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119851.

The man is a writer. The girl is a ……… girl.

Answer»

The man is a writer. The girl is a school girl.

119852.

The girl is a ………… student.

Answer»

The girl is a good student.

119853.

The man’s name is Bond. The girl’s name is _______

Answer»

The man’s name is Bond. The girl’s name is Usha .

119854.

The girl knows the goat language because.

Answer»

She had her own goats at home

119855.

Who saved the plant from the goats? How?

Answer»

Usha advanced on the goat shouting with an open blue umbrella and drives them away.

119856.

The man and the girl share a common interest. They both keep looking for new ………..

Answer»

The man and the girl share a common interest. They both keep looking for new species .

119857.

The author had wondered what its name could be. But the villagers had given it the name ………

Answer»

The author had wondered what its name could be. But the villagers had given it the name Basant .

119858.

We call this day Yugadi. What do people in Himachal Pradesh call it?

Answer»

Basant Panchami

119859.

The two friends could not say that the new flower was their discovery because

Answer»

they did not know its botanical name

119860.

They are both attracted by i. a new flower. ii. the goats that they meet. iii. the rain clouds in the Himalayas. iv. the cold winds that hum and whistle through the pines.

Answer»

i. a new flower

119861.

Quarks inside protons and neutrons are thought to carry fractional charges [(+2/3)e; (-1/3)e]. Why do they not show up in Millikan’s oil-drop experiment?

Answer»

Quarks having the fractional charges are thought to be confined within a proton or a neutron only. These quarks are bound by forces, which grow stronger, if they are tried to be pulled apart. Thus, the quarks always remain together. It follows that though fractional v charges exist in nature, the observable charges are always integral multiples of e.

119862.

Designate each subshell with n = 4.

Answer»
Value of nValue of lSubshell
404s
14p
24d
34f

119863.

On the basis of Pauli's exclusion principle show that the maximum number of electrons in the M-Shell (n = 3) of any individual atom is 18.

Answer»

According to Pauli's exclusion principle, "only two electrons may exist in the same orbital and these electrons must have opposite spin."

For M-shell n = 3

Maximum number of electrons in the shell

= 2n2

= 2(3)2

= 18

119864.

What is Pauli's exclusion principle? 

Answer»

According to this principle, "No two electrons in an atom can have the same set of four quantum numbers."

119865.

Why Pauli's Exclusion principle is called exclusion principle?

Answer»

This is because according to the principle, if one electron in an atom has same particular values for the four quantum numbers, then all the other electrons in that atom are excluded from having the same set of values.

119866.

What is friction? Define coefficient of static friction and coefficient of kinetic friction. Give the necessary formula for each.

Answer»

1. The property which resists the relative motion between two surfaces in contact is called friction. 

2. The coefficient of static friction is defined as the ratio of limiting force of friction to the normal reaction. 

Formula: μs = FL/N

3. The coefficient of kinetic friction is defined as the ratio of force of kinetic friction to the normal reaction between the two surfaces in contact.

Formula : μs = Fk/N

119867.

A block of mass 37 kg rests on a rough horizontal plane having coefficient of static friction 0.3. Find out the least force required to just move the block horizontally.

Answer»

Given: m = 37 kg, µs = 0.3, g = 9.8 m /s2 

To find : Limiting force (FL)

Formula : FL = µsN = µs mg

Calculation: From formula,

FL = 0.3 × 37 × 9.8 = 108.8 N

The force required to move the block is 108.8 N.

119868.

Until 1950, the building in the picture was known as ‘Viceroy’s House’, and served as the residence of the Governor General of India.What is his/her term of office?

Answer»

The President is elected for a period of 5 years. He or she can be re-elected after his or her term.

119869.

Until 1950, the building in the picture was known as ‘Viceroy’s House’, and served as the residence of the Governor General of India.How is he or she elected?

Answer»

The President is elected indirectly by the elected members of the Legislature as he or she is a nominal (de jure) and not the de facto head. An Electoral college elects the President. The Electoral College elects the President. 

The Electoral College consists of the following members:

1. The elected members of both Houses of Parliament.

2. The elected members of the State Legislative Assemblies

119870.

Until 1950, the building in the picture was known as ‘Viceroy’s House’, and served as the residence of the Governor General of India.Identify the building. Whose official residence is it now?

Answer»

Rashtrapati Bhavan, President of India.

119871.

What is Orbital?

Answer»

The region of space around the nucleus where the probability of finding an electron is maximum is called an orbital.

119872.

