This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the smallest prime number |
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Answer» 2 is the smallest prime number. |
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| 2. |
The sides of two similar triangles are in the ratio `2: 3`, then the areas of these triangles are in the ratio ________. |
| Answer» Correct Answer - `4 : 9` | |
| 3. |
`Delta PQR` is right angled isosceles triangle, right angled at R. Find value of `sin` P. |
| Answer» `Sin P = 1//sqrt2` | |
| 4. |
If 12P5 + 5. 12P4 = 13Pr , find r. |
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Answer» We have (n–1)Pr + r. (n–1)P(r–1) = nPr and r ≤ n 12P5 + 5.12P4 = 13P5 = 13Pr (given) ⇒ r = 5 |
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| 5. |
The number of real roots of `x^(8) - x^(5) + x^(2) - x + 1 = 0` is |
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Answer» Correct Answer - `0` `(1)` when `x lt 0 rArr` expression `gt 0` `(2)` when `x = 0 rArr` expression `= 1 gt 0` `(3)` when `0 lt x lt x^(8) + x^(2) (1 - x^(3)) + (1 - x) gt 0` `(4) x = 1, 1-1 + 1 - 1 + 1 gt 0` `(5) x gt 1, x^(5)(x^(3) - 1) + x( x - 1) + 1 gt 0` so `x^(8) - x^(5) + x^(2) - x + 1 gt 0, cancelAAx in R` so on real roots |
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| 6. |
If `x^(2) - 3x + 2` is factor of `x^(4) - px^(2) + q` then `2q - p` is equal to |
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Answer» Correct Answer - `3` `x^(2) - 3x + 2 = 0` `(x - 2)(x - 1) = 0 rArr x = 1 , 2` so `1 - p + q = 0 rArr p = +5` `16 - 4p + q = 0` `2q - p = 8 -5 = 3` |
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| 7. |
Let `a,bepsilonR^+` for which `60^a=3` and `60^b=5` then `12^((1-a-b)/(2(1-b)))` is equal to |
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Answer» Correct Answer - `2` `60^(a) = 3 rArr a = log_(60)3` `60^(b) = 5 rArr b = b = log_(60)5` `(1 - a - b)/(2(1 - b)) = (1 - log_(60) 3 - log_(60) 5)/(2(1 - log_(60)5)) = log_(60)((60)/(3 xx 5))/(2log_(60)((60)/(5)))` `(log_(60)(4))/(2log_(60)(12)) = (log_(60)2)/(log_(60)12) = log_(12)2` `:. (12)^(log_(12)2 = 2` |
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| 8. |
Polynomial `P(x)` contains only terms of aodd degree. when `P(x)` is divided by `(x - 3)`, the ramainder is `6`. If `P(x)` is divided by `(x^(2) - 9)` then remainder is `g(x)`. Then find the value of `g(2)`. |
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Answer» Correct Answer - `4` As `P(x)` has only add degree terms `:. P(-x) = -P(x)` `rArr P(-3) = -P(3) = -6` Let `P(x) = Q(x^(2) - 9) + g(x)` where `Q` is quetient and `g(x)` is remainder `g(x) = ax + b` `P(x) = Q(x^(2)- 9) + ax + b` `x = 3, P(3) = 3a + b = 6 ….(i)` `x = -3, P(-3) = -3a + b = -6 ....(ii)` `b = 0` and `a = 2` `:. g(x) = 2x` `:. g(2) = 4` |
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| 9. |
If `a,b,c in R - {0}` and `a^(2) = bc` and `a + b +c = abc` then the least possible value of `a^(2)` is |
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Answer» Correct Answer - `3` Given `bc = a^(2) …(i)` `b + c = abc - a` `b + c = a^(3) - a…..(ii)` `:.` equation `x^(2) - (b + c)x + bc = 0overset(b)underset(c)(lt)` `x^(2) - (a^(3) - a) x + a^(2) = 0` has two roots `b` and `c`. `b` and `c` are equal so `D ge 0` `(a^(3) - a)^(2) - 4a^(2) ge 0` `a^(2)(a^(4) -2a^(2) - 3) ge 0` `a^(2)(a^(2) - 3)(a^(2) + 1) ge 0` `a^(2) - 3 ge 0` `:. a^(2) ge 3` `:. (a^(2))_(min) = 3` |
