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20401.

List the similarities and differences between aerobic and anaerobic respiration.

Answer»

Similarities

1. Food is oxidized in both cases and energy is released. It yields by products and takes place in a cell. 

Differences

2. Carbon dioxide and water are the end products of aerobic respiration, while alcohol is the end product of anaerobic respiration. Aerobic respiration releases more energy than an aerobic respiration.

20402.

In human beings respiratory organs are lungs. What are the respiratory organs of plants?

Answer»

Stomata act as respiratory organs in plants.

20403.

The process of breathing in and out is called A) InspirationB) Expiration C) Inspiration and expiration D) None of these

Answer»

C) Inspiration and expiration

20404.

Sometimes when we do heavy exercise, anaerobic respiration takes place in our muscle cells. What is produced during this process?(a) alcohol and lactic acid(b) alcohol and CO2(c) lactic acid and CO2(d) lactic acid only

Answer»

(d) lactic acid only

20405.

A steel rod (Y = 2.0 × 1011 Nm-2, and α = 10-5 °C-1) of length 1 m and area of crosssection 1 cm2 is heated from 0°C to 200°C without being allowed to extend or bend. What is the tension produced in the rod?

Answer»

Here, the equation of thermal expansion for linear expansion will be applied because of increase in temperature of the rod, length, increase.

∆T = 200°C – 0°C = 200°C, α = 10-5 °C-1, l = 1 m

Area of cross – section, A = 1 cm2 = 1 × 10-4m2

∴ \(\frac{∆l}{l}\) = α∆T = 10-5 × 200 = 2 × 10-3

Tension produced in steel rod = YAα∆T

= 2.0 × 1011 × 1 × 10-4 × 2 × 10-3 = 4 × 104 N.

20406.

Mark ‘T’ if the statement is true and ‘F’ if it is false:(i) During heavy exercise, the breathing rate of a person slows down. (T/F)(ii) Plants carry out photosynthesis only during the day and respiration only at night. (T/F)(iii) Frogs breathe through their skins as well as their lungs. (T/F)(iv) The fishes have lungs for respiration. (T/F)(v) The size of the chest cavity increases during inhalation. (T/F)

Answer»

(i) During heavy exercise the breathing rate of a person slows down. (False)
(ii) Plants carry out photosynthesis only during the day and respiration only at night. (False)
(iii) Frogs breathe through their skins as well as their lungs. (True)
(iv) The fishes have lungs for respiration. (False)
(v) The size of the chest cavity increases during inhalation. (True)

20407.

What is respiration? How is it different from breathing?

Answer»

Respiration: 

1. It is oxidation of food to form carbon dioxide, water vapour and energy. 

2. It is a biological process. 

3. Energy is released in the form of ATP. 

4. Enzymes are involved in this process. 

Breathing: 

1. It is simply an intake of fresh air and removal of foul air. 

2. It is a physical process. 

3. No energy is released rather used. 

4. No Enzymes are involved in the process.

20408.

The normal range of breathing rate per minute in an average adult person at rest is(i) 9-12(ii) 15-18(iii) 21-24(iv) 30-33

Answer»

Correct option is (ii) 15-18

20409.

Expiration rate after exercises A) Increase B) Decrease C) NormalD) Either increse or decrese

Answer»

Correct option is A) Increase

20410.

Which of the following are the reasons for urbanisation in India? A) Natural increase B) Declaration of rural areas as urban areas C) Migration of people from rural to urban areas D) All the above

Answer»

D) All the above

20411.

What were the economic reasons responsible for the revolt of 1857 C.E. ?

Answer»

The British aimed at bringing prosperity to England at the cost of Indians which impoverished most sections of Indian society. Landlords and peasants who lost their lands participated in the revolt.

20412.

What were the social and religious reasons responsible for the revolt of 1857 C.E. ?

Answer»

The Policy of Social Reforms brought in by the Company made people feel insecure and suspicious as they felt the government was trying to convert them to Christianity and destroy Indian religion and culture forever. People felt that Indian social system was deliberately undermined in railways, jails and military. Any new changes aroused dissatisfaction. Thus many people joined the freedom movement to sustain their socio-religious beliefs.