The position of their centre of mass from A is

Answer» formula for COM is = mass of A (distance from the line we want to find COM) +mass of B (d from line)+ mass of C (d from line) / mass of( A+B+C)

as all spheres are identical so mass will be same of all 3

now there can be 2 ways of approaching this question

first one if we find COM from the line passing through center of sphere of A then its distance from line will be 0

so m(0)+m(2R)+m(4R) / 3m = 2R

second one if we are finding it from the line A is starting then distance of center of A will be R so m(R)+m(3R)+m(5R) / 3m= 3R

hope it will help you
119873.

When you exercise in the morning, by considering your body as thermodynamic system, which of the following is true?(a) ∆U > 0, W > 0 (b) ∆U < 0, W > 0 (c) ∆U < 0, W < 0 (d) ∆U = 0, W > 0

Answer»

(b) ∆U < 0, W > 0

119874.

Define heat capacity (or) thermal capacity?

Answer»

The heat capacity of a body is defined as the amount of heat required to raise its temperature through one degree

119875.

A hot cup of coffee is kept on the table. After some time it attains a thermal equilibrium with the surroundings. By considering the air molecules in the room as a thermodynamic system, which of the following is true? (a) ∆U &gt; 0, Q = 0 (b) ∆U &gt; 0, W &lt; 0 (c) ∆U &gt; 0, Q &gt; 0 (d) ∆U = 0, Q &gt; 0

Answer»

(c) ∆U > 0, Q > 0

119876.

Which three revolutionaries and fast friends were hanged on the same day?

Answer»

These three revolutionaries and fast friends which were hanged on the same day (23rd March 1931) are: Bhagat Singh, Sukhdev and Rajguru.

119877.

A ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet. (i) In which direction will it move? (ii) What will be the direction of it’s magnetic moment?

Answer»

(i) Away from the magnet.

(ii) Magnetic moment is from left to right

119878.

A toroid of n turns, mean radius R and cross-sectional radius a carries current I. It is placed on a horizontal table taken as x-y plane. Its magnetic moment m (a) is non-zero and points in the z-direction by symmetry. (b) points along the axis of the tortoid (m = mφ ). (c) is zero, otherwise there would be a field falling as 1/r3 at large distances outside the toroid. (d) is pointing radially outwards.

Answer»

(c) is zero, otherwise there would be a field falling as 1/r3 at large distances outside the toroid. 

119879.

Why is the first ionisation energy of oxygen lower than that of nitrogen?

Answer»

1. Electronic configuration : 

7N Is2 2s2 2px1 2py1  2pz1 

8O Is2 Is2 2px2 2py1  2pz1 

2. Nitrogen has extra stability due to half-filled porbitals. Therefore it has higher first ionisation enthalpy. 

3. Oxygen by losing one electron from 2px orbital acquires extra stability of half-filled 7-orbitals and hence has lower ionisation enthalpy. 

4. Therefore oxygen has lower ionisation enthalpy than nitrogen.

119880.

Pramila calculated oscillations of a pendulum by fixing length of thread at 1 m, 2 m, 3 m, ……………… From the data independent variable is A) no. of oscillations B) length C) time D) mass of bob

Answer»

Correct option is B) length

119881.

Which of the following is correct ? A) MW B) kW C) Watts D) K.W

Answer»

Correct option is A) MW

119882.

Which of the following is correct presentation of units ? A) 2 Kg B) 2kg C) 2 kg D) 2 kgs

Answer»

Correct option is C) 2 kg

119883.

An object is placed at the following distances from a convex lens of focal length 15 cm :(a) 35 cm(b) 30 cm(c) 20 cm(d) 10 cmWhich position of the object will produce : (i) a magnified real image ? (ii) a magnified virtual image ?(iii) a diminished real image ?(iv) an image of same size as the object ?

Answer»

Here, f =15cm and 2f = 30cm

(i) 20 cm (Because a magnified real image is formed when the object is placed between f and 2f).

(ii) 10cm (Because a magnified virtual image is formed when the object is placed between f and the lens).

(iii) 35cm (Because a diminished real image is formed when the object is placed beyonf 2f).

(iv) 30cm (Because an image of same size as the object is formed when the object is placed at 2f).

119884.

Which of the following is not correct? A) 4 joules B) 4 j C) 4 J D) None

Answer»

Correct option is B) 4 j

119885.

How could you find the focal length of a convex lens rapidly but approximately ?

Answer»

To determine the focal length of a convex lens, we put the convex lens in a holder and keep it in front of a distant object like a window or tree, so that the rays coming from the window pass through it. A cardboard screen is put behind the lens. We change the distance of the screen from the convex lens until a clear inverted image of the window is formed on the screen. Measure the distance of the screen from the lens with a scale. This distance will be the focal length of convex lens.

119886.

When an object is placed at a distance of 36 cm from a convex lens, an image of the same size as the object is formed. What will be the nature of image formed when the object is placed at a distance of:(a) 10 cm from the lens ?(b) 20 cm from the lens ?