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| 10. |
Range of \(\cfrac{x^2}{x^4+1}\). |
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Answer» f(x) = \(\cfrac{x^2}{x^4+1}\) = \(\cfrac{1}{x^2+\cfrac1{x^2}}\) = \(\cfrac{1}{\left(x+\cfrac1{x}\right)^2-2}\) \(\because\) \({\left(x+\cfrac1{x}\right)^2}\) \(\geq\) 22 or \({\left(x+\cfrac1{x}\right)^2}\) \(\geq\) 4 = \({\left(x+\cfrac1{x}\right)^2}\) - 2 \(\geq\) 4 - 2 = \({\left(x+\cfrac1{x}\right)^2}\) - 2 \(\geq\) 2 = \(\cfrac{1}{\left(x+\cfrac{1}{x}\right)^2-2}\) \(\leq\) \(\cfrac12\) = \(\cfrac{x^2}{x^4+1}\) \(\leq\) \(\cfrac12\)....(i) Also, x2 \(\geq\) 0 and x4 + 1 \(\geq\) 1 = \(\cfrac{x^2}{x^4+1}\) \(\geq\) 0 ...(ii) (\(\because\) Division of two positive numbers be always positive) Then from (i) and (ii),we obtain 0 \(\leq\) \(\cfrac{x^2}{x^4+1}\) \(\leq\) \(\cfrac12\) \(\therefore\) Range of f(x) = \(\cfrac{x^2}{x^4+1}\) is [0,\(\cfrac12\)]. |
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| 11. |
In a ` A B C`if `b+c=3a ,t h e ncotB/2dotcotC/2`has the value equalto:``4b. 3 c. 2d. 1A. `4`B. `3`C. `2`D. `1` |
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Answer» Correct Answer - C In `a Delta ABC if b + c = 3a` ………… `cot.(B)/(2).cot.(C )/(2)=(s(s-b))/(Delta)(s(s-c))/(Delta)((s-a))/(s-a) = (s)/(s-a)` `= (2s)/(2s-2a)` but `a+b+c = 4a implies 2s = 4a` Hence `cot. (B)/(2). cot. (C )/(2)` `= (4a)/(2a) = 2I` |
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| 12. |
Show that the square to `(sqrt(26-15))//(5sqrt(2)-sqrt(38-5sqrt(3)))`is a rational number. |
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Answer» Correct Answer - `3` `5sqrt(2) - sqrt(38 + 5sqrt(3)) = 5sqrt(2) - (1)/(sqrt(2)) sqrt(76 + 2 sqrt(75))` `= 5sqrt(2) - (1)/(sqrt(2)) -(sqrt(75) + 1) = (sqrt(3)(3sqrt(3) - 5))/(sqrt(2))` `:. (sqrt(26 - 15sqrt(3)))/(5sqrt(2) - sqrt(38 + 5 sqrt(3))) = (sqrt(52 - 30sqrt(3)))/(sqrt(3)(3sqrt(3) - 5))` `= (3sqrt(3) - 6)/(sqrt(3)(3sqrt(3)-5)) = (1)/(sqrt(3))` so `p = 1 q = 3` |
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| 13. |
In the expansion of `(x+x^(2)+x^(3)+…….) (1+x+x^(2)+x^(3)) (x^(2)+x^(3)+x^(4)+……+x^(10))` the coefficient of `x^(6)` isA. `10`B. `18`C. `30`D. `12` |
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Answer» Correct Answer - A In the expansion ……….. `(x+x^(2)+…….)………` Coefficient of `x^(6)` in the expansion `(x+x^(2)+…..)` `(1+x+x^(2)+x^(3))(x^(2)+…….+x^(10))` = Coefficient of `x^(6)` in the expension `x^(3)(1+x+x^(2)+……) (1+x+x^(2)+x^(3))(1+x+x^(2)+....+x^(8))` = Coefficient of `x^(3)` in the expansion `(1-x^(4))(1-x^(9))(1-x)^(-3)` = Coefficient of `x^(3)` in the expansion `(1-x)^(-3) = ^(5)C_(3) = 10` |
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| 14. |
A={a,b,c} B={1,2,3,4}. Then number of elements in set C= {f:A-->B 2€f(A) and f is not one one} |
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Answer» C = {f : A → B 2 ∈ f(A) and f is not one-one} Case-I : If f(x) = 2 ∀ x∈ A, then number of function = 1 Case-II : If f(x) = 2 for exactly two elements then total number of many-one function = 3C23C1 = 9 Case -III : If f(x) = 2 for exactly one element then total number of many-one function = 3C13C1 = 9 Total = 19 |
