This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
a. State the reason which has led to the requirement of easy to wear clothing for women. b. Describe any two ways in which Mughal culture influenced Indian women wear. |
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Answer» a. With changing times, the role of the women have become multi dimensional; from handling office to home; to kids and simultaneously balancing their social and personal responsibilities. Working for home or for office, with a hectic schedule has led to the requirement of an easy to wear, maintain and comfortable dressing, which has become a necessity for today's lifestyle. b. Influence of Mughal culture:
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| 2. |
Discuss the different ways of finishing necklines in a garment. |
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Answer» The necklines in a garment can be finished with a collar or a separate finishing like facing or piping, since the neckline is cut as a shape it has a substantial amount of stretch so it needs to be secured properly. The neckline also frames the face of the wearer hence it draws maximum attention. Both kinds of facings that are cut on bias or a shaped facing are prevalent in all kinds of clothing around the world, however, piping is generally only used in Indian garments specially the sari blouses. Piping: is a bias strip of fabric 1¼" wide and is attached to the neckline on the seam line after stretching. The piping is finished either by hemming or machine stitch. It is finished to about 1/8" - 1/4" wide ready on the right side of the garment. It is a popular finish for blouses and other Indian garments. Facings are of two kinds - bias facing and shaped facing. Bias facing: is a similar strip of fabric like piping but is attached to the neckline without stretching. The same is finished completely on the wrong side. Shaped facing: A shaped facing is cut following the shape of the neckline and is attached on the right side and then is completely turned in. The width of this facing varies for each design but is generally 1½" wide. |
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| 3. |
Men’s wear clothing can be divided into many categories. Explain any three categories of Men’s wear. |
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Answer» 1. Casual wear clothing can be worn during leisure activities or informal occasions. Examples of such clothes are T- shirts, jeans, cargo pants, shorts etc. 2. Sportswear clothing is worn either while playing a sport or may be inspired from any sports activity. These are informal, interchangeable separates. 3. Active sportswear clothing is worn specifically while participating in a sports activity like swimming, scuba diving etc. 4. Outer wear clothing is designed to be worn over other garments, when outdoors. Overcoats, cloaks etc. 5. Formal wear clothing is worn during formal office situations or specific formal occasions. They can be ethnic or western. Ethnic category may include sherwani, kurta, churidar, dhoti and pyjama. Western category may include formal or dressshirts, trousers, jackets and suits. |
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| 4. |
Distinguish between tubed tyre and tubeless tyre. |
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| 5. |
Write advantages of Tubeless tyre. |
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Answer» a. The tubeless tyres are lighter and run cooler than tube tyre. b. It retains air for a long period even after being punctured by nail, provided the nail remains in the tyre. c. Any hole in the tubeless tyre can be repaired simply by rubber plugging. d. It can be retreated in the same manner as the tube tyre. |
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| 6. |
Fashion Designer _____won a president award for the movie Devdas. a. Neeta Lulla b. Manish Malhotra c. Sabyasachi d. Rohit Bal |
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Answer» Fashion Designer Neeta Lulla won a president award for the movie Devdas. |
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| 7. |
How is sleeveless bodice different from basic bodice? a. In sleeveless bodice armhole level goes down by ½ inchb. In sleeveless bodice armhole level goes up by ½ inch c. In sleeveless bodice armhole level goes out by ½ inch d. In sleeveless bodice armhole level goes inside by ½ inch |
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Answer» Correct option: b. In sleeveless bodice armhole level goes up by ½ inch |
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| 8. |
Write the advantages of tubeless tyres over tubed tyre. |
