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There are different types of forests found in different regions of India due to variations in climatic condition and uneven rainfall. On one hand, Evergreen forests are found in western Himalayas and in the western and eastern slopes of Western Ghats, and on the other hand, Autumn Forests are found in the north – western plains and mid and low areas of Ganga. With the change in amount of rainfall, pattern of forests also changes. In western Rajasthan, Dry forests are found du,e to minimum amount of rainfall.

(b) In desert areas

Older alluvial soil is found in flooded regions where overflowing water cannot reach.

Soil conservation is an effort for increasing or maintaining the fertility of soil. It is the prevention of soil loss from erosion or reduced fertility Caused by over – usage, acidification, salinization or any other chemical contamination. Slash and burn and other unsustainable methods of subsistence farming are practiced in some lesser – developed areas.

The alluvial soils are found in the pains. These type of soils are formed mainly due to silt deposited by the rivers. In India, alluvial soils found in the Northern plains were formed due to the sediments deposited by Indo – Gangetic Brahmaputra rivers. In coastal regions, some alluvial deposits were formed due to tidal action. Rocks of the Himalayas form the parent material. Thus, the parent material of these soils is of transported origin.

(c) Gully erosion

Correct Answer is: (c) Rajasthan

(c) p – amino benzene suiphonic acid

(d) Leaving the land layered

Correct Option (c) P_A < P_B , T_A > T_B

Explanation: 

For state A, C_p - C_v = R i.e. the gas behaves as ideal gas.

For state B, C_p - C_v  = 1.06 R (≠ R) i.e. the gas does not behave like ideal gas.

and we know that at high temperature and at low pressure nature of gas may be ideal. So we can say that (c) P_A < P_B and T_A > T_B

A perfect gas molecule has only translational K.E.

E = 3/2 k_BT

Correct Option (a) 6.02 x 10²³/22400

Explanation: 

Number of molecule in 22.4 litre gas at N.T.P.    6.023 x 10²³

or number of molecule in 22.4 x 10³ cm³ =  6.023 x 10²³    [As 22.4 litre = 22.4 x 10³  cm³]  

:.   Number of molecules in  1 cm³ =  6.023 x 10²³/22400

θ = ± mλ/e. 

जहाँ, θ = कोणीय स्थिति, m कोई पूर्णांक, 

λ = तरंगदैर्घ्य, 

e = स्लिटों के बीच की दूरी।

कोणीय चौड़ाई = 2λ/d अर्थात् यह रेखा-छिद्र की चौड़ाई d के व्युत्क्रमानुपाती है। इसलिए स्लिट की चौड़ाई कम करने से केन्द्रीय उच्चिष्ठ की चौड़ाई बढ़ जाएगी।

निर्वात् में गतिमान प्रकाश के लिए डॉप्लर प्रभाव में प्रेक्षक द्वारा ग्रहण किए गए प्रकाश की आभासी आवृत्ति दोनों ही दशाओं में समान होती है। भले ही दर्शक, स्थिर स्रोत की ओर गति कर रहा हो अथवा स्रोत समान चाल से दर्शक की ओर गतिमान हो। इस प्रकार प्रकाश में डॉप्लर प्रभाव सममित है। दूसरी ओर ध्वनि तरंगों को चलने के लिए माध्यम की आवश्यकता होती है, इसलिए भले ही चाहे उक्त दोनों स्थितियों में प्रेक्षक तथा स्रोत के बीच समान आपेक्षिक गति होने के कारण ये स्थितियाँ समान प्रतीत होती हैं परन्तु वे समान नहीं हैं। ऐसा इस कारण से है कि दोनों दशाओं में प्रेक्षक का माध्यम के सापेक्ष वेग भिन्न-भिन्न है; अतः उक्त दोनों दशाओं में सुनी गई ध्वनि की आभासी आवृत्तियाँ समान नहीं हो सकतीं।

यदि किसी माध्यम में प्रकाश की गति की बात की जाए तो पुनः दोनों स्थितियाँ अलग-अलग हो जाएँगी चूंकि दोनों स्थितियों में प्रेक्षक का माध्यम के सापेक्ष वेग भिन्न-भिन्न होगा। अतः इस दशा में प्रेक्षक द्वारा ग्रहण किए गए प्रकाश की आवृत्ति के भिन्न डॉप्लर सूत्रों की अपेक्षा की जानी चाहिए।