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| 15. |
\( y=\sqrt{4 x-x^{3}} \) |
| Answer» What we have to find, range, domain or what? | |
| 16. |
If three vertices of a parallelogram taken in order are `(-1, 0), (3, 2) and (2, 3)` then area of the parallelogram isA. `12`B. `(21)/(2)`C. `6`D. `3` |
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Answer» Correct Answer - C If the vertices of ……….. `A(-1, 0), (B(3, 2), C(2, 3), then D is (-2, 1)` `:.` area (parallelogram ABCD) = 6 |
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| 17. |
If `m` is the slope of the straight line through the point `(1, 2)`, whose distance from the point `(13, 1)` has the greatest value, then `(2)/(3) m` is equal toA. `2`B. `4`C. `8`D. `12` |
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Answer» Correct Answer - C If `m` is the stope………… Stope of the joining `(1, 2)` and `(13, 1)` is `(1)/(12)` `:.` slope of the equired line is `12` `:. (2)/(3) m = 8` |
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| 18. |
If `x = 13 + 2sqrt(42)`, then `sqrt(x) + (1)/(sqrt(x))` is equal to `asqrt(b)` then find the value of `b - a` ? |
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Answer» Correct Answer - `5` Given `x = 13 + 2sqrt(42)` `x = 7 + 6 + 2sqrt(6 xx 7)` `x = (sqrt(7) + sqrt(6))^(2)` `:. sqrt(x) = sqrt(7) + sqrt(6)` `(1)/(sqrt(x)) = (1)/(sqrt(7) + sqrt(6)) xx (sqrt(7) - sqrt(6))/(sqrt(7) - sqrt(6)) = (sqrt(7) - sqrt(6))/(7 - 6)` `(1)/(sqrt(x)) = sqrt(7) - sqrt(6)` `:. sqrt(x) + (1)/(sqrt(x)) = 2sqrt(7) = asqrt(b)` `b = 7, a = 2` `rArr b - a = 5` |
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| 19. |
Both the roots of the equation `(x-b)(x-c)+(x-a)(x-c)+(x-a)(x-b)=0`are alwaysa. positive b. realc. negative d. noneof theseA. positiveB. negativeC. realD. real and equal |
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Answer» Correct Answer - C `(x-b)(x-c) + (x-a)(x-c) + (x-a)(x-b) = 0` `rArr 3x^(2) - 2 (a + b + c)x + (ab + bc + ca) = 0` Now `D = 4 (a + b+ c)^(2) - 12(ab + bc + ca)` `= 4(a^(2) + b^(2) + c^(2) - ab - bc - ca)` `= 2[(a - b)^(2) + (b - c)^(2) + (c - a)^(2)]` which is always positive or zero so roots are real |
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| 20. |
If `alpha,beta`are the roots of the equation `x^2-2x+3=0`obtain the equation whose roots are `alpha^3-3alpha^2+5alpha-2`and `beta^3-beta^2+beta=5`A. `x^(2) + 3x + 2 = 0`B. `x^(2) - 3x + 2 = 0`C. `x^(2) - 3x - 2 = 0`D. none of these |
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Answer» Correct Answer - B Given `x^(2) - 2x + 3 = 0overset(alpha)underset(beta)(lt)` `alpha + beta = 2` and `alphabeta = 3` `:. alpha^(2) - 2alpha + 3 = 0 rArr alpha^(2) = 2alpha - 3` `alpha^(3) = 2alpha^(2) - 3alpha` Similarly `beta^(3) = 2beta^(2) - 3beta` Now `P = alpha^(3) - 3alpha^(2) + 5alpha - 2` `=2alpha^(2) - 3alpha - 3alpha^(2) + 5alpha - 2 = -alpha^(2) + 2alpha - 2` `= 3 - 2 = 1` `:. Q = beta^(2) - beta^(2) + beta + 5` `= (2beta^(2) - 3beta) - beta^(2) + beta + 5 = beta^(2) - beta + 5` `= -3 + 5 = 2` `:.` Sum of roots `= P + Q = 1 + 2 = 3` `:.` Product `PQ = 2` `:.` Required equation `x^(2) - 3x + 2 = 0`. |
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| 21. |