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Answer» Advantages of Tubeless Tyres: a) The tubeless tyres are lighter and run cooler than the tubed tyres. b) The main advantage of tubeless tyre is that it retains air for comparatively longer time period even after being punctured by nail, provided the nail remains in the tyre. But the tubed tyre releases the air immediately after being punctured. c) With the tubeless tyre the vehicles can run for around 50 kms. or more even the tyre is punctured. d) Any hole in the tubeless tyre can be repaired simply by rubber plugging. e) It can be re-treaded in the same manner as the tubed tyre. |
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| 9. |
Explain the issue and return procedure in the Newark system? Write its advantages and disadvantages? |
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Answer» Newark System. Issue procedure:
Return Procedure:
Advantages:
Disadvantages:
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| 10. |
How much seam allowance is suggested for straight hemline of a kurta? a. 1 inches b. 2 inches c. 1.5 inches d. 2.5 inches |
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Answer» Correct option: b. 2 inches |
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| 11. |
Explain step by step how to remove the wheel from the stub axle. |
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Answer» Procedure of removing wheel from the Stub axle: a) Park the vehicle on hard level ground and chock the wheels with wooden blocks to lock the wheels. b) Loosen the wheel nuts with the help of wheel spanner. c) Lift the particular wheel and clear the ground with the help of jack by placing it under the axle. d) Remove the grease cup with the help of hammer and screw driver. e) Remove the split pin after straightening it. f) Unscrew the castle nut and take it out. g) Remove the brake drum from stub axle h) Remove the wheel and wheel hub from stub axle. |
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| 12. |
The seam allowance measurement followed on sharp curves is:a. 1/2” b. 1/4” c. 1/8” |
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Answer» b. 1/4” The seam allowance measurement followed on sharp curves is 1/4”. |
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| 13. |
Cut of a garment for a more curvaceous body of a woman is called as : a. Missy b. Petite c. Junior |
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Answer» a. Missy Cut of a garment for a more curvaceous body of a woman is called as Missy. |
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| 14. |
Name the tool used for opening any seam or stitches a. Pinking shears b. Seam ripper c. Scissors d. Notcher |
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Answer» Correct option: b. Seam ripper |
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| 15. |
A properly fitted crotch seam of the bifurcated garment is the one which has: a. excessive ease in the crotch area b. generally has one inch of ease in the crotch area c. slight ease in the crotch area |
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Answer» b. generally has one inch of ease in the crotch area A properly fitted crotch seam of the bifurcated garment is the one which has generally has one inch of ease in the crotch area. |
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| 16. |
Seam ripper is used for opening any _______. |
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Answer» .Seam ripper is used for opening any Seams or stitches. |
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| 17. |
Printed designs are _______ on the right side, more _______ on the back. |
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Answer» Printed designs are sharper, on the right side, more blurred on the back. |
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| 18. |
______, dressmaker to the Queen Marie Antoinette, was named the Minister of fashion. |
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Answer» Rose Bertin, dressmaker to the Queen Marie Antoinette, was named the Minister of fashion. |
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| 19. |
In the exp of finding sp heat capacity of an unknown sphere `(S_(2))` mass of the sphere and caloreter aro `1000m` and `200gm` respectively and sp heat capacity of calorimeter is equal to `(1)/(2)cal//gm^(@)C` The mass of liquid 9water) used is `900gm` Initially both the water and the calorimeter were at room temp `20.0^(@)C` while used is `900gm` Initially both the water and the calorimeter were at room temp `20.0^(@)C` while the sphere was at temp `800^(@)C` initially If the steady state temp was found to be `40.0^(@)C` estimate sp heat capacity of the unknown sphere `(S_(2))` `(use S_(water) = 1 cal//g^(@)C)` Also fin the maximum permissible error in sp heat capacity of unknown sphere `(S_(2))` mass end specific heats of sphere and calorimater are correctly known) . |
