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101.

Describe, in brief, the changes the uterus undergoes.(i) to receive the zygote.(ii) if zygote is not formed.

Answer»

(i) The uterus prepares itself every month to receive a fertilized egg/zygote- The inner uterus lining (endometrium) becomes thick and is supplied with blood to nourish the embryo.  

(ii) If the egg is not fertilized, then the uterus lining is not required. Hence, it breaks down and gets released in the form of blood and mucus through the vagina. This process lasts for 2-8 days. This cycle occurs every month and is known as menstruation.

102.

Explain the terms: (i) Implantation (ii) Placenta

Answer»

(i) Implantation: The zygote when fixes itself on the inner thick wall of uterus for further development is called implantation. 

(ii) Placenta: It is the special tissue in the form of a disc which is embedded in the uterus wall. It provides large surface area for glucose and oxygen to pass from mother to the embryo. The waste generated by the embryo also passes into the mother’s blood through this placenta

103.

(a) Explain the terms: (i) Implantation (ii) Placenta (b) What is the average duration of human pregnancy?

Answer»

 (a) (i) Implantation: The embedding of a fertilised mammalian egg (embryo) into the inner thick wall of the uterus (womb) where it will continue its development is called implantation. 

(ii) Placenta: It is a complex double-layered spongy vascular tissue in human female formed by the joint activity of maternal and foetal tissues in the wall of uterus that is meant for attachment, nourishment and waste disposal for the foetus. 

(b) The average duration of human pregnancy is 40 weeks or 280 days.

104.

What is implantation? Where does it take place? Mention the structure involved and its function.

Answer»

The embryo sinks down and reaches into soft and thick lining of the uterus. The embedding of the embryo in the thick lining of uterus is called implantation. 

The implantation occurs in the uterus. 

The placenta is a grows into a disc like structure between uterine wall and the embryo. Placenta forms finger like projection called villi towards embryo. This creates large surface area for the exchange of glucose and gasses between mother and embryo.

105.

What changes are observed in the uterus if fertilization does not occur?

Answer»

Following changes occur in the uterus if fertilization does not occur 

  • Extra lining of Uterus degenerates
  • Uterus lining fragments gets discharged through vagina
  • Unfertilized egg gets discharged 
  • Menstruation takes place
106.

What are the benefits of using mechanical barriers during sexual acts?

Answer»
  • Mechanical barriers prevents unwanted pregnancy.
  • Mechanical barriers prevent sexually transmitted diseases.
107.

What changes are observed in the uterus subsequent to implantation of the young embryo?

Answer»

Following changes are observed in the uterus subsequent to implantation of young embryo. 

  • Uterine lining thickens to support to developing embryo.(PLACENTA) 
  • Uterine lining is richly supplied with blood vessels so that nutrition and oxygen could be supplied to the developing foetus.
108.

Read the following passage carefully.Dr. Bhimrao Ramji Ambedkar also known as Babasaheb, was born into a Mahar family on 14th April 1891 at Mhow in Madhya Pradesh. Bhimrao started experiencing the pangs of untouchability right from his childhood. His father was working in a distant village named Koregaon. When Bhimrao was nine years old, he, along with his brother and cousin, went to Koregaon to spend the summer vacation with his father. They had written a letter to his father about their arrival. But his father had not received the letter in time. Therefore, he did not come to the railway station to receive the children. Now, answer the following questions.1. When and where was Ambedkar born?2. What did Ambedkar experience right from his childhood?3. Where was Ambedkar’s father working?4. Why did Ambedkar want to go to Koregaon?5. Why did Ambedkar’s father not come to the Railway Station to receive the children?

Answer»

1. Ambedkar was born on 14th April 1891 at Mhow in Madhya Pradesh.

2. The pangs of untouchability

3. In Koregaon village

4. To spend his summer vacation

5. He did not know about their arrival.

109.

When and where was Ambedkar born?

Answer»

Ambedkar was born on 14th April 1891 at Mhow in Madhya Pradesh.

110.

