This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Avogardo's number(N) is equal to(a) 6.023 x 1024(b) 6.023 x 1023(c) 6.023 x 10-23(d) 11.2 |
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Answer» Answer (b) 6.023 x 1023 |
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| 2. |
Modern periodic table is given by(a) Debonair(b) Mendeleef(c) Mendel(d) none of them |
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Answer» Answer (d) none of them none of them |
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| 3. |
Elements of group-15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is(a) Bi2O5 (b) BiF5 (c) BiCl5 (d) Bi2S5 |
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Answer» The compound is (b) BiF5 |
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| 4. |
Nitrogen is relatively inactive element because(a) its atom has a stable electronic configuration(b) it has low atomic radius(c) its electronegativity is fairly high(d) dissociation energy of its molecule is fairly high |
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Answer» (d) N2 molecule contains triple bond between N atoms having very high dissociation energy (946 kJ mol–1) due to which it is relatively inactive. |
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| 5. |
Which of the following has the highest pπ – pπ bonding tendency ?(a) N (b) P (c) As (d) Sb |
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Answer» (a) Nitrogen due to small size is able to show pπ -pπ lateral overlap forming N = N, rest elements due to bigger size are not able to show pπ -pπ lateral overlap |
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| 6. |
Nitrogen forms N2, but phosphorus is converted into P4 from P, the reason is(a) Triple bond is present between phosphorus atom(b) pπ – pπ bonding is strong(c) pπ – pπ bonding is weak(d) Multiple bond is formed easily |
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Answer» (c) Nitrogen form N2 (i.e. N = N) but phosphorus form P4 , because in P2 , pπ — pπ bonding is present which is a weaker bonding |
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| 7. |
Which of the following statements is not correct for nitrogen?(a) Its electronegativity is very high(b) d-orbitals are available for bonding(c) It is a typical non-metal(d) Its molecular size is small |
| Answer» (b) In case of nitrogen, d-orbitals are not available | |
| 8. |
The three important oxidation states of phosphorus are(a) –3, +3 and +5 (b) –3, +3 and –5(c) –3, +3 and +2 (d) –3, +3 and +4 |
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Answer» (a) –3, +3 and +5 |
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| 9. |
Pick out the wrong statement.(a) Nitrogen has the ability to form pπ -pπ bonds with itself.(b) Bismuth forms metallic bonds in elemental state.(c) Catenation tendency is higher in nitrogen when compared with other elements of the same group.(d) Nitrogen has higher first ionisation enthalpy when compared with other elements of the same group |
| Answer» (c) Catenation tendency is higher in phosphorus when compared with other elements of same group | |
| 10. |
Collectively the elements of group 15 are called –(a) pnicogens (b) pnicopens(c) nicopen (d) None of these |
| Answer» (a) Collectively these elements are called pnicogens and their compound pniconides | |
| 11. |
Which one of the following elements is most metallic ?(a) P (b) As (c) Sb (d) Bi |
| Answer» (d) Metallic character increases down the group, Bi is most metallic | |
| 12. |
Which of the follow group 15 element forms metallic bonds in elemental state ?(a) As (b) P (c) Sb (d) B |
| Answer» (d) Bismuth forms metallic bonds in elemental state | |
| 13. |
Which of the following statement is incorrect for group 15 elements ?(a) Order of ionization enthalpies is ΔiH1 < ΔiH2 < ΔiH3(b) The boiling point and melting point increases from top to bottom in the group(c) Dinitrogen is a gas while all others are solids(d) All statements are correct |
| Answer» (b) The melting point in group 15 increases upto arsenic and then decreases upto bismuth. | |
| 14. |
Maximum covalence of nitrogen is '4' but the heavier elements of group 15 show covalence greater than '4' Why ? |
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Answer» [Hint : Nitrogen is not having vacant d- orbitals in its octet, hence cannot expand its octet, while heavier members have vacant d-orbitals to expand their octet.] |
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| 15. |
How does ammonia solution react with Ag+ (aq) ? Write the balanced chemical equation. |
