Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The rms speed of oxygen molecules in a gas is v. If the temerature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become (a) v (b) v √2 (c) 2v (d) 4v.

Answer» The correct answer is (c)
2.

How do you calculate gross profit under single entry system?

Answer»

The differences between closing capital and opening capital adjusted with additional capital and drawings called Gross profit or gross loss 

[closing capital + drawings – Additional capital – opening capital = gross profit]

3.

What is statement of Profit or Loss?

Answer»

Statement of Profit or Loss is a statement prepared under single entry system. It is prepared for the purpose of ascertaining Profit or Loss of a business in a given period. 

4.

Write the Balance Sheet Equation.

Answer»

Balance Sheet Equation. 

Assets = Capital + Liability. 

5.

Solar cooker works on which principle?

Answer»

Solar cooker works on the principle of converting sunlight at a point due to concave mirror.

6.

Define the term virtual image.

Answer»

Virtual image: Virtual image ¡s the ¡mage formed due to diverging of light rays. 

(OR) 

The Image formed due to the extension of rays in the backward direction.

7.

Define spherical mirror.

Answer»

Spherical mirror: A mirror that has a curved reflective surface is a spherical mirror.

8.

What is reflected Ray?

Answer»

Reflected Ray: The ray which is reflected from the surface is called a reflected ray.

Reflected ray is a ray which is reflected back from the surface. 

Angle of incidence= Angle of refraction


9.

Define reflection.

Answer»

Reflection: The bouncing back of the light is called reflection.

10.

Define ray diagram.

Answer»

Ray diagram: A diagram showing the paths of selected rays through an optical system.

11.

What is real image?

Answer»

Real image: The image formed due to the converging of light rays is a real image.

Image which can be obtained on a screen is called a real image. 

12.

Define Image distance.

Answer»

Image distance (v): The distance between image and mirror is called image distance.

13.

Define focal length (f).

Answer»

Focal length (f): The distance between vertex and focus.

14.

What is principal axis (or) Central axis?

Answer»

Principal axis (or) Central axis: The horizontal line which passes through the center of curvature and pole.

15.

Define focus or focal point (F).

Answer»

Focus or focal point (F): The rays coming from distinct objects parallel to the concave mirror will converge at a point called focus or focal point.

16.

Define pole (P) (or) vertex.

Answer»

Pole (P) (or) Vertex: The point where the central axis touches the mirror.

17.

What is a diverging mirror ?

Answer»

Convex mirror diverges the parallel light beam. So it is called a diverging mirror.

18.

What is the height of the object and height of the image if measured downwards ?

Answer»

The height of the object and height of the image is negative if measured downwards.

19.

What is the focal length of concave and convex mirror?

Answer»

Focal length is positive for a concave mirror and negative for a convex mirror.

20.

What is mirror formula ?

Answer»

Mirror formula is \(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\)

f = focal length; u = object distance; v = image distance

21.

What is image distance for real and virtual image?

Answer»

The image distance is negative for a real image and positive for a virtual image.

22.

What type of image will form in convex mirror ?

Answer»

We always get a virtual and diminished image due to a convex mirror.

23.

Give reasons : Zinc salts are colourless.

Answer»
  • Colour of the ions of d-block elements depends on the number of unpaired electrons in (n – 1) d-orbitals. 
  • Zinc forms salts of Zn2+ ions. 
  • The electronic configuration of Zn+2 is [Ar] 3d10
  • Since Zn+2 does not have unpaired electrons in 3d-orbital, d→d transition cannot take place, hence, Zn+2 ions form colourless salts.
24.

What will be the colour of Cd2+ salts? Explain.

Answer»
  • The electronic configuration of, 48Cd [Kr]36 3d10 5s2 and Cd2+ [Kr]363d10
  • Cd2+ ions have completely filled 3d subshell and there are no unpaired electrons in 3d-orbital. 
  • Hence d → d transition is not possible. 
  • Therefore, Cd2+ ions do not absorb radiations in the visible region and the salts of Cd2+ ions are colourless (or white). 
25.

How does the copy-paste system in SPARSH differ from that of our current system ?