What did Ambedkar do at the time of the Second Round Table Conference in London? a) He bought nothing there. b) He bought so many books there. c) He bought so many clothes there.

Answer»

b) He bought so many books there.

111.

Write the Summary of 'Dr.B.R. AMBEDKAR'.

Answer»

Swapna wrote a letter to her friend Kusuma describing the details of her project work. In her letter, she mentioned some important incidents in Dr. B. R.Ambedkar’s life. 

When Bhimrao was nine years old, he, along with his brother and cousin, went to Koregaon to spend the summer vacation with his father. On the way, they were ill-treated by the cart-man. A man refused to give drinking water. They had to sleep without water and food. 

There was a Brahmin teacher in his high school who showed great love and affection for Bhimrao. Dr. Ambedkar remembered the teacher throughout his life. Ambedkar felt that lack of education is the root cause of caste discrimination in India. He decided to uplift the oppressed classes and remove caste barriers. 

Ambedkar went to the USA to join Columbia University. He completed his M.A and Ph.D. there. Then, he joined the London School of Economics and graduated in Political Science. 

Babasaheb was a voracious reader throughout his life. He purchased about 2,000 old books when he was in New York. 

He was appointed Chairman of the Drafting Committee to write India’s new Constitution. He was appointed the first Law Minister in Jawaharlal Nehru’s cabinet. 

In the year 199p, Dr. Ambedkar was awarded the ‘Bharat Ratna’ after his death. The Government of India released a stamp in memory of his valuable services to modern India. 

In her letter, Swapna says that Babasaheb achieved such success because of his reading habit.

112.

Write the Summary of 'the Trekking Champion'.

Answer»

Malli Masthan Babu belonged to Nellore District. He obtained his M.Tech Degree from IIT – Kharagpur. He was interested in trekking and climbing high-altitude mountains. 

He climbed and reached the highest peaks in all the seven continents in the year 2006. He was regarded as the fastest “seven summiteers” in the world, that is, the fastest person to climb summits on all seven continents. 

Unfortunately, while descending the Andes, Malli was caught in bad weather and died on its slopes on 24 March 2015. But his uncrushable spirit inspires us forever.

113.

Fill in the blanks with the suitable adverbs given in the box. [slowly, heavily; carefully, wonderfully, angrity] 1. It’s raining ......... . 2. She plays the piano ........ . 3. The snail was moving ........... . 4 He yelled ........5. He always drives his car ........

Answer»

1. heavily 

2. wonderfully 

3. slowly 

4. angrily 

5. carefully

114.

Class 11 chemistry MCQ Question of States of Matter with Answers?

Answer»

The three essential states wherein a matter can exist are solid, liquid and gas. A matter can exist in a minimum of one than one state, model water exists in all of the three states. The condition of a matter relies upon the intermolecular powers and game plan of atoms. The property of a substance stays an equivalent as before, independent of its state however the p rate of reaction changes with the adjustment of the physical state. On increasing and decreasing the temperature or pressing factor, one condition of a matter gets changed over to a different state. apart from these, there are two different conditions of issues referred to as Plasma and Bose-Einstein Condensate.

Students are encouraged to practice the Class 11 Chemistry MCQ Questions of States of Matter with Answers are accessible here. Students can solve these State of Matter Class 11 MCQ Questions with Answers and evaluate their preparation level.  MCQ Questions for Class 11 Chemistry with Answers are ready according to the Latest Exam Pattern and Syllabus.

Let’s start practice the MCQ Questions for class 11 chemistry state of matter and revise this chapter fastly.

