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After the revolt in Naseerabad, British authorities went to Neemuch.

(b) Jodhpur’s ruler Man Singh

Correct Answer is: (b) Kushal Singh

British rulers had understood that from the perspective of rule over India, the native rulers were useful for them. Now the British policy changed. In order to satisfy the rulers, the principle of doctrine of lapse’ was brought to an end. The learning of English education was organised for rulers. Their service was rewarded and they were given territories to establish more faith towards British crown and western civilisation.

(1) d-orbitals are degenerate orbitals and they acquire extra stability when half-filled (3d⁵) or completely filled (3d¹⁰). 

Hence,

3d⁴ and 3d⁹ electronic configurations are less stable.

(2) The energy difference between 3d and 4s subshells is very low, hence there arises a transfer of one electron from 45 orbital to 3d orbital.

The electronic configuration changes as,

3d⁴, 4s² → 3d⁵ 4s¹ 

3d⁹,4s² → 3d¹⁰ 4s¹

Therefore transition elements, with electronic configurations 3d⁴, 4s² and 3d⁹, 4s² do not exist.

This is because the energies of orbits in which the electrons revolve are fixed.

Cl^- =1s² 2s² 2p⁶ 3s² 3p⁶, 

Cu²⁺=1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁹ 

Cr³⁺= 1s² 2s² 2p⁶ 3s² 3p⁶ 3d³

The line spectrum is of great interest in the study of electronic structure. Each element has a unique line emission spectrum. The characteristics in atomic spectra can be used in chemical analysis to identify unknown atoms in the same ways as finger prints are used to identify people.

Spectral lines are regarded as the finger prints of the elements because the elements can be identified from these lines. Just like finger prints, the spectral lines of no two elements resemble each other.

Cu(29) = 1s² ,2s² ,2p⁶ ,3s² ,3p⁶ , 3d¹⁰,4s¹ . 

Cr (z=24) =1s² ,2s² ,2p⁶ ,3s² ,3p⁶ , 3d⁵ ,4s¹ .

No two persons can have identical finger prints. Like that every element emit or absorb a radiation of fixed wave length. 

Rydberg formula 1/ ʎ = R_H(1/n₁ ² – 1/n₂ ² ) 

Rh=109677 cm^-1

 3d¹⁰ & 4d¹⁰ = 20.

m = 10g 

m = 0.01kg 

∆v = 4% of 90 m/s 

= 3.6 m/s 

∆x = h/4π m∆v 

Put the values =1.46 x 10-³³ meter

Metallurgy is a science of extracting metals from their ores and modifying the metals into alloys for various uses, based on their physical and chemical properties and their structural arrangement of atoms.

Electron affinity is the amount of energy released when a gaseous atom gains an electron to form its anion. It is also measured in kJ / mol.

Noble gases were not invented at that time.

(b) stable configuration of electrons

Both helium (He) and neon (Ne) have filled outermost shells. Helium has a duplet in its K shells, while neon has an octet in its L shells.

Marble tiles feel colder than a carpet though both of them are at the same temperature because the marble is really good at conducting heat away from your hand but because the carpet isn't as dense and has lots of air between the fibres it is not a very good heat conductor. Because the marble is a good heat conductor it cools down your feet quickly and so they feel colder but the carpet cannot cool down your feet.

We can estimate the time by the position of the Sun and its shadow.

Large Samrat clock was built by Maharaja of Jaipur, Swai Jai Singh in 1735 AD.

Small time upto 2 seconds can be measured.

1. Sand ,sun-light 

2. lunar month 

3. ball 

4. Metre/ second 

5. straight line

The oscillation that is produced by a small metallic ball or a piece of stone suspended from rigid support by a thread is called a simple pendulum. Time taken by the pendulum to complete one oscillation is called periodic table of simple pendulum.

(d) All these

The time period between two new moon day is called Lunar month.

Large Samrat Clock” situated in Jaipur.

