This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which one of the following is a metallic minerals?(a) Lime stone (b) Coal(c) Mica (d) Iron |
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Answer» Iron is a metallic minerals. |
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| 2. |
Which one of the following state is the largest production of groundnut ?(a) Maharashtra (b) Gujarat(c) Bihar (d) Rajasthan |
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Answer» Gujarat is the largest production of groundnut. |
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| 3. |
A rectangular bar having a cross-sectional area of 80 mm2 has a tensile force of 20 kN applied to it. Determine the stress in the bar. |
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Answer» Stress \(\sigma\) = \(\cfrac{force F}{area A}\) = \(\cfrac{20\times10^3}{80\times10^{-6}}\) = 250 x 106 pa = 250 Mpa |
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| 4. |
Which one of the following is a non-renewable source of energy?(a) Solar(b) Coal(c) Petroleum (d) Atomic energy |
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Answer» Solar is a non-renewable source of energy. |
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| 5. |
Which of the following is a kharif crops ?(a) Wheat(b) Rice(c) Gram (d) Barley |
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Answer» Rice is a kharif crops. |
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| 6. |
A circular section cable has a tensile force of 1 kN applied to it and the force produces a stress of 7.8 MPa in the cable. Calculate the diameter of the cable. |
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Answer» Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) hence, cross-sectional area, A = \(\cfrac{forcce F}{stress\,\sigma}\) = \(\cfrac{1\times10^3}{7.8\times10^6}\) = 128.2 x 10-6 m2 Circular area = \(\pi\)r2 = 128.2 x 10-6 m2 from which, r2 = \(\cfrac{128.2 \times10^{-6}}{\pi}\) and radius r = \(\sqrt{\cfrac{128.2 \times10^{-6}}{\pi}}\) = 6.388 10-3 m = 6.388 mm and diameter d = 2 x r = 2 x 6.388 = 12.78 mm |
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| 7. |
A square-sectioned support of side 12 mm is loaded with a compressive force of 10 kN. Determine the compressive stress in the support. |
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Answer» Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) = \(\cfrac{10\times10^3}{12\times12\times10^{-6}}\) = 69.44 x 106 pa = 69.44 mpa |
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| 8. |
Where is the headquarter of the East Central Railways?(a) Allahabad (b) Hajipur(c) Kolkata (d) Gorakhpur |
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Answer» Hajipur is the headquarter of the East Central Railways. |
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| 9. |
A bolt having a diameter of 5 mm is loaded so that the shear stress in it is 120 MPa. Determine the value of the shear force on the bolt. |
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Answer» Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) = hence, force = stress x area = stress \(\pi\)r2 = 120 x 106 x \(\pi\) \(\left(\cfrac{5\times10^{-3}}{2}\right)^2\) = 2356 N or 2.356 kN |
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| 10. |
Which one of the following continent has the highest population growth?(a) Africa (b) South America(c) North America (d) Asia |
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Answer» Asia continent has the highest population growth. |
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| 11. |
A split pin requires a force of 400 N to shear it. The maximum shear stress before shear occurs is 120 MPa. Determine the minimum diameter of the pin. |
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Answer» Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) = hence, cross-sectional area, A = \(\cfrac{forcce F}{stress\,\sigma}\) = \(\cfrac{400}{120\times10^6}\) = 3.333 x 10-6 m2 Circular area = \(\pi\)r2 = 3.3333 x 10-6 m2 from which, r2 = \(\cfrac{3.3333 \times10^{-6}}\pi\) and radius r = \(\sqrt{\cfrac{3.3333 \times10^{-6}}\pi}\) = 1.030 x 10-3 m = 1.030 mm diameter d = 2 x r = 2 x 1.030 = 2.06 mm |
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| 12. |
Important cotton production area is:(a) Daccan(b) North area(c) North – east area (d) Eastern area |
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Answer» Important cotton production area is Daccan. |
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| 13. |
Which one of the following activities is included in agriculture?(a) Crop cultivation (b) Animal husbandry(c) Fishing (d) All the above |
