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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
40° N latitude acts as demarcation line between ________.1. North and South Vietnam2. Egypt and Sudan3. North and South Korea4. USA and Canada |
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Answer» Correct Answer - Option 1 : North and South Vietnam The correct answer is North and South Vietnam.
List of important Boundary lines:
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| 2. |
Where is the headquarters of SAARC(a) New Delhi(b) Islamabad(c) Kathmandu(d) Dhaka |
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Answer» Dhaka is the headquarters of SAARC. |
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| 3. |
Vini Mahajan was the first female chief secretary of the state of ______.1. Gujarat2. Tripura3. Kerala4. Punjab |
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Answer» Correct Answer - Option 4 : Punjab The correct answer is Punjab.
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| 4. |
Which temple complex will be renovated by Indian assistance in Nepal?A. Shiva templeB. Pashupatinath templeC. honuman templeD. Dakshinaawatar Temple |
| Answer» Correct Answer - B | |
| 5. |
The ______ temple in Nepal is also known as the 'Monkey Temple'.1. Pashupatinath2. Buddasubba3. Swayambhunath4. Barashetra |
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Answer» Correct Answer - Option 3 : Swayambhunath The correct answer is Swayambhunath.
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| 6. |
Match List-I with List-II and select the correct answer using the code given below: List- I (Aravalli Peak) List-II (District)(A) Raghunathgarh(i) Sirohi(B) Ser(ii) Sikar(C) Jarga (iii) Jaipur(D) Jaigarh iv) Udaipur1. (A) - (ii), (B) - (i), (C) - (iv), (D) - (iii)2. (A) - (i), (B) - (iii), (C) - (ii), (D) - (iv)3. (A) - (iii), (B) - (ii), (C) - (iv), (D) - (i)4. (A) - (iv), (B) - (iii), (C) - (i), (D) - (ii) |
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Answer» Correct Answer - Option 1 : (A) - (ii), (B) - (i), (C) - (iv), (D) - (iii) The Correct Answer is (A) - (ii), (B) - (i), (C) - (iv), (D) - (iii).
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| 7. |
Which of the following promote curvature of cell membrane?(a) Phosphatidyl choline (PC)(b) Phosphatidyl serine (PS)(c) Phosphatidyl ethanolamine (PE)(d) Phosphatidyl inositol(PI) |
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Answer» Correct option is (c) Phosphatidyl ethanolamine (PE) Easy explanation: PE promotes the curvature of cell membrane. This is important in the budding and fusion of cell membranes during maturation. |
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| 8. |
In animals, the amount of cholesterol present in cell membrane is ___________(a) 20%(b) 15%(c) 50%(d) 33.33% |
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Answer» Correct answer is (d) 33.33% Explanation: Animal cell membrane is made up of 50% protein and 50% Lipids. 60% of all lipids in the membrane are cholesterol molecules. About one third of the cell membrane is made up of cholesterol(1/3rd of 100%= 33.33%). |
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| 9. |
What percentage increase in wavelength leads to `75%` loss of photon energy in a photon-electron collision?A. 200B. 100C. 67D. 300 |
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Answer» Correct Answer - D Energy of a photons =`(hC)/(lambda)=E, E =0.25 E =(hC)/(lambda)` So % change in wavelength `=(4lambda-lambda)/(lambda) xx100% =300%` |
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| 10. |
When an atom or an ion is missing from its normal lattice site, a lattice vacancy (Schottky detect) is created In stoichiometric ionic crystals, a vacancy of one ion has to be accompanied by the vacancy of the oppositely charged ion in order to maintain electrical neutrality. In a Frenkel defect an ion leaves its position in the lattice and occupies an interstitial void.This is the Frenkel defect commonly found along with the Schottky defects and interstitials.In pure alkali halides, Frendel defect are not found since the ions cannot get into the intenstitial sites.Frenkel defects are found in silver halides because of the small size of the `Ag^+` ion.Unlike Schottky defects. Frenkel defects do not change the density of the solids.In certain