Practice MCQ Questions for class 11 Chemistry Chapter-Wise

1. The vapour pressure of water at 300 K in a closed container is 0.4 atm. If the volume of container is doubled, its vapour pressure at 300 K will be

(a) 0.8 atm
(b) 0.2 atm
(c) 0.4 atm
(d) 0.6 atm

2. The state of matter that shows the uniformity of behavior :

(a) Solid Liquid
(b) Liquid
(c) Gas
(d) None of the Above

3. A gas deviates from ideal behavior at a high pressure because its molecules:

(a) Attract one another
(b) Show the Tyndall Effect
(c) Have kinetic energy
(d) Are bound by covalent bonds

4. The value of universal gas constant R depends on

(a) Temperature of Gas
(b) Volume of Gas
(c) Number of Moles of Gas
(d) Units of Volume,Temperature and Pressure

5. In van der Waal equation of state of gas laws, the constant b is a measure of

(a) Intermolecular collisions per unit volume
(b) Intermolecular attraction
(c) Volume occupied by the molecules
(d) Intermolecular repulsions

6. The states of matter having no definite shape but definite volume:

(a) Gas
(b) Liquid
(c) Solid
(d) None of the Above

7. The rise or fall of a liquid within a tube of small bore is called:

(a) Surface Tension
(b) Capillary Action
(c) Viscosity
(d) Formation of Curvature

8. Falling drop of water is spherical due to:

(a) Hydrogen Bonding
(b) Surface Tension
(c) Capillary Action
(d) Vlscosity

9. The rates of diffusion of gases are inversely proportional to square root of their densities . This statement refers to :

(a) Daltons Law
(b) Grahams Law
(c) Avogadros Law
(d) None of the Above

10.  The law, which states that at constant temperature, the volume of a given mass of gas is inversely proportional is pressure, is known as:

(a) Boyles law
(b) Charles law
(c) Combine gas law
(d) Avogadro's law

11. When you heat a sample of gas, what happens to the particles that make up the gas?

(a) The particles move faster
(b) The particles break apart
(c) The particles get smaller
(d) The particles become more dense

12. Which of the following is not a type of van der Waal's forces?

(a) Ion - dipole forces
(b) London forces
(c) Dipole-induced dipole forces
(d) Dipole - dipole forces

13. The interaction energy of London force is inversely proportional to sixth power of the distance between two interacting particles but their magnitude depends upon

(a) polarisability of interacting particles
(b) strength of permanent dipoles in the particles
(c) mass of interacting particles
(d) charge of interacting particles

14. Dipole-induced dipole interactions are present in which of the following pairs

(a) HCl and He atoms
(b) H2O and alcohol
(c) Cl2 and CCl4
(d) None of these

15. Which of the following exhibits the weakest intermolecular forces?

(a) He
(b) H2O
(c) NH3
(d) None of these

16.  Which of the following is the correct order of thermal energy in three states of matter?

(a) Solid < Liquid < Gas
(b) Liquid < Solid < Gas
(c) Liquid < Gas < Solid
(d) Gas < Solid < Liquid

17. Which one of the following statements is not correct about the three states of matter i.e., solid, liquid and gaseous?

(a) Gases like liquids possess definite volumes
(b) Molecules of a solid possess vibratory motion
(c) The density of solid is highest whereas that of gases is lowest
(d) Molecules of a solid possess least energy whereas those of a gas possess highest energy

18. Which is lighter than dry air?

(a) Moist air
(b) SO2
(c) Cl2  
(d) O2

19. The beans are cooked earlier in pressure cooker, because - 

(a) Boiling point increases with increasing pressure
(b) Boiling point decreases with increasing pressure
(c) Extra pressure of pressure cooker softens the beans  
(d) Internal energy is not lost while cooking in pressure cooker

20. The compressibility factor for H2 and He is usually:

(a) >1
(b) =1
(c) <1
(d) either of these

21. Boyle's law is applicable in :

(a) Isobaric process
(b) Isochoric process
(c) Isothermal process
(d) Adiabatic process

22. With the increase of pressure, the mean free path:

(a) decreases
(b) increases
(c) becomes zero
(d) remains the same

23. Air at sea level is dense. This is a practical application of:

(a) Boyle's law
(b) Charles' law
(c) Avogadro's law
(d) Dalton's law

24. The gas among the following can be most steadily liquefied is -

(a) NH3
(b) Cl2
(c) SO2
(d) CO2

25. If 300 ml of a gas at \(27^\circ C\) is cooled to \(7^\circ C\) at constant pressure, its final volume will be-

(a) 135 ml
(b) 540 ml
(c) 350 ml
(d) 280 ml

Answer:

1.  Answer : (c) 0.4 atm

Explanation: Vapour pressure will be the same because it doesn't depend on the volume it depends only on Temperature.

