom the poet desires to see Him face to face after departing from this world. यहाँ पायलट शब्द भगवान के लिए प्रयुक्त किया गया है जिससे कवि इस संसार से चले जाने के पश्चात् आमने-सामने मिलना चाहता है? |
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| 7. |
Explain the phrase “our bourne of Time and Place”.“आर बार्न ऑफ टाईम एण्ड प्लेस” इस वाक्यांश को समझाइये। |
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Answer» In this phrase the poet wants to clear that the human being has taken birth in this world from this ocean and then mixes in it once again and the sea is in the form of our creator who is almighty. इस कहावत में कवि स्पष्ट करता है कि मानव ने इस संसार में महासागर में से जन्म लिया है तथा पुनः इसी में मिल जाता है। यह महासागर हमारे निर्माता के रूप में है जो कि सर्वशक्तिमान है। |
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| 8. |
Which words and phrases in the poem suggest the idea of death and dying?इस कविता में कौनसे शब्द तथा मुहावरे मृत्यु के विचार एवं मरने को दर्शाते हैं? |
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Answer» “Sunset and evening star”, “And one clear call for me”, “I hope to see my Pilot face to face”. These are the words and phrases in the poem which suggest the idea of the death and dying. “सनसेट एण्ड इवनिंग स्टार”, “एण्ड वन क्लियर काल फॉर मी”, “आई होप टू सी माई पाइलट फेस टू फेस” ये वे शब्द एवं मुहावरे हैं जो मृत्यु व मृत्यु के विचारों को कविता में सुझाते हैं। |
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| 9. |
Which expressions in the poem reveal the optimistic mood of the speaker?कविता में कौनसी अभिव्यक्ति कवि के आशावादी स्वभाव को व्यक्त करती है? |
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Answer» The speaker reveals the sense of optimistic mood in the poem by expressing his views that he hopes to see his Pilot face to face and he will return to his home once again. It clears that the poet believes in immortality of soul. इस कविता में वक्ता आशावादी मनोदशा व्यक्त करता है। वह अपने निर्माता से आमने-सामने मिलने की इच्छा दर्शाता है और कहता है कि वह एक बार पुनः अपने घर लौट आयेगा। यह स्पष्ट करता है कि कवि आत्मा की अमरता में विश्वास करता है। |
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| 10. |
In which atmosphere does the speaker want to die?वक्ता किसे माहौल में मरना चाहता है? |
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Answer» The speaker wants to die in the atmosphere of peace and joy with an optimistic thought of getting a new life after death. वक्ता आशावादी तथा खुशी के माहौल में मरना चाहता है तथा विचार करता है कि उसे मृत्यु के बाद नया जीवन मिलेगा। |
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| 11. |
What is the wish of the speaker?वक्ता की क्या इच्छा है? |
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Answer» The speaker wishes to see his creator face to face after crossing the ocean which is in the form of the world. वक्ता इस महासागर रूपी संसार को पार करके अपने निर्माता से आमने-सामने मिलना चाहता है। |
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| 12. |
Why doesn’t the speaker want to die in a mournful atmosphere?वक्ता दु:खद वातावरण में क्यों नहीं मरना चाहता है? |
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Answer» The speaker does not want to die in a mournful atmosphere because he realises that death is the beginning of new life and he believes in the immortality of soul in this mortal world. कवि दु:खद माहौल में मरना नहीं चाहता है क्योंकि वह महसूस करता है कि मृत्यु नए जीवन की शुरुआत है और वह इस नश्वर संसार में आत्मा की अमरता में विश्वास करता है। |
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| 13. |
Observe the following picture and respond.1. Guess the characters in the picture.2. How do you think are they related to each other?3. Why did the young man meet the other person?4. What is the man with a beard saying?5. Why do we listen to persons? |
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Answer» 1. The characters in the picture are a wise man and common man. 2. The man with beard was a guru and the other man was a disciple. 3. The young man met the other person to take his advice. 4. The man with a beard is saying something good. 5. We listen to persons to get good advice out of their experience. |
