This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Select the mismatchA. Frankia - AlnusB. Rhodospirillum - MycorrhizaC. Anabaena - nitrogen fixerD. Rhizobium - Alfalfa |
| Answer» Rhodospirillum is anaerobic, free living nitrogen fixer. Mycorrhiza is a symbiotic relationship between fungi and roots of higher plants | |
| 2. |
In Bougainvillea, thorns are the modifications ofA. StipulesB. Adventitious rootC. StemD. Leaf |
| Answer» Thorns are hard, pointed straight structures for protection. These are modified stem | |
| 3. |
A temporary endocrine gland in the human body isA. Pineal glandB. Corpus cardiacumC. Corpus luteumD. Corpus allatum |
| Answer» Corpus luteum is the temporary endocrine structure formed in the ovary after ovulation. It is responsible for the release of the hormones like progesterone, oestrogen etc. | |
| 4. |
Most of drugs are antacids EXCEPT: a) Misoprostol b) Maalox c) Mylanta d) Almagel |
|
Answer» a) Misoprostol |
|
| 5. |
The association of histone `H_(1)` with a nucleosome indicatesA. Transcriptionis occurringB. DNA replication is occurringC. The DNA is condensed into a Chromatin FibreD. The DNA double helix is exposed |
|
Answer» The association of H1 protein indicates the complete formation of nucleosome. Therefore the DNA is in condensed form |
|
| 6. |
Which drug is an analog of prostaglandin E1? a) Misoprostole b) De-nol c) Sucralfate d) Omeprazole |
|
Answer» a) Misoprostole |
|
| 7. |
Select the drug stimulating the protective function of the mucous barrier and the stability of the mucous membrane against damaging factors: a) De-nol b) Sucralfate c) Misoprostol d) Omeprazole |
|
Answer» c) Misoprostol |
|
| 8. |
Tick the drug forming a physical barrier to HCL and Pepsin: a) Ranitidine b) Sucralfate c) Omeprazole d) Pirenzepine |
|
Answer» b) Sucralfate |
|
| 9. |
Indicate the drug that cause metabolic alkalosis: a) Sodium bicarbonate b) Cimetidine c) Pepto-Bismol d) Carbenoxolone |
|
Answer» a) Sodium bicarbonate |
|
| 10. |
Cimetidine has no effect on hepatic drug metabolism. It’s a) True b) False |
|
Answer» Cimetidine has no effect on hepatic drug metabolism. It’s False. |
|
| 11. |
The xylem in plants are responsible for(a) transport of water (b) transport of food (c) transport of amino acids (d) transport of oxygen |
| Answer» (a) transport of water | |
| 12. |
How much quantity of the vegetables is recommended by ICMR, New Delhi per capita every day for balance diet? a) 300 g/day b) 120 g/day c) 75 g/day d) 500 g/day |
|
Answer» Correct option: a) 300g/day |
|
| 13. |
Papain, a digestive enzyme is extracted from which of the following crops? a) Rose b) Cabbage c) Papaya d) Rice |
|
Answer» Correct option: c) Papaya |
|
| 14. |
Leaves of a healthy potted plant were coated with vaseline. Will this plant remain healthy for long? Give reasons for your answer. |
|
Answer» The plant will not remain healthy for long and it will die. This plant will not remain healthy for a long time because |
|
| 15. |
(a) oxygen(b) temperature(c) water in guard cells(d) concentration of CO2 in stomata |
| Answer» (c) water in guard cells | |
| 16. |
What are the components of the transport system in human beings? What are the functions of these components? |
|
Answer» The main components of the transport system in human beings are the heart, blood, and blood vessels.