If `x=2` is a real root of cubic equation f (x) = `3x^(3)+bx^(2)+bx+3=0`. Then the value of lim_(xrarr(1)/(2)) (e^(f(x)-1)/(2x-1))`A. `(27)/(4)`B. `-(27)/(4)`C. `-(27)/(8)`D. `(27)/(8)` |
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Answer» Correct Answer - C `3x^(3)+bx^(2)+bx+3=3(x^(3)+1)+bx(x+1)=0` has roots `- 1,2,(1)/(2)` so, `underset(xrarr(1)/(2))(lim)((3x^(3)+bx^(2)+bx+3)/(2x-1))=(3(x-1)(x-2)(x-(1)/(2)))/(2(x-(1)/(2)))` `(3)/(2).(3)/(2).(-3)/(2)=-(27)/(8)` |
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| 22. |
The number of common tangent(s) to the circles `x^2+y^2+2x+8y-23=0`and `x^2+y^2-4x-10 y-19=0`is1 (b) 2(c) 3 (d)4A. `1`B. `2`C. `3`D. `4` |
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Answer» Correct Answer - C the number ber of ………… `x^(2)+y^(2)+2x+8y-23= 0` ………..(1) `x^(2)+y^(2)-4x-10y+19 = 0` ………..(2) `c_(1) -= (-1, -4)` , `r_(1) = sqrt(1+16+23) = 2sqrt(10)` `c_(2)-= (2, 5)` , `r_(2)= sqrt(4+25-19) = sqrt(10)` Here `c_(1)c_(2) = sqrt(9+81), r_(1)+r_(2)= 3sqrt(10)` Hence circles touch each other externally So there are 3 common tangent |
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| 23. |
`F(x)=x^(5)+log,(x+sqrt(1+x^(2)))`, Then for all `alpha, beta in R` such that `alpha+beta gt 0`A. `F(alpha)+F(beta)lt0`B. `F(alpha)+F(beta)gt0`C. `F(alpha+7)+F(beta)lt0`D. `F(alpha)+F(beta+1)=0` |
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Answer» Correct Answer - B `F(x)` is an odd function so ` F(alpha)+F(-alpha)=0` `F(x)` is uarr function so is `alpha+beta gt implies alpha gt -beta implies F(alpha)+F(beta)gt0` |
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| 24. |
The digits, from `0 to 9` are written on `10` slips of paper (one digit on each slip) and placed in a box. If three of the slips are drawn and arranged, then the number of possible different arrangements isA. `1000`B. `720`C. `810`D. None of these |
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Answer» Correct Answer - B The digits, from 0 to 9 …….. `.^(10)P_(3) = 720` |
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| 25. |
If equation `(cos^(-1)x)^(4)-8(cos^(-1)x)^(3) + a (cos^(-1)x)^(2)+b (cos^(-1)x)+16=0` has four positive real roots, where a, b epsilon R then `[x]` = (Where [.] G.I.F.)A. `1`B. `0`C. `-1`D. `2` |
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Answer» Correct Answer - C All th roots of given equation are equal therefore `cos^(-1) x=2` `therefore x = cos 2` `[x]=[cos 2] =-1` |
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| 26. |
If `(a+(1)/(a))^(2)= 3`, then `a^(3)+(1)/(a^(3))` equalsA. `6 sqrt(3)`B. `3 sqrt(3)`C. `0`D. `7 sqrt(7)` |
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Answer» Correct Answer - C If `(a+(1)/(a))^(2) = 3` ………… `a^(3)+(1)/(a^(3)) = (a+(1)/(a)) ((a+(1)/(a))^(2)-3)` `= (a+(1)/(a)) (3-3) = 0` |
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| 27. |
If `alpha, beta` are roots of `x^(2)-2x-1=0`, then value of `5alpha^(4)+12beta^(3)` isA. 153B. 169C. 183D. None of these |
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Answer» Correct Answer - C `2x^(3)y dy+(1-y^(2))(x^(2)y^(2)+y^(2)-1)dx=0` `implies ((2y)/(1-y^(2)))(dy)/(dx)+(x^(2)y^(2)+y^(2)-1)/(x^(3))=0` `implies ((2y)/(1-y^(2)))(dy)/(dx)+(y^(2))/(x)=(1-y^(2))/(x^(3))` `implies (2y)/((1-y^(2))^(2))(dy)/(dx)+(1)/(x)((y^(2))/(1-y^(2)))=(1)/(x^(3))` `(dt)/(dx)+(1)/(x)t=(1)/(x^(3))("where " t = (y^(2))/(1-y^(2)))` `x(dt)/(dx)+t=(1)/(x^(2))implies (d)/(dx)(tx)=(1)/(x^(2))` `tx=-(1)/(x)+C` `(x^(2)y^(2))/(1-y^(2))=(Cx-1)impliesx^(2)y^(2)=(Cx-1)(1-y^(2))` |