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| 14. |
Compare and contrast the characters of Antonio and Bassanio. |
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Answer» Antonio and Bassanio are true friends. Both love each other and are ready to help. Yet each of them has his own characteristics which are given below : Both are sincere and intimate. Antonio is so much sincere for Bassanio that he signs a fatal bond for his friend’s happiness. The bond is to be expired but he does not tell Bassanio lest he should mar his happiness in Belmont. When Bassanio goes to Belmont, he bursts into tears. Bassanio also loves and trusts Antonio. He clearly tells him that he wants money to win the hand to Portia. Both are Christians and hate the jews. So they do not tolerate Judaism. Antonio finds faults with Shylock for his usuary, abuses him and even spits at him. Moreover there are some characteristics which one has while another does not have. Antonio is weak hearted. At the expiry of bond, he goes to Shylock and begs him of mercy. Due to this weakness, he is called a Passive hero. Bassanio is extravagant and fortune hunter. Yet he is a cultured man and never uses bad words about Shylock or his religion. |
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| 15. |
Which of the following is an antiseptic?0.2% phenol, 1% phenol |
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Answer» 0.2% phenol. |
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| 16. |
What are drugs? How are they classified? |
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Answer» A drug is a substance that is used to modify or explore physiological systems or pathological states for the benefits of the recipient. it is used for the purpose of diagnosis, prevention cure or relief of a disease. Classification of drugs: Drugs care classified based on their proportions such as chemical structure, pharmacological effect, target system, site of action etc. 1. Classification based on the chemical structure: In this classification, drugs with a common chemical skelton are classified into a single group. For example, ampicillin, amoxicillin, methiceillin etc. all have similar structure and are classified into a single group called penicillin. Similarly we have other group of drugs such as opiates, steroids, catecholamines etc. Compounds having similar chemical structure are expected to have similar chemical properties. However, their biological actions are not always similar. 2. Classification based on the pharmacological effect:
3. Classification based on the target system: In this classification, the drugs are grouped based on the biological system (or) process that they target in the recipient.
4. Classification based on the site of action: 1. The drug molecule interacts with biomolecules such as enzymes, receptors etc, which are referred as drug targets. 2. We can classify the drug based on the drug target with which it binds. 3. This classification is highly specific compared to the others. These compounds often have a common mechanism of action, as the target is the same. |
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| 17. |
Assertion(A): Transparent soaps are made by dissolving soaps in ethanol. Reason (R): Ethanol made things invisible. (a) Both A and R are correct and R explains A. (b) Both A and R are correct but R does not explain A. (c) A is correct but R Is wrong. (d) A is wrong but R is correct |
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Answer» (c) A is correct but R Is wrong |
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| 18. |
How many points are there in the intersection of two distinct lines? (A) infinite (B) two (C) one (D) not a single |
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Answer» (C) The answer is one |
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| 19. |
Explain the cleaning action of soap. Why do soaps not work in hard water? |
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Answer» Soap has hydrocarbon part which is hydrophobic and attract dirt, grease, oil, etc. Whereas hydrophobic part – CooNa attracts water which takes away oil, dirt, and grease. Soaps do not work in hard water because Ca2+ and Mg2+ ions present in hard water. |