20413.

Why did the 1857 revolt prove a failure ?ORWhat were the reasons for the failure of the revolt of 1857?

Answer»

The revolution was a failure because of:

  • Lack of coordination among rebels and absence of centralised leadership. There was no provision for reinforcement of men, money and arms.
  • The revolt happened way before the fixed date thus disrupting the planning and alerting the British.
  • Being concentrated mainly in North India. Many social reformers refrained from joining the revolt proving that the intellectual class did not support the revolt.
  • India was ruled by various rulers; thus the feelings of nationalism had not developed among Indians. Many leaders sided the British or remained passive during the revolt.
  • Sikhs and Gurkhas fought from the side of the British which proved to be a great disadvantage.
  • The British army was superior with latest weapons and good military commanders.
  • Indian leaders were fighting to regain control of their individual territories and not for the whole nation.
20414.

What were the main reasons for the outbreak of the revolt of 1857 C.E. ?ORWhich incident led to the revolt of 1857 C.E. ?

Answer»

Mangal Pandey, a soldier of Barrackpore battalion, opposed to use the cow-and-pig-fat greased cartridge of the new Enfield Rifle. Indian soldiers who had agreed to join the revolt wanted to wait until 31st May, but 26-year-old Mangal Pandey could not. He refused to use the Enfield Rifle. As a result the revolt began earlier than the fixed date. This disrupted the planning and the objectives of the revolt could not be achieved.

Sargeant Major Hewson ordered for his arrest, but Mangal Pandey shot him and defeated another British officer also. Indian soldiers refused to arrest Mangal. When he was cornered, Mangal shot himself with his own ‘ Sifle. A bleeding Mangal Pandey was taken to hospital to get information about the revolt from him. The British pretended to run a case against Mangal on 6th April, 1857. The entire procedure was purposely in English. Though he was sentenced to death, he did not divulge any information to the British. He was hanged at 5:30 a.m. on 8th April, 1857. Thus, Mangal Pandey became the First Martyr of the 1857 revolt which began earlier than planned.

20415.

How was the symbol of ‘Lotus and Roti’ circulated to spread word about the revolt ?

Answer»

The ‘Lotus and Roti’ symbol were circulated across India and Bards, priests and auliyas played a significant role in spreading word about the revolt.

20416.

Which states have been benefitted by the Bhakra Nangal Project?

Answer»

Punjab, Haryana and Rajasthan

20417.

A train covered a certain distance at a uniform speed. If the train would have been 10 km/h faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/h; it would have taken 3 hours more than the scheduled time. Find the distance covered by the train.

Answer»

Solution:
Let the speed of the train by x km/hr
And the time taken by the train be ‘y’ hrs
Distance traveled by the train is x.y = xy

Case I
If the train would have been 10 km/hr faster, it would have taken 2 hours less than the scheduled time.
⇒ (x + 10) (y - 2) = xy
⇒ -2x + 10y = 20
⇒ x – 5y = -10 ---------------- (1)

Case II
If the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time
⇒ (x - 10) (y +  3) = xy
⇒ 3x – 10y - 30 = 0
⇒ 3x – 10y = 30 ----------------(2)

Solving the equations (1) and (2), we get y = 12, x = 50

Therefore, the distance of the journey = 50 × 12 = 600 km.

20418.

A battery lights a bulb. Describe the energy change involved in the process.

Answer»

When the bulb is connected to the battery the chemical energy of the battery is converted into the electrical energy. When bulb receives this electrical energy it converts it into light and heat energy. The figure below shows the energy transformation in more descriptive way.

Chemical Energy → Electrical Energy → Light Energy + Heat Energy

20419.

A block of ice is floating in a liquid of specific gravity 1.2, contained in the beaker. What will be the effect on the level of liquid in the beaker when the whole ice melts?

Answer»

The level of water in a beaker will rise. It is so because the density of water formed by melting of ice is less than the density of liquid in a beaker. Due to which the volume of water formed by melting the ice will be more than that of the portion of the ice in the liquid while floating in the liquid.