ionic solids (e.g. AgBr) both Schottky and Frenkel defects occur. The defects discussed above do not disturb the stoichiometry of the crystalline meterial.There is large Such solids showing deviations from the ideal stoichiometric composition form an important group of solids For example in the vanadium oxide, `VO_x`, x can be anywhere between 0.6 and 1.3.There are solids which are difficult to prepare in the stoichiometric composition.Thus, the ideal composition in compounds such as FeO is difficult to obtain (normally we get a composition of `Fe_(0.85) O` but it may range from `Fe_(0.93)` O to `Fe_(0.96)O`).Non-stoichiometric behaviour is most commonly found for transition metal compounds through is also known for some lanthanoids and actinodes. Zinc oxide loses oxygen reversibly at high temperature and turns yellow in colour.The excess metal is accomdated interstitially, giving rise to electrons trapped in the neighbourhood.the enhanced electrical conductivity of the non-stoichiometric ZnO arises from these electrons . Anion vacancies in alkali halides are produced by heating the alkali halide crystals in an atmosphere of the alkali metal vapour.When the metal atoms deposite on the surface they diffuse into the crystal and after ionisation the alkali metal ion occupies cationic vacancy whereas electron occupies anionic vacancy.Electrons trapped in anion vacancies are referred to as F-centres (from Farbe the German word for colour) that gives rise to interesting colour in alkali halides.Thus, the excess of potassium in KCl makes the crystal appear violet and the excess of lithium in LiCl makes it pink. The type of seciconductor shown by crystal capable of showing Schotlky defect, will be.A. p-typeB. n-typeC. bothD. None |
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Answer» Correct Answer - A p-type semiconduction is due to empty spaces or holes which is in Schottky defect n-type semiconduction is due to moving electrons |
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| 11. |
When an atom or an ion is missing from its nomal lattice site a lattice vacanecy (Schottky defect) is created. In stoichmeteric ionic crystals, a vacancy of one ion has to be accompanied by the vacancy of the oppositely charge ion in order to maintain electrical neutrality. In a Frenken defect an ion leaves its position in the lattice and occupies an interstitial void. This id the Frenkel defect commonly found along with the Schottky defects and interstitial. In pure alkali halides. Frenked defects are not found since the ions cannot get into the interstitial sites. Frenkel defects are found in silver halides because of the small size of the `Ag^(+)` ion. Unike Schottky defects, Frenkel defect do not change the density of the solids. in certain ionic solids (e.g., AgBr) both schottky and Frenkel defect occur. The Defects idiscussed above do not disturb the stoichiometery of the crystalline material. there is large variety of non-stoichiometric inorganic solids which contains an excess or deficienty of one of the elements. Such solids showing deviations from the ideal stoichiometric composition from an important group of solids. For example in the vanadium oxide, `VO_(x),x` can be anywehere between 0.6 and 1.3 there are solids such as difficult to prepare in the soichiometric omposition thus, the ideal composition in compounds such as `FeO` is difficult to obtain (normally we get a compositiion of `Fe(0.95)`O but it may range from `Fe_(0.93)`O to `Fe_(0.96)O`). Non-stoichiometric behavious is most commonly found for transition metal compounds through is also known for some lathanoids and actinoids. Zinc oxide loses oxygen reversible at high temperature and turns yellow in colour. the excess metal is accomodated interstitial, giving rise to electrons trapped in the neighbourhood, the enchanced electrical conductivity of the non-stoichiometric ZnO arises from these electrons. Anion vacancies in alkali halides are produced by heating the alkali halid crystals in an atmosphere of the alkali metal vapour. when the metal atoms deposit on the surface they diffuse into the cystal and after ionisation the alkali metal ion occupies cationic vacancy whereas electron occupies anionic vacancy. Electrons trapped i anion vacancies are referred to as F-centers (From Farbe the German word for colouf) that gives rise to interesting colour in alkali halides. Thus, the excess of potassium i KCl makes the crystal appear violet and the excess of lithium in LiCl makes it pink. Which of the following is most appropritate crystal to show Fremkel defect ?A. CsClB. NaClC. AgBrD. `CaCl_2` |