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| 20. |
Write the following statements in conditional form.i. Every rhombus is a square. ii. Annies in a linear pair are supplementary.iii. A triangle is a figure formed by three segments iv. A number having only two divisors is called a prime number |
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Answer» i If a quadrilateral is a rhombus, then it is a square. ii. If iwo angles are in a linear pair, then they are supplementary. iii. If a figure is a triangle, then it is formed by three segments. iv. If a number has only two divisors, then it is a prime number. |
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| 21. |
Students are asked to stand in a line for mass drill. How will you check whether the students standing are in a line or not ? |
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Answer» If one stands in front of the line and observes only the first student standing in the line, then all the students standing in that line are collinear i.e., standing in the same line. We can use this property of collinearity to check whether the students are standing in the same line or not. |
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| 22. |
From the information given below, find which of the point is between the other two. If the points are not collinear, state so.i. d(P, R) = 7, d(P, Q) = 10, d(Q, R) = 3ii. d(R, S) = 8, d(S, T) = 6, d(R, T) = 4iii. d(A, B) = 16, d(C, A) = 9, d(B, C) = 7 iv. d(L, M) =11, d(M, N) = 12, d(N, L) = 8 v. d(X, Y) = 15, d(Y, Z) = 7, d(X, Z) = 8 vi. d(D, E) = 5, d(E, F) = 8, d(D, F) = 6 |
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Answer» i. Given, d(P, R) = 7, d(P, Q) = 10, d(Q, R) = 3 d(P, Q) = 10 …(i) d(P, R) + d(Q, R) = 7 + 3 = 10 .. .(ii) ∴ d(P, Q) = d(P, R) + d(Q, R) …[From (i) and (ii)] ∴ Point R is between the points P and Q i. e., P – R – Q or Q – R – P. ∴ Points P, R, Q are collinear. ii. Given, d(R, S) = 8, d(S, T) = 6, d(R, T) = 4 d(R, S) = 8 …(i) d(S, T) + d(R, T) = 6 + 4 = 10 …(ii) ∴ d(R, S) ≠ d(S, T) + d(R, T) … [From (i) and (ii)] ∴ The given points are not collinear. iii. Given, d(A, B) = 16, d(C, A) = 9, d(B, C) = 7 d(A, B) = 16 …(i) d(C, A) + d(B, C) = 9 + 7 = 16 …(ii) ∴ d(A, B) = d(C, A) + d(B, C) …[From(i) and (ii)] ∴ Point C is between the points A and B. i. e., A – C – B or B – C – A. ∴ Points A, C, B are collinear iv. Given, d(L, M) = 11, d(M, N) = 12, d(N, L) = 8 d(M, N) = 12 …(i) d(L, M) + d(N, L) = 11 + 8 = 19 …(ii) ∴d(M, N) + d(L, M) + d(N, L) … [From (i) and (ii)] ∴ The given points are not collinear. v. Given, d(X, Y) = 15, d(Y, Z) = 7, d(X, Z) = 8 d(X, Y) = 15 …(i) d(X,Z) + d(Y, Z) = 8 + 7= 15 …(ii) ∴ d(X, Y) = d(X, Z) + d(Y, Z) …[From (i) and (ii)] ∴ Point Z is between the points X and Y i. e.,X – Z – Y or Y – Z – X. ∴ Points X, Z, Y are collinear. vi. Given, d(D, E) = 5, d(E, F) = 8, d(D, F) = 6 d(E, F) = 8 …(i) d(D, E) + d(D, F) = 5 + 6 = 11 …(ii) ∴ d(E, F) ≠ d(D, E) + d(D, F) … [From (i) and (ii)] ∴ The given points are not collinear. |
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| 23. |
Draw a point on a paper and use your ruler to draw lines that pass through it. How many such lines can you draw? |
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Answer» An infinite number of lines can be drawn through one point. |
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| 24. |
If the co-ordinate of A is x and that of B is . y, find d(A, B).i. x = 1, y = 7 ii. x = 6, y = -2 iii. x = -3, y = 7 iv. x = -4, y = -5v. x = -3, y = -6 vi. x = 4, y = -8 |
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Answer» i. Co-ordinate of point A is x = 1. Co-ordinate of point B is y = 7 Since, 7 > 1 ∴ d(A, B) = 7 – 1 ∴ d(A, B) = 6 ii. Co-ordinate of point A is x = 6. Co-ordinate of point B is y = -2. Since, 6 > -2 ∴ d(A, B) = 6 – ( -2) = 6 + 2 ∴ d(A, B) = 8 iii. Co-ordinate of point A is x = -3 Co-ordinate of point B is y = 7. Since, 7 > -3 ∴ d(A, B) = 7 – (-3) = 7 + 3 ∴ d(A, B) = 10 iv. Co-ordinate of point A is x = -4. Co-ordinate of point B is y = -5. Since, -4 > -5 ∴ d(A, B) = -4 – (-5)= -4 + 5 ∴ d(A, B) = 1 v. Co-ordinate of point A is x =-3. Co-ordinate of point B is y = -6. Since, -3 > -6 ∴ d(A, B) = -3 – (-6) = -3 + 6 ∴ d(A, B) = 3 vi. Co-ordinate of point A is x = 4. Co-ordinate of point B is y = -8. Since, 4 > -8 ∴ d(A, B) = 4 – (-8) = 4 + 8 ∴d(A, B) = 12 |
