InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
In β-oxidation 3-ketoacyl-CoA is splitted at the 2, 3 position by the enzyme: (A) Hydratase (B) Dehydrogenase (C) Reducatse (D) Thiolase |
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Answer» (D) Thiolase |
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| 202. |
All the following statements about acetyl CoA carboxylase are true except (A) It is required for de novo synthesis of fatty acids (B) It is required for mitochondrial elongation of fatty acids (C) It is required for microsomal elongation of fatty acids (D) Insulin converts its inactive form into its active form |
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Answer» (B) It is required for mitochondrial elongation of fatty acids |
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| 203. |
The common precursor in the biosynthesis of triacylglycerol and phospholipids is (A) 1, 2-Diacylglycerol phosphate (B) 1-Acylglycerol 3-phosphate (C) Glycerol 3-phosphate (D) Dihydroxyacetone phosphate |
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Answer» (A) 1, 2-Diacylglycerol phosphate |
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| 204. |
In the biosynthesis of triglycerides from glycerol 3-phosphate and acyl-CoA, the first intermediate formed is (A) 2-Monoacylglycerol (B) 1, 2-Diacylglycerol (C) Lysophosphatidic acid (D) Phosphatidic acid |
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Answer» (D) Phosphatidic acid |
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| 205. |
The rate limiting reaction in the lipogenic pathway is (A) Acetyl-CoA carboxylase step (B) Ketoacyl synthase step (C) Ketoacyl reductase step (D) Hydratase step |
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Answer» (A) Acetyl-CoA carboxylase step |
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| 206. |
In the pathway leading to biosynthesis of acetoacetate from acetyl-CoA in liver, the immediate precursor of aceotacetate is (A) Acetoacetyl-CoA (B) 3-Hydroxybutyryl-CoA (C) 3-Hydroxy-3-methyl-glutaryl-CoA (D) 3-Hydroxybutyrate |
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Answer» (A) Acetoacetyl-CoA |
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| 207. |
The fruit when kept is open, tastes bitter after 2 hours because of (A) Loss of water from juice (B) Decreased concentration of fructose in juice (C) Fermentation by yeast (D) Contamination by bacterial enzymes |
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Answer» (D) Contamination by bacterial enzymes |
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| 208. |
Part of enzyme which combines with nonprotein part to form functional enzyme is (A) Apoenzyme (B) Coenzyme (C) Prosthetic group (D) None of these |
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Answer» (C) Prosthetic group |
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| 209. |
Who got Nobel Prize in 1978 for working on enzymes? (A) Koshland (B) Arber and Nathans (C) Nass and Nass (D) H.G. Khorana |
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Answer» (A) Koshland |
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| 210. |
The enzyme which can add water to a carbon-carbon double bond or remove water to create a double bond without breaking the bond is(A) Hydratase (B) Hydroxylase (C) Hydrolase (D) Esterase |
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Answer» (A) Hydratase |
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| 211. |
An example of lyases is (A) Glutamine synthetase (B) Fumarase (C) Cholinesterase (D) Amylase |
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Answer» An example of lyases is Fumarase. |
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| 212. |
Enzyme catalysed reactions occur in (A) Pico seconds (B) Micro seconds (C) Milli seconds (D) None of these |
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Answer» (C) Milli seconds |
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| 213. |
An organic substance bound to an enzyme and essential for the activity of enzyme is called (A) Holoenzyme (B) Apoenzyme (C) Coenzyme (D) Isoenzyme |
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Answer» (C) Coenzyme |
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| 214. |
Activation or inactivation of certain key regulatory enzymes is accomplished by covalent modification of the amino acid: (A) Tyrosine (B) Phenylalanine (C) Lysine (D) Serine |
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Answer» Activation or inactivation of certain key regulatory enzymes is Serine. |
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| 215. |
The shape of an enzyme and consequently its activity can be reversibly altered from moment to moment by (A) Heat (B) Amino acid substrate (C) Allosteric subunits (D) Sulfur substitutions |
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Answer» (C) Allosteric subunits |
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| 216. |
On what structural level of the enzyme (primary, secondary, tertiary or quaternary) does the enzymesubstrate interaction depend? |
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Answer» The substrate binds to the enzyme in the activation centres. These are specific three-dimensional sites and thus they depend on the protein tertiary and quaternary structures. The primary and secondary structures, however, condition the other structures and so they are equally important. |