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Answer» [Hint : Ag+ (aq) + 2NH3 (aq) => [Ag(NH3)2]+ (aq)] |
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| 16. |
Choose the weakest acid among the following :A. `F_(3)"CCOOH"`B. `FCH_(2)COOH`C. `CH_(3)COOH`D. `(CH_(3))_(2)CHCOOH` |
| Answer» Correct Answer - D | |
| 17. |
Among the following which one is most basic in aqueous solution ?A. `NH_(3)`B. `CH_(3)NH_(2)`C. `(CH_(3))_(2)NH`D. `(CH_(3))_(3)N` |
| Answer» Correct Answer - C | |
| 18. |
The airport is A LONG WAY FROM the centre of the city. A) far from B) not far from C) in the distance D) remote E) distant |
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Answer» Correct option is B) not far from |
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| 19. |
His parents were very RELIGIOUS and the boy had to sing at church services. A) devoted B) faithful C) reluctant D) atheistic E) competent |
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Answer» Correct option is D) atheistic |
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| 20. |
Which of the following represent a set of nucleophiles?(a) BF3 , H2O, NH2- (b) AlCl3 , BF3 , NH3 (c) CN- , RCH2- , ROH (d) H+ , RNH3+ , CCl2 |
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Answer» (c) CN- , RCH2- , ROH |
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| 21. |
Consider the following statements:(I) E2 reaction is a bimolecular elimination reaction of second order (II) E2 reaction takes place in two steps. (III) E2 reaction generally Jakes place in primary alkyl halides.Which of the above statements is/are not correct? (a) (I) only (b) (II) only (c) (III) only (d) (I) & (III) |
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Answer» (II) E2 reaction takes place in two steps. |
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| 22. |
Which structure does NOT play a part in the motion of cells?a) microvilli b) cilia c) flagella d) pseudopodia |
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Answer» MICROVILLI does NOT play a part in the motion of cells. |
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| 23. |
Which structure does NOT play a part in the motion of cells?a) microvilli b) cilia c) flagella d) pseudopodia |
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Answer» Which structure does NOT play a part in the motion of cells MICROVILLI |
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| 24. |
Which type of muscle is a syncytium?a) skeletal b) cardiac c) smooth d) all of the above |
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Answer» SKELETAL muscle is a syncytium. |
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| 25. |
When the potential difference across a membrane of a neuron equals the threshold, what results?a) movement of the membrane b) action potential c) relaxation d) contraction |
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Answer» ACTION POTENTIAL |
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| 26. |
Which of the following is NOT a type of neuron?a) sensoryb) motorc) associationd) stimulatory |
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Answer» STIMULATORY. |
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| 27. |
Which of the following are NOT part of a neuron? a) synapse b) axon c) Nissl bodies d) dendrite |
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Answer» SYNAPSE are NOT part of a neuron. |
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| 28. |
From which grandparent or grandparents did you inherit your mitochondria , Is it your:a) mother's parents b) paternal grandfather c) grand mothers d) maternal grandmother |
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Answer» maternal grandmother |
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| 29. |
Environmental pollution affectsA. Biotic componentsB. Plants onlyC. Man onlyD. Biotic and abiotic components of environment |
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Answer» Correct Answer - D (D) Environmental pollution affects biotic and abiotic components of environment. |
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| 30. |
Name the outer portion of a stem or root, bounded externally by the epidermis, and internally by the cells of the pericycle. |
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Answer» Cortex is the outer portion of a stem or root, bounded externally by the epidermis, and internally by the cells of the pericycle. |
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| 31. |
Deforestation is not a major environmental problem in w) the Amazon x) Borneo y) Oregon z) West Germany |