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| 25. |
Points A, B, C are given below. Check, with a stretched thread, whether the three points are collinear or not. If they are collinear, write which one of them is between the other two. |
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Answer» Point B is between the points A and C. |
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| 26. |
Find the distances with the help of the number line given below.i. d(B, E) ii. d (J, J) iii. d(P, C)iv. d(J, H) v. d(K, O)vi. d(O, E) vii. d(P, J)viii. d(Q, B) |
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Answer» i. Co-ordinate of the point B is 2. Co-ordinate of the point E is 5. Since, 5 > 2 ∴ d(B, E) = 5 – 2 ∴ d(B, E) = 3 ii. Co-ordinate of the point J is -2. Co-ordinate of the point A is 1. Since, 1 > -2 ∴ d(J, A) = 1 – (-2) = 1 + 2 ∴ d(J, A) = 3 iii. Co-ordinate of the point P is -4. Co-ordinate of the point C is 3. Since, 3 > -4 ∴ d(P,C) = 3 – (-4) = 3 + 4 ∴ d(P,C) = 7 iv. Co-ordinate of the point J is -2. Co-ordinate of the point H is -1. Since, -1 > -2 ∴ d(J,H) = – 1 – (-2) = -1 + 2 ∴ d(J,H) = 1 v. Co-ordinate of the point K is -3. Co-ordinate of the point O is 0. Since,0 > -3 ∴ d(K, O) = 0 – (-3) = 0 + 3 ∴ d(K, O) = 3 vi. Co-ordinate of the point O is 0. ∴ Co-ordinate of the point E is 5. Since, 5 > 0 ∴ d(O, E) = 5 – 0 ∴ d(O, E) = 5 vii. Co-ordinate of the point P is -4. Co-ordinate of the point J is -2. Since -2 > -4 ∴ d(P, J) = -2 – (-4) = – 2+ 4 ∴ d(P, J) = 2 viii. Co-ordinate of the point Q is -5. Co-ordinate of the point B is 2. Since,2 > -5 ∴ d(Q,B) = 2 – (-5) = 2 + 5 ∴ d(Q, B) = 7 |
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| 27. |
Write the following statements in conditional form.i. Every rhombus is a square. ii. Annies in a linear pair are supplementary. iii. A triangle is a figure formed by three segmentsiv. A number having only two divisors is called a prime number. |
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Answer» i. If a quadrilateral is a rhombus, then it is a square. ii. If two angles are in a linear pair, then they are supplementary. iii. If a figure is a triangle, then it is formed by three segments. iv. If a number has only two divisors, then it is a prime number. |
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| 28. |
Write the converse of each of the following statements. i. If the sum of measures of angles in a figure is 180°, then the figure is a triangle. ii. If the sum of measures of two angles is 90°, thfcn they are eomplement of each otheriii. If the corresponding angles formed by a transversal of two lines are congruent, then the two lines are parallel. iv. If the sum of the digits of a number is divisible by 3, then the number is divisible by 3 |
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Answer» i. If a figure is a triangle, then the sum of the measures of its angles is 180°. ii. if two angles are eomplement of each other, then sum of their measures is 90°, iii. If two lines are parallel, then the corresponding angles formed by a transversal of two lines are congruent. iv. If a number is divisible by 3, then the sum of its digits is also divisible by 3. |
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| 29. |
Write the antecedent (given part) and the consequent (part to be proved) in the following statements. i. If all sides of a triangle are congruent, then its all angles are congruent.ii. The diagonals of a parallelogram bisect each other. |
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Answer» i. If all sides of a triangle are congruent, then its all angles are congruent. Antecedent (Given): All the sides of the triangle are congruent. Consequent (To prove): All the angles are congruent. ii. The diagonals of a parallelogram bisect each other. Conditional statement: “If a quadrilateral is a parallelogram then its diagonals bisect each other. Antecedent (Given): Quadrilateral is a parallelogram. Consequent (To prove): Its diagonals bisect each other. |