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| 217. |
Which one of the following regulatory actions involves a reversible covalent modification of the enzyme? (A) Phosphorylation of ser-OH on the enzyme (B) Allosteric modulation (C) Competitive inhibition (D) Non-competitive inhibition |
| Answer» (A) Phosphorylation of ser-OH on the enzyme | |
| 218. |
How does the formation of the enzyme-substrate complex explain the reduction of the activation energy of chemical reactions? |
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Answer» The enzyme possibly works as a test tube within which reagents meet to form products. With the facilitation of the meeting provided by enzymes, it is easier for collisions between reagents to occur and thus the activation energy of the chemical reaction is reduced. This is one of the possible hypotheses. |
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| 219. |
Galactose 1-phosphate is converted to uridine diphosphate galactose, the reaction is catalysed by the enzyme: (A) Glactokinase (B) Galactose 1-phosphate uridyl transferase (C) Uridine diphospho galactose 4-epimerase (D) UDP glucose pyrophosphorylase |
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Answer» (B) Galactose 1-phosphate uridyl transferase |
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| 220. |
An enzyme is a (A) Carbohydrate (B) Lipid (C) Protein (D) Nucleic acid |
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Answer» An enzyme is a Protein. |
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| 221. |
The Michaehis-Menten hypothesis: (A) Postulates the formation of an enzyme substrate complex (B) Enables us to calculate the isoelectric point of an enzyme (C) States that the rate of a chemical reaction may be independent of substrate concentration (D) States that the reaction rate is proportional to substrate concentration |
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Answer» (A) Postulates the formation of an enzyme substrate complex |
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| 222. |
The activity of HMG-CoA reductase is inhibited by (A) A fungal inhibitor mevastatin (B) Probucol (C) Nicotinic acid (D) Clofibrate |
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Answer» (A) A fungal inhibitor mevastatin |
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| 223. |
HMG-CoA reductase activity is increased by administration of the hormone: (A) Insulin (B) Glucagon (C) Epinephrine (D) Glucocorticoids |
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Answer» The Correct option is (A) Insulin |
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| 224. |
The protein, which is in fact a multifunctional enzyme complex in higher organism is (A) Acetyl transacylase (B) Malonyl transacylase (C) 3-Hydroxy acyl-ACP dehyratase (D) Fatty acid synthase |
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Answer» (D) Fatty acid synthase |
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| 225. |
The best known cause of galactosemia is the deficiency of (A) Galactose 1-phosphate and uridyl transferase (B) Phosphoglucomutase (C) Galactokinase (D) Lactose synthase |
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Answer» (A) Galactose 1-phosphate and uridyl transferase |
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| 226. |
HMG-CoA is converted to mevalonate by reduction catalysed by (A) HMG-CoA synthetase (B) HMG-CoA reductase (C) Mevalonate kinase (D) Thiolase |
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Answer» (B) HMG-CoA reductase |
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| 227. |
Coenzymes are (A) Heat stable, dialyzable, non protein organic molecules (B) Soluble, colloidal, protein molecules (C) Structural analogue of enzymes (D) Different forms of enzymes |
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Answer» (A) Heat stable, dialyzable, non protein organic molecules |
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| 228. |
In gluconeogensis, an allosteric activator required in the synthesis of oxaloacetate from bicarbonate and pyruvate, which is catalysed by the enzyme pyruvate carboxylase is (A) Acetyl CoA (B) Succinate (C) Isocitrate (D) Citrate |
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Answer» (A) Acetyl CoA |
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| 229. |
The pH optima of most of the enzymes is (A) Between 2 and 4 (B) Between 5 and 9 (C) Between 8 and 12(D) Above 12 |
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Answer» (B) Between 5 and 9 |
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| 230. |
The enzyme phosphoenolpyruvate carboxykinase catalyses the conversion of oxaloacetate to phosphoenolpyruvate requires (A) ATP (B) ADP (C) AMP (D) GTP |
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Answer» The Correct option is (D) GTP |
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| 231. |
In the intestine the rate of absorption is highest for (A) Glucose and galactose (B) Fructose and mannose (C) Fructose and pentose (D) Mannose and pentose |
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Answer» (A) Glucose and galactose |
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| 232. |
Hereditary fructose intolerance involves the absence of the enzyme: (A) Aldalose B (B) Fructokinase (C) Triokinase (D) Phosphotriose isomerase |