किसी माध्यम में दो अथवा दो से अधिक प्रगामी तरंगें एक साथ परन्तु एक-दूसरे की गति को बिना प्रभावित किये चल सकती हैं। अत: माध्यम के प्रत्येक कण का किसी क्षण परिणामी विस्थापन दोनों तरंगों द्वारा अलग-अलग उत्पन्न विस्थापनों के सदिश (vector) योग के बराबर होता है। इस सिद्धान्त को ‘अध्यारोपण का सिद्धान्त’ कहते हैं।

तरंगों के अध्यारोपण से तीन प्रकार के प्रभाव प्राप्त होते हैं- 

• व्यतिकरण,

• विस्पन्द, 

• अप्रगामी तरंगें।

Correct Option (b) V₁

Explanation: 

Average speed of gas molecule v_{av =} √8kT/m. It depends on temperature and molecular mass. So the average speed of oxygen will be same in vessel A and vessel C and that is equal to V₁ .

The three units which are used to measure the temperature: Degree Celsius, Fahrenheit and Kelvin.

Boiling point of mercury is 357°C

1. Its expansion is uniform. (For equal amounts of heat it expands by equal lengths.) 

2. If is opaque and shining. 

3. It does not stick to the sides of the glass tube. 

4. It is a good conductor of heat. 

5. It has a high boiling point (357°C) and a low freezing point (-39°C). Hence a wide range of temperatures can be measured using a mercury thermometer.

1. (c) 

2. (a)

3. (d) 

4. (b)

The freezing point of water is 32°F

Curve (a)  represents the relation between Celsius and Fahrenheit temperatures 

The correct answer is: (a)

(a) Fahrenheit and kelvin 

Ruler appears on the top and on the left side of the document window. It allows to format the horizontal or vertical alignment of text in a document. Two types of rulers are available in MS-Word 2007 as follows: 

1. Horizontal ruler indicates the width of the document. 

2. Vertical ruler indicates the height of the document.

The correct answer is: (c)

(c) high temperature and low pressure 
 

(a) The coefficient of linear expansion has dimension K^-1.

Virus infected cells secrete proteins called interferons, which are low molecular weight proteins and act as cytokine barriers, They protect non-infected cell. from further infection.

Since, mean square velocity is directly proportional to temperature. If temperature is zero then mean square velocity is zero and since K. E. of molecules cannot be negative and hence temperature less than absolute zone is not possible. 

The correct answer is (c). (d)

(c) The kinetic energy of the oxygen molecule increases and that of the hydrogen molecule decreases. 

(d) The kinetic energy of the hydrogen molecule increases and that of the oxygen molecule decreases.

Atomicity and temperature.

Zero is the volume of a gas at absolute zero of temperature.

(b) with smaller average speed

(a) the kinetic energy of 1mole

STP 22.4 litre.

Gas in which intermolecular forces are absent.

Increases √3 times.

Hydrogen (rms speed is greater)

Here, P ∝ T

∴ \(\frac{P_2}{P_1}\) = \(\frac{T_2}{T_1}\) = \(\frac{600}{300}\) = 2

∴ P = 2P₁ = 2 × 5 × 10⁴ Pa = 10⁵ Pa is the required pressure.

Work is done against friction. This work done is converted into heat. Temperature rises. PV = nRT, As volume of tyre is const. P ∝ T. 

Answer is (A) P ∝ d

PV = RT, but V = M/d. Hence P/M = RTd.

Therefore at constant temperature, P∝ d.

N_A = 6.023 × 10²³.

The main assumptions of kinetic theory of gases are :

1. A gas is made up of a large number of sub-microscopic particles called atoms.
2. Gases consist of particles in constant random motion. They continue to move in a straight line until they collide with each other on the walls of their container.
3. Gas pressure is due to the moleiMIeS colliding with the walls of the container. All of these collisions are perfectly elastic. This means that there is no change in energy of either the particles or the wall upon collision. So, no energy is lost or gained from collisions.
4. No molecular forces are at work. The potential energy of molecules is zero. So, whole of the energy. in an ideal gas is kinetic energy only. There is no attraction or repulsion between the particles.
5. The time taken for the collision is negligible as compared with the time between collisions.
6. The kinetic energy of a gas is a measure of its kelvin temperature. Each gas molecule has different speed but the temperature and kinetic energy of gas refer to the average of these speeds.
7. The average kinetic energy of an atom of gas is directly proportional to the temperature. An increase in temperature increases the speed in which the gas molecules move.
8. All gases at a given temperature have same average kinetic energy.
9. fighter molecules of a gas move faster than the heavier molecules.

Answer is (C) Temperature

Answer is (B) 2 x 10⁵ Pa. 

It is a case, as if volume is halved, 

So the pressure is doubled.

Answer is (D) regular