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| 30. |
Write converses of the following statements.i. The alternate angles formed by two parallel lines and their transversal are congruent.ii. If a pair of the interior angles made by a transversal of two lines are supplementary, then the lines are parallel.iii. The diagonals of a rectangle are congruent. |
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Answer» i. If the alternate angles made by two lines and their transversal are congruent, then the two lines are parallel. ii. If two parallel lines are intersected by a transversal, then the interior angles formed bv the transversal are supplementary. iii. If the diagonals of a quadrilateral are congruent, then that quadrilateral is a rectangle |
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| 31. |
Write the antecedent (given part) and the consequent (part to be proved) in the following statements. i. If all sides of a triangle are congruent, then its all angles are congruentii. The diagonals of a parallelogram bisect each other. |
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Answer» i. If all sides of a triangle are congruent, then its all angles are congruent. Antecedent (Given): All the sides of the triangle are congruent. Consequent (To prove): All the angles are congruent. ii. The diagonals of a parallelogram bisect each other. Conditional statement: “If a quadrilateral is a parallelogram then its diagonals bisect each other. Antecedent (Given): Quadrilateral is a parallelogram. Consequent (To prove): Its diagonals bisect each other. |
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| 32. |
Answer the questions with the help of figure given below.i. State the points which are equidistant from point B.ii. Write a pair of points equidistant from point.iii. Find d(U,V), d(P,C), d(V,B), d(U, L). |
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Answer» i. Points equidistant from point B are a. A and C, because d(B, A) = d(B, C) = 2 b. D and P, because d(B, D) = d(B, P) = 4 ii. Points equidistant from point Q are a. L and U, because d(Q, L) = d(Q, U) = 1 b. P and R, because d(P, Q) = d(Q, R) = 2 iii. a. Co-ordinate of the point U is -5. Co-ordinate of the point V is 5. Since, 5 > -5 ∴ d(U, V) = 5 – (-5) = 5 + 5 ∴ d(U, V) = 10 b. Co-ordinate of the point P is -2. Co-ordinate of the point C is 4. Since, 4 > -2 ∴ d(P, C) = 4 – (-2) = 4 + 2 ∴ d(P, C) = 6 c. Co-ordinate of the point V is 5. Co-ordinate of the point B is 2. Since, 5 > 2 ∴ d(V, B) = 5 – 2 ∴ d(V, B) = 3 d. Co-ordinate of the point U is -5. Co-ordinate of the point L is -3. Since, -3 > -5 ∴ d(U, L) = -3 – (-5) = -3 + 5 ∴ d(U, L) = 2 |
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| 33. |
Write the following statements in ‘if-then’ form. i. The opposite angles of a parallelogram are congruent. ii. The diagonals of a rectangle are congruent.iii. In an isosceles triangle, the segment joining the vertex and the midpoint of the base is perpendicular to the base. |
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Answer» i. If a quadrilateral is a parallelogram, then its opposite angles are congruent. ii. If a quadrilateral is a rectangle, then its diagonals are congruent. iii. If a triangle is isosceles triangle, then segment joining the vertex of a triangle and midpoint of the base is perpendicular to the base. |
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| 34. |
Write the converse of each of the following statements. i. If the sum of measures of angles in a figure is 180°, then the figure is a triangle. ii. If the sum of measures of two angles is 90°, then they are complement of each other. iii. If the corresponding angles formed by a transversal of two lines are congruent, then the two lines are parallel. iv. If the sum of the digits of a number is divisible by 3, then the number is divisible by 3. |
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Answer» i. If a figure is a triangle, then the sum of the measures of its angles is 180°. ii. if two angles are complement of each other, then sum of their measures is 90°, iii. If two lines are parallel, then the corresponding angles formed by a transversal of two lines are congruent. iv. If a number is divisible by 3, then the sum of its digits is also divisible by 3. |