The transport system (called circulatory system) in human beings mainly consists of heart, blood and blood vessels. Functions of component of circulatory system: |
|
| 17. |
Our forefathers did not invent machinery because..........(a) they knew we would become slaves. (b) they knoew we would be happy. (c) they did not like to see us comfortable. (d) they were jealous of us. |
|
Answer» Our forefathers did not invent machinery because they knew we would become slaves. |
|
| 18. |
(a) kidney → ureter → urethra → urinary bladder(b) kidney → urinary bladder → urethra → ureter(c) kidney → ureters → urinary bladder → urethra(d) urinary bladder → kidney → ureter → urethra |
| Answer» (c) kidney → ureters → urinary bladder → urethra | |
| 19. |
(a) The process in plants that links light energy with chemicalenergy(b) Organisms that can prepare their own food(c) The cell organelle where photosynthesis occurs(d) Cells that surround a stomatal pore(e) Organisms that cannot prepare their own food(f) An enzyme secreted from gastric glands in stomach that actson proteins |
|
Answer» (a) Photosynthesis (b) Autotrophs (c) Chloroplast (d) Guard Cells (e) Heterotrophs (f) Pepsin |
|
| 20. |
What are the conditions necessary for fixation of atmospheric nitrogen by Rhizobium. What is their role in N2 -fixation? |
|
Answer» Rhizobium is a symbiotic bacteria present in the root nodules of leguminous plants. |
|
| 21. |
Which of the following is a prime number?(a) 10(b) 7(c) 15(d) 9 |
|
Answer» The correct option is (b) 7 |
|
| 22. |
An Δ ABC AC2 = AB2 +BC2 then ∠ B is(a) 75°(b) 60°(c) 45°(d) 90° |
|
Answer» An Δ ABC AC2 = AB2 +BC2 then ∠ B = 90° |
|
| 23. |
Which is zeros of Quadratic polynomial x2-5x+6(a) (-3,2)(b) (-1,-2)(c) (3,-2)(d) (3,2) |
|
Answer» The correct option is (d) (3,2) |
|
| 24. |
The only good (a) /about these pens (b) /are their colour and there size (c) /no error |
|
Answer» The only good thing/ about these pens(b) / are their colour and their size.(c)/ No error Answer (c) : ‘Is’ in place of ‘are’. The subject ‘the only good thing ‘ is singular and thus the verb will be singular. (c) : ‘Is’ in place of ‘are’. The subject ‘the only good thing ‘ is singular and thus the verb will be singular. |
|
| 25. |
I am sure that (a) neither the house nor its contents (b) is for sale (c) no error |
|
Answer» Part (c) correct Replace 'is' by 'are' |
|
| 26. |
I will wait for you (a) /at the office (b) /till you will finish your work (c)/no error |
|
Answer» Part (c) correct Remove 'will' |
|
| 27. |
Although she works hard.... She fail A) butB) and C) yet D) than |
|
Answer» Although she works hard yet She fail |
|
| 28. |
A flock of lions (a) /roamed about (b) /fearlessly in the jungle (c)no error (d) |
|
Answer» Correct Option: a Replace ‘flock’ by ‘herd’. |
|
| 29. |
Students should not take part (a) /in party politics and political demonstrations (b) /as they interfere in serious study (c) /no error Find the error and discuss |
|
Answer» c) as they interfere in serious study Explanation: Incorrect preposition is used. The preposition after ‘interfere’ here should be ‘with’. So the correct sentence in option (c) will be - 'as they interfere with serious study' |
|
| 30. |
They work hard lest they..... in the examination A) will fail B) failed C) should fail D) fail |
|
Answer» Correct option: (c) should fail lest + should + v1 |
|
| 31. |
You can get (a) /all the informations you want (b) /in this book (c)/no error (d) Find the error and why this answer is the right discuss |
|
Answer» Answer: Option B Explanation: all the information you want |
|
| 32. |
These kind (a) /of shirts (b) /are rather expensive for him to buy (c) /no error (d) |
|
Answer» Part (a) error. These kinds of shirts are rather expensive for him to buy. |
|
| 33. |