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| 28. |
Let `vec(p),vec(q),vec(r)` be three unit vectors such that `vec(p)xxvec(q)=vec(r)`. If `vec(a)` is any vector such that `[vec(a)vec(q)vec(r )]=1,[vec(a)vec(r)vec(p )]=2`, and `[vec(a)vec(p)vec(q )]=3`, then `vec(a)=`A. `vec(p)+3q+vec(r )`B. `vec(3p)+vec(2q)+vec(r )`C. vec(p)-vec(2q)-vec(3r)`D. `vec(p)+vec(2q)+vec(3q)` |
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Answer» Correct Answer - D Given that `vec(p)xxvec(q)=vec(r )` `implies (vec(p)xxvec(q)).vec(r )=|vec(r )|^(2)implies[vec(p)vec(q)vec(r )]=1` Let `(a)=xvec(p)+yvec(q)+zvec(r)....(1)` Take dot product in equation (1)both sides with `vec(p)xxvec(q), vec(q)xxvec(r)` and `vec(r )xxvec(p)` we get `x=1, y=2, z=3.` |
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| 29. |
If one root of the equation `x^(2)+px+q=0` is `2+sqrt(3)` where `p, q epsilon I` and roots of the equation `rx^(2)+x+q=0` are `tan 268^(@)` and `cot 88^(@)` then value of `p+q+r` is :A. `-1`B. `-2`C. `-3`D. `-4` |
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Answer» Correct Answer - B If one root of ………… `x^(2)+px+q=0` has one root `2+sqrt(3)` then other root `= 2 - sqrt(3)` "sum" of roots `= - (P)/(1)= 2+sqrt(3)+2-sqrt(3)` `implies P = -4` product of roots `= (q)/(1) = (2+sqrt(3))(2-sqrt(3))` `implies q = 1` …..(i) product of roots `= (q)/(1) = (2+sqrt(3))(2-sqrt(3))` `implies q=1` ....(ii) now `rx^(2)+x+q=0` roots are tan `(268^(@)) tan (180^(@)+88^(@)) = tan 88^(@)` and `cot 88^(@)` `:.` Product of roots `= tan 88^(@) .cot 88^(@) = (q)/(r )` `implies 1 = (q)/(r ) implies q = r` ....(iii) `:. p+q+r= -4+1+1= -2` |
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| 30. |
Let `R` be the relation defined on power set of A such that `ARB hArr n(P(A)) = n(P(B))` can be : (where `P(A)` denotes power set of `(A)`A. ReflexiveB. SymmetricC. TransitiveD. Equiivalence |
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Answer» Correct Answer - A::B::C::D Let `R` be the ……….. `(A.B) in R implies n(P(A)) = n(P(B))` `implies 2^(n(A)) = 2^(n(B))` Now, `n(A)=n(A) implies (A,A)in R AA A` `implies R` is reflexive Let `(A,B) in R implies n(A) = n(B) implies n(B)= n(A) implies (B,A) in R` `:.` symmetric Let `(A,B) in R implies n(A)=n(B)` Let `(B,C)in R implies n(B) = n(C )` `implies n(A) = n(C )` `implies (A,C)in R :.` transitive `:.` equivalence |
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| 31. |
Let `P_(1)=x+y+z+1=0, P_(2)=x-y+2z+1=0,P_(3)=3x+y+4z+7=0` be three planes. Find the distance of line of intersection of planes `P_(1)=0` and `P_(2) =0` from the plane `P_(3) =0.`A. `(2)/sqrt(26)`B. `(4)/sqrt(26)`C. `sqrt((1)/(26))`D. `(7)/sqrt(26)` |
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Answer» Correct Answer - B Let direction ratios of line are a,b,c Now `a+b+c=0` `a-b+2c=0` `(a)/(3)=(b)/(-1)=(c )/(-2)` So direction ratios of line are `(3,-1,-2)` `x+y+z+1+0….(1)` `x-y+2z+1=0….(2)` Put z=0, we get `x=1, y=0` Equation of line of intersection of `P_(1)=0 P_(2)=0` is parallel to the plane `P_(3)=0`. Sodistance of point `(-1,0,0)` from `P_(3)=0` is `|(-3+7)/sqrt(9+1+16)| = (4)/sqrt(26)` |