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Answer» Crop cultivation, Animal husbandry and Fishing activities are included in agriculture. |
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| 14. |
Which of the following crops are grown on mountain slopes?(a) Jute(b) Tea(c) Sugarcane (d) Cotton |
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Answer» Tea crops are grown on mountain slopes. |
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| 15. |
Which one of the following states has the lowest population in India?(a) Himachal Pradesh (b) Arunachal Pradesh(c) Sikkim (d) Goa |
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Answer» Sikkim states has the lowest population in India. |
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| 16. |
Partisan means: (a) Party which runs the government (b) Affair of the state or the science of government (c) A person who is strongly committed to a party. (d) A group of people who come together to promote common beliefs |
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Answer» Partisan means a person who is strongly committed to a party. |
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| 17. |
A tube of outside diameter 60 mm and inside diameter 40 mm is subjected to a tensile load of 60 kN. Determine the stress in the tube. |
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Answer» Area of tube end (annulus) = \(\pi\) \(\left(\cfrac{D^2}{4}-\cfrac{d^2}{4}\right)\) = \(\pi\) \(\left(\cfrac{(60\times10^{-3})^2}{4}-\cfrac{(40\times10^{-3})^2}{4}\right)\) = 1.5708 x 10-3 mm2 Stress \(\sigma\) = \(\cfrac{force F}{area A}\) = \(\cfrac{60\times10^3}{1.5708\times10^{-3}}\) = 38.20 x 106 pa = 38.2 Mpa |
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| 18. |
Multi-party system advocates: (I) The political parties which govern the country (II) The government is formed by various parties coming together (III) Does not permit free competition for power (IV) This system allows a variety of interests and opinions to enjoy political representation (a) A,B & C (b) A, C & D (c) D & C (d) B and D |
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Answer» Correct option (d) B and D |
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| 19. |
Delhi is of which type of city?(a) Administrative(b) Commercial(c) industrial (d) educational |
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Answer» Delhi is Administrative city. |
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| 20. |
Recognized political parties stand for : (a) Parties recognized by the Election Commission with all the privileges and facilities (b) Parties those are present in only one of the federal units (c) Parties those are present in several and all units of the federation (d) Communal parties based on regional diversities. |
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Answer» Recognized political parties stand for Parties recognized by the Election Commission with all the privileges and facilities. |
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| 21. |
In which of the following groups are the words intimately related ?1. arboreal animals, sharp claws, trees2. fish, gills, terrestrial3. hole, rats, aquatic4. frog, amphibian, whale |
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Answer» Correct Answer - Option 1 : arboreal animals, sharp claws, trees In a biological context, arboreal is a term used to associate with trees, any mammal/animal which lives on trees are arboreal.
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| 22. |
Consider the following:I. PeacockII. LotusIII. LionIV. ElephantWhich of the above is/are not an Indian national symbol?1. III only2. IV only3. II and IV4. III and IV |
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Answer» Correct Answer - Option 1 : III only A national symbol is some specific considering and manifesting itself as a national community. The national animal tiger symbolizes power, the national flower lotus symbolizes purity, the national tree banyan symbolizes immortality, the national bird, the peacock symbolizes elegance, and the national fruit mango symbolizes the tropical climate of India. National Symbols of India
Hence, we can say that lion is not an Indian national symbol |
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| 23. |
The minimum population density necessary for a settlement to be designated as urban settlement is –(a) 100 persons per sq. km (b) 400 persons per sq. km(c) 500 persons per sq. km (d) 1000 persons per sq. km |
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Answer» The minimum population density necessary for a settlement to be designated as urban settlement is 400 persons per sq. km. |