What is beats? Give an analytical description of the phenomenon of beats. Show that the beat frequency is equal to the difference of frequencies of the component oscillation. |
Answer»
Let us consider two waves of slightly different frequencies n1 and n2 (n1 ~ n2 < 10) having equal amplitude travelling in a medium in the same direction. At time t = 0, both waves travel in same phase. The equations of the two waves are y1 = a sin ω1t y1 = a sin (2πn1)t …... (1) y2 = a sin ω2t = a sin (2πn2)t …... (2) When the two waves superimpose, the resultant displacement is given by y = y1 + y2 y = a sin (2πn1)t + a sin (2πn2)t …... (3) Therefore y = 2a sin 2π(n1+ n2/2)t cos 2π(n1– n2/2)t …... (4) Substitute A = 2a cos 2π(n1– n2/2)t and n = n1 + n2/2 in equation (4) y = A sin 2πnt This represents a simple harmonic wave of frequency n = n1 + n2/2 and amplitude A which changes with time. (i) The resultant amplitude is maximum (i.e) ± 2a, if cos 2π [n1-n2/2] t = ±1 So, 2π [n1-n2/2] t = ±mπ (Here, m = 0,1,2....) or (n1 – n2)t = m The first maximum is obtained at t1 = 0 The second maximum is obtained at, t2 = 1/n1 – n2 The third maximum at t3 = 2/n1 – n2 and so on. The time interval between two successive maxima is, t2 – t1 = t3 – t2 = 1/n1 – n2 Hence the number of beats produced per second is equal to the reciprocal of the time interval between two successive maxima. |
|
| 34. |
The rice from Dehradoon is (a) /more superior (b) /to that Saharanpur (c) /no error (d) |
|
Answer» /to that Saharanpur |
|
| 35. |
A tank is filled with a transparent liquid to height "H". A coin suspended by a thread in the liquid us gradually lowered till it touches the bottom. The apparent depth is determined corresponding to different positions of the coin. (a) Plot a graph showing variation of the apparent and real depth of the coin. (b) What is the physical significance of the slope of the graph. |
|
Answer» sorry I don't understand that |
|
| 36. |
Give the plural form of the given word .Myself A) ourselvesB) myselfs C)ourselfD) myselves |
| Answer» Ourselves is the right answer | |
| 37. |
Although he has known Suresh (a) /for only two years (b) but he is his best friend. (c)/no error (d) |
|
Answer» (b) but he is his best friend It should be yet, he is his best friend |
|
| 38. |
My cousin brother (a) is coming from Mumbai (b) after a long interval (c) /no error |
|
Answer» Part (a) Remove "brother" Explanation: A cousin is defined as a son or a daughter, of a brother or a sister, of the father or the mother. No person can be your cousin and brother at the same time or, for that matter, your cousin and sister either. To elaborate, one may talk about a male cousin or a female cousin, when needed. |
|
| 39. |
In Column I, a family of concurrent lines is given and their points of concurrence are given in Column II. Match the items of Column I with those of Column I with those of Column II.(A) If a, b, c are real as 2a + 3b + c = 0, then the lines ax + by + c = 0 are concurrent(P) (2/5,3/5)(B) If a is a parameter, then the family of lines (1 + a)x + (2 - a) y + 5 = 0 is concurrent at(q) (2, 3)(C) The lines (a d)x + ay + (a + d) = 0 for different values of d are concurrent at(r) (1, 2)(D) For different values m and n, the lines (m + 2n)x + (m - 3n)y m + n = 0 are concurrent at(s) (-5/3,-5/3)(t) ()1,-2 |
|
Answer» (A) 2a + 3b + c = 0 ⇒ ax + by + c = 0 passes through (2, 3). Answer: (A) → (q) (B) The equation (1 + a)x + (2 - a)y + 5 = 0 is written as (x + 2y + 5) + a(x - y) = 0, Hence, the line passes through the intersection of the lines x + 2y + 5 = 0 and x - y = 0 and the point of intersection is (-5/3,-5/3) Answer: (B) → (s) (C) The equation (a - d)x + ay + (a + d) = 0 is written as a(x + y + 1) + d (1 - x) = 0 so that this line passes through the intersection of the lines 1 - x = 0 and x + y + 1 = 0 which is given by (1, -2). Answer: (C) → (t) (D) The equation (m + 2n)x + (m - 3n)y - m + n = 0 is written as m(x + y -1 = 0) . Hence, the line passes through the intersection of the lines x + y - 1 = 0 and 2x - 3y + 1 = 0 which is given by (2/5, 3/5). Answer: (C) → (p) |