20420.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Answer»

Work done by the force of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions/heights of the object, which is zero.

Work done by gravity is given by the expression,

W = mgh, where, h = Vertical displacement = 0

W = mg × 0 = 0 J

Therefore, the work done by gravity on the given object is zero joule.

20421.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground the initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Answer»

Work done by the force of gravity, W = mgh.
Where h = difference in height of initial and final positions of the object.
According to question, the initial and final positions of the object lie in the same horizontal line. So h = 0.
∴ Work done W = mg × 0 = 0

20422.

A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (let than 2 seconds). The later ball is thrown at a velocity of half the first. The vertical gap between first and second balls is +15 m at t = 2s. The gap is found to remain constant. Calculate the velocity with which the balls were thrown and the exact time interval between their throw.

Answer»

Let the speeds of two balls (1 & 2) be v1 and v2, if v1 = 2v, v2 = v

If y1 and y2 the displacement covered by the balls 1 and 2, respectively, then

 \(y_1=\frac{v^2_1}{2g}=\frac{4v^2}{2g}\) and \(v_2=\frac{v^2_2}{2g}=\frac{v^2}{2g}\)

since, y1 − y2 = 15 m,

\(\frac{4v^2}{2g}-\frac{v^2}{2g}\) = 15 m

or \(\frac{3v^2}{2g}\) = 15 m

\(v^2=\sqrt{5m\times(2\times10)}\) m/s2

v = 10 m/s

clearly, v1 = 20 m/s, v2 = 10 m/s.

Time interval = 1 s.

20423.

A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 seconds). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is +15 m at t = 2 s. The gap is found to remain constant. Calculate the velocity with which the balls were thrown and the exact time interval between their throw.

Answer»

v1=20 m/s, v2 = 10m/s, time difference = 1s.

20424.

A particle falling vertically from a height hits a plane surface inclined to horizontal at an angle θ with speed v0 and rebounds elastically (Fig.). Find the distance along the plane where if will hit second time.(Hint: (i) After rebound, particle still has speed v0 to start. (ii) Work out angle particle speed has with horizontal after it rebounds. (iii) Rest is similar to if particle is projected up the incline.)

Answer»

As θ = 0, T = \(\frac{2v_0\,cos\,\theta}{g\,cos\,\theta}\)\(\frac{2v_0}{g}\)

Considering motion along x-axis, 

X = L, ux= v0 cos θ, ax= g sin θ, t = T = \(\frac{2v_0}{g}\)

From kinematics equation- 

= \(u_xt+\frac{1}{2}a_xt^2\)

L =\(v_0\,sin\,\theta t+\frac{1}{2}g\,sin\,\theta\, t^2\)

 = \((v_0sin\,\theta)(T)+\frac{1}{2}g\,sin\,\theta\, T^2\)

= \((v_0 sin \,\theta)(\frac{2v_0}{g})+\frac{1}{2}g\,sin\,\theta\times(\frac{2v_0}{g})\)

= \(\frac{2v^2_0}{g} sin\,\theta +\frac{1}{2}g\, sin\,\theta+\frac{4v^2_0}{g^2}\)

= Distance, L = \(\frac{4v^2_0}{g} sin\,\theta\).

20425.

It is a common observation that rain clouds can be at about a kilometer altitude above the grounds.(a) If a rain drop falls from such a height freely under gravity, what will be its speed? Also calculate in km/h. (g = 10 m/s2 )(b) A typical rain drop is about 4 mm diameter. Momentum is mass × speed in magnitude. Estimate its momentum when it hits ground.(c) Estimate the time required to flatten the drop.(d) Rate of change of momentum is force. Estimate how much force such a drop would exert on you.(e) Estimate the order of magnitude force on umbrella. Typical lateral separation between two rain drops is 5 cm.(Assume that umbrella is circular and has a diameter of 1 m and cloth is not pierced through !!)