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| 32. |
Figure of merit γ is a. Ratio of output signal to noise ratio to input signal to noiseratio b. Ratio of input signal to noise ratio to output signal to noiseratio c. Ratio of output signal to input signal to a system d. Ratio of input signal to output signal to a system |
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Answer» a. Ratio of output signal to noise ratio to input signal to noiseratio |
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| 33. |
`Let sec ^(2)((pi)/(9))+sec^(2)((2pi)/(9))+sec_(2)((4pi)/(9))=S` and `Sigma_(k-1)^(89) cos^(6)(k^(o))=(a)/(b)` ,where a,b are coprime, then which of the following is/are correct?A. Number of positive divisors of a+b + S is 4B. Number of positive divisors of a+b + S is 8C. S is a perfect squareD. a+b is a prime number |
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Answer» Correct Answer - A::C::D `sec^(2)((pi)/(9))+sec^(2)((2pi)/(9))+sec^(2)((4pi)/(9))` `=((cos.(2pi)/(9))^(2)(cos.(4pi)/(9))^(2) +(cos.(4pi)/(9))^(2)(cos.(pi)/(9))^(2)+cos^(2)((pi)/(9))cos^(2)((2pi)/(9)))/(cos.(pi)/(9)cos.(2pi)/(9)cos.(4pi)/(9))^(2)` Using CD formulas `=(1)/(4)([(cos.(2pi)/(3)+cos.(2pi)/(9))^(2)+(cos.(5pi)/(9)+cos.(pi)/(3))^(2)+(cos.(pi)/(3)+cos.(pi)/(9))^(2)])/(((1)/(64)))` `= 16 ((3)/(4)+cos^(2).(pi)/(9)+cos^(2).(2pi)/(9)+cos^(2).(4pi)/(9)+cos.(pi)/(9)-cos^(2).(2pi)/(9)-cos.(4pi)/(9))` `=16((3)/(9)+(3)/(2))` `therefore cos .(pi)/(9)-cos^(2).(2pi)/(9)-cos.(4pi)/(9)=0 =36` `underset(k=1)overset(89)Sigmacos^(6)(k^(@))= underset(k=1)overset(89)Sigmasin^(6)(k^(@))=(1)/(2)underset(k=1)overset(89)sum(sin^(6)(k^(@))+cos^(6)(k^(@)))` `(1)/(2)(underset(k=1)overset(89)Sigma(1-(3)/(4)sin^(2)(2k^(@))))=(89)/(2)-(3)/(8)underset(k=1)overset(89)Sigma(2k)^(@)` `=(89)/(2)-(3)/(8)xx45` `(a)/(b)=(221)/(8)` `a221,b=8` |
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| 34. |
Consider the equation `sectheta+ cottheta = 31/12` On the basis of above, answer the following Number of values of theta where `theta in ((pi)/(2),(3pi)/(2))` is equal toA. `0`B. `1`C. `2`D. `3` |
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Answer» Correct Answer - B Let `t =tan,(theta)/(2)` `implies (1+t^(2))/(1-t^(2))+(1-t^(2))/(2t)=(31)/(12)` `implies6t^(4)+43t^(3)-12t^(2)-19t+6=0` `implies(3t-1)(2t^(3)+15t^(2)+t-6)=0` `implies t=(1)/(3),alpha,beta,gamma` where `alpha in(-8,-7)implies(theta)/(2)in((pi)/(2),(3pi)/(4))` `beta in (-1,(-1)/(2))implies(theta)/(2) in ((3pi)/(4),(7pi)/(8))` `gamma in((1)/(2),1)implies(theta)/(2)in(0,(pi)/(4))` (i) if `0lttheta lt (pi)/(2)` then `t=(1)/(3)` or `t in ((1)/(2),1)` `implies tan theta =(3)/(4) "or if" tan. (theta)/(2)in((1)/(2),1)implies "tan" theta in ((4)/(3),oo)` `implies"Min value of" [tan theta] =0` (ii)No. of values of `theta in ((pi)/(2),(3pi)/(2))` will be 1 |
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| 35. |
For what purposes transformer ratio meter can be used? |
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Answer» Transformer ratio meter can be used for, a. To find the ratio of a transformer. b. To find the phase angle deviation of primary and secondary voltage of transformer. c. To find the magnitude of magnetizing currents. |
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| 36. |