|
| 40. |
I have done my best (a) /the whole thing is now (b) /in the laps of the Gods (c) /no error (d)Find the error.Give the right answer and why this answer is right discuss |
|
Answer» (c) Replace ‘laps’ by ‘lap’. |
|
| 41. |
The maximum value of x1/2, x > 0 is(A) 1/ee(B) (1/e)c(C) 1(D) None of these |
|
Answer» correct option: (A) 1/ee |
|
| 42. |
The interval in which f(x) = (x + 1)3 (x – 3)3 is increasing(A) [1, ∞] (B) [1, ∞] (C) [–1, ∞] (D) [–∞, 1] |
|
Answer» correct option: (A) [1, ∞] |
|
| 43. |
The heights of two towers are 210 metres and 70 metres respectively. If the angle of elevation of the top of the first twoere form the bottom of the second tower be `60^@` , then find the angle of elevation of the top of the scecond tower from the bottom of the first tower. |
| Answer» Correct Answer - `30^@` | |
| 44. |
Write a biography on Sandhya Mukhopadhyay |
|
Answer» Mukherjee was born in Dhakuria, Calcutta, on 4 October 1931 to Narendranath Mukherjee, a railway official, and Hemprova Devi. She was the youngest of six children. Her grandfather was a police officer, and the family had lived in Dhakuria since 1911. Sandhya started her music training under the direction of Pandit Santosh Kumar Basu, Professor A T Kannan, and Professor Chinmoy Lahiri. However, her guru was Ustad Bade Ghulam Ali Khan followed by his son Ustad Munavvar Ali Khan, under whom she mastered Indian classical music. According to Manorma Sharma, "Sandhya has been able to maintain her popularity as a classical vocalist even after acquiring the gloss and the glow of playback singing. Though classically trained, the bulk of her work consists of Bengali modern songs. She began her career in Mumbai singing Hindi songs, starting with a song in the film Taarana in 1950. She sang, as a playback singer, in 17 Hindi films. She decided to come back to and settle in her home city Kolkata in 1952 due to personal reasons. She married Bengali poet Shymal Gupta in 1966. Gupta went on to write the lyrics for many of her songs. She received Banga Bhushan the highest civilian honor in the Indian state of West Bengal in 2011. She also won the National film award for best playback singer for her songs in the films Jay Jayanti and Nishi Padma in the year 1970. Her best-known collaboration is arguable with the Bengali singer Hemanta Mukherjee with whom she sang numerous duets, primarily as playback for Bengali films. Hemanta and Sandhya became known as the voices behind the pairings of the Bengali superstar Uttam Kumar and his numerous heroines, most notably being the actress Suchitra Sen, whose singing voice she became. Besides Hemanta's Mukherjee compositions, her largest body of work is with Robin Chattopadhyay and Nachiketa Ghosh. During the Bangladesh Liberation War, she joined the mass movement among Indian Bengali artists to raise money for the millions of refugees who had poured into Kolkata and West Bengal to escape the fighting, and to raise global awareness for the cause of Bangladesh. She assisted Bangladeshi musician Samar as he set up the Swadhin Bangla Betar Kendra, the clandestine radio station broadcasting to Bangladesh, and recorded several patriotic songs for him. On the occasion of the release of Sheikh Mujib Rahman the imprisoned leader of the new country of Bangladesh, she released a song Bangabandhu Tumi Phirey Ele. She later became one of the first foreign artists to visit Dhaka, performing at an open-air concert in Paltan Maidan in Dhaka to celebrate the first Ekushey February after Bangladeshi independence in 1971. On 26 January 2022, on Republic day and a few days before testing positive for Covid 19, Mukherjee was awarded the Padma Shri for her performance in music. However, she refused the award, labeling it "disparaging and degrading". Mukherjee died of cardiac arrest at a private hospital in Kolkata on 15 February 2022, at the age of 90. what is your name |
