This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A galvanometer of resistance 98 ohms is shunted by a resistance of 2 ohms. The fraction of the total current that pass through is.A. `1//50`B. `1//49`C. `1//2`D. `1//98` |
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Answer» Correct Answer - A Fraction of current passing thorught galvanometer is give by `rArr (I_(g))/(l) = (S)/(S+G) = (2)/(2+98) = (2)/(100)` or `(l_(g))/(l) = (1)/(50)` |
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| 2. |
The principles of Ashoka's Dharma (Dhamma) were taken from (a) Buddhism (b) Jainism (c) Brahmanism (d) The moral virtues of all Indian religions of that period |
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Answer» (d) The moral virtues of all Indian religions of that period |
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| 3. |
A disc of mass m and radius r is gently placed on another disc of mass 2m and radius r. The disc of mass 2m is rotating with angular velocity `omega_(0)` initially. The disc is placed such that axis of both are concident. The coefficient of friction is `mu` for surfaces of contact Assume that pressure on disc is uniformely distributed. Time elapsed in this processA. `(omega_(0)R)/(mug)`B. `(2omega_(0)R)/(mug)`C. `(omega_(0)R)/(2mug)`D. `(omega_(0)R)/(4mug)` |
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Answer» Correct Answer - B `sigma=(-((Deltar)/(r)))/(((Deltal)/(l)))` `(DeltaA)/(A)=(2Deltar)/(r)=-2%implies ((Deltar)/(r))~=-1%` `sigma=-(((Deltar)/(r)))/(((Deltal)/(l)))` `(0.4) =-((-1%))/(((Deltal)/(l)))implies ((Deltal)/(l))=(10)/(4)% " "(Deltal)/(l)=2.5%` |
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| 4. |
A small particle of mass ` m` is projected at an angle `theta` with the ` x`- axis with an initial velocity ` v_(0)` in the ` x-y `plane as shown in the figure . At a time ` t lt ( v_(0) sin theta)/(g) `, the angular momentum of the particle is where `hat (i) , hat (j) and hat(k)` are unit vectors along `x , y and z` - axis respectively. A. `-mgv_(0)t^(2)costhetahat(j)`B. `mgv_(0)tcosthetahat(k)`C. `-(1)/(2)mgv_(0)t^(2)costhetahat(k)`D. `(1)/(2)mgv_(0)t^(2)costhetahat(i)` |
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Answer» Correct Answer - 3 `vec(L)=vec(r)xx(m vec(v))` `vec(r)=v_(0)cos thetat hat(i)+(v_(0)sinthetat-(1)/(2)g t^(2))hat(j)` `vec(v)=v_(0)cos theta hat(i)+(v_(0)sintheta-g t)hat(j)` `vec(L)=mv_(0)costhetat(-(1)/(2)g t)hat(k)` `=-(1)/(2)mg v_(0) t^(2) costheta hat(k)` |
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| 5. |
A disc of mass m and radius r is gently placed on another disc of mass 2m and radius r. The disc of mass 2m is rotating with angular velocity `omega_(0)` initially. The disc is placed such that axis of both are concident. The coefficient of friction is `mu` for surfaces of contact Assume that pressure on disc is uniformely distributed. Loss in kinetic energy of systemA. `(1)/(6)mr^(2)omega_(0)^(2)`B. `(1)/(3)mr^(2)omega_(0)^(2)`C. `(1)/(2)mr^(2)omega_(0)^(2)`D. None of these |
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Answer» Correct Answer - A By COE `Mg.(L)/(2)=(1)/(2)((ML^(2))/(3))omega^(2)implies omega^(2)=(3g)/(L)` To find tension at mid point `T-(M)/(2)g=(M)/(2)(a_(cm))_("lower half")` `T-(M)/(2)g=(M)/(2)(omega^(2)(3L)/(4))` `T-(M)/(2)g=(M)/(2)((3g)/(L)(3L)/(4))` `T=(Mg)/(2)+(9Mg)/(8)=(13Mg)/(8)` Stress at mid point = `(T)/(A) = (13Mg)/(8A)` `S = (13dALg)/(8A)=(13dLg)/(8)` |
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| 6. |
A particle is projected with a velocity v such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)A. `(4v^(2))/(5g)`B. `(4g)/(5v^(2))`C. `(v^(2))/(g)`D. `(4v^(2))/(sqrt (5)g)` |
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Answer» Correct Answer - 1 `R=2H` given Let `theta`=angle of projection `(2v_(x)v_(y))/(g)=2.(v_(y)^(2))/(2g)` `(v_(y))/(v_(x))=2` `tantheta=2` From tringle we can say that `sintheta=(2)/(sqrt(5)),costheta=(1)/(sqrt(5))` `:.` Range of projectile `R=(2v^(2)sintheta costheta)/(g)` `=(2v^(2))/(g)xx(2)/(sqrt(5))xx(1)/(sqrt(5))=(4v^(2))/(5g)` |
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| 7. |
A particle is projected with speed `v = sqrt(150)m//s` from the horizontal surface such that its range on the horizontal plane is twice the greatest height attained by it. Then half of range of the projectile in meter is (use g = 10 `m//s^(2)`) |
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Answer» Correct Answer - 3 `v=sqrt(2(10)Rcos60^(@))=sqrt(10)` `N-mgcos60^(@)=(mv^(2))/(R )implies N=15` Newton `therefore" Force on wall = N sin "60^(@)=(15sqrt(3))/(2) " "therefore P = 3` |
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| 8. |
Which social evil was conspicuously absent in ancient India? (a) Polygamy (b) Sati system (c) Devadasi system (d) Purdah system |
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Answer» (d) Purdah system |
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| 9. |