2.   Answer : (c) Gas

Explanation: Of the three states of matter, the gaseous state is the simplest and shows greatest uniformity in behaviour. Gases show almost similar behaviour irrespective of their chemical nature. This state is characterized by gases maintain neither the volume nor the shape. They completely fill the container in which they are placed.

3. Answer : (a) Attract one another

Explanation: At high pressure, the volume is decreased appreciably, so the attractive forces become large and the molecules are crowded together. Thus, pressure correction is necessary and the gas deviates more from ideal behaviour.

4. Answer : (d) Units of Volume, Temperature and Pressure

Explanation: The value of the universal gas constant R depends on the units used for pressure, volume and temperature. Therefore, it depends on the units of measurement.

5. Answer : (c) Volume occupied by the molecules

Explanation: In van der Waals equation of state, the constants a and b represent the magnitude of intermolecular attraction and excluded volume respectively and are specific to a particular gas. The constant b is a measure of the volume occupied by the molecules.

6. Answer : (b) Liquid

Explanation: The particles of a solid are closely packed in position and can only vibrate in place. The particles of a liquid and gas are free to move. A liquid has a definite volume but no definite shape, whereas a gas has neither a definite volume nor a definite shape.

7. Answer : (b) Capillary Action

Explanation: Capillarity, rise or depression of a liquid in a small passage such as a tube of small cross-sectional area, like the spaces between the fibres of a towel or the openings in a porous material. Capillarity is not limited to the vertical direction. Water is drawn into the fibres of a towel, no matter how the towel is oriented.

8. Answer : (b) Surface Tension

Explanation: The cohesive forces between liquid molecules is responsible for the surface tension. The molecules of water on the surface don't have like molecules around it.So the water droplets tend to be pulled into shape of spherical due to cohesive forces.Thats why, the drop of water is always spherical.

9. Answer : (b) Grahams Law

Explanation: Graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. In the same conditions of temperature and pressure, the molar mass is proportional to the mass density.

10. Answer : (a) Boyles law

Explanation: P is inversely proportional to V when T and n are constant according to Boyle's law.

\(P\propto\frac{1}{V}\)

\(P=\frac{K_1}{V}\)

where Kis proportionality constant.

11. Answer : (a) The particles move faster

Explanation: There is a great deal of empty space between particles, which have a lot of kinetic energy. The particles move very fast and collide into one another when the gas is heated up, causing them to diffuse, or spread out, until they are evenly distributed throughout the volume of the container.

12. Answer : (a) Ion - dipole forces

Explanation: The term van der Waals force is a general term for those intermolecular forces that include all forces except ion-dipole forces when are relatively strong. Ion-dipole forces occur between an ion(either a cation or an anion) and a polar molecule. The Dutch physicist J van der Waals was the first to suggest the importance of intermolecular forces.

13. Answer : (a) polarisability of interacting particles

Explanation: Greater the polarisability of the interacting particles, greater is the magnitude of interaction energy.

14. Answer : (a) HCl and He atoms

Explanation: HCl is a polar molecule, whereas He atoms are non-polar so in between them dipole-induced dipole interactions exist.

15. Answer : (a) He

Explanation: Intermolecular forces in He are van der Waals forces which are the weakest in nature.

16. Answer : (a) Solid < Liquid < Gas

Explanation: Gas molecules are in continuous random motion and have the highest energy. When the thermal energy of the gas molecules is decreased by reducing the temperature, the molecules come closer together and are converted into a liquid and further, when the thermal energy of the liquids is decreased, it is converted into solid state.

17. Answer : (a) Gases like liquids possess definite volumes

Explanation: Gases do not have definite shape and volume. Their volume is equal to the volume of the container.