What do you understand by tan delta for a insulating material? |
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Answer» Tan delta measurement is done to find the qualities of insulating material. Tan delta is angle between current due to surface leakage or current due to capacitance and the capacitive current. That is Tan δ = Ir / Ic. |
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| 37. |
What are the design objectives of Electrical System? |
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Answer» a. To evacuate generated electrical power. b. To provide required power to SUT, UT, DG, UPS, and CUPS. c. To provide required emergency power from onsite DG, UPS & CUPS. d. To provide Fast transfer in event of Class IV failure. Emergency transfer in events of Class III and Class II failure. e. Load shedding in event of one DG available. f. To provide un-interruptible or few milli seconds interrupted power supply by UPS and un-interruptible power supply by CUPS. g. To provide operational flexibility by providing required qualities of requirement. h. To provide isolation, Alarms, indication, protection of the system. i. To provide fire protection. j. To provide surge and lightning protection. k. To provide adequate lighting. l. To provide equipment earthing, system earthing, and personnel protection. m. To provide necessary electrical and physical isolation of electrical equipments. |
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| 38. |
What is the range of resistances that can be measured using following. |
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Answer» The range of resistances that can be measured using are. a. Wheatstone bridge – 1 milli Ω to 11 MΩ. b. Kelvins double bridge – 0.2 micro Ω to 11 Ω. c. Megger – Insulation resistances more than 100 kΩ |
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| 39. |
What is the difference in action of lock out pressure signal on 6.6 kV and 220 kV breakers? |
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Answer» When lock out signal comes to 6.6 kV breakers the breaker will trip. Where as in case of 220 kV breakers the breaker will not trip. If the breaker is open it will be open only and can not be closed. If it is in closed condition it will be closed. |
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| 40. |
What type breakers are provided in 6.6 kV buses? |
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Answer» ABB. Make, SF6 gas, 1250A and 2000A capacity circuit breakers are provided in 6.6 kV buses. |
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| 41. |
List some important loads to 6.6 kV buses. |
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Answer» a. Auxiliary transformers. b. PHT motors. c. BFP motors. d. CEP motors. e. CCW motors. f. Chiller motors. g. Pressuring pump motors. |
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| 42. |
What is the purpose of CVT (capacitance voltage transformer)? |
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Answer» Purposes of CVT are. a. To indicate if line is charged or not. b. To synchronize grid with generator. c. For power line communication and carrier tripping. |
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| 43. |
What are three types of secondary instruments? |