Answer»

In our current copy-paste system, we use physical digital devices like pen drive, hard disk, laptop, tablet, i-pad, bluetooth, etc. They are either with cord or cordless. While in SPARSH, we have directly to touch the source from where we have to copy. The contents will be stored in our physical body. Then we have to touch the recipient device and the contents will be pasted there.

26.

The idea of stationary orbits was first given by ……(a) Rutherford (b) J.J. Thomson (c) Nails Bohr (d) Max Planck

Answer»

(c) Niels Bohr.

27.

For a Five Year Old Boy Poem Summary in English.

Answer»

The Poem ‘For a five Year old is written by Fleur Adcock.. In the poem, the poet ironically points out the contradictions in our day to day dealings of life. She points out the differences between what we preach and low we act. She ironically points out that by nature human beings do not practice what they preach.

The poet illustrates this human behaviour by narrating a fictitious episode in which she imagines her five year old child calling out to her after it sees a snail climbing up the window silly after a rainy night. The mother (Poet) goes to the child’s room and explains that it would be unkind to leave it there, because it might climb down to the floor. So it is better to take care of it, before someone unknowingly squashes it. She asks the child to pick it up carefully and carry it outside to the garden and leave it there to feed on daffodil flowers.

In the next stanza the poet wonders why such a kind of faith still prevails where people still believe that character is built by mere words of advice, than by actions of others. She feels sad, because the child believed in her words and acted gently with the snail. She feels sad but amazed because the child believed the words of her mother (Poet) who was actually not gentle in her actions. The mother (Poet) had taken her words seriously even though it knew that the mother had drowned the child’s kittens and betrayed even her close relatives. The Poet had also conveyed such harsh truths to others. The harsh truth is that, it is human nature to preach one thing and practice another and that is how things go on in this world.

She strongly believes that being a mother of a child, she is right in advising her child to be good and gentle. And so both the mother and child are kind to little creatures like snails.

28.

Give an example to show that the following statement is false. Any two forces acting on a body can be combined into single force that would have same effect.

Answer»

A single force i.e. resultant of two forces acting on a body depends upon the angle between them also. The simple example for this is if two forces 5 N and 5 N acting on the object in the opposite direction, the single resultant force acting on the body is zero. But, if two forces acting on the object along the same direction, then the resultant i.e. the single force is 5 + 5 = 10 N. Hence the given statement “any two forces acting on a body can be combined into single force that would leave same effect” is wrong.

29.

torment of inertia of a uniform solid sphere about an axis passing through the center along its diameter is –(a) \(\frac{2}{3}\) MR2(b) \(\frac{5}{3}\) MR2(c) \(\frac{7}{5}\)MR2(d) \(\frac{2}{5}\)MR2

Answer»

Correct answer is (d) \(\frac{2}{5}\)MR2

30.

Describe the Elastic Property of Matter.

Answer»

Elastic Property of Matter :

(1) Elasticity : The property of matter by virtue of which a body tends to regain its original shape and size after the removal of deforming force is called elasticity. 

(2) Plasticity : The property of matter by virtue of which it does not regain its original shape and size after the removal of deforming force is called plasticity. 

(3) Perfectly elastic body : If on the removal of deforming forces the body regain its original configuration completely it is said to be perfectly elastic. A quartz fibre and phosphor is the nearest approach to the perfectly elastic body. 

(4) Perfectly plastic body : If the body does not have any tendency to recover its original configuration on the removal of deforming force, it is said to be perfectly plastic. Paraffin wax, wet clay are the nearest approach to the perfectly plastic body. Practically there is no material which is either perfectly elastic or perfectly plastic. 

(5) Reason of elasticity : On applying the deforming forces, restoring forces are developed.When the deforming force is removed, these restoring forces bring the molecules of the solid to their respective equilibrium position (r = r0) and hence the body regains its original form. 

(6) Elastic limit : The maximum deforming force upto which a body retains its property of elasticity is called elastic limit of the material of body. Elastic limit is the property of a body whereas elasticity is the property of material of the body. 

(7) Elastic fatigue : The temporary loss of elastic properties because of the action of repeated alternating deforming force is called elastic fatigue. 