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Answer» WEST GERMANY . |
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| 32. |
In most species of Paramecium there are how many contractile vacuoles? Is it:a) one b) two c) three d) four |
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Answer» In most species of Paramecium there are Tow contractile vacuoles. |
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| 33. |
POPULATION GROWTHA. EmigrationB. MortalityC. NatalityD. All the above |
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Answer» Correct Answer - D (D) Population growth is indicated by emigration, mortality and natality. |
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| 34. |
The major fibrous proteins are:a) peptone and edestin b) glutelin and leucinec) valine and lysine d) myosin and actin |
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Answer» Myosin and Actin. |
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| 35. |
How many statements are correct? (a) Hind II always cut DNA molecules at particular point by recognizing a specific sequence of 6 bases. (b)After the restriction endonuclease action, single stranded portions which are overhanging stretches called sticky ends because they form nucleotide bonds with their complementary cut counter part. (c)The separated bands of DNA are cut out from the agarosegel and extracted from gel piece. This step is known as spooling. (d)Taq polymerase is used between annealing and extension of r-DNA technology.A. 1B. 2C. 0D. 3 |
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Answer» Correct Answer - C (C) (a) Hind-II always cut DNA molecules at particular point by recognising a specific sequence of 6 base pairs. (b) After the restriction endonuclease action, single stranded portions which are overhanging stretches called sticky ends because they form hydrogen bonds with their complementary cut counter part. (c) The separated bands of DNA are cut out from the agarose gel and extracted from gel piece. This step is known as elution. (d) Taq polymerase is used between annealing and extension of PCR. |
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| 36. |
Which of the following is not a major pollutant from automobiles.w) carbon monoxide x) unburned hydrocarbons y) nitrous oxide z) sulfur dioxide |
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Answer» SULFUR DIOXIDE . |
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| 37. |
What are the advantages of using natural gas (or CNG) as a fuel? |
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Answer» CNG Run vehicles have low maintenance cost as compared to other vehicles this significantly less emission of pollutants like carbon dioxide oxides of Nitrogen and Sulphur and other better than petrol and diesel therefore the use of CNG can help in reducing global warming. |
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| 38. |
Which of the following is believed to be responsible for the hole in the ozone layer over Antarctic?w) carbon dioxide x) compounds containing sulfur y) radioactivity z) compounds containing chlorine |
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Answer» COMPOUNDS CONTAINING CHLORINE |
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| 39. |
What are the major products (or fractions) of petroleum refining? Give one use of each petroleum product. |
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Answer» Petroleum refinery is an industrial process plant where crude oil is transformed and refined into more useful products such as petroleum, diesel fuel, asphalt base, heating oil, kerosene, liquefied petroleum gas, jet fuel and fuel oils.etc. It is used in domestic household work such as cooking equipments and fuels |
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| 40. |
The blastula develops into the: a) gastrulab) morula c) endoderm d) zygote |
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Answer» The blastula develops into the GASTRULA . |
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| 41. |
A layer of dead skin cells is found in the:a) subcutaneous tissue b) dermis c) epidermis d) no dead cells are in the skin |
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Answer» A layer of dead skin cells is found in the EPIDERMIS. |
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| 42. |
The nervous system develops from which germ layer?a) ectoderm b) mesoderm c) endoderm d) none of the above |
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Answer» The nervous system develops from ECTODERM germ layer. |