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Answer» The three types of secondary instruments are, a. Indicating type: It only indicates the electrical quantity measured. Example: Ammeter, Voltmeter, Frequency meter etc. b. Integrating type: It integrates (sums up) the quantity being measured. Example: Energy meter. c. Recording meter: It records as well as indicates the electrical quantity being measured. Example: 3 pen graphical recorder. |
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| 44. |
What are the advantages of digital instruments over analog instruments? |
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Answer» The advantages of digital instruments over analog instrument are. a. Human errors are avoided (comparative error) because the output is displayed in form of numbers. b. Power consumption of digital meters are low as compared to analog meters. |
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| 45. |
Give three operating forces acting on indicating instruments. |
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Answer» a. Deflecting force. b. Controlling force. c. Damping force. |
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| 46. |
Why earth switches are provided in 220 kV bays? |
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Answer» When bay CB trips, both end (station and grid) CB will trip. The earth switches are provided because the grid will always be alive so to prevent any shocks to the operator or maintenance personnel who is working on the line or bay due to accidental energizing of the bus. |
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| 47. |
What are the two main classifications of analog instruments? |
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Answer» The two main classifications of instruments are, a. Absolute instruments. Example tangent galvanometer. b. Secondary instruments. Example ammeter, voltmeter. Analog instruments are classified according to their electrical quantity they measure. Example frequency meter, voltmeter, etc. Principles they work are moving coil, induction. |
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| 48. |
List out the components of station output system. |
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Answer» Main generator, Generator transformer, PT, CT, CVT, lightning arrestor, wave trap, main 220 kV bus, transfer bus, SF6 circuit breakers and isolators, line protection scheme, GT and Generator protection scheme, bus bar protection scheme etc. |
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| 49. |
For how long 220 V DC batteries can supply power UPS? |
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Answer» 220 V DC batteries can supply Power UPS for 30 minutes. Within this time class III power supply should be restored by DG’s. |
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| 50. |
What are the main sources of power supply to 6.6 kV buses? |
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Answer» The main sources of power supply to 6.6 kV buses are. a. Unit transformer which steps down the generated voltage to 6.6 kV from the generator. b. Start up transformer, which steps down the grid voltage to 6.6 kV. |
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