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Answer» To determine the specitle heat capacity of unkonw soild We use`s_("solid")=(m_(1)s_(1)+m_(2)s_(2))/(m_(1))((0_(s)-0_(2))/(0_(1)-0_(s)))and" get "s_(solid)=1//2cal//g// .^(@)C` `((Deltas)/(s))_(max)=20Deltatheta((1)/(0_(s.s)-2_(2))+(1)/(0_(1)-0_(s s)))=2(0.1^(@)C)((1)/(40.0-20.0)+(1)/(80.0-40.0))=1.5%` . |
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| 20. |
define food preservative ?what is vaccinations ? give example of each of the following types of microorganisms ?algae protozoa fungiwhy oil is added while making pickel ? |
Answer»
(1) Sea weeds , Chlamydomonas (2) Amoeba , Paramecium (3) Yeast , Mushroom When pickle is stored, it shouldn't come in contact with air. Atmospheric air contains moisture. This moisture aids in the growth of mold. After the pickle is transfered to a bottle, oil is poured to block the air from coming in contact with the pickle, and then the bottle is tightly closed with its lid. |
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| 21. |
Describe the events that occur during the action potential. |
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Answer» The action potential has three main stages: depolarization, repolarization, and hyperpolarization. Depolarization is caused when positively charged sodium ions rush into a neuron with the opening of voltage-gated sodium channels. |
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| 22. |
As the mass number A increases which of the following quantities related to a nucleus does not change?(A) Mass(B) Volume(C) Density(D) Binding energy |
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Answer» Correct answer is (A) Mass |
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| 23. |
For a two `-` body sstem in absence of external forces, the kinetic energy as measured from ground frame is `K_(0)` and from centre of mass frame is `K_(cm)`. Pick up the wrong statement.A. The kinetic energy as measured from center of mass frame is leastB. Only the portion of energy `K_(cm)` can be transferred from one form to another due to internal changes in the system.C. The system always retains at least `K_(o)-K_(cm)` amount of kinetic energy as measured from ground frame irrespective of any kind of internal changes in the system.D. The system always retains at least `K_(cm)` amount of kinetic energy as measured from ground frame irrespective of any kind of internal changes in the system. |
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Answer» Correct Answer - D It can be shown that `K_(0)=K_(cm)+(1)/(2)WV_(cm)^(2)` where `M` is the total mass of the system and `V_(cm)` is velocity of centre of mass with respect to ground. Due to internal changes `K_(cm)` can change but `V_(cm)` will remain same. Hence only `K_(cm)` portion of kintic energy can be transformed to some other form of energy. Thus `D` is the wrong statement. |
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| 24. |
Three charges q,-q and q0 are placed as shown in figure. The magnitude of the net force on the charge q0 at point O is [k = \(\frac{1}{(4\pi∈_o)}\)](a) 0(b) \(\frac{2kqq_0}{a^2}\) (c) \(\frac{\sqrt2kqq_0}{a^2}\)(d) \(\frac{1}{\sqrt2}\) \(\frac{kqq_0}{a^2}\) |
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Answer» Option : (c) \(\frac{\sqrt2kqq_0}{a^2}\) |
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| 25. |
An uncharged object has A. more protons B. more electrons C. equal electrons and protons D. no protons and electrons |
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Answer» C. equal electrons and protons |
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| 26. |
Where an electric charge experiences a force, there is an A. electric field B. magnetic field C. electric current D. conventional current |
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Answer» A. electric field |
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| 27. |
Fields that act on objects with masses are A. electric fields B. magnetic fields C. force fields D. gravitational fields |
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Answer» D. gravitational fields |
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| 28. |
Electric field strength can be defined as A. E = Q⁄F B. E = W⁄F C. E = F ⁄Q D. E = P ⁄Q |