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| 24. |
DIRECTIONS : Match List-I with List-II and select the correct answer using the codes given below the lists.Match List-I and List-II and select the correct answer from the codes given below:List-I (Type of winds)List-II (Region)A. Blizzard1. Pairie PlainsB. Chinook2. Siberian PlainsC. Bora3. GreenlandD. Khamsin 4. Egypt A B C D (a) 3 1 4 2 (b) 1 2 3 4 (c) 2 1 3 4 (d) 4 3 1 2 |
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Answer» (c) Blizzard – Siberian Plains. A blizzard is a severe snowstorm caused by strong sustained winds of at least 56 km/h (35 mph) and lasting for a prolonged period of time – typically three hours or more. Chinook – Prairie Plains. Chinook winds blows in the interior west of North America, where the Canadian Prairies and Great Plains meet various mountain ranges, although the original usage is in reference to wet, warm coastal winds in the Pacific Northwest of the United States of America. Bora – Green land. Cold and usually dry katabatic winds, like the Bora, result from the downslope gravity flow of cold, dense air. Katabatic flows slumping down from uplands or mountains may be funneled and strengthened by the landscape and are then known as mountain gap wind. Khamsin – Egypt. Khamsin can be triggered by depressions that move eastwards along the southern parts of the Mediterranean or along the North African coast from February to June. In Egypt, khamsin usually arrives in April but occasionally occurs between March to May, carrying great quantities of sand and dust from the deserts, with a speed up to 140 kilometres per hour, and a rise of temperatures as much as 20°C in two hours. |
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| 25. |
DIRECTIONS : Match List-I with List-II and select the correct answer using the codes given below the lists.Match List-I with List-II and select the correct answer using the code given below:List-I (Current)List-II (Feature)A. Kuroshio current1. Warm current in Atlantic OceanB. Peru current2. Cold current in the Atlantic OceanC. Labrador current3. Warm current in the Pacific OceanD. Florida current4. Cold current in the Pacific Ocean A B C D (a) 3 4 2 1 (b) 3 2 4 1 (c) 1 4 2 3 (d) 1 2 4 3 |
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Answer» (a) A. Kuroshio current – warm Pacific current B. Peru current – cold current in Pacific ocean C. Labrador current – cold current in Atlantic ocean D. Florida current – Warm current in Atlantic ocean |
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| 26. |
Which of the following fertilizer plants is not in the public sector? (a) Bhatinda (b) Nangal (c) Kota (d) Gorakhpur |
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Answer» Kota is fertilizer plants is not in the public sector. |
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| 27. |
During crushing or bearing failure of riveted joints(a) The holes in the plates become oval shaped and joints become loose (b) There is tearing of the plate at an edge (c) The plates will crack in radial directions and joints fail (d) The rivet heads will shear out by applied stress |
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Answer» (a) The holes in the plates become oval shaped and joints become loose Crushing strength of plate/rivet crushing failure of the plate/rivet. This type of failure occurs when the compressive stress between the shank of the rivet and the plate exceeds the yield stress in compression. The failure results in elongating the rivet hole in the plate and loosening of the joint. |
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| 28. |
Which of the following is drought prone region?(a) West Bengal(b) Uttar Pradesh(c) Gujarat (d) Uttarakhand |
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Answer» Gujarat is drought prone region. |
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| 29. |
Which of the following state has longer period of sugarcane crushing ?(a) Punjab(b) Uttar Pradesh(c) Bihar (d) Tamilnadu |
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Answer» Tamilnadu state has longer period of sugarcane crushing. |
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| 30. |
Which country assisted India in the launching of her first satellite 'Aryabhatta'? (a) USA (b) United Kingdom (c) Former USSR (d) Germany |
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Answer» (c) Former USSR |
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| 31. |
Naharkatiya oilfields are located in (a) Tripura (b) West Bengal (c) Assam (d) Madhya Pradesh |
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Answer» Naharkatiya oilfields are located in Assam. |
