This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A small sphere falls from rest in a viscous liquid. Due to frication, heat is produced. Find the relation between the rate of production of heat and the radius of the sphere at terminal velocity.A. `r^(5)`B. `r^(2)`C. `r^(3)`D. `r^(4)` |
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Answer» Correct Answer - A |
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| 2. |
Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by `Deltax` on applying force F, how much force is needed to stretch wire 2 by the same amount?A. 4FB. 6FC. 9FD. F |
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Answer» Correct Answer - C |
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| 3. |
The power radiated by a black body is P, and it radiates maximum energy around the wavelength `lambda_(0)`. If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength `3lambda_(0)//4`, the power radiated by it will increase by a factor ofA. `256/81`B. `4/3`C. `3/4`D. `84/256 |
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Answer» Correct Answer - A |
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| 4. |
A refrigerator with its door open is left running in a closed room. If the fan is also on and heat transfer from the room is negligible, the room temperature will1.Tall for some time and then rise2.keep on increasing3.decrease continuously4.remain unaffected |
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Answer» Correct Answer - Option 2 : keep on increasing Explanation:
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| 5. |
State stoke’s law and define terminal velocity? |
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Answer» Stoke’s law: When a body falls through a highly viscous liquid, it drags the layer of the liquid immediately in contact with it. This results in a relative motion between the different layers of the liquid. As a result of this, the falling body experiences a viscous force F. Stoke performed many experiments on the motion of small spherical bodies in different fluids and concluded that the viscous force F acting on the spherical body depends on 1. Coefficient of viscosity q of the liquid 2. Radius a of the sphere and 3. Velocity v of the spherical body Dimensionally it can be proved that ∴ F = k ηav Experimentally Stoke found that k = 6π This is Stoke’s law Terminal velocity: Terminal velocity of a body is defined as the constant velocity acquired by a body while falling through a viscous liquid. |
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| 6. |
What are geostationary and polar satellites? |
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Answer» Geostationary Satellite: It is the satellite which appears at a fixed position and at a definite height to an observer on Earth. Polar Satellite: It is the satellite which revolves in polar orbit around the Earth. |
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| 7. |
An iceberg of density `900kg//m^(3)` is floating in water of density `1000 kg//m^(3)`. The percentage of volume of ice cube outside the water isA. 0.2B. 0.35C. 0.1D. 0.11 |
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Answer» Correct Answer - C |
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| 8. |
A soap bubble of radius `1//sqrtpi "cm"` is expanded to radius `2//sqrtpi "cm".` Calculate the work done. Surface tension of soap solution `=30 "dyne"" "cm^(-1).`A. 180 ergsB. 360ergsC. 720 ergsD. 960 ergs |
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Answer» Correct Answer - C `W= 8pi T(r_(2)^(2) -r_(1)^(2)) =8pi T[ ((2)/(sqrtpi))^(2)- ((1)/(sqrtpi))^(2)]` `therefore W =8xxpi 30xx3/pi =720 erg ` |
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| 9. |
A small mass m is attached to a massless string whose other end is fixed at P as shown in the figure. The mass is undergoing circular motion in the x-y plane with centre at O and constant angular speed `omega`. If the angular momentum of the system. calculated about O and P are denoted. by `vecL_O and vecL_P` respectively, then. A. vecL _(0) and vecL _(P)` do not very with timeB. `vecL _(0)` varies with time while `vecL _(P)` remains constantC. `vecL _(0) ` remains constnat while `vecL_(P)` varies with timeD. `vec L _(0) and vecL _(0)` both vary with time |