It is due to this reason : 

(i) Bridges are declared unsafe after a long time of their use. 

(ii) Spring balances show wrong readings after they have been used for a long time. 

(iii) We are able to break the wire by repeated bending. 

(8) Ealstic after effect : The time delay in which the substance regains its original condition after the removal of deforming force is called elastic after effect. It is negligible for perfectly elastic substance, like quartz, phosphor bronze and large for glass fibre.

31.

State the law of floatation.

Answer»

The law of floatation states that a body will float in a liquid if the weight of the liquid displaced by the immersed part of the body equals the weight of the body.

32.

What do you mean by upthrust or buoyancy?

Answer»

The upward force exerted by a fluid that opposes the weight of an immersed object in a fluid is called upthrust or buoyant force.

33.

State Archimedes principle.

Answer»

If states that when a body is partially or wholly immersed in a fluid, it experiences an upward thrust equal to the weight of the fluid displaced by it and its upthrust acts through the centre of gravity of the liquid displaced.

34.

Each sperm contains a special organelle known as an acrosome that contains hydrolytic enzymes. It also contains numerous mitochondria. What are the likely functions of these organelles in relation to the sperms' overall functions? AcrosomeNumerous mitochondria(A)Digests through egg membranes for sperm to penetrate.Provide energy for beating action of flagellum.(B)Digests through uterine lining to reach egg.Provide energy for respiration(C)Digests through oviducts to reach egg.Direct overall activities of the sperm.(D)Directs movement of the sperm though the female reproductive tract. Provide energy for fertilisation of egg,

Answer»

Correct option   (A)

Explanation:

The egg is surrounded by additional outer membranes, in addition to the cell surface membrane. The acrosomal enzymes serve to break down these membranes to bring about fusion of sperm and egg. The swimming action of the sperm by means of its flagella requires energy that is supplied by numerous mitochondria.

35.

A student decides to study the impact of removing certain flower parts on fruit formation in plant species X. He chooses three separate plants that are growing in the same plot under uniform conditions. The data is given in the table below.PlantsPart removedlmpact on formation1Anther30% less fruit formed than average plant in the polt2StigmaNo fruit formed3PetalNo significant impactWhich of the following can be inferred from the above data? (A) Anthers and stigmas are crucial in sexual reproduction in species X. (B) Pollen grains are probably unable to germinate if they land on other parts of the carpel besides the stigma. (C) Species X is likely to be wind-pollinated. (D) Species X relies completely on cross-pollination.

Answer»

Correct option  (D) Species X relies completely on cross-pollination. 

Explanation:

The removal of anthers affects fruit formation in plant 1, this implies that species X relies partially on self-pollination. The removal of either anthers or stigmas affects rate of fruit formation significantly. No fruits are observed when the stigmas in plant 2 are removed. This shows that pollen grains are probably unable to germinate if they land on any other part of the carpel besides the stigma. The petals do not seem to play a significant role in facilitating fruit formation. Species X is therefore likely to be wind-pollinated with reduced petals.

36.

The given diagram shows the carpel of an insect pollinated flower. What is the most likely reason for the non germination of pollen grain Z?(A) Pollen grains X and Y were brought to the stigma earlier, therefore, their germination inhibited the germination of pollen grain Z. (B) Pollen grain Z was brought to the flower by wind, while pollen grains X and Y were brought to the flower by insects. (C) Pollen grain Z lacks protrusions that allow it to adhere properly onto the stigma surface. (D) Pollen grain Z comes from a flower of an incompatible species.

Answer»

Correct option (D) Pollen grain Z comes from a flower of an incompatible species. 

Explanation:

Pollen grains can only germinate if the pollen grain and stigma are compatible, i.e., of the same or closely related species, Pollen grains X and Y must have come from a compatible species. Only compatible pollen grains germinate and form pollen tubes.

37.

Which among the following is an example of hydrophytes?(A) Lotus(B) Hydrilla(C) Trapa(D) All of these

Answer»

(D) All of these

38.

Mutations can be induced by(A) Gamma radiation(B) Infrared radiation(C) Ethylene(D) IAA

Answer»

(A) Gamma radiation

39.