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| 32. |
DIRECTIONS : Match List-I with List-II and select the correct answer using the codes given below the lists.Which of the following pairs are correctly matched?(River)(Countries)1. NigerGuinea2. OrangeS. Africa3. KaraiEgypt4. Nile MaliSelect the correct answer using the codes given below: (a) 1 and 2 (b) 1 and 3 (c) 1, 3 and 4 (d) 2, 3 and 4 |
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Answer» (a) The Niger river is the principal river of western Africa, extending about 4,180 km. Its drainage basin is 2,117,700 km2 in area. Its source is in the Guinea Highlands in southeastern Guinea. The Orange river, Gariep river, Groote river or Senqu river is the longest river in South Africa. It rises in the Drakensberg mountains in Lesotho, flowing westwards through South Africa to the Atlantic Ocean. |
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| 33. |
Find the co-ordinate of the focus, equation of the directrix and length of the Latus Rectum of the parabola y2 = 8x. |
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Answer» Equation of parabola y2 = 8x compare with the standard form y2 = 4ax ∴ 4a = 8 ∴ a = 2 ∴ focus = (a,0) = (2,0) Equation of directrix : x = -a. x = -2 or [x + 2 = 0] Latus rectum = 4a = 8. |
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| 34. |
Find the middle term in the expansion of (x/3 + 9y)10 |
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Answer» x = x/3, a = 9y, n = 10, r = 5 n = 10 (even) there is only one middle term is (n/2 + 1) = (10/2 + 1) = 6th term General term Tr+1 = nCr xn-r ar ⇒ Ts+1 = 10C5 (x/3)10 - 5(9y)5 T6 = 10C5 (x/3)5 g5 y5 ⇒ T6 = 10C5 . x5/35 × 95 y5 = 10C5 (xy)5 × (310/35) T6 = [10C5 (xy)5 35] is the middle term. |
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| 35. |
Figure shows the part of an infinite plane sheet of charge. Which of the following graphs correctly shows the behavior of electric field intensity as we move from point O to A |
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Answer» Answer is : (c) |
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| 36. |
In Gauss Theorem, Number of electric field lines entering the surface is __________ to the field lines leaving the surface. A. greater B. less C. equal D. two times |
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Answer» Number of electric field lines entering the surface is equal to the field lines leaving the surface. |
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| 37. |
A parabola with vertex at origin has its focus at the centre of x2 + y2 – 10x + 9 = 0 Find the direction its directrix and latus rectum. |
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Answer» The centre of the circle = (5,0). The equation y2 = 20x ⇒ y2 = 4ax ⇒ a = 5 directrix is x = -5, LR = 20. |
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| 38. |
If I. = Asin(wt-kx)Where i=current T= time X= distance |
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Answer» As sin function is dimensionless and wt- kx is dimensionless now difference of two quantity ( wt) and ( kx) is dimensionless therefore wt= M0L0T0 =>w* time(T1) = M0L0T0 =>w= M0L0T0 / T1 = M0L0T-1 also kx= M0L0T0 =>k* distance(L1) = M0L0T0 =>k= M0L0T0 /L1 =M0L-1T0 |
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| 39. |
If an A.P. if mth term is n and the nth term is m, where m ≠ n, find the pth term |
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Answer» We have am = a + (m – 1)d = n, …… (1) and an = a + (n – 1)d = m …….. (2) Solving (1) and (2), we get (m, n) d = n – m, or d = -1, and a = n + m – 1 ……. (3) Therefore ap = a + (p – 1)d ……. (4) = n + m – 1 + (p – 1) (-1) = n + m – p Hence, the pth term is n + m – p. |
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| 40. |
The points on parabola y^2=12x whose focal distance is 4 are? |
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Answer» The coordinate will be : (3, 6), (3, -6) Explanation: As we know that coordinates of the focus of parabola with equation y2=4ax are (a,0). The focal distance of this parabola is 2a. Here, y2 = 12x when we compare it to y2 = 4ax then so coordinates are (3, 6), (3, -6) |
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| 41. |
Define the term fibres. |
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Answer» Fibres: A long fine continuous thread or filament |
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| 42. |
If 6th term of an AP. Is -10 and it's 10 term is -26,then find first term and difference |
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Answer» T6=a+5d=-10......(1) T10=a+9d=-26....(2) where a is the 1st term and d is the common difference. Subtracting (1) from (2) 4d=-16 =>d,= -4 So a+5×4=-10 =>a = -30 |