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Answer» Correct Answer - C Magnitude and direction of `L_(0)` remains constant and magnitude of `L _(P)` also remains constant but direaction changes. (According to right hand thumb rule) |
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| 10. |
Two masses `m_1` and `m_2` are attached to the ends of a massless string which passes over a frictionless pulley attached to the top of an inclined plane. The angle of inclination of the plane is `theta`. Take `g=10ms^(-2)` if `m_(1)=10 kg,m_(2)=5 kg , theta=30^(@)`, what is the acceleration of mass `m_(2)`?A. zeroB. `(2//3)ms^(-2)`C. `5 ms^(-2)`D. `10//3 ms^(-2)` |
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Answer» Correct Answer - A `a=((m_(2)-m_(1) sin alpha)g)/((m_(1)+m_(2)))=((5-10 sin 30^(@))g)/((m_(1)+m_(2)))=0` |
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| 11. |
Find `1+1/2+1/4+1/8+`…. Upto `oo`.A. `oo`B. `1`C. `2`D. `1.925` |
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Answer» Correct Answer - C Here, `a=1, r= (1)/(2)` So, `S_(oo) = (a)/(1-r)= (1)/(1-(1)/(2))= 2` |
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| 12. |
Use should/must/ought to appropriately in the following sentences. (i) People who live in glass houses _____________ not throw stones. (ii) You ______ wipe your feet before coming into the house, especially during the rains. (iii) You _________________ do what the teacher tells you. (iv) The pupils were told that they ______________ write more neatly. (v) Sign in front of a park: You _______________ not walk on the grass. (vi) You _____________ be ashamed of yourself having made such a remark. (vii) He left home at 9 o’clock. He _______________ be here any minute. (viii) “Whatever happened to the chocolate cake?” “How _______________ I know? I have just arrived.” |
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Answer» (i) People who live in glass houses should not throw stones. (ii) You ought to wipe your feet before coming into the house, especially during the rains. (iii) You should do what the teacher tells you. (iv) The pupils were told that they should write more neatly. (v) Sign in front of a park: You must not walk on the grass. (vi) You should be ashamed of yourself having made such a remark. (vii) He left home at 9 o’clock. He should be here any minute. (viii) “Whatever happened to the chocolate cake?” “How should I know? I have just arrived.” |
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| 13. |
The friend shook the bicycle violently. Find two or three sentences in the text which express the author’s disapproval of it. |
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Answer» The sentences in the text which express the author’s disapproval of his friend shaking the bicycle violently are as follows: (i) I said, “Don’t do that; you’ll hurt it.” (ii) I did not see why he should shake it; it had not done anything to him. (iii) Besides, if it wanted shaking, I was the proper person to shake it. I felt much as I should had he started whacking my dog. |
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| 14. |
In what condition did the author find the bicycle when he returned from the tool shed? |
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Answer» When the author returned from the tool shed, he saw his friend sitting on the ground with the front wheel between his legs. He was playing with it, twiddling it round between his fingers, and the remnant of the machine was lying on the gravel path beside him |
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| 15. |
What special treatment did the chain receive? |
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Answer» The author’s friend tightened the chain till it did not move. Then he loosened it until it was twice as loose as it was before. |
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| 16. |
“Nothing is easier than taking off the gear case.” Comment on or continue this sentence in the light of what actually happens. |
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Answer» The author’s friend wanted to check the chain of the bicycle. For this, he began taking off the gearcase. The author tried to dissuade him from doing that by telling him that if anything does go wrong with the gearcase of a bicycle, then it is cheaper to sell the bicycle than set about repairing the damaged gearcase. However, his friend disagreed and said that nothing was easier than taking off a gearcase. The author notes with sarcasm that his friend was indeed right. In less than five minutes, he had the gearcase in two pieces, lying on the path. |