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Answer» Correct Answer - C Because of small size of `Ag^(+)` ion. |
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| 12. |
Statement 1: Though light of a single frequency (monochromatic light) is incident on a metal, the kinetic energies of emitted photoelectrons are not equal. Statement 2: The energy of electrons just after they absorb photons incident on metal surface may be lost in collision with other atoms in the metal before the electron is ejected out of the metal.A. Statement-1 is true, Statement-2: is true, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is true, Statement-2: is true, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is true but statement-2 is falseD. Statement-1 is false, Statement-2 is true |
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Answer» Correct Answer - A Energy of photoelectrons emitted is difference because after absorbing the photon electrons within metals collide with other atom before being ejected out of metal. Hence statement 2 is correct explanation of statement-1. |
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| 13. |
When an atom or an ion is missing from its normal lattice site, a lattice vacancy (Schottky detect) is created In stoichiometric ionic crystals, a vacancy of one ion has to be accompanied by the vacancy of the oppositely charged ion in order to maintain electrical neutrality. In a Frenkel defect an ion leaves its position in the lattice and occupies an interstitial void.This is the Frenkel defect commonly found along with the Schottky defects and interstitials.In pure alkali halides, Frendel defect are not found since the ions cannot get into the intenstitial sites.Frenkel defects are found in silver halides because of the small size of the `Ag^+` ion.Unlike Schottky defects. Frenkel defects do not change the density of the solids.In certain ionic solids (e.g. AgBr) both Schottky and Frenkel defects occur. The defects discussed above do not disturb the stoichiometry of the crystalline meterial.There is large Such solids showing deviations from the ideal stoichiometric composition form an important group of solids For example in the vanadium oxide, `VO_x`, x can be anywhere between 0.6 and 1.3.There are solids which are difficult to prepare in the stoichiometric composition.Thus, the ideal composition in compounds such as FeO is difficult to obtain (normally we get a composition of `Fe_(0.85) O` but it may range from `Fe_(0.93)` O to `Fe_(0.96)O`).Non-stoichiometric behaviour is most commonly found for transition metal compounds through is also known for some lanthanoids and actinodes. Zinc oxide loses oxygen reversibly at high temperature and turns yellow in colour.The excess metal is accomdated interstitially, giving rise to electrons trapped in the neighbourhood.the enhanced electrical conductivity of the non-stoichiometric ZnO arises from these electrons . Anion vacancies in alkali halides are produced by heating the alkali halide crystals in an atmosphere of the alkali metal vapour.When the metal atoms deposite on the surface they diffuse into the crystal and after ionisation the alkali metal ion occupies cationic vacancy whereas electron occupies anionic vacancy.Electrons trapped in anion vacancies are referred to as F-centres (from Farbe the German word for colour) that gives rise to interesting colour in alkali halides.Thus, the excess of potassium in KCl makes the crystal appear violet and the excess of lithium in LiCl makes it pink. In the crystal of `Fe_(0.93)O`, the percentage of Fe (II) will beA. `15%`B. `85%`C. `30%`D. `78%` |
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Answer» Correct Answer - A 3x+(0.93-x)x2=2 x=0.14 % of Fe as Fe(III)=`0.14/0.93xx100=15%` |
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| 14. |
Match List I with List II and select the correct answer using the code given below the lists : `{:("List-I","List-II"),((A)"For ionic solid"r_+/r_(-)=0.51,(p)"Anion-anion contact present, cation lies in octahedral void"),((B)"For ionic solid"r_+/r_(-)=0.414,(q)"Anion-anion contact missing, cation lies in tetrahedral void"),((C )"For ionic solid"r_+/r_(-)=0.4,(r)"Anion-anion contact missing, cation lies in cubical void"),((D)"For ionic solid"r_+/r_(-)=0.9,(s)"Anion-anion contact missing, cation lies in octahedral void"):}` |