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Answer» The Correct option is C. E = F ⁄Q |
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| 29. |
At all the points the uniform fields have A. different strength B. same strength C. zero strength D. infinite strength |
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Answer» B. same strength |
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| 30. |
The potential energy of a particle of mass 1 kg in a conservative field is given as `U = (3x^(2)y^(2) + 6x) J`, where x and y are measured in meter. Initially particle is at (1, 1) & at rest, then incorrect statement is :A. `vec(F) = - [(6xy^(2) + 6) hat(i) + 6x^(2)y hat(j)]`B. Magnitude of initial acceleration of particle is `6 sqrt5 s^(2)`.C. Work done to slowly bring the particle to origin is `- 9 J`D. If particle is left free it move in stringht line. |
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Answer» Correct Answer - D Force on the particle will be given as `vec(F) = bar(V) U` `= (delU)/(delx) hat(i) - (del U)/(del y) = - (6 xy^(2) + 6) hat(i) - (6x^(2) y) hat(j)` Now, for acceleration at `( t = 0)` and `x = 1, y = 1` `vec(a) = (vec(F))/(M) = 12 hat(i) - 6 hat(j)` `|vec(a)| = .^(6)sqrt5 m//s^(2)` Particle is at rest at `x = 1, y = 1`, then `P.E. + K.E. = M.E.` `u (1, 1) + K.E. (1, 1) = M.E.` `rArr M.E. = 9 J` `DeltaU + DeltaK = DeltaW` `DeltaW = DeltaU = U (0, 0) - U (1, 1)` `DeltaW = -9 J` |
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| 31. |
Electric field strength on a dust particle having charge equal to 8 × 10- 19 when plates are separated by distance of 2 cm and have a potential difference of 5 kV is A. 2.0 × 10 -13 N B. 3 N C. 5 N D. 20 N |
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Answer» A. 2.0 × 10-13 N |
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| 32. |
A free electron and a free proton are placed between two oppositely charged parallel plates. Both are closer to the positive plate than the negative plate.Which of the following statements is true?I. The force on the proton is greater than the force on the electron. II. The potential energy of the proton is greater than that of the electron. III. The potential energy of the proton and the electron is the same. (i) I only (ii) II only (iii) III and I only (iv)II and I only |
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Answer» Answer is II. The potential energy of the proton is greater than that of the electron. ∵ Fp = Fe ∵ F = qE E = same 'q' = same Now, P∈ = qV(r) (P.∈)p > (P.∈)e |
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| 33. |
Two large oppositely charged insulated plates have a uniform electric field between them as shown. The distance between the plates is increased by a small amount. Which of the following statements is/are correct. Statement-(i) The electric field strength decreases. Statement-(ii) The electro force of attraction betweeen the plates increases. Statements-(iii) The potential difference between the plates increases.A. i onlyB. ii onlyC. iii onlyD. i and iii only |
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Answer» Correct Answer - C Since charge and charge density on plate remains constant, electric field between the plates does not change due to increase in separation of plates. Now charge on one plate and electric field in its surroundings does not change, therefore magnitude of electrostatic force on that plate remains constant. Only the electroastic potential difference between the plates increases as a result of increase in their separation. |
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| 34. |
Are there any intellectual people willing to give me their Whatsapp number so i can ask them doubts about 12th grade physics, chemistry and maths? |
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Answer» Hi Ipshita, You can ask any doubt here on sarthaks, you will get answers from mentors and experts quickly. |
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| 35. |
Form a new word by adding a suitable suffix to the root word “need”. (a) ________ness (b) ________ted. (c) ________y (d) ________ment |
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Answer» Correct answer is (c) needy |
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| 36. |
Form a new word by adding a suitable suffix to the root word “work”. (a) ment__________ (b) ________abolie (c) __________ ize (d) ________ |
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Answer» Correct answer is (b) workaholic |
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| 37. |
The suicide bags of the cells are (a) plastids (b) mitochondria (c) lysosomes (d) ribosomes |