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| 17. |
Mention any two types of strain |
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Answer» a) longitudinal strain b) shearing strain c) bulk strain |
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| 18. |
State and explain Hooke’s law. |
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Answer» Within elastic limit stress and strain are proportional to each other. Stress ∝ strain OR stress/stain = constant (modulus of elasticity). |
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| 19. |
Mention any two types of stress. |
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Answer» a) longitudinal stress b) shearing stress |
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| 20. |
Suppose a quantity x can be dimensionally represented in terms of M, L and T, that is,[x]=Ma Lb Tc. The quantity mass(a) can always be dimensionally represented in terms of L, T and x,(b) can never be dimensoinally represented in terms of L, T and x, (c) may be represented in terms of L, T and x if a = 0,(d) may be represented in terms of L, T and x if a≠ 0. |
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Answer» (d) may be represented in terms of L, T and x if a ≠0. Explanation: a≠0 If a = 0, then we cannot represent mass dimensionally in terms of L, T and x, otherwise it can be represented in terms of L, T and x. |
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| 21. |
Time taken by a radioactive substance to decay half is calledA. time delayB. half lifeC. time constantD. half period |
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Answer» B. half life |
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| 22. |
Radioactive decay is aA. random processB. non-spontaneous processC. regular processD. massive process |
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Answer» A. random process |
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| 23. |
STATEMENT-1: A real image is formed when two rays, starting from a point, and moving along different paths, meet again at some other point. STATEMENT-2: A real image can never be formed by reflection in a convex mirror or refraction in a concave lens. (a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (b) Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement-1. (c) Statement-1 is True, Statement-2 is False. (d) Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer is: (c) Statement-1 is True, Statement-2 is False. |
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| 24. |
In the circuit shown the cells are ideal and of equal emfs, the capacitance of the capacitor is `C` and the resistance of the resistor is `R`. `X` is first joined to `Y`and then to `Z`. After a long time, the total heat produced in the resistor will be A. equal to the energy finally stored in the capacitor.B. half to the energy finally stored in the capacitor.C. twice to the energy finally stored in the capacitor.D. four times the energy finally stored in the capacitor. |
| Answer» Charge flow through the battery will be `2CV`, while the energy stored in capacitor will be the same. | |
| 25. |
In the circuit shown above, the cells are ideal and of equal emfs, the capacitance of the capacitor is C and the resistance of the resistor is R. X is first joined to Y and then to Z. After a long time, the total heat produced in the resistor will be (a) equal to the energy finally stored in the capacitor (b) half the energy finally stored in the capacitor (c) twice the energy finally stored in the capacitor (d) four times the energy finally stored in the capacitor |
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Answer» Correct Answer is: (d) four times the energy finally stored in the capacitor The charge on the capacitor will change from -ℰC to +ℰC, where ℰ = emf of each cell. ∴ total charge flowing through the cell B is 2ℰC. ∴ total energy supplied by B is 2ℰ2C. The energy finally stored in the capacitor is ℰ = 1/2 ℰ2C. ∴ heat produced = 2ℰ2C = 4ℰ. |
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| 26. |
In the given circuit, the potential difference across the capacitor is `12V`. Each resistance is of `3Omega`. The cell is ideal. The emf of the cell is A. `15V`B. `9V`C. `12V`D. `24V` |