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| 43. |
The primary role of aldosterone is1. Conserve sodium, promote potassium excretion2. Conserve potassium, promote sodium excretion3. Conserve sodium and potassium4. Promote excretion of sodium and Potassium |
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Answer» Correct Answer - Option 1 : Conserve sodium, promote potassium excretion Explanation: Aldosterone
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| 44. |
The Sub Centre is renamed as 1. Health & sciences Centre2. Health Centre3. Health and wellness Centre4. Health sciences treatment and palliative centre |
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Answer» Correct Answer - Option 3 : Health and wellness Centre Explanation: Health and Wellness Centres (HWCs)
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| 45. |
The (∂E/∂T)p of different types of half cells are as follows : (Where E is the electromotive force) Which of the above half cells would be preferred to be used as reference electrode ? (A) A (B) B (C) C (D) D |
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Answer» Correct option is (C) C A cell with less variation in EMF with temperature is preferred as reference electrode because it can be used for wider range of temperature without much derivation from standard value so a cell with less (∂E/∂T)p is preferred. |
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| 46. |
Before birth, the alveoli in a baby’s lungs are expanded and filled with1. Air2. Fluid3. Blood4. Meconium |
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Answer» Correct Answer - Option 2 : Fluid Explanation:
Once the baby takes the first breath, a number of changes occur in the infant's lungs and circulatory system:
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| 47. |
Complete the equations for the following nuclear processes: (a)`._(17)^(35) Cl + ._(1)^(0)n rarr... + ._(2)^(4)He` (b) `._(92)^(235)U + ._(0)^(1) n rarr ...+ ._(54)^(137)Xe + 2 _(0)^(1)n` (c) `._(13)^(27) Al + ._(2)^(4) He rarr ... + ._(0)^(1) n` (d) `...(n,p) ._(16)^(35) S` (e) `._(94)^(239) Pu (alpha, beta^(-))...` |
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Answer» Correct Answer - `{:(a.``._(15)P^(32),,b. ``._(38)Sr^(97),,c. ``._(15)P^(30)),(d.``._(17)Cl^(35),,e. ``._(97)P^(243),,):}` `a.` `._(17)Cl^(35)+``._(0)n^(1)rarr ``._(15)P^(32)+``._(2)He^(4)` `b.` `._(92)U^(235)=``._(0)n^(1)rarr ``._(38)Sr^(97)+``._(54)Xe^(137)+2``._(0)n^(1)` `c.` `._(13)Al^(27)+``._(2)He^(4)rarr``._(15)P^(30)+``._(0)n^(1)` `d.` `._(17)Cl^(35)+``._(0)n^(1) rarr ``._(16)S^(350+``._(1)H^(1)` `e.` `._(94)Pu^(239)+``._(2)He^(4)rarr ``._(97)Bk^(243)+``._(-1)e^(0)` |
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| 48. |
The first line of drugs for the treatment of tuberculosis are:1. Isoniazid, Rifampicin, Pyrazinamide, Ethambutol and streptomycin2. Rifampicin, INH, streptomycin, PAS and Amikacin3. Rifampicin, INH, streptomycin, Kanamycin and Ethambutol4. Rifampicin, INH, Streptomycin, Kanamycin and PAS |
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Answer» Correct Answer - Option 1 : Isoniazid, Rifampicin, Pyrazinamide, Ethambutol and streptomycin Explanation: Treatment for TB Disease
The first-line anti-TB agents that form the core of treatment regimens are:
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| 49. |
Calculate the binding energy per nucleon for `C^(12),N^(14), O^(16)`, and comment on their relative magnitudes. Masses of proton and neutron are `1.0078` and `1.0087m_(u)`, respectively. `(m_(u)=931MeV)` |
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Answer» Correct Answer - `C^(12)=7.68MeV` `N^(14)=7.68MeV` `O^(16)=7.68MeV` Stability is same. `a. C^(12),` proton `=6`, neutron `=6` `Delta_(m)=(6xx1.0078+6xx1.0087)-12` `=(6.0468+6.0522)-12` `=12.099-12=0.099m _(u)` `BE` per nucleus `=(0.099xx931)/(12)MeV=7.68MeV` `b.` `N^(14), proton =7`, neutron `=7` `Delta m=(7xx1.0078+7xx1.0087)-14` `=(7.0546+7.0609)-14` `=14.1155-14=0.1155m_(u)` `BE` per nucleus `=(0.1155xx931)/(14)MeV=7.68m_(u)` `c.` `O^(16),` proton `=8` neutron `=8` `Delta_(m)=(8xx1.0078+8xx1.0087)-16` `=(8.0624+8.0696)-16` `=0.132m_(u)` `BE` per nucleus `=(0.132xx931)/(16)MeV=7.68MeV` |
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| 50. |
Why do radioactive element decay? |
| Answer» The stable nuclei are found to have `n//p` ratio in the range `1` to `1.5` . The nuclei whose `n//p` ratio lies outside this range `i.e.,(lt1)` or `(gt1.5)` lose `alpha-`or `beta-`particles so that their `n//p` ratio shifts into the stability belt. | |