In mature Polygonum type of embryo sac, these are found – (a) Seven cells and eight nuclei (b) Seven nuclei and eight cells (c) Eight cells and eight nuclei (d) Seven cells and seven nuclei

Answer»

The answer is (a) Seven cells and eight nuclei

A Polygonum type of embryo is 7 celled and 8 nucleate where these are 3 antipodals, 2 synergids, one egg cell and one secondary nucleus which is binucleated. 

40.

Write a note on pollenkitt.

Answer»

Pollenkitt is contributed by the tapetum and coloured yellow or orange and is chiefly made of carotenoids or flavonoids. It is an oily layer forming a thick viscous coating over pollen surface. It attracts insects and protects damage from UV radiation.

41.

Which of the following are isoelectronic and isostructural ? NO3 , CO32-, CIO3- , So3a. NO3- , CO32-b. SO3 , NO3- c. CIO3- , CO32-d. CIO3- , SO3

Answer»

Correct option is a. NO3- , CO32-

42.

How many moles of glucose are present in 720 g of glucose?

Answer»

Glucose = C6H4O4 

Molecular mass of Glucose = (12 x 6) + (1 x 12) + (16 x 6) 

= 72 + 12 + 96 = 180 

= 720/180 

= 4 moles.

43.

Energy of an electron in the ground state of the hydrogen atom is -2.18 x 10-18 J. Calculate the ionization enthalpy of atomic hydrogen in terms of kJ mol-1 .

Answer»

Energy of an electron in the ground state of the hydrogen atom = -2.18 x 10-18 J

H → H+ + e- 

Energy required to ionize 1 mole of hydrogen atoms, we multiply by the Avogadro constant. 

E = 2.18 x 10-18 x 6.023 x 1023 

= 13.123 x 105 J mol-1 

I.E = +1312 K J mol-1

44.

Halogens and chalcogens have highly negative electron gain enthalpies. Why?

Answer»
  • Group 16 (chaicogens) and Group 17 (halogens) are interested to add two or one electrons respectively to attain stable noble gas configuration. 
  • Because of this interest these elements have highly negative electron gain enthalpies.
45.

Define matter. What are the types of matter?

Answer»

\(\bullet\)  A matter is anything which has mass and occupies space. 

 \(\bullet\)  Matters exist in all three states such as solid, liquid and gas.

46.

Define equivalent mass of a salt.

Answer»

Equivalent mass of a salt: 

It is defined as the number of parts by mass of the salt that is produced by the neutralization of one equivalent of an acid by a base. Therefore the equivalent mass of the salt is equal to its molar mass.

47.

Which of the following compound(s) has/have percentage of carbon same as that in ethylene (C2H2 )? (a) propene (b) ethyne(c) benzene (d) ethane

Answer»

(a) propene

Molar mass of carbon 

Percentage of carbon in ethylene(C2H6 ) =  (Molar mass of carbon) / (Molar mass) x 100

= 24/28 × 100 

= 85.71% 

Percentage of carbon in propene (C3H6 ) = 24/28 × 100 

= 85.7 1%

48.

The oxidation number of carboxylic carbon atom in CH3COOH is ……(a) + 2 (b) + 4 (c) + 1 (d) + 3

Answer»

(d) + 3 

CH3COOH 

-3 + 3 + x – 4 + 1 = 0

x – 3 = 0 

x = + 3

Carboxylic carbon oxidation number = +3

49.

Distinguish among the different physical states of matter.

Answer»

Differences among three physical states of matter (solid, liquid and gas) are as follows

S.No.PropertiesSolidLiquidGas
1.VolumeDefiniteDefiniteNo define
2. ShapeNo definiteNo definiteNo definite
3.Molecular arrangementVery closely packedLoosely packedVery loosely packed
4.Freedom of movementNot much freedomMove around and better than solidMove easy and fast
5.CompressibilityNon-compressibleLess compressibleEasily compressible
50.

Which one of the following is used as a standard for atomic mass? (a) 6C12(b) 7C12(c) 6C13 (d) 6C14

Answer»

The correct answer is: (a) 6C12