Answer»

(a) v = \(\sqrt {2gh}\) = \(\sqrt{2\times10\times1000}\) = 141 m/s = 507.6 km/h.

(b) \(m=\frac{4\pi}{3}r^3ρ=\frac{4\pi}{3}{(2\times10^{-3})}^3(10^3)\) = 3.4 x 10-5 kg.

ρ = mv ≈ 4.7 × 10-3 kg m/s ≈ 5 × 10-3 kg m/s.

(c) Diameter ≈ 4 mm

∆t ≈ \(\frac {d}{v}\) = 28 μs ≈ 30 μs

(d) F = \(\frac{\Delta p}{\Delta t}\) = \(\frac{4.7\times 10^{-3}}{28\times10^{-4}}\) ≈ 168 N ≈ 1.7 × 102 N.

(e) Area of cross-section =\(\frac{\pi d^2}{4}\) ≈ 0.8 m2.

With average separation of 5 cm, no. of drops that will fall almost simultaneously is 

\(\frac{0.8\, m^2}{{(5\times10{-2})}^2}\) ≈ 320.

Net force ≈ 54000 N

(Practically drops are damped by air viscosity).

20426.

Even when rain is falling vertically downwards the front screen of a moving car gets wet. On the other hand the back screen remains dry. Why?

Answer» The rain strikes car in the direction of the relative velocity of the rain with respect to air.
20427.

Which of the two persons shown in the figure (9-Q1) is more likely to fall down? Which external force is responsible for his falling down?

Answer»

Moving cart with an acceleration is a non-inertial frame for the passengers. So both of them will experience a pseudo force in the opposite direction of the movement. The person sitting on the left will be saved by the wall of the cart but not the person on the right. So the person on the right is more likely to fall and the force responsible for it is the pseudo force.

20428.

Small plants, soft perishable stems, attain height upto five feet, generally annuals and biennials these plants are a. Herbs b. Shrubs c. Trees d. None of these

Answer»

Correct answer is a. Herbs 

20429.

Why do we see dew droplets on leaves in the early morning?

Answer»

At night the water lost by leaves does not get evaporated and gets collected on the leaves in the form of dew drops.

20430.

Leaves need oxygen and carbondioxide How do they get these gases?

Answer»

Leaves take in these gases from atmosphere through small pores present on them called stomata.

20431.

Name two flower, each with joined and separated sepals.

Answer»

Two flower with joined sepals: China rose and cotton. 

Two flower with separated sepals: Rose and jasmine.

20432.

Write the names of the parts of a flower.

Answer» The parts of a flower are sepals, petals, stamens and pistil.
20433.

Explain the structure of a typical flower with the help of a diagram?

Answer»

A typical flower contains the following parts: 

1. Stalk: The part by which a flower is attached to the branch is called stalk 

2. Sepals: The small green leaf like structure of the flower are called sepals 

3. Petals:The big coloured leaf- like structure are called petals. Different flower have petals of different colours. 

4. Stamen: It is the male part of the flower It has two parts 

  • Filament & 
  • Anther 

5. Pistil: The inner most part of a flower is called pistil. It has three parts 

  • Stigma 
  • Style and 
  • Ovary It is the female part of the flower.
20434.

Why does white flower bloom at night?

Answer»

White colour attracts night insects for pollination.

20435.

Fill in the blanks with the terms that are listed below:anther, male, ovary, ovule, petals, pistil, stamen, filament.Sepals, ______(a)______, stamens and ______(b)______ are theparts of a flower. Stamen is made up of ______(c)______ and ______(d)______ and it represents the ______(e)______ part of theflower. The female part of the flower is called the ______(f)______.The basal, swollen part of the pistil is called the ______(g)______ which contains the ______(h)______.

Answer» (a)– sepals;

(b)– petals;

(c)– pistil;

(d)– filament;

(e)– anther;

(f)– male;

(g)– pistil;

(h)– ovary; (i)– ovules
20436.

What is the function of a stem in a plant?