18. Answer : (a) Moist air

Explanation: Dry air consists mostly of nitrogen and oxygen molecules, which weigh more than water molecules.Therefore, moist air is lighter than dry air if both are at the same temperature and pressure.

19. Answer : (a) Boiling point increases with increasing pressure

Explanation: The beans are cooked earlier in pressure cooker because boiling point decreases with increasing pressure.

20. Answer : (a) >1

Explanation: ∵ for Hand He, PV > nRT and Z >1

21. Answer : (c) Isothermal process

Explanation: Boyle's law is applicable to an isothermal process where temperature remains constant.

22. Answer : (a) decreases

Explanation: On increasing pressure, the volume decreases and density increases. So, molecules get closer to each other hence mean free path also decreases.

23. Answer : (a) Boyle's law

Explanation: p1/d1 = p2/d2 (at a constant temperature) This is the Boyles law. So the case-Air at sea level is dense is studied under Boyles law.

24. Answer : (c) SO2

Explanation: The van der Waals constant a shows the force of attraction between two molecules. Hence, the higher the value of a, the higher the attraction. Therefore, the gas will be readily liquefied. Therefore, SO2 will be readily liquified.

25. Answer :(d) 280 ml

Explanation: \(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)

\(\frac{300\;mL}{300\;K}=\frac{V_2}{280\;K}\)

V= 280mL

Click here to practice MCQ Questions for States of Matter class 11

115.

According to you, what are the factors that determine the state of matter.

Answer»

The factors that determine the different states of the matter are pressure, temperature.

116.

The behaviour of matter in different states is governed by various physical laws. According to you what are the factors that determine the state of matter?

Answer» Pressure, temperature, mass and volume
117.

Find the radian measure corresponding to the following degree measures:(i) 300° (ii) 35° (iii) -56° (iv)135° (v) -300°(vi) 7° 30′ (vii) 125° 30’ (viii) -47° 30′

Answer»

As we know that 180° = π rad ⇒ 1° = π/ 180 rad

(i) 300°

(300 × π/180) rad

5π/3
∴ Radian measure of 300° is 5π/3

(ii) 35°

(35 × π/180) rad

7π/36

∴ Radian measure of 35° is 7π/36

(iii) -56°

(-56 × π/180) rad

-14π/45

∴ Radian measure of -56° is -14π/45

(iv) 135°

(135 × π/180) rad

3π/4

∴ Radian measure of 135° is 3π/4

(v) -300°

(-300 × π/180) rad

-5π/3

∴ Radian measure of -300° is -5π/3

(vi) 7° 30′

As we know that, 30′ = (1/2)°

7° 30′ = (7 1/2)°

= (15/2)°

= (15/2 × π/180) rad

= π/24

∴ Radian measure of 7° 30′ is π/24

(vii) 125° 30′

As we know that, 30′ = (1/2)°

125° 30’ = (125 1/2)°

= (251/2)°

= (251/2 × π/180) rad

= 251π/360

∴ Radian measure of 125° 30′ is 251π/360

(viii) -47° 30′

As we know that, 30′ = (1/2)°

-47° 30’ = – (47 1/2)°

= – (95/2)°

= – (95/2 × π/180) rad

= – 19π/72

Thus, radian measure of -47° 30′ is – 19π/72

118.

In a circle of diameter 30 cm, the length of a chord is 15 cm. Find the length of the minor arc of the chord.

Answer»

: Diameter = 30 cm 

Length of chord = 15 cm 

Radius = 15 cm [r = 0.5 x diameter] 

Since the radius is equal to the length of the chord 

Hence the formed triangle in the circle is an equilateral triangle. 

θ = 60° 

We know that l = r × θ

l = 15 x 60 x π/180 = 5 x π = 5 x 3.14 = 15.7

Therefore, the length of the minor arc is 15.7 cm

119.