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| 35. |
Write converses of the following statements. i. The alternate angles formed by two parallel lines and their transversal are congruent. ii. If a pair of the interior angles made by a transversal of two lines are supplementary, then the lines are parallel. iii. The diagonals of a rectangle are congruent. |
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Answer» i. If the alternate angles made by two lines and their transversal are congruent, then the two lines are parallel. ii. If two parallel lines are intersected by a transversal, then the interior angles formed by the transversal are supplementary. iii. If the diagonals of a quadrilateral are congruent, then that quadrilateral is a rectangle. |
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| 36. |
Select the correct alternative answer for the questions given below.How many midpoints does a segment have?(A) only one (B) two (C) three (D) many |
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Answer» (A) only one |
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| 37. |
Answer the following questions. i. If A – B – C and d(A, C) = 17, d(B, C) = 6.5, then d (A, B) = ?ii. If P – Q – R and d(P, Q) = 3.4, d(Q, R) = 5.7, then d(P, R) = ? |
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Answer» i. Given, (A, C) = 17, d(B, C) = 6.5 d(A, C) = d(A, B) + d(B, C) …[A – B – C] ∴ 17 = d(A, B) + 6.5 ∴ d(A,B)= 17 – 6.5 ∴ d(A, B) = 10.5 ii. Given, d(P, Q) = 3.4, d(Q, R) = 5.7 d(P,R) = d(P,Q) + d(Q,R) …[P – Q – R] = 34 + 5.7 ∴ d(P, R) = 9.1 |
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| 38. |
Write the answers to the following questions with reference to the figure given below:i. Write the name of the opposite ray of ray RP ii. Write the intersection set of ray PQ and ray RP. iii. Write the union set of ray PQ and ray QR. iv. State the rays of which seg QR is a subset. v. Write the pair of opposite rays with common end point R. vi. Write any two rays with common end point S. vii. Write the intersection set of ray SP and ray ST. |
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Answer» i. Ray RS or ray RT ii. Ray PQ iii. Line QR iv. Ray QR, ray QS, ray QT, ray RQ, ray SQ, ray TQ v. Ray RP and ray RS, ray RQ and ray RT vi. Ray ST, ray SR vii. Point S |
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| 39. |
Write the following statements in ‘if-then’ form. i. The opposite angles of a parallelogram are congruent. ii. The diagonals of a rectangle are congruent.iii. In an isosceles triangle, the segment joining the vertex and the midpoint of the base is perpendicular to the base. |
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Answer» i. If a quadrilateral is a parallelogram, then its opposite angles are congruent. ii. If a quadrilateral is a rectangle, then its diagonals are congruent. iii. If a triangle is isosceles triangle, then segment joining the vertex of a triangle and midpoint of the base is perpendicular to the base. |
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| 40. |
What are biodegradable and non- biodegradable detergents? Give one example of each. Explain the cleansing action of soaps. |
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Answer» Detergents that can be degraded by bacteria are called biodegradable detergents. Such detergents have straight hydrocarbon chains. For example: Sodium Lauryl sulphate. Detergents that cannot be degraded have highly branched hydrocarbon chains. For example: Sodium - 4- (1, 3, 5,7 - tetra methyl octyl) benzene sulphonate. Soap molecules form micelles around an oil droplet (dirt) in such a way that the hydrophobic parts of the stearate ions attach themselves to the oil droplet and the hydrophilic parts project outside the oil droplet. Due to the polar nature of the hydrophilic parts, the stearate ions (along with the dirt) are pulled into water, thereby removing the dirt from the cloth. |
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| 41. |