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| 43. |
Differential co-efficient of ax is(A) ax (B) ax loga(C) ax/log a(D) log ax |
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Answer» Correct option: (B) ax log a |
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| 44. |
Tangent of the curve y = x3 + 3x at x = –1 and x = 1 are(A) parallel (B) intersecting at right angles(C) intersecting at an angle of 45º (D) None of these |
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Answer» Correct option: (A) parallel |
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| 45. |
Show that the maximum value of x + (1/x) is less than its minimum value. |
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Answer» Let y = x + (1/x) ∴ dy/dx = 1 - (1/x2) or, dy/dx = ((x2 - 1)/x2) For maximum or minimum value of y, dy/dx = 0 ∴ ((1 - x2)/x2) = 0 = 1 - x2 = 0 x = 1,-1 Again, d2y/dx2 = 2/x3 At, x = 1, d2y/dx2 = 2 > 0 So, y has minimum value at x = 1 and minimum value of y = x + (1/x) = 1 + (1/1) = 2 and at, x = -1, d2y/dx2 = 2/(-1)3 = -2 < 0 So, y has maximum value at x = -1 and maximum value of y = -1 + (1/-1) = -2 So, minimum value of given function is greater than maximum value. |
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| 46. |
A car is moving with a constant velocity `10 m//s` towards the stationary wall. The car blows a horn of frequency `320 Hz`. The velocity of sound in air is `330 m//s`. The beats frequency received by the observer is A. `2Hz`B. `4 Hz`C. `6 Hz`D. `8 Hz` |
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Answer» Correct Answer - B `f_(1) = ((v - v_(D))/(v - v_(s))) f` and the freqency of sound received by the observer after reflection from the stationary wall is `f_(2) = ((v + v_(D))/(v - v_(s)))f` `:.` Beats frequency received by the observe, `f_(b) = f_(2) - f_(1) = ((v + v_(D))/(v - v_(s))) f - ((v - v_(D))/(v - v_(s))) f` `:. f_(b) = ((2v_(D))f)/((v - v_(s))) = (2 xx 2)/((330 - 10)) xx 320 = 4Hz`. |
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| 47. |
In the expansion of (1+x)n the coefficient of pth and (p+1)th terms are respectively p and q. The p + q = |
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Answer» option b is the correct answer........ first find general tern of (1+x)n Tr+1 = nCr xr Tp= T(p-1)+1 = nCp-1 xp-1 Cofficient of pth term = P nCp-1 = P Tp+1= T(p)+1 = nCp xp Cofficient of (P+1)th term = q nCp= q P+q = nCp-1 + nCp =n+1Cp |
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| 48. |
Verify by the method of contradiction √2 is irrational |
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Answer» Let us assume that √2 is rational i.e.. the gives statement is false. ∴ √2 = 1/2 ≠ 0 a and b have no conunon factor. Squaring ∴ 2 = a2/b2 ⇒ [a2 = 2b2] ⇒ 2 divides a Again put a = 2C(C ∈ Z) ⇒ ∴ (2c)2 = 2b2 ∴ 4c2 = 2b2 or [b2 = 2c2]2 divide b i.e., 2 divides both a and b hence our assumption is i.e.. a and b does flot have common contradict out statement √2 is rational is false. ∴ √2 is irrational. |
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| 49. |
Verify by the method of contradiction that √2 is irrational |
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Answer» If possible Let √2 is rational ∴ √2 = p/q, p, q ∈ z, q ≠ 0 We assume that p and q do not have any common factor p = √2q ⇒ p = 2q2 p2 is a multiple of 2 ⇒ ∴ p is a multiple of 2 ∴ p = 2k, k ∈ z ⇒ p2 = 4k 2q2 = 4k2 ⇒ q2 = 2k2 q2 = 2k2 q2 is a multiple of 2 ⇒ ∴ q is a multiple of z ∴ p and q are both multiple of 2 and hence has a common factor z which is a contradiction ∴ our assumption is wron ∴ √2 is irrational |
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| 50. |
Spindal machine work |
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Answer» Spindle moulder machine are commonly used to trim and shape wood to make it ideal for various uses such as in shutters, windows, frames, doors, etc. These tools also allow tenoning for window assemblage, that is, a milling process used to join side jambs to head jambs in window frames and frames in general. These are ‘secondary processing’ tools, which work on solid wood and are not used on timber that is to be cut to measure, but on wood that is to be finished, milled and subsequently worked. The guard's main purpose is to provide pressure on the workpiece to hold it very firmly onto the table and horizontally against the fence. Compared to its smaller cousin, the router table, a spindle moulder is able to produce work with a much larger profile such as a crown moulding. |
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