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Answer» Correct Answer - A`to`s ; B`to`p ; C`to`q ; D`to` r `0.225 le r_+/r_- lt 0.414 " " "Cation is in tetrahedral void" " " 0.732 le r_+/r_- lt 1` cubical void `0.414 le r_+/r_- lt 0.732` Cation is in octahedral voids |
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| 15. |
Let `m_(p)` be the mass of a poton , `M_(1)` the mass of a `_(10)^(20) Ne` nucleus and `M_(2)` the mass of a `_(20)^(40) Ca` nucleus . ThenA. `M_(2)=2M_(1)`B. `M_(2) gt 2M_(1)`C. `M_(2) ltM_(1)`D. `M_(1) lt 10(m_(n)+m_(p))` |
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Answer» Correct Answer - D Due to mass defect (which is finally responsible for the binding energy of the nucleus). Mass of a nucleus is always less than the sum of masses of its constituent particles. `._(10)^(20)Ne` is made up of 10 protons plus 10 neutrons. Therefore mass of `._(10)^(20) Ne` nucleaus `M_(1) lt 10 (m_(p)+m_(n))` Also, heavier the nucleus, more is the mass defect Thus, `20(m_(n)+m_(p))-M_(2) gt 10 (m_(p)+m_(n))-M_(1)` or `10 (m_(p)+m_(n)) gt M_(2) -M_(1)` or `M_(2) lt M_(1)+10(m_(p)+m_(n))` Since `M_(1) gt 10(m_(p)+m_(n))` `:. M_(2) lt 2M_(1)` |
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| 16. |
Study of pollen grains is known as? |
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Answer» palynology
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| 17. |
Two electrons starting from rest are accelerated by equal potential difference.A. they will have different kinetic energyB. they will have same linear momentumC. they will same linear momentum de broglie wavelengthD. they may produce x-rays of same minimum wavelength when they strike different targets |
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Answer» Correct Answer - D kinetic energy of an electron is given by `k=1/2 mv^(2) =eV =` same for both electron Where V= Speed of electron Linear momentum of two electron may be different, in direction but their magnitude i.e. `mv=sqrt(2mk)` will be same. De-Broglie wavelength is given by `lambda=h/(mv)` =same for both electrons Minimum wavelength of produced x-rays is given by `lambda_("min")=(hc)/(eV)` =same for both electrons |
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| 18. |
What will be the ratio of de - Broglie wavelengths of proton and `alpha` - particle of same energy ?A. 1B. 2C. 4D. `0.25` |
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Answer» Correct Answer - B de-Broglie wave length `lamda = (lamda)/(P)=(lamda)/(sqrt(2km)) rArr (lamda_(P))/(lamda_(alpha)) = sqrt((m_(alpha))/(m_(rho)))=2` |
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| 19. |
Two electrons starting from rest are accelerated by equal potential difference.A. they will not have same kinetic energyB. they will have same linear momentumC. they will not have same de-Broglie wave lengthD. None of these correct |
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Answer» Correct Answer - D Kinetic energy of an electron is given by `k = (1)/(2) mv_(2) = eV` = same for both electron Where V = speed of electron V = potential difference Linear momentum of two electron may be different in direction but their magnitude i.e `mv = sqrt(2 mk)` will be same De-Broglie wavelength is given by `lamda = (h)/(mv)` = same for both electrons Minimum wavelength of produced x-rays is given by `lamda_(min) = (hc)/(eV)` = same for both electrons. |
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| 20. |
Match the reaction of glucose with their products.(Column I) Reaction of Glucose(Column II)Products(A) With HI(i) Gluconic acid(B) With HNO3(ii) Glucose pentaacetate(C) With Br2(iii) n - hexane(D) with Ac2O(iv) Saccharic acid(a) A → (i); B → (iii); C → (ii); D → (iv)(b) A → (iv); B → (iii); C → (i); D → (ii)(c) A → (iii); B→ (ii); C → (iv); D → (i)(d) A → (iii); B → (iv); C → (1); D→ (ii) |
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Answer» (d) A → (iii); B → (iv); C → (1); D→ (ii) With HI ⇒ n - hexane With HNO3 ⇒ Saccharic acid With Br2 ⇒ Gluconic acid With Ac20 ⇒ Glucose pentaacetate |
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| 21. |