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Answer» Correct Answer - A In the steady state, no current flows through the capacitor. |
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| 27. |
In a complete rotation, spindle of a screw gauge advances by `(1)/(2)mm`. There are `50` divisions on circular scale. The main scale has `(1)/(2)mm` marks to (is graduated to `(1)/(2)mm`) If a wire is put between the jaws, `3` main scale divisions are clearly visible, and `20th` division of circular scale coincides with reference line. Find diameter of wire in correct significant figures.A. `1.7mm`B. `1.70mm`C. `3.40mm`D. `3.20mm` |
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Answer» Correct Answer - B dia. of e is `(3xx(1)/(2)mm)+(2.0)((1//2mm)/(50))` `=1.5+0.20=1.70mm` |
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| 28. |
Two cells `a` and `B` of emf `1.3 V` amd `1.5V `respectively are arranged as shown in figure. The voltmeter reds `1.45V`. The voltmeter is assumed to be ideal. Then A. `r_A = 2r_B`B. `r_A = 3r_B`C. `r_B= 2r_A`D. `r_B = 3r_A` |
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Answer» Correct Answer - B b. `1.45 = 1.3 + Ir_A` `1.45 = 1.5 - Ir_B` `Ir_B = 0.05` `Ir_A = 0.15` Dividing, we get `r_B/r_A = 1/3` or `r_A = 3r_B` . |
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| 29. |
100 cells each of emf 5V and internal resistance 1 Ω are to be arranged so as to produce maximum current in a 25 Ω resistance. Each row contains equal number of cells. The number of rows should be(a) 2 (b) 4 (c) 5 (d) 100 |
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Answer» Correct option (a) 2 Explanation: Total no. of cells, = mn = 100 Current will be maximum when R = nr/m; 25 = n x 1/m ⇒ n = 25 m From equation (i) and (ii) n = 50 and m = 2 |
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| 30. |
What is the change in internal energy of a system, if 10J of heat is supplied to it and 15J of work is done by it? |
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Answer» Since it is a closed system. Δu = q – w Δu = 10J – 15J Δu = -5J |
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| 31. |
A gas is compressed at a constant pressure of `50N//m^(2)` from a volume `10m^(3)` to a volume of `4m^(3)`. 100J of heat is added to the gas then its internal energy isA. Increased by 400 JB. Increased by 200 JC. Increased by 100 JD. Decreased by 200 J |
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Answer» Correct Answer - A From FLOT `DeltaU=DeltaU+DeltaW=DeltaU+PDeltaV` `rArr 100=DeltaU+ 50 xx (4 -10) rArr DeltaU=400 J` |
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| 32. |
Identify the conductor that is used to electroplate printed circuits and communications equipment.1. Copper2. Aluminium3. Silver4. Rhodium |
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Answer» Correct Answer - Option 3 : Silver Metal Plating Process:
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| 33. |
Variation of magnification`"("m")"` produced by a thin convex lens versus distance `"("v")"` of image from pole of the lens is shown in the graph. Which of the following statements is not correct ? A. Focal length of the lens is equal to intercept on v-axisB. Focal length of the lens is equal to inverse of the slope of the line (in magnitude)C. Magnitude of intercept on m-axis is equal to unityD. Magnitude of intercept on v-axis is equal to unity |
| Answer» Correct Answer - D | |
| 34. |
Two sound waves of slightly different frequently have amplitude ratio `11//9`. What is the different of sound levels in decibels of maximum and minmum intensities head at a point ?A. 100B. 10C. 16D. 20 |
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Answer» Correct Answer - D `SL_(2) - SL_(1) = 10 log (l_(max))/(l_(min)) = 10 log [((sqrtl_(1) + sqrtl_(2))^(2))/((sqrtl_(1) - sqrtl_(2))^(2))]` `=10 "log"(((a_(1))/(a_(2))+1)^(2))/(((a_(1))/(a_(2))-1)^(2))=20dB` |
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| 35. |
The graph shows how the magnification `m` produced by a convex thin lens varies with image distance `v`. What was the focal length of the used ? A. `b//c`B. `b//ca`C. `bc//a`D. `c//b` |
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Answer» Correct Answer - A `(1)/(v) + (1)/(u) = (1)/(f) :. U = (fv)/(f - v)` `:. (v)/(u) = (f - v)/(f) = 1 - (v)/(f)` `|m|=|1 - (v)/(f)| :.` slope `(1)/(f) = b//c` |