Answer the questions with the help of figure given below.i. State the points which are equidistant from point B. ii. Write a pair of points equidistant from point.iii. Find d(U,V), d(P,C), d(V,B), d(U, L). |
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Answer» i. Points equidistant from point B are a. A and C, because d(B, A) = d(B, C) = 2 b. D and P, because d(B, D) = d(B, P) = 4 ii. Points equidistant from point Q are a. L and U, because d(Q, L) = d(Q, U) = 1 b. P and R, because d(P, Q) = d(Q, R) = 2 iii. a. Co-ordinate of the point U is -5. Coordinate of the point V is 5. Since, 5 > -5 ∴ d(U, V) = 5 – (-5) = 5 + 5 ∴ d(U, V) = 10 b. Co-ordinate of the point P is -2. Co-ordinate of the point C is 4. Since, 4 > -2 ∴ d(P, C) = 4 – (-2) = 4 + 2 ∴ d(P, C) = 6 c. Co-ordinate of the point V is 5. Co-ordinate of the point B is 2. Since, 5 > 2 ∴ d(V, B) = 5 – 2 ∴ d(V, B) = 3 d. Co-ordinate of the point U is -5. Co-ordinate of the point L is -3. Since, -3 > -5 ∴ d(U, L) = -3 – (-5) = -3 + 5 ∴ d(U, L) = 2 |
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| 42. |
Prepare a short profile of Charles De Coster using the hints given below. Name: Charles De Coster Birth: 1827 Place of Birth: Munich Famous as: Father of Belgian literatureNotable works: The Legend of TylUlenspiegel and Lamme Goedzak Death: 1879 |
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Answer» Charles De Coster: Charles De Coster was born in 1827 in Munich. He was famous as the Father of Belgian Literature. The Legend of Tyl and Lamme Goedzak are his notable works. He passed away in 1879. |
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| 43. |
Define with example the antifertility drugs. |
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Answer» The drugs which are used for birth control. e.g Oral pil. |
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| 44. |
How are prisms and cylinders alike? |
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Answer» A prism becomes a cylinder provided the number of sides of its base becomes large and larger. |
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| 45. |
The following ten sentences are about a friend of yours in the class. You may seek her confirmation on the statements made.1. You ……….. Sandra, aren’t you? 2. Venu and Reshma …………. their parents, ………..? 3. Your father works in a bank………….? 4. Your mother is a housewife …………..? 5. Syam and Sayanth ………………? 6. Your hobby ………….? 7. You wake up …………..? 8. You have been studying …………..? 9. You studied at ……………. before coming here………….? 10………………………? |
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Answer» 1. Are 2. Visited, didn’t they? 3. Doesn’t he? 4. Isn’t she? 5. Are your brothers aren’t they? 6. Is collecting stamps, isn’t it? 7. At 50’ clock, don’t you? 8. For three hours, haven’t you? 9. Kollam, didn’t you? 10. You will invite me to your house, won’t you? |
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| 46. |
Faster than fairies, faster than witches, Bridges and houses, hedges and ditches: And charging along like troops in a battle All through the meadows the horses and cattle: All of the sights of the hill and the plain Fly as thick as driving rain; And ever again, in the wink of an eye, Painted stations whistle by 1. What is faster than fairies and faster than witches? 2. Pick out two pairs of rhyming words. 3. What idea is expressed in the lines ‘…. in the wink of and eye, painted stations whistle by? 4. Write down an instance of simile used in the poem. |
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Answer» 1. Train 2. Witches – ditches, battle- cattle, plain rain 3. Sudden movement of the train/ The train passed the stations so quickly. 4. Fly as thick as |
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| 47. |
Some figures are given below. Answer the given question after seeing each figure sincerely.(i) What is the shape of all faces of cube?(ii) What is the shape of all faces of Cuboid?(iii) What is the shape of plane face of Cylinder? |
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Answer» (i) Square (ii) Rectangular (iii) Circular |
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| 48. |