Correct decreasing order of energy of the orbitals having following set of quantum numbersA) n = 3, l = 0, m = 0B) n = 4, l = 0, m = 0C) n = 3, l = 1, m = 0D) n = 3, l = 2, m = 1(a) A > C > B > D(b) D > B > C > A(c) A > B > C > D(d) D > C > B > A |
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Answer» (b) D > B > C > A Following the principle of (n+1) rule, the correct order of energy is D > B > C > The subshells with the lowest (n+1) value has the lowest energy. When two or more subshells have the same (n+1) value, then the subshell with the lowest value of n have lowest energy |
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| 22. |
Outermost electronic configuration of 4 elements A, B, C, D A-3s2, B-3s23p1, C-3s23p3, D-3s23p4Correct order of 1st ionisation enthalpy(a) B > A > C > D(b) D > C > B > A(c) C > D > B > A(d) D > C > A > B |
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Answer» (c) C > D > B > A Ionization energy increases along a period But ionisation energy of C-3s23p3 is more than D-3s23p4 as C has half-filled p subshells giving extra stability ∴ Correct order of first ionisation energy is C > D > B > A |
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| 23. |
It _____ a lot _____ our holiday. A) didn’t rain / during B) didn’t / during C) didn’t rained / on D) not rain / in |
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Answer» A) didn’t rain / during |
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| 24. |
I look forward ____ you soon. A) of visitingB) to visiting C) to visit D) visiting |
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Answer» Correct option is B) to visiting |
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| 25. |
He is ____ to understand my instructions. A) very stupid B) stupid enough C) too stupid D) such a stupid |
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Answer» Correct option is C) too stupid |
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| 26. |
A: Did you read this book? B: No, I didn’t. I wish I ____ it. A) read B) can read C) had read D) will read |
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Answer» Correct option is C) had read |
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| 27. |
Select the Suitable Antonyms,1. early (a) soon (b) late (c) beginning2. shady (a) dark (b) dim (c) sunny3. behind (a) beyond (b) ahead (c) around4. alone (a) group (b) separate (c) single5. obviously (a) clearly (b) evidently (c) invisibly |
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Answer» 1. (b) late 2. (c) sunny 3. (b) ahead 4. (a) group 5. (c) invisibly |
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| 28. |
Select the Suitable Synonyms.1. whoop (a) jump (b) run (c) shout2. momentum (a) the force of moving body (b) the rhythm of a body (c) the gravity of a body3. stampede (a) procession (b) rush (c) march4. dislodged (a) freed (b) threw (c) caught5. haughtily (a) proudly (b) hastily (c) arrogantly |
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Answer» 1. (c) shout 2. (a) the force of a moving body 3. (b) rush 4. (a) freed 5. (c) arrogantly |
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| 29. |
Which option adjusts the brightness of the image? a. Exposure b. Color balance c. Placement d. Shading |
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Answer» Correct answer is a. Exposure |
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| 30. |
Select the Suitable Synonyms.1. imposing (a) cheap (b) simple (c) grand2. invariably (a) never (b) always (c) often3. determined (a) decided (b) planned (c) thought4. blur (a) clear (b) unclear(c) obvious5. gradually (a) slowly (b) suddenly (c) abruptly |
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Answer» 1. (c) grand 2. (b) always 3. (a) decided 4. (b) unclear 5. (a) slowly |
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| 31. |
With a _______, objects appear to be carved out of a substance, such as rock or wood. a. 2D texture b. 3D texture c. Environment texture d. Layered texture |
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Answer» Correct answer is b. 3D texture |
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| 32. |