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| 36. |
A point object is located at a distance of 100cm from a screen. A lens of focal length 23 cm mounted on a movable frictionless stad is kept between the source and the screen. The stand is attached to a spring of natureal length 50cm and spring constant `800N//m` as shown in Figure . Mass of the stand with lens is 2 kg. How much impulse P should be imparted to the stand so that a real image of the object is formed on the screen after a fixed time gap? Also find this time gap. (Neglect width width of the stand) A. `(pi)/(10)sec`B. `(pi)/(20)sec`C. `(pi)/(30)sec`D. `(pi)/(40)sec` |
| Answer» Correct Answer - D | |
| 37. |
When a ray of light enters a glass slab its wavelength(a) decreases(b) increases(c) remains unchanged(d) data are not complete |
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Answer» Correct answer is (a) decreases |
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| 38. |
When a ray of light enters a glass slab from air (a) its wavelength decreases (b) its wavelength increases (c) its frequency increases (d) neither its wavelength nor its frequency changes |
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Answer» (a) its wavelength decreases Wavelength, λ = \(\frac{velocity}{frequency}\) = \(\frac{u}{v}\) When light travels from air to glass, frequency ν remains unchanged, velocity u decreases and hence wave length λ also decreses |
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| 39. |
The limit of resolution of microscope, if the numerical aperture of microscope is `0.12`, and the wavelength of light used is 600 nm, isA. `0.25xx10^(-7)m`B. `2.5xx10^(-7)m`C. `25xx10^(-7)m`D. `250xx10^(-7)m` |
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Answer» Correct Answer - C `25xx10^(-7)m` `mu sin theta=0.12, lamda =6000Å, dimplies` `d=(lamda)/(2 mu sin theta)` `=(6xx10^(-7))/(2xx0.12)` `=(6xx10^(-7))/(0.24)` `d= 25xx10^(-7)m.` |
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| 40. |
An air bubble in glass slab of refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness of the slab is,(a) 8 cm (b) 10 cm (c) 12 cm(d) 16 cm |
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Answer» (c) 12 cm Let d1 = 5 cm and d2 = 3 cm ; n = 1.5 Actual width is the sum of real depth from 2 sides Thickness of slab = d1 n + d2 n = (5 x 1.5) +(3 x 1.5)= 12 cm |
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| 41. |
STATEMENT-1: In high-quality optical devices, such as camera, binocular, periscope, et.c prisms are used in place of plane mirrors to reflect light. STATEMENT-2: In plane mirrors, reflections occur both in the front and rear (silvered) surfaces.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation, for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is a False, Statement-2 is True. |
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Answer» Correct Answer - A |
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| 42. |
STATEMENT-1: The specific heat capacity of a gas at constant pressure is always greter than its specific heat capacity at constant volume. STATEMENT-2: Work is done by a gas when it expands.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation, for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is a False, Statement-2 is True. |
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Answer» Correct Answer - A |
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| 43. |
STATEMENT-1: Real images cannot be formed by reflection of light in a convex mirror. STATEMENT-2: Parallel rays incident on a convex mirror must diverge after reflection. (a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (b) Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement-1. (c) Statement-1 is True, Statement-2 is False. (d) Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer is: (d) Statement-1 is False, Statement-2 is True. |
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| 44. |
STATEMENT-1: Real images cannot be formed by reflection of light in a convex mirror. STATEMENT-2: Parallel rays incident on a convex mirror must diverge after reflection.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation, for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is a False, Statement-2 is True. |
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Answer» Correct Answer - D |