Answer»

A stem performs the following functions:

  • The stem and its branches hold leaves to get maximum sunlight.
  • It transports water from roots to different parts of the plant.
  • It transports food from leaves to different parts of the plant.
  • It bears leaves, flowers, and fruits.
20437.

Correct the following statements and rewrite them in your notebook.(a) Stem absorbs water and minerals from the soil.(b) Leaves hold the plant upright.(c) Roots conduct water to the leaves.(d) The number of petals and stamens in a flower is always equal.(e) If the sepals of a flower are joined together, its petals are also joined together.(f) If the petals of a flower are joined together, then the pistil is joined to the petal.

Answer»

(a) Roots absorb water and minerals from the soil.

(b) Roots hold the plant upright.

(c) Stem conducts water to the leaves.

(d) The number of petals and stamens in a flower usually have no relation.

(e) If the sepals of a flower are joined together, its petals are not necessarily joined together.

(f) If the petals of a flower are joined together, then the pistil is not necessarily joined to the petal.

20438.

Is it possible for you to find out whether a plant has taproot or fibrous roots by looking at the impression of its leaf on a sheet of paper?

Answer»

We cannot exactly recognise the leaves without seeing them. We may be able to have some idea by touching and smelling them.

20439.

In which part of a flower you are likely to find the ovary?

Answer»

We find an ovary in the pistil. It is the lowermost part of the pistil.

20440.

Is it possible for you to find out whether a plant has taproot or fibrous roots by looking at the impression on its leaf on a sheet of paper?

Answer»

Yes, by taking the impression of the leaf. Put the leaf under a white sheet and gently rub the pencil on it with tip sideways. We will get an impression of the leaf with lines on it. If the leaf has parallel venation then the plant has the fibrous root and if the leaf has reticulate venation then the plant has a taproot.

20441.

Correct the following statement and rewrite them in your notebook.a. Stem absorb water and minerals from the soilb. Leaves hold the plant uprightc. Roots conduct water to the leavesd. The number of petals and sepals in a flower is always equal.e. If the sepal of a flower are joined together, its petals are also joined togetherf. If the petals of a flower are joined together, then the pistil is joined to the petal

Answer»

(a) Roots absorb water and minerals from the soil

(b) Roots hold the plant upright.

(c)Stem conduct water to the leaves

(d) The number of petals and sepals in a flower is usually equal.

(e) If the sepal of a flower are joined together its petals are not necessarily joined together

(f) If the petals of a flower are joined together them the pistil is not necessarily joined to the petal.

20442.

Can you find a plant in your house or in yours neighborhood, which has a long but a weak stem?Write its name. In which category would you classify it?

Answer»

It is a money plant. It is a climber.

20443.

One Astronomical unit is (a) 3.153 × 107 m (b) 1.496 × 107 m (c) 9.46 × 1012 m (d) 3.26 × 1015 m

Answer»

Correct answer is (b) 1.496 × 107 m

20444.

Length cannot be measured by …. (a) fermi (b) angstrom (c) parsec (d) debye

Answer»

Correct answer is (d) debye

20445.

One parsec is ….. (a) 3.153 × 107 m (b) 3.26 × 1015 m (c) 30.84 × 1015 m (d) 9.46 × 1015 m

Answer»

Correct answer is (c) 30.84 × 1015

20446.

One Fermi is ….. (a) 10-9 m (b) 10-10 m (c) 10-12 m (d) 10-15 m

Answer»

Correct answer is (d) 10-15 m

20447.

One Angstrom is ……… (a) 10-9 m (b) 10-10 m (c) 10-12 m (d) 10-15 m

Answer»

Correct answer is  (b) 10-10 m

20448.

One degree of arc is ……. (a) 1″ (b) 60″ (c) 60′ (d) 60°

Answer»

Correct answer is (c) 60′

20449.

The unit of moment of force …… (a) Nm2(b) Nm (c) N (d) NJ rad

Answer»

Correct answer is (b) Nm

20450.

1 radian is …… (a) 2.91 × 10-4 m (b) 57.27° (c) 180°(d) \(\frac{π}{180}\)

Answer»

Correct answer is (b) 57.27°