N molecules each of mass m of gas A and 2 N molecules each of mass 2m of gas B are contained in the same vessel which is maintined at a temperature T. The mean square of the velocity of the molecules of B type is denoted by `v^(2)` and the mean square of the x-component of the velocity of a tye is denoted by `omega^(2)`. What is the ratio of `omega^(2)//v^(2) = ?`A. 2B. 1C. `(1//3)`D. `(2//3)` |
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Answer» Correct Answer - 4 `V_(rms)=sqrt((3RT)/(M_(w)))` `V_(rms)=sqrt((3RT)/(mN_(a)))` `V^(2)_(rms) propto (1)/(m)` `(V^(2)_(rmsA))/(V^(2)_(rms B)) = (m_(B))/(m_(A))` `(3W^(2))/(V^(2))=(2m)/(m)` `(W^(2))/(V^(2))=(2)/(3)` |
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| 33. |
A bead C can move freely on a horizontal rod. The bead is connected by blocks B and D by strings as shown in the figure. If the velocity of B is v. Find the velocity of block D. (A) v/3 (B) 4v/3 (C) v (D) 3v/4 |
| Answer» The correct answer is (C) v | |
| 34. |
A rope of mass 5kg is moving vertically in vertical position with an upwards force of 100N acting at the upper end and a downwards force of 70N acting at the lower end. The tension at midpoint of the rope is (A) 100N (B) 85N (C) 75N (D) 105N |
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Answer» (B) The tension at midpoint of the rope is 85N. |
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| 35. |
A particle of mass m is constrained to move on x-axis. A force F acts on the particle. F always points toward the position labeled E. For example, when the particle is to the left of E, F points to the right. The magnitude of F is a constant F except at point E where it is zero. The system is horizontal. F is the net force acting on the particle. The particle is displaced a distance A towards left from the equilibrium position E and released from rest at t = 0. Take point E at x = 0.If the time taken by the particle to return to the initial point is considered to be the time period, what is the period of the motion? |
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Answer» (A) 4(√(2Am/F)) |
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| 36. |
In the given figure find the velocity and acceleration of B, if instantaneous velocity and acceleration of A are as shown in the figure. (A) v = 0.5m/s, a = 1m/s2 (B) v = 1m/s, a = 2m/s2 (C) v = 2m/s, a = 4m/s2 (D) v = 1m/s, a = 1m/s2 |
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Answer» (A) v = 0.5m/s, a = 1m/s2 |
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| 37. |
AB is a light rod and OAB is the light string on the pulley. What is the force applied by the thread on the pulley :(A) mg/2(B) √3mg(C) √2mg(D) mg |
| Answer» The correct answer is (D) mg. | |
| 38. |
Assuming all the surface to be frictionless, acceleration of the block C shown in the figure is :(A) 8m/s2 (B) 5m/s2 (C) 4m/s2 (D) 6m/s2 |
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Answer» (C) Acceleration of the block C is 4m/s2. |
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| 39. |
Two massless rings slide on a smooth circular loop of the wire whose axis lies in a horizontal plane. A smooth massless inextensible string passes through the r ings, which car r ies masses m1 & m2 at the two ends and mass m3 between the rings. If there is equilibrium when the line connnecting each ring with centre substends an angle 300 with vertical as shown in figure. Then the ratio of masses are:(A) m1 = 2m2 = m3 (B) 2m1 = m2 = 2m3 (C) m1 = m2 = m3 (D) None of these |
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Answer» (C) m1 = m2 = m3 |
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| 40. |
A metal sphere is hung by a string fixed on a wall. The forces acting on the sphere are shown in the figure. Which of the following statements are correct : |
| Answer» The correct answer is (ABD) | |
| 41. |
What should be the minimum force P to be applied to the string so that block of mass M just begins to move up the frictionless plane :(A) Mg tanθ/2(B) Mgcotθ/2(C) (Mgcosθ)/(1 + sinθ)(D) none |
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Answer» (A) Mg tanθ/2 |
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| 42. |
A pearl of mass m is in a position to slide over a smooth wire. At the initial instant the pearl is in the middle of the wire. The wire moves linearly in a horizontal plane with an acceleration a in a direction having angle θ with the wire. The acceleration of the pearl with reference to wire is (A) gsinθ - acosθ (B) gsinθ - gcosθ (C) gsinθ - acosθ(D) gcosθ + a sinθ |