The pronunciation of two or three words loudly like” Jai Rajasthan”takes approximately one second by us. At rest, the pulse rate of a normal healthy man is 72 times in one minute

i. e., 12 times in 10 second. In children, it can be slightly increased.

(a) periodic motion

The correct way of writing unit of distance is km.

The time taken by the earth to make one revolution around the sun is considered as one year.

(d) all the above

(b) Odometer

Meter per second is International unit of Speed.

Distance = speed x time

Speed = distance / time.

(b) Periodic motion

It can be estimated by comparing distance from a fixed point which object is moving fast and which is slow.

Speed=distance / time distance 100 km Time taken 2 hours Speed =100 km / 2 hours = 50 km / h

The speed of motor cycle is fast and that of bullock cart is slow.

(c) 240 hours

Speed of motorcycle = 40 km/hr 

Time taken = 1.5 hrs

Distance travelled = speed x distance

= 40 x 1.5 km =60 km

(b) Rs 50

Let the C.P. of the pair of sunglasses be Rs x

Then S.P. = \(\frac{X\times 125}{100}\) = Rs \(\frac{5X}{4}\)

New C.P. = Rs \(\big(\frac{75}{100}\times X\big)\) = Rs \(\frac{3X}{4}\)

New S.P. = Rs \(\big(\frac{5X}{4}-10\big)\)

Given, \(\frac{5X}{4}\) - 10 = \(\frac{140}{100}\) x \(\frac{3X}{4}\) \(\Rightarrow\) \(\frac{5X}{4}\) - \(\frac{21X}{20}\) = 10

\(\Rightarrow\) \(\frac{25X-21X}{20}\) = 10

\(\Rightarrow\) 4x = 200

\(\Rightarrow\) x = Rs 50.

(i) Given CP = Rs. 2300, overhead expenses = Rs. 300 and gain = Rs. 260

We know that Gain % = {(Gain/ (CP + overhead expenses)} x 100

= {260/ (2300 + 300} x 100

= {260/2600} x 100

Gain = 10%

(ii) Given CP = Rs. 3500, overhead expenses = Rs. 150 and loss = Rs. 146

We know that Loss % = {(Loss/ (CP + overhead expenses)} x 100

= {146/ (3500+ 150)} x 100

= {146/3650} x 100

= 14600/3650

Loss = 4%

(a) Rs 40

Let the C.P. of the article be Rs x. Then,

S.P. at a loss of 10% =\(\frac{X\times 90}{100}\) = Rs \(\frac{90X}{100}\)

S.P. at a gain of 12\(\frac{1}{2}\)% = \(\frac{X\times112.5}{100}\) = Rs \(\frac{112.5X}{100}\)

Given,\(\frac{112.5X}{100}\) - \(\frac{90X}{100}\) = 9

\(\Rightarrow\)  \(\frac{22.5X}{100}\) = 9  \(\Rightarrow\)x = \(\frac{900}{22.5}\) = Rs 40.

VAT = 12% 

Selling Price = Rs.20776 

Let x be the original price of watch. 

VAT Amount = 12% of x 

= 12x/100 

x + 12x/100 = 20776 

112x/100 = 20776 

x = (20776 × 100) / 112 

= Rs.18550 

So, Original Price of parts of Car excluding VAT is Rs.18550.

Let × be the Cost Price of Cycle. 

SP when cycle is sold at gain of 14% = x + 14x/100 = 114x/100 

SP when cycle is sold at gain of 10% = x + 10x/100 = 110x/100 

114x/100 – 110x/100 = 260 

4x/100 = 260 

x = (260 × 100)/4 

= 6500 

So, the cost price of Cycle is Rs.6500

Selling Price = Rs.882 

Original Price = Rs.840 

VAT Amount = 882- 840 

= Rs.42 

VAT % = (VAT Amount/Original Price) × 100 

= (42/840) × 100 

= 5% 

So, Rate of VAT is 5%