Find the distances with the help of the number line given below.i. d(B, E)ii. d (J, J) iii. d(P, C) iv. d(J, H) v. d(K, O) vi. d(O, E) vii. d(P, J) viii. d(Q, B) |
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Answer» i. Co-ordinate of the point B is 2. Co-ordinate of the point E is 5. Since, 5 > 2 ∴ d(B, E) = 5 – 2 ∴ d(B, E) = 3 ii. Co-ordinate of the point J is -2. Co-ordinate of the point A is 1. Since, 1 > -2 ∴ d(J, A) = 1 – (-2) = 1 + 2 ∴ d(J, A) = 3 iii. Co-ordinate of the point P is -4. Co-ordinate of the point C is 3. Since, 3 > -4 ∴ d(P,C) = 3 – (-4) = 3 + 4 ∴ d(P,C) = 7 iv. Co-ordinate of the point J is -2. Co-ordinate of the point H is -1. Since, -1 > -2 ∴ d(J,H) = – 1 – (-2) = -1 + 2 ∴ d(J,H) = 1 v. Co-ordinate of the point K is -3. Co-ordinate of the point O is 0. Since,0 > -3 ∴ d(K, O) = 0 – (-3) = 0 + 3 ∴ d(K, O) = 3 vi. Co-ordinate of the point O is 0. ∴ Co-ordinate of the point E is 5. Since, 5 > 0 ∴ d(O, E) = 5 – 0 ∴ d(O, E) = 5 vii. Co-ordinate of the point P is -4. Co-ordinate of the point J is -2. Since -2 > -4 ∴ d(P, J) = -2 – (-4) = – 2+ 4 ∴ d(P, J) = 2 viii. Co-ordinate of the point Q is -5. Co-ordinate of the point B is 2. Since,2 > -5 ∴ d(Q,B) = 2 – (-5) = 2 + 5 ∴ d(Q, B) = 7 |
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| 49. |
If the co-ordinate of A is x and that of B is . y, find d(A, B). i. x = 1, y = 7 ii. x = 6, y = -2 iii. x = -3, y = 7 iv. x = -4, y = -5 v. x = -3, y = -6 vi. x = 4, y = -8 |
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Answer» i. Co-ordinate of point A is x = 1. Co-ordinate of point B is y = 7 Since, 7 > 1 ∴ d(A, B) = 7 – 1 ∴ d(A, B) = 6 ii. Co-ordinate of point A is x = 6. Co-ordinate of point B is y = -2. Since, 6 > -2 ∴ d(A, B) = 6 – ( -2) = 6 + 2 ∴ d(A, B) = 8 iii. Co-ordinate of point A is x = -3. Co-ordinate of point B is y = 7. Since, 7 > -3 ∴ d(A, B) = 7 – (-3) = 7 + 3 ∴ d(A, B) = 10 iv. Co-ordinate of point A is x = -4. Co-ordinate of point B is y = -5. Since, -4 > -5 ∴ d(A, B) = -4 – (-5) = -4 + 5 ∴ d(A, B) = 1 v. Co-ordinate of point A is x =-3. Co-ordinate of point B is y = -6. Since, -3 > -6 ∴ d(A, B) = -3 – (-6) = -3 + 6 ∴ d(A, B) = 3 vi. Co-ordinate of point A is x = 4. Co-ordinate of point B is y = -8. Since, 4 > -8 ∴ d(A, B) = 4 – (-8) = 4 + 8 ∴ d(A, B) = 12 |
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| 50. |
From the information given below, find which of the point is between the other two. If the points are not collinear, state so. i. d(P, R) = 7, d(P, Q) = 10, d(Q, R) = 3 ii. d(R, S) = 8, d(S, T) = 6, d(R, T) = 4 iii. d(A, B) = 16, d(C, A) = 9, d(B, C) = 7 iv. d(L, M) =11, d(M, N) = 12, d(N, L) = 8 v. d(X, Y) = 15, d(Y, Z) = 7, d(X, Z) = 8 vi. d(D, E) = 5, d(E, F) = 8, d(D, F) = 6 |
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Answer» i. Given, d(P, R) = 7, d(P, Q) = 10, d(Q, R) = 3 d(P, Q) = 10 …(i) d(P, R) + d(Q, R) = 7 + 3 = 10 .. .(ii) ∴ d(P, Q) = d(P, R) + d(Q, R) …[From (i) and (ii)] ∴ Point R is between the points P and Q i. e., P – R – Q or Q – R – P. ∴ Points P, R, Q are collinear. ii. Given, d(R, S) = 8, d(S, T) = 6, d(R, T) = 4 d(R, S) = 8 …(i) d(S, T) + d(R, T) = 6 + 4 = 10 …(h) ∴ d(R, S) ≠ d(S, T) + d(R, T) … [From (i) and (ii)] ∴ The given points are not collinear. iii. Given, d(A, B) = 16, d(C, A) = 9, d(B, C) = 7 d(A, B) = 16 …(i) d(C, A) + d(B, C) = 9 + 7 = 16 …(ii) ∴ d(A, B) = d(C, A) + d(B, C) …[From(i) and (ii)] ∴ Point C is between the points A and B. i. e., A – C – B or B – C – A. ∴ Points A, C, B are collinear iv. Given, d(L, M) = 11, d(M, N) = 12, d(N, L) = 8 d(M, N) = 12 …(i) d(L, M) + d(N, L) = 11 + 8 = 19 …(ii) ∴d(M, N) + d(L, M) + d(N, L) … [From (i) and (ii)] ∴ The given points are not collinear. v. Given, d(X, Y) = 15, d(Y, Z) = 7, d(X, Z) = 8 d(X, Y) = 15 …(i) d(X,Z) + d(Y, Z) = 8 + 7= 15 …(ii) ∴ d(X, Y) = d(X, Z) + d(Y, Z) …[From (i) and (ii)] ∴ Point Z is between the points X and Y i. e.,X – Z – Y or Y – Z – X. ∴ Points X, Z, Y are collinear. vi. Given, d(D, E) = 5, d(E, F) = 8, d(D, F) = 6 d(E, F) = 8 …(i) d(D, E) + d(D, F) = 5 + 6 = 11 …(ii) ∴ d(E, F) ≠ d(D, E) + d(D, F) … [From (i) and (ii)] ∴ The given points are not collinear. |
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