|
| 45. |
The decimal representation of `(11)/(2^(3) xx 5)` willA. terminate after 1 decimal placeB. terminate after 2 decimal placesC. terminate after 3 decimal placesD. not terminate |
|
Answer» Correct Answer - c 3 decimal places |
|
| 46. |
The LCM of smallest two digit composite number and smallest composite number isA. 12B. 4C. 20D. 44 |
|
Answer» Correct Answer - c Correct Answer - 20 |
|
| 47. |
Find dy/dx if y=e²×sinx |
|
Answer» we should find \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x \) \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x=\mathrm{e}^2 \frac{\mathrm{d}}{\mathrm{d}x} \sin x=\mathrm{e}^2 \cos x \) |
|
| 48. |
Find dy/dx if y=e²×sinx |
|
Answer» we should find \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x \) \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x=\mathrm{e}^2 \frac{\mathrm{d}}{\mathrm{d}x} \sin x=\mathrm{e}^2 \cos x \) y = e2x sin x \(\frac{dy}{dx}\) = e2x d/dx sin x + (d/dx e2x) sin x (By UV formula) = e2x cos x + 2 e2x sin x (By chain rule) = e2x(cos x+2 sin x) |
|
| 49. |
Show that rn vector r is an irrotational Vector for any value of n but is solenoidal only if n = −3. |
|
Answer» Let \(\hat{F} = r^n \,\hat{r}\) \(= r^n (x\hat{i} + y\hat{j} + z\hat{k})\) \(=x r^n \hat{i} + y r^n\hat{j} + z r^n\hat{k}\) \(\vec{\Delta} \times \vec{F}\) \(= \begin{vmatrix} \hat{i} & \hat{j} & \hat{k}\\ \frac{\delta}{\delta x} & \frac{\delta}{\delta y} & \frac{\delta}{\delta z}\\ xr^n & yr^n & zr^n \end{vmatrix}\) \(= \hat{i}(nz\,r^{n-1} \frac{\delta r}{\delta y} - ny\,r^{n-1}\frac{\delta r}{\delta z})\) \(+ \hat{j}(nx\,r^{n-1} \frac{\delta r}{\delta z} - nz\,r^{n-1}\frac{\delta r}{\delta x})\) \(+ \hat{k}(ny\,r^{n-1} \frac{\delta r}{\delta x} - nx\,r^{n-1}\frac{\delta r}{\delta y})\) \(= \hat{i}(nyz\,r^{n - 2} - nyz\,r^{n - 2})\) \( + \hat{j}(nxz\,r^{n - 2} - nxz\,r^{n - 2})\) \( + \hat{k}(nxy\,r^{n - 2} - nxy\,r^{n - 2})\) \((\because r^2 = x^2 + y^2 + z^2\) \(\Rightarrow \frac{\delta r}{\delta x} = \frac{x}{r},\) \(\frac{\delta r}{\delta y} = \frac{y}{r}\) \(\&\) \(\frac{\delta r}{\delta z} = \frac{z}{r})\) \(= 0\hat{i} + 0\hat{j} + 0\hat{k}\) \(= \hat{0}\) \(\therefore \) For all values of n, vector F is irrational. Now \(\hat{\Delta}.\hat{F}\) \(= \left(\frac{\delta}{\delta x}\hat{i} + \frac{\delta}{\delta y}\hat{j} + \frac{\delta}{\delta z}\hat{k}\right)\) \(.\left(xr^n\hat{i} + yr^n\hat{j} + zr^n\hat{k}\right)\) \(= \frac{\delta}{\delta x}xr^n + \frac{\delta}{\delta y}yr^n + \frac{\delta}{\delta z}zr^n\) \(= (nx\,r^{n-1} \frac{\delta r}{\delta x} + r^n)\) \(+ (ny\,r^{n-1}\frac{\delta r}{\delta y} + r^n)\) \(+ (nz\,r^{n-1}\frac{\delta r}{\delta z} + r^n)\) \(= 3r^n + (nx^2 r^{n - 2} + ny^2 r^{n - 2}\) \(+ nz^2 r^{n - 2})\) \((\because \frac{\delta r}{\delta x} = \frac{x}{r}, \frac{\delta r}{\delta y} = \frac{y}{r}\) \(\&\) \(\frac{\delta r}{\delta z} = \frac{z}{r})\) \(= 3r^n +nr^{n - 2}(x^2 + y^2 + z^2)\) \(= 3r^n +nr^{n}\) \((\because x^2 + y^2 + z^2 = r^2)\) \(= (3 + n)r^n\) \(\therefore \vec{\Delta}.\vec{F} = 0\) when n = -3. \(\therefore \vec{F} = r^n\vec{r}\) is solenoidal only if n = -3. |
|
| 50. |
If A = \(\begin{bmatrix}1 &-1 & 0 \\[0.3em]2 & 3 & 4 \\[0.3em]0 &1 & 2\end{bmatrix}\) and B = \(\begin{bmatrix}2 &2 & -4 \\[0.3em]-4 & 2 & -4 \\[0.3em]2 &-1 & 5\end{bmatrix}\), then :If A = [(1,-1,0)(2,3,4)(0,1,2)] and B = [(2,2,-4)(-4,2,-4)(2,-1,5)], then :(a) A-1 = B(b) A-1 = 6B(c) B-1 = B(d) B-1 = \(\frac{1}{6}\)A |
|
Answer» Option : (d) \(AB=\begin{bmatrix}1&-1&0\\2&3&4\\0&1&2\end{bmatrix}\begin{bmatrix}2&2&-4\\-4&2&-4\\2&-1&5\end{bmatrix}=\begin{bmatrix}6&0&0\\0&6&0\\0&0&6\end{bmatrix},\) \(\Rightarrow AB=6I\Rightarrow B^{-1}=\frac{1}{6}A\) |
|