Answer»

Here, 2f = 36 cm, f = 18 cm.

(a) When the object is placed at a distance of 10 cm from the lens, the object lies within the focus. Hence, the image formed is virtual, erect and magnified.

(b) When the object is placed at a distance of 20 cm from the lens, the object lies between f and 2f. Hence, the image formed is real, inverted and magnified.

119887.

How would you alter the above diagram to show how a converging lens can produce a beam of parallel rays of light.

Answer»

Place a source of light at the focus of the converging lens.

119888.

How did the cobra regard his opponent? Were they true warriors?

Answer»

The cobra regarded his opponent as a superb fighter, clever and aggressive. They were true warriors as they fought valiantly.

119889.

In a classroom, four friends found out the focal length of a lens by conducting an experiment. The value came out to be 12.1cm, 12.2cm, 12.05 cm, 12.3 cm. The friends discussed the reasons for the differences or defects. Mention those reasons.

Answer»

Students got different focal lengths. 

1. By observing the values they got all positive values. This indicates they are given by convex lens. 

2. All the students got exact interger but different decimal value.

Reasons : 

The difference in values is due to least count errors, parallax errors, random errors and systematic errors, etc.

119890.

The cobra was a good fighter. Pick out one of his fighting techniques.

Answer»

The cobra stood on the defensive, swaying slowly from side to side, trying to mesmerize the mongoose into making a false move. His great hood came down so swiftly that the writer thought the mongoose would be killed.

119891.

Do as DirectedThe improved models found eager buyers.(Rewrite beginning ‘ It was…’)

Answer»

It was the improved models that found eager buyers.

119892.

Observe the given figure and name the following rays:(i) ray AB (ii) Ray BC (iii) ray CD

Answer»

(i) The ray AB is the incident ray. 

(ii) The ray BC is the refracted ray. 

(iii) The ray CD is the emergent ray.

119893.

Atomic models have been improved over the years. Arrange the following atomic models in the order of their chronological order:(i) Rutherford’s atomic model(ii) Thomson’s atomic model(iii) Bohr’s atomic modelA. (i), (ii) and (iii)B. (ii), (iii) and (i)C. (ii), (i) and (iii)D. (iii), (ii) and (i)

Answer»

Thomson proposed the first atomic model followed by Rutherford and Bohr.

Hence, option C is the correct option.

119894.

Bohr models of atoms A, B, C, D are given (Symbols are not real).a) Write the atomic number, mass number and electronic configuration of the atoms. b) Among these, which are isotopes? Why?

Answer»
 Element Atomic Number Mass Number Electron Configuration
 A 6 12 2,4
 B 7 15 2,8,5
 C 6 14 2,4
119895.

Give two examples of the effect of atmospheric refraction on a small scale in local environment.

Answer»

1. The occurrence of a mirage

2. Flickering of an object seen through a turbulent stream of hot air rising above the Holi fire are examples of the effect of atmospheric refraction on a small scale in local environment.

119896.

How is refraction of light related to refractive index?

Answer»

When a ray of light travels obliquely from an optically rarer medium (lower refractive index) to an optically denser medium (higher refractive index), the ray bends towards the normal. When a ray of light travels obliquely from an optically denser medium to an optically rarer medium, the ray bends away from the normal. For a given angle of incidence (i ≠ 0), the extent of refraction (bending) of light is different in different media.

If the refractive index of the second medium with respect to the first medium is greater than 1, the greater the refractive index, the greater is the bending of the ray of light towards the normal. If the refractive index of the second medium with respect to the first medium is less than 1, the greater the refractive index, the lesser is the bending of the ray of light away from the normal.

119897.

Which of the following effect is not related to refraction ? A) A coin kept at a bottom of vessel filled with water appears to be raised B) A lemon kept in a glass of water appears to bigger than its sizeC) A thick glass slab is placed over some printed letters, they appear raised when viewed through glass slab. D) Formation of shadows.

Answer»

A) A coin kept at a bottom of vessel filled with water appears to be raised

119898.

During refraction light follows ……………………….. A) Snell’s law B) Archimedes law C) Pascal’s law D) Galilio’s law

Answer»

Correct option is  A) Snell’s law

119899.

Which of the following is Snell’s law ? A) n1 sin i = sin r/n2 B) n1 /n2 = sin r/sin i C) n2 /n1 = sin r/sin i D) n2 sin i = constant

Answer»

B) n1 /n2 = sin r/sin i 

119900.

Refractive index of glass relative to water is 9/8. The refractive index of water relative to glass is ………………… A) 8 B) 1.33 C) 1.5 D) 8/9

Answer»

Correct option is  D) 8/9