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Answer» (c) Lysosomes are organelles that contain digestive enzymes (acid hydrolases). They digest excess or worn out organelles, food particles, and engulfed viruses or bacteria. The membrane surrounding a lysosome prevents the digestive enzymes inside from destroying the cell. |
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| 38. |
ER remains associated with(a) dictyosomes (b) mitochondria(c) karyotheca (d) chloroplast |
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Answer» (c) karyotheca |
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| 39. |
Vacuole is surrounded by (a) plasmalemma (b) cell wall (c) tonoplast (d) plasmodesmata |
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Answer» (c) tonoplast |
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| 40. |
`"______"` is a couple of layer thick, made of narrow, thin walled and nearly rectangular cells. It cuts dervatives on both sides. The outer cells differentiate into `"_____"` or `"______"` while the inner cells differentiate into `"______"` or `"_______"`. The three together is called `"_______"` Select the right sequence of words to complete the above given paragraph.A. Phellogen, cork, phellem, secondary cortex, phelloderm, peridermB. Phellem, phelloderm, cork, secondary cortex, phellogen, peridermC. Phellogen, cork, periderm, secondary cortex, phellem, phellodermD. Phellem, secondary cortex, periderm, cork, phellogen, phelloderm |
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Answer» Correct Answer - A |
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| 41. |
Find dervatives of the following functions: (i) `y=2x^(3)` , (ii) `y=4/x` , (iii) `y=3e^(x)` , (iv) `y=6 ln x` , (v) `y=5 sin x` |
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Answer» (i) `y=2x^(3)rArr (dy)/(dx)=2[3x^(3-1)]=6x^(2)` (ii) `y=4/x=4x^(-1)rArr (dy)/(dx)=4[(-1)x^(-1-1)]=-4/x^(2)` (iii) `y=3e^(x)rArr (dy)/(dx)=3e^(x)` (iv) `y=6 ln xrArr (dy)/(dx)=6(1/x)=6/x` (v) `y=5 sin xrArr (dy)/(dx)=5 (cos x)=5 cos x` |
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| 42. |
By using above basic addition/ subtraction formulae, prove that (i) `tan (A+B)=(tan A+tan B)/(1-tan A tan B)` , (ii) `tan (A-B)=(tan A-tanB)/(1+tan A tan B)` (iii) `sin2theta=2sintheta costheta` , (iv) `cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1` (v) `tan 2theta=(2 tan theta)/(1-tan^(2) theta)` |
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Answer» (i) `tan (A+B)=(sin (A+B))/(cos (A+B))=(sin A cos B+cos A sin B)/(cos A cos B-sin A sin B)` `=(cos A cos B((sin A)/(cosA)+(sin B)/(cos B)))/(cos A cos B(1-(sin A sin B)/(cos a cos B)))=(tan A +tan B)/(1-tan A tan B)` (ii) `tan (A-B)=(sin (A-B))/(cos(A-B))=(sin A cos B- cos A sin B)/(cos A cos B+ sin A sin B)` `=(cos A cos B[(sinA)/(cos A)-(sin B)/(cos B)])/(cos A cos B[1+(sin A sin B)/(cos A cos B)])=(tan A-tan B)/(1+tan A tan B)` (iii) `sin 2theta=sin (theta+theta)=sin theta+costheta+costheta sin theta=2 sin theta costheta` (iv) `cos2theta=cos(theta+theta)=costheta costheta-sintheta sintheta=cos^(2)theta-sin^(2)theta=1-sin^(2)theta-sin^(2)theta=1-2sin^(2)theta` `=1-2(1-cos^(2)theta)=2 cos^(2)theta-1` (v) `tan2theta=tan(theta+theta)=(tan theta+tan theta)/(1-tan theta tan theta)=(2 tan theta)/(1-tan^(2) theta)` |
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| 43. |
Find the value of :A. `sin 74^(@)`B. `cos 106^(@)`C. `sin 15^(@)`D. `cos 75^(@)` |
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Answer» Correct Answer - D (i) `sin 74^(@)=sin (2xx37^(@))=2 sin 37 cos 37^(@)=2(3/5)(4/5)=24/25` (ii) `cos 106^(@)=cos (2xx53^(@))=cos^(2) 53^(@)-sin^(2) 53^(@)=(3/5)^(2)-(4/5)^(2)=(9-16)/25=7/25` (iii) `sin 15^(@)=sin (45^(@)-30^(@))=sin 45^(@) cos 30^(@)-cos 45^(@) sin 30^(@)=1/sqrt(2)xxsqrt(3)/2-1/sqrt(2)xx1/2=(sqrt(3)-1)/(2sqrt(2))` (iv) `cos 75^(@)=cos(45^(@)+30^(@))=cos 45^(@) cos 30^(@)-sin 45^(@) sin 30^(@)=1/sqrt(2)xxsqrt(3)/2-1/sqrt(2)xx1/2=(sqrt(3)-1)/(2sqrt(2))` |
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| 44. |
Q15. The input to a bridge rectifier is through a step down Transformer of turn ratio \( 10: 1 \), the supply voltage is \( 230 V \) at \( 50 Hz \). the load resistance is \( 12 K \) ohm secondary winding resistance of the transformer is \( 4 ohm \) diode forward resistance is \( 2 ohm \), to calculate the efficiency of bridge rectifier. |
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Answer» please answer this question fast i have my exam tomorrow |
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| 45. |