Find the radius of a circle in which a central angle of 45° intercepts an arc of length 33 cm. (Take π = 22/7)

Answer»

We know,

Central angle (θ) = (length arc)/radius ….(1)

Convert angle in radian:

Angle in radians = Angle in degrees x π/180° = 45° x π/180° = π/4

From (1),

Radius = (length arc)/Central angle

= 33/(π/4)

= 132 x 7/22 = 42

Therefore radius is 42 cm.

120.

The difference between the two acute angles of a right triangle is (π/5)c. Find these angles in radians and degrees.

Answer»

Angle in degree = π/5 x 180/π = 36°

Let x and y are two acute angles of a right triangle.

So, x – y= 36° ……(1)

Also we know,

x + y = 90° ……(2)

Solving (1) and (2), we get

2x= 126°

or x = 63°

Form (2), 63° + y = 90°

or y = 27°

Therefore, two acute angles are 63° and 27°.

Represent angle into radian:

We know, Angle in radians = Angle in degrees x π/180°

Angle in radians = 63° x π/180°

= 7π/20

And Angle in radians = 27° x π/180°

= 3π/20

121.

A railroad curve is to be laid out on a circle. What radius should be used if the track is to change direction by 25° at a distance of 40 meters?

Answer»

Given length of arc = 40 m 

And θ = 25° 

We know that 180° = π rad ⇒ 1° = π/ 180 rad

⇒ 25° = \((25\times\frac{π}{180})\) = \(\frac{5π}{36}\) radius

We know that θ = \(\frac{arc}{radius}\)

⇒ \(\frac{5π}{36}\) = \(\frac{40}{radius}\)

⇒ Radius = \(\frac{40}{\frac{5π}{36}}\)

\(\frac{40\times36\times7}{5\times22}\)

= 91.64 m 

So, 

the radius of the track should be 91.64 m.

122.

A train is moving on a circular curve of radius 1500 m at the rate of 66 km per hour. Through what angle has it turned in 10 seconds?

Answer»

Radius = 1500 m. 

Train speed at rate of 66km/hr = 18.33 m/s 

Therefore, Distance covered in 1 second = 18.33 m 

Distance covered in 10 second = 18.33 × 10 = 183.33m 

We know that θ = Distance / radius 

θ = 183.33 / 1500 

= 0.122 radian

Therefore θ = 0.122 x 180/π = 7°

123.

The angle between the minute and hour hands of a clock at 8:30 is A. 80° B. 75° C. 60° D. 105°

Answer»

We know, in clock 1 rotation gives 360° 

i.e. 60 minutes=360° and 12 hours=360° 

So,1 minute=6° and 1 hour=30° 

Now, 

For hour hand: 

8 hours=8×30°=240° and for another 30 minute (which is half of hour) =30°÷2=15° 

i.e. angle traced by hour hand is 240°+15°=255° 

Now, For minute hand: 

30 minute=30×6°=180° 

i.e. angle traced by minute hand is 180°. 

So, the angle between hour hand and minute hand=255°-180° 

=75°

124.

The angles of a quadrilateral are in AP, and the greatest angle is double the least. Express the least angle in radians.

Answer»

Let the smallest term be x, and the largest term be 2x 

Then AP formed= x, ?, ?, 2x 

So,

sn = n/2[2a + (n - 1) d]

sn = n/2[a + (a + (n - 1)d)] = n/2

[From term + (last term)]

360°= 4/2 [x+ 2x]....[We know that → a+(n-1) d= last term= 2x] 

⇒ 180°= 3x 

⇒ x= 60° 

Now, 60° is least angle. 

= 60°= π/180° × 60° 

⇒ 60° = π/3 rad

125.

A wheel makes 180 revolutions in 1 minute. Through how many radians does it turn in 1 second?

Answer»

Given that Number of revolutions per minute = 180 

Then per second, it will be = 180/60 =3 

We know that In one complete revolution, the wheel turns at an angle of 2π rad. 

Then for 3 complete revolutions, it will take 3 × 2 π = 6 π radians.

126.

The large hand of a clock Is 42 cm long. How many centi-metres does its extremity move in 20 minutes?