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Answer» Hereditary fructose intolerance involves the absence of the enzyme Aldalose B. |
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| 233. |
Amylopectinosis is caused due to absence of (A) Debranching enzyme (B) Branching enzyme (C) Acid maltase (D) Glucose-6-phosphatase |
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Answer» Amylopectinosis is caused due to absence of branching enzyme. |
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| 234. |
The enzymes of the pentose phosphate pathway are found in the (A) Cytosol (B) Mitochondria (C) Nucleus (D) Endoplasmic reticulum |
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Answer» The enzymes of the pentose phosphate pathway are found in the Cytosol. |
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| 235. |
The substrate for amylase is (A) Cane sugar (B) Starch (C) Lactose (D) Ribose |
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Answer» The substrate for amylase is Starch. |
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| 236. |
The pH optima for lactase is (A) 1.0-2.0 (B) 5.4–6.0 (C) 5.0–7.0 (D) 5.8–6.2 |
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Answer» The pH optima for lactase is 5.4–6.0. |
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| 237. |
The ion which activates salivary amylase activity is (A) Chloride (B) Bicarbonate (C) Sodium (D) Potassium |
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Answer» (A) Chloride |
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| 238. |
The pancreatic amylase activity is increased in the presence of (A) Hydrochloric acid (B) Bile salts (C) Thiocyanate ions (D) Calcium ions |
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Answer» (B) Bile salts |
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| 239. |
The pH optima for pancreatic analyse is (A) 4.0 (B) 7.1 (C) 7.9 (D) 8.6 |
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Answer» The pH optima for pancreatic analyse is 8.6. |
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| 240. |
The pH optima for salivary analyse is (A) 6.6–6.8 (B) 2.0–7.5 (C) 7.9 (D) 8.6 |
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Answer» The pH optima for salivary analyse is 6.6–6.8. |
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| 241. |
Oxidation of one molecule of glucose yields (A) 12 ATP (B) 24 ATP (C) 38 ATP (D) 48 ATP |
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Answer» Oxidation of one molecule of glucose yields 38 ATP. |
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| 242. |
In citric acid cycle, NAD is reduced in (A) One reactions (B) Two reactions (C) Three reactions (D) Four reactions |
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Answer» (C) Three reactions |
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| 243. |
The number of ATP molecules generated for each turn of the citric acid cycle is (A) 8 (B) 12(C) 24 (D) 38 |
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Answer» The number of ATP molecules generated for each turn of the citric acid cycle is 12. |
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| 244. |
If results of the serum bilirubin, serum ALP, LDH and AST determinations suggest obstructive jaundice, the best confirmatory test would be the estimation of (A) Serum ALT (B) Serum 5’ nucleotidase (C) Serum Pseudo cholinesterase (D) None of these |
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Answer» (B) Serum 5’ nucleotidase |
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| 245. |
Which enzyme estimation will be helpful in differentiating the elevated serum ALP found in obstructive jaundice as well as bone disorders? (A) Serum AST (B) Serum ALT (C) Serum LDH (D) Serum γ-GT |
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Answer» (D) Serum γ-GT |
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| 246. |
The CK isoenzymes present in cardiac muscle is (A) BB and MB (B) MM and MB (C) BB only (D) MB only |
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Answer» (B) MM and MB |
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| 247. |
Serum AST activity is not characteristically elevated as the result of (A) Myocardial infarction (B) Passive congestion of liver (C) Muscular dystrophies (D) Peptic ulcer |
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Answer» (D) Peptic ulcer |
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| 248. |
The isozyme CK-MB is specifically increased in the blood of patients who had (A) Skeletal muscle disease (B) Recent myocardial infarction (C) Infective hepatitis (D) Myxoedema |
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Answer» (B) Recent myocardial infarction |
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| 249. |
A demonstrable inducer is absent in (A) Allosteric enzyme (B) Constitutive enzyme (C) Inhibited enzyme (D) Co-operative enzyme |
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Answer» (B) Constitutive enzyme |
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| 250. |
An inducer is absent in the type of enzyme: (A) Allosteric enzyme (B) Constitutive enzyme (C) Co-operative enzyme (D) Isoenzymic enzyme |
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Answer» (B) Constitutive enzyme |
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