A particle lies on the bottom of a tank `T` filled with water upto s height of `90 cm`. The medium above the surface of water is of `R.I = 1.2` above which there is mirror `M`. Beyond the mirror `M` the region contains air (`mu =1`). The distance of the image formed by the mirrro after reflection of the rays coming from `P` is ____ cm (w.r.t mirror). . |
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Answer» Correct Answer - 150 cm For refraction at water surface `u = - 90 cm rArr mu_(2) = 1.2` `mu_(1)=4//3 rArr v=(u mu_(2))/(mu_(1))=-81 cm` This image formed at `81 + 69 = 150 cm` below the mirror, after reflection from the mirror will form its new image `150 cm` above it. |
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| 46. |
The velocity time graph of a particle moving along a straight line is shown in the figure. In the time interval from `t=0` to `t=8` second, answer the following three question. The value of `("maximum speed")/("average speed")` for the given time interval is :A. `(8)/(9)`B. `(8)/(3)`C. `(16)/(9)`D. `(16)/(3)` |
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Answer» Correct Answer - C Distance travelled `=(1)/(2)xx4 xx(2+4)(1)/(2)-xx 2 xx(2+4)=6m` magnitude of displacement `=(1)/(2)xx 4xx(2+4)(1)/(2)-xx 2xx(2+4)=6m` average speed `= (18)/(8)` `|"average velocity"| = (6)/(8)` `("maximum speed")/("average speed")=(4)/(18)xx8=(16)/(9)` And `(|"maximum velocity"|)/(|"average velocity"|)=(4)/(6) xx8 =(16)/(3)`. |
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| 47. |
The velocity time graph of a particle moving along a straight line is shown in the figure. In the time interval from `t=0` to `t=8` second, answer the following three question. The distance travelled by the particle is :A. 18 mB. 6 mC. 8 mD. none of these |
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Answer» Correct Answer - A Distance travelled `=(1)/(2)xx4 xx(2+4)(1)/(2)-xx 2 xx(2+4)=6m` magnitude of displacement `=(1)/(2)xx 4xx(2+4)(1)/(2)-xx 2xx(2+4)=6m` average speed `= (18)/(8)` `|"average velocity"| = (6)/(8)` `("maximum speed")/("average speed")=(4)/(18)xx8=(16)/(9)` And `(|"maximum velocity"|)/(|"average velocity"|)=(4)/(6) xx8 =(16)/(3)`. |
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| 48. |
Two resistance are measured in ohm and is given as:- `R_(1)=3Omega+-1% &R_(2)=6Omega+-2%` When they are connected in parallel, the percentage error in equivalent resistance isA. 0.03B. `4.5%`C. `0.67%`D. `1.33%` |
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Answer» Correct Answer - D `(1)/(R_(eq))=(1)/(R_(1))+(1)/(R_(2))rArr(dR_(eq))/(R_(eq)^(2))=(dR_(1))/(R_(1)^(2))+(dR_(2))/(R_(2)^(2))` ltbr. Given `dR_(1)//R_(1)=1//100,dR_(2)//R_(2)=2//100` `(dR_(eq))/(R_(eq))=R_(eq){(dR_(1))/(R_(1)).(1)/(R_(1))+(dR_(2))/(R_(2)).(1)/(R_(2))}` % error `=2{(1)/(3)+(2)/(6)}=4//3%` |
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| 49. |
A unifom cylinder of steel of mass M radius R is placed on frictionless bearings and sct to rotate about its axis with angular velocity `omega_(0)` After the cylinder has reached the specified state of rotation, it is heated from temperature `T_(0)to (T_(0)+DeltaT)` without any mechanical contact. If (DeltaI)/I is the fractional change in moment of inertia of the cylinder and `(Deltaomega)/(omega_(0))` be the fractional change in the angular velocity of the cylinder and alpha be the coefficient of linear expansion, thenA. `(DeltaI)/I=(2DeltaR)/R`B. `(DeltaI)/I=(2Deltaomega)/(omega_(0))`C. `(Deltaomega)/(omega_(0))=-2alphaDeltaT`D. `(DeltaI)/I=-(2DeltaR)/R` |
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Answer» Correct Answer - A::C `I=(MR^(2))/2` &Mis constantRightarrow`IalphaR^(2)` `:.(DeltaI)/I=2((DeltaR)/R)=2alpha(DeltaT)` on heating also no external torque present :.`L=Iw`=constant `:.w alpha1/I` `:.(Deltaw)/w=-(DeltaI)/I=-((DeltaR)/R)=-2alpha(DeltaT)` |
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| 50. |
If an AC voltage 100 V is applied between points A and B, then current of 1 A and phase difference between current and voltage will be `Deltaphi=37^(@)` . IF the same voltage is applied between points B and C, then current of 5 A and `Deltaphi =53^(@)` What will be the impedance `(in Omega)` in the chain, if the same voltage is applied between points A and C? Round off to nearest integer. |
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Answer» Correct Answer - `0119` `tanphi=(wL_(1))/R_(1)=3/4` `wL_(1)=3/4R_(1)` `1=100/sqrt(9/16R_(1)^(2)+R_(1)^(2))` `R_(1)=80Omega omegaL_(1)=60Omega` `(wL_(2))/R_(2)=4/3 Rightarrow wL_(2)=4/3R_(2)` `5=100/sqrt(16/9 R_(2)^(2)+R_(2)^(2)) Rightarrow R_(2)=12 Omega, WL_(2)=16Omega` `z=sqrt((wL_(1)+wL_(2))^(2)+(R_(1)+R_(2))^(2)) =119 Omega` |
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