Answer»

For 20 minutes = θ = 4 x 30° = 120° 

We know that l = r × θ 

l = 42 x 120 x π/180 = 28 x 22/7 = 88

Therefore, the length is equal to 88 cm.

127.

If an object is placed symmetrically between two plane mirrors, inclined at an angle of 72°, then total number of images formed is:A. 5B. 4 C. 2 D. infinite

Answer»

The number of images formed if two plane mirrors are kept at an angle θ is given by,

\(\frac{360^o}{\theta}\,if\,\frac{360^o}{\theta}\) is odd and it is given by \(\frac{360^o}{\theta}\,-1\,if\,\frac{360^o}{\theta}\)is even.

For \(\theta\)= 72o, number of image is \(\frac{360^o}{72^o}\,=\,5\) as \(\frac{360^o}{72^o}\,=\,5\) is an odd number.

128.

Multiple images are formed by a thick plane mirror. Which of the following is the brightest of all the images?A. FirstB. secondC. thirdD. fourth

Answer»

For a thick plane mirror, first reflection will take place through the glass surface and the second through the silvered surface. The silvered surface is much more reflective than the glass surface. The third reflection will be after reflection from front and then from the silvered surface. So, the second reflection will be more effective and the second image will be the brightest.

129.

वैद्युत चुम्बकीय प्रेरण का लेन्ज का नियम क्या है? 

Answer»

किसी परिपथ में प्रेरित विद्युत वाहक बल, अथवा प्रेरित धारा की दिशा सदैव ऐसी होती है कि यह उस कारण का विरोध करती है जिससे वह स्वयं उत्पन्न होती है।

130.

लेन्ज का नियम किसके संरक्षण नियम के अनुरूप उत्पन्न होता है? (i) आवेश (ii) संवेग (iii) ऊर्जा (iv) द्रव्यमान

Answer»

लेन्ज का नियम ऊर्जा संरक्षण नियम के अनुरूप उत्पन्न होता है|

131.

गलनांक की परिभाषा लिखिये।

Answer»

वह निश्चित ताप जिस पर कोई ठोस गरम करने पर द्रव में बदलता है, उसे पदार्थ का गलनांक कहते हैं। बर्फ कां गलनांक 0°C है।

132.

द्रवों में ऊष्मा संचरण होता है-(अ) चालन द्वारा(ब) संवहन द्वारा(स) विकिरण द्वारा(द) इनमें से कोई नहीं

Answer»

सही विकल्प है (ब) संवहन द्वारा

133.

द्रव के गैस में बदलने की क्रिया को कहते हैं-(अ) गलनांक(ब) हिमांक(स) वाष्पीकरण(द) संघनन

Answer»

सही विकल्प है (स) वाष्पीकरण

134.

0.2 किग्रा द्रव को 135°C से 25°C तक ठंडा करने में द्रव से निकली ऊष्मीय ऊर्जा ज्ञात कीजिये। जबकि द्रव की विशिष्ट ऊष्मा 750 जूल/किग्रा °C है।

Answer»

ऊष्मीय ऊर्जा = पदार्थ का द्रव्यमान x पदार्थ की विशिष्ट ऊष्मा x पदार्थ की तापवृद्धि
उष्मीय ऊर्जा = Q = ?
पदार्थ का द्रव्यमान = 0.2 किग्रा
पदार्थ का विशिष्ट ऊष्मा = 750 जूल/किग्रा.°C = 110°C
Q = m x S x ∆t = 0.2 किग्रा. x 750 जूल x 110°C = 16500 जूल

135.

ऊष्मीय ऊर्जा का मात्रक है-(अ) मीटर(ब) जूल(स) न्यूटन(द) कूलॉम

Answer»

सही विकल्प है (ब) जूल

136.