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| 45. |
From the figure shown establish a relation between `mu_(1),mu_(2),mu_(3)`. A. `mu_(3)gtmu_(2)gtmu_(1)`B. `mu_(3)ltmu_(2)ltmu_(1)`C. `mu_(2)gtmu_(3),mu_(3)=mu_(1)`D. `mu_(2)gtmu_(1),mu_(3)=mu_(2)` |
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Answer» Correct Answer - C `mu_(1)=mu_(3)` since there is no bending at first surface. `mu_(3)ltmu_(2)` since the ray bends towards normal as it passes from `mu_(3)` to `mu_(2)` medium. |
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| 46. |
A transparent thin film of uniform thickness and refractive index `n_(1)``=1.4` is coated on the convex spherical surface of radius R at one end of a long solid glass cylinder of refractive index `n_(2)``=1.5`, as shown in the figure. Rays of light parallel to the axis of the cylinder traversing through the film from air to glass get focused at distance `f_(1)` from the film, while rays of light traversing from glass to air get focused at distance `f_(2)` from the film, Then ` A. `|f_(1)|=3R`B. `|f_(1)|=2.8R`C. `|f_(2)|=2R`D. `|f_(2)|=1.4 R` |
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Answer» Correct Answer - A::C `(1)/(f_("film"))=(n_(1)-1)((1)/(R)-(1)/(R))` `rArr f_("film")=infty` (infinite) No effect of presence of film From Air to Glass : Using single spherical Refraction :- `(n_(2))/(v)-(1)/(u)=(n_(2)-1)/(R),(1.5)/(v)-(1)/(prop)=(1.5-1)/(R)` `v=3R f_(1)=3R` From Glass to Air : - |
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| 47. |
A parachutist drops from an aeroplane for `10s` before the parachute opens out. Then he descends with a net retardation of `2.5ms^(-2)`. If he bails out of plane at a height of `2495m` and `g=10ms^(-2)`, his velocity on reaching the ground will veA. `2.5ms^(-1)`B. `7.5ms^(-1)`C. `5ms^(-1)`D. `10ms^(-1)` |
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Answer» Correct Answer - C Distance covered in first `10 sec` `S_(i)=(1)/(2)(10)(10)^(2)=500m` Remaining height from ground `=2495-500=1995m` `u=gt=10xx10=100m//s` velocity on reaching the ground `v^(2)=(100)^(2)+2(-2.5)xx1995` `v^(2)=10000-9975=25` `v=5m//s`. |
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| 48. |
The torque (vector τ) experienced by a current - loop of magnetic moment (vector M) placed in magnetic field B is (A) (vector τ = M x B)(B) (vector τ = B x M)(C) (vector τ = M/M)(D) (vector τ = M. B) |
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Answer» (A) (vector τ = M x B) |
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| 49. |
Two charges `q_(1)` and `q_(2)` are placed `30 cm` apart, as shown in the figure. A third charge `q_(3)` is moved along the arc of a circle of radius `40 cm` from `C` to `D`. The change in the potential energy o fthe system is `(q_(3))/(4pi epsilon_(0))k`., where `k` is A. `8 q_(2)`B. `8 q_(1)`C. `6 q_(2)`D. `6 q_(1)` |
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Answer» Correct Answer - A The change in potential energy of the system is `U_(D) - U_(C)` as discussed under. When charge `q_(3)` is at C, then its potential energy is `U_(C) = (1)/(4 pi epsilon_(0))((q_(1)q_(3))/(0.4) +(q_(2) q_(3))/(0.1))` When charge `q_(3)` is at D, then ` U_(C) = (1)/(4 pi epsilon_(0))((q_(1)q_(3))/(0.4) +(q_(2) q_(3))/(0.1))` Hence, change in potential energy `(1)/(4 pi epsilon_(0))((q_(2)q_(3))/(0.1)+(q_(2)q_(3))/(0.5))` `:. (q_(3))/(4 pi epsilon_(0))=(1)/(4 pi epsilon_(0))((q_(2)q_(3))/(0.1)+(q_(2)q_(3))/(0.5))` `rArr k=q_(2)(10 -2)=8q_(2)`. |
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| 50. |
The lens shown is equiconvex having refractive Index. 1.5. In the situation shown the final image of object coincides with the object. The region between lens and mirror is now filled with a liquid of Rrefractive Index 2. Then find the separation between O & image formed by convex mirror.A. 33 cmB. 66 cmC. 16 cmD. 32 cm |
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Answer» Case-1: Radius of curvature of lens is 20 cm Image of fomred by convex lens should be at centre of curvature of mirror `(1)/(V)+(1)/(30)=(1)/(20)` `(1)/(V)=(1)/(20)-(1)/(30)impliesV=60cm` Radius curvature of mirror should be 40 m. Case-II `(2)/(V_(1))+(1)/(30)=(1.5-1)/(20)+(2-1.5)/(-20)` `impliesV=-60` So for convex mirror `u=-80` `(1)/(V)-(1)/(80)=(1)/(20)` `V=16cm` Separation between object and this image `O=66cm` |
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