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Answer» (A) gsinθ - acosθ |
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| 43. |
A weight can be hung in any of the following four ways by string of same type. In which case is the string most likely to break?(A) A (B) B (C) C (D) D |
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Answer» The correct answer is (C) C Explanation: The correct explanation is that the force exerted i.e.(Wg) in all case but in case 1 , 2 , 4 the force is transferred to whole string as these 3 strings are longer in comparison to c so there will not much effect created in case of 1 , 2 and 4 hence there will chance of string c to get broken as much force is transferred at a time... |
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| 44. |
A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration 'a' directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration 'a'(relative to car) vertically. The tension in the string is equal to.(A) m√(g2 + a2)(B) m√(g2 + a2) - ma(C) m√(g2 + a2) + ma(D) m(g + a) |
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Answer» (C) m√(g2 + a2) + ma |
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| 45. |
A particle of mass m is constrained to move on x-axis. A force F acts on the particle. F always points toward the position labeled E. For example, when the particle is to the left of E, F points to the right. The magnitude of F is a constant F except at point E where it is zero. The system is horizontal. F is the net force acting on the particle. The particle is displaced a distance A towards left from the equilibrium position E and released from rest at t = 0. Take point E at x = 0.Find minimum time it will take to reach from x = - A/2 to 0.(A) 3/2√(mA/F)(√2 - 1)(B) √(mA/F)(√2 -1)(C) 2√(mA/F)(√2 - 1)(D) none |
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Answer» (B) √(mA/F)(√2 -1) |
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| 46. |
A uniform chain of length 2L is hanging in equilibrium position, if end B is given a slightly downward displacement the imbalance causes an acceleration. Here pulley is small and smooth & string is inextensibleThe velocity v of the string when it slips out of the pulley (height of pulley from floor > 2L)(A) √(gL/2)(B) √2gL(C) √gL(D) none of these |
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Answer» (C) The velocity v is √gL |
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| 47. |
In the diagram shown in figure, match the following :(g = 10m/s2)Table-1Table-2(A)Acceleration of 2kg block in m/s2(p)8(B)Net force on 3kg block in N(q)25(C)Normal reaction between 2kg and 1kg in N(r)2(D)Normal reaction between 3kg and 2kg in N(s)45(t)None |
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Answer»
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| 48. |
STATEMENT-1: Block A is moving on horizontal surface towards right under action of force F. All surfaces are smooth. At the instant shown the force exerted by block A on block B is equal to net force on block B. STATEMENT-2: From Newton's third law, the force exerted by block A on B is equal in magnitude to force exerted by block B on A.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, Statement-2 is True. (E) Statement-1 and Statement-2 both are False. |
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Answer» (D) Statement-1 is False, Statement-2 is True. |
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| 49. |
STATEMENT-1: Non zero work has to be done on a moving particle to change its momentum. STATEMENT-2: To change momentum of a particle a non zero net force should act on it.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, Statement-2 is True. (E) Statement-1 and Statement-2 both are False. |
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Answer» (D) Statement-1 is False, Statement-2 is True. |
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| 50. |
STATEMENT-1: A body in equilibrium may not be at rest. STATEMENT-2: When a body is at rest, it must be in equilibrium.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, Statement-2 is True. (E) Statement-1 and Statement-2 both are False. |
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Answer» (C) Statement-1 is True, Statement-2 is False. |
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