सेल के विद्युत वाहक बल एवं टर्मिनल विभवान्तर में अन्तर स्पष्ट कीजिए। 

Answer»

एकांक आवेश को पूरे परिपथ में सेल सहित प्रवाहित करने में सेल द्वारा दी गयी ऊर्जा को सेल का ‘विद्युत वाहक बल’ कहते हैं, जबकि किसी परिपथ के दो बिन्दुओं के बीच एकांक आवेश को प्रवाहित करने में किए गए कार्य को उन बिन्दुओं के बीच ‘टर्मिनल विभवान्तर’ कहते हैं।

137.

Which of the following is not an example of response to stimulus?(a) Watering in mouth when we see delicious food items.(b) Closing of leaves of mimosa plant when touched.(c) Shutting our eyes when an object is suddenly thrown in our direction.(d) A chick hatching out of an egg.

Answer»

(d) A chick hatching out of an egg.

138.

Which of the following is correct for respiration in plants?(a) Respiration takes place only during day time.(b) Respiration takes place only during night.(c) Respiration takes place both during day and night.(d) Respiration takes place only when plants are not making food.

Answer»

(c) Respiration takes place both during day and night.

139.

Which one of the following is not associated with reproduction?(a) A new leaf coming out of a tree branch.(b) A dog giving birth to puppy.(c) A seed growing into a plant.(d) Chick hatching from an egg.

Answer»

(a) A new leaf coming out of a tree branch.

140.

Which of the following is an incorrect statement about excretion?(a) Excretion takes place in plants.(b) Excretion takes place both in plants and animals.(c) Excretion is the process of getting rid of excess water only.(d) Secretion is one method of excretion.

Answer»

(c) Excretion is the process of getting rid of excess water only.

141.

Boojho comes across an animal having a stream-lined and slippery body. What is the habitat of the animal?(a) Water(b) Desert(c) Grassland(d) Mountain

Answer» (a) Water,  Answer is correct
142.

Choose the set that represents only the biotic components of a habitat.(a) Tiger, Deer, Grass, Soil(b) Rocks, Soil, Plants, Air(c) Sand, Turtle, Crab, Rocks(d) Aquatic plant, Fish, Frog, Insect

Answer»

(d) Aquatic plant, Fish, Frog, Insect

143.

Sea animals like dolphins and whales breathe through ___ (a) Nose (b) Gills (c) Blow holes (d) Fins

Answer»

Sea animals like dolphins and whales breathe through Blow holes.

144.

Fill up the blanks: (a) The presence of specific features, which enable a plant or an animal to live in a particular habitat is called ...........(b) The habitats of the plants and animals that live in water are called ........habitat.

Answer»

(a) The presence of specific features, which enable a plant or an animal to live in a particular habitat is called Adaption. 

(b) The habitats of the plants and animals that live in water are called Aquatic habitat.

145.

Fill in the blanks: (a) Saline water, hot air and sand are............................................... components of a habitat.(b) The habitat of plants and animals that live in . .............. is called the aquatic habitat.(c) ................ enable a plant or an animal to live in its surroundings.(d) Plants and animals that live on land are said to live in ............... habitats

Answer» saline water , hot air ,sand are abiotic components of a habitat
146.

Fill in the blanks:(a) Saline water, hot air and sand are............................................... components of a habitat.(b) The habitat of plants and animals that live in . .............. is called the aquatic habitat.(c) ................ enable a plant or an animal to live in its surroundings.(d) Plants and animals that live on land are said to live in ............... habitats

Answer» (a) abiotic

(b) water

(c) adaptations

(d) terrestrial
147.

The presence of specific features and habits, which enable a plant or an animal to live in a particular habitat is called (a) Adaptation (b) Adoption (c) Acclimatization (d) habitat

Answer»

(a) Adaptation

148.

In the sea, plants and animals are surrounded by ___ water. (a) Fresh (b) Saline (c) Acidic (d) Marshy

Answer»

In the sea, plants and animals are surrounded by Saline water.

149.

Which of the things in the following list are non-living?Plough, Mushroom, Sewing machine, Radio, Boat, Water hyacinth, Earthworm

Answer»

Non-living things: Plough, Sewing machine, Radio, Boat.

150.

What are predators ?

Answer»

The animals which kill other animals for their food are called predators.