A monochromatic light is travelling in a medium of refractive index n = 1.6. It enters a stack of glass layers from the bottom side at an angle θ = 30°. The interfaces of the glass layers are parallel to each other. The refractive indices of different glass layers are monotonically decreasing as nm = n - mΔn, where nm is the refractive index of the mth slab and Δn = 0.1 (see the figure). The ray is refracted out parallel to the interface between the (m -1)th and mth slabs from the right side of the stack. What is the value of m? |
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Answer» n sin θ = (n - mΔn) x sin 90° ⇒ m = n/2Δn ⇒ m = 8 |
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| 10. |
A Galvanometer is an instrument that can be used to construct an ammeter for measuring current. It can be used to convert to a voltmeter. It can also be used as a multimeter. In all cases resistance must be connected to galvanometer either in series or in parallel to effect the change. To turn into an ammeter a low resistance in parallel of suitable value and to convert to a voltmeter a resistance is connected in series. You are given a galvanometer for which a current of 10 mA is required for full deflection. The internal resistance of the galvanometer is 100 ohm.Then answer the following questionsWhich of the following formula correctly applies to the ammeter circuit. (1) VR > Vr (2) Vr > VR (3) VR = Vr(4) more information required |
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Answer» Correct option (3) VR = Vr Explanation: Resistance R is connected in parallel with galvanometer. Hence Vr = VR |
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| 11. |
Find the minimum radius for a planet of mean density `rho` and temperature `T` which can detain oxygen in its atmosphere. (`M_(0)=`Molecular weight of Oxygen and `G=`Universal Gravitational constant)A. `sqrt((7)/(8)(RT)/(GM_(0)rhopi))`B. `sqrt((9)/(8)(RT)/(GM_(0)rhopi))`C. `sqrt((15)/(9)(RT)/(GM_(0)rhopi))`D. `sqrt((15)/(8)(RT)/(GM_(0)rhopi))` |
| Answer» `(3RT)/(2)=(M_(0)GM_(p))/(R_(p))` and use `M_(p)=(4)/(3)rho pi R_(p)^(3)` | |
| 12. |
One increasing the operating voltage in a x-ray tube by `1.5` times, the shortest wavelength decreases by `26 "pm"`. Find the original value of operating voltage.A. `16 KV`B. `20 KV`C. `22 KV`D. `26 KV` |
| Answer» Use `eV=(hc)/(lambda)` and `(hc)/(lambda-Deltalambda)=1.5eV` | |
| 13. |
A point mass `m` is displaced slightly from point `O` and released. It is constrained to move along parabolic path having equation `x^(2)=ky` then its angular frequency of oscillation is : A. `sqrt((g)/(2k))`B. `sqrt((2g)/(k))`C. `sqrt((g)/(k))`D. `sqrt((3g)/(2k))` |
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Answer» `F=-mg sin theta` `sin theta=tan theta=(dy)/(dx)=(2x)/(k)` `F=-((2mg)/(k))x` `omega=sqrt((2g)/(k))` |
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| 14. |
A force of constant magnitude F acts on a particle moving in a plane such that it is perpendicular to the velocity `vecv(|vecv|=v)` of the body and the force is always direct towards a fixed point. Then the angle turned by the velocity vector of the particle as it covers a distance S is (take mass of the particle as m)A. `(FS)/(2mv^(2))`B. `(2FS)/(mv^(2))`C. `(FS^(2))/(mv)`D. `(FS)/(mv^(2))` |
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Answer» Since `vecFbotvecV` the particle will move along a circle `thereforeF=(mv^(2))/(R)&theta=(S)/(R)impliestheta=(FS)/(mv^(2))` |
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| 15. |
A long horizontal rod has a bead which can slide along its length and is initially placed at a distance L from one end A of the rod. The rod is set in angular motion about A with a constant angular acceleration α. If the coefficient of friction between the rod and the bead is μ and the gravity is neglected, the time after which the bead starts slipping is(a) √(μ/α)(b) μ/√α(c) 1/√(μα)(d) infinitesimal |
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Answer» Correct Answer is: (a) √(μ/α). The linear acceleration of the bead is a = Lα. ∴ the reaction force on the bead due to the rod is N = ma = mLα. After time t, the angular velocity of the bead is ω = αt . ∴ the centripetal acceleration of the bead is ω2L = α2t2L. ∴ the force of friction at limiting position is μN = μmLα. ∴ for slipping, μmLα = mα2t2L or t = √(μ/α) |
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| 16. |
What is the dimension of Luminous flux :(1) [cd1](2) [cd1T1](3) [cd1L2] (4) [cd1L1T1] |
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Answer» Correct option (1) [cd1] Explanation: Dimension of Luminous flux is cd. |
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| 17. |
Write the steps of starting of 3 phase induction motor. |
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Answer» The three phase induction motor may be started by connecting the motor directly to the full voltage of the supply. The motor can also be started by applying a reduced voltage to the motor when the motor is started. The torque of the induction motor is proportional to the square of the applied voltage. Thus, a greater torque is exerted by a motor when it is started on full voltage than when it is started on the reduced voltage. The three methods to start the 3 phase induction motor are:
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| 18. |
A train leaves _____ Berlin and arrives _____ Bonn in time. A) from / to B) from / in C) from / at D) in / from |
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Answer» Correct option is B) from / in |
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| 19. |
We use adverbs _____ the beginning and the end of a sentence, but sometimes _____ the middle of a sentence. A) at / in B) in / at C) on / at D) at / on |
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Answer» Correct option is A) at / in |
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| 20. |
“_____ did the story take place?” “A long time ago.” A) How many B) What C) Where D) When |
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Answer» Correct option is D) When |
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| 21. |
Oh dear, I have a ________ tire. I must put some air in it. A) shallow B) flat C) low D) bent E) level |
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Answer» Correct option is B) flat |
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| 22. |
The game of tennis was very _____ . A) tired B) tire C) tiring D) tires |
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Answer» Correct option is C) tiring |
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| 23. |
Which of the following trend is/are correct?A. `CIO_(2)gtSO_(2)gtCO_(2)gtP_(2)O_(5)` (acidic nature)B. `NagtSigtAlgtMg`(second I.P.)C. `SgtSegtTegtO`(electron affinity)D. `H_(3)PO_(2)gtH_(3)PO_(3)gtH_(3)PO_(4)(Ka_(1))` |
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Answer» Correct Answer - C::D `Cl` is most electronegative among `Cl, S,P` & `C` so `ClO_(2)` is most acidic and `Ea` of `O` is least in its `gp`, `H-underset(1) underset(H) underset(|) overset(O) overset(||)(P)-O^(-), H-O-underset(2) underset(H) underset(|)overset (O) overset(||)(P)-O^(-)` Due to cross conjugation in (2), 1 is weaker base than 2 so `H_(3)PO_(2)` is stronger acid than `H_(3)PO_(3)`, similarly relate `H_(3)PO_(4)` for option (b) refer `e^(-)` configuration & `ENCimpliesNagtAlgtSigtMg`. |
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| 24. |
An object and a plane mirror are shown in figure. Mirror is moved with velocity `V` as shown. The velocity of image is : .A. `2 V sin theta`B. 2 VC. `2 V cos theta`D. none of these |
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Answer» Correct Answer - A `vec(V)_(1)=vec(V)_(0)m=` (normal to plane mirror) `rArr vec(V)_(1)m-vec(V)_(m)=-(vec(V)_(0)-vec(V)_(m))` `vec(V)_(1)-V sin theta =-(0-V sin theta)` `V_(1)=2V sin theta`. |
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| 25. |
A ray of light falls on a plane mirror. When the mirror is turned, about an axis at right angles to the plane of mirror by `20^(@)` the angle between the incident ray and new reflected ray is `45^(@)`. The angle between the incident ray and original reflected ray was therefore.A. `65^(@)`B. `20^(@)` or `65^(@)`C. `25^(@)`D. `45^(@)` |
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Answer» Correct Answer - D If mirror is turned about an axis perpendicular to plane of mirror, then there will be no change in incident angle and reflected angle so angle between incident & reflected rays after rotation will be same as before. |
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| 26. |
In Fig, `E =5` volt , `r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega` and `C = 3 muF`. Then the numbercal value of the charge on each plate of the capacitor is A. 3`muC`B. 6`muC`C. 12`muC`D. 24`muC` |
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Answer» Correct Answer - 2 At steady state, No current will flow through capacitor, So I = `E/(R_(2)+r)=5/(4+1)=1A` Potential difference a cross capacitor = `ixxR_(2)` `=1xx4=4v` Charge on each capacitor =`(C/2)xx4` `=(3/2)xx4=6muC` |
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| 27. |
How many players there are in cricket team’s playing ? |
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Answer» Answer: 11 players |
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| 28. |
A cart loaded with sand having total mass `m_(0)=1800kg` moves on a straight horizontal road starting from rest under the action of a force of 120N. The sand spills through a small hole hole in the bottom at a rate of 0.5 kg/sec. What will be the velocity of cart after 20 min?A. 220 m/secB. 240 ln `((3)/(2))`C. 120m/secD. None of these |
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Answer» `F=ma=(mdu)/(dt)` `dv=(F)/(m)dt` `int_(0)^(v)dv=int_(0)^(1200s)(120)/((1800-0.51))dt` `=(1200)/(-0.5)[n(1800-0.5t)^(200)` `=240ln((3)/(2))` |
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| 29. |
A bead of mass m is atached to a spring of natural length `(3R)/(4)` with other end of it fixed at O.The bead moves in a track of which part ABC is semicircular of radius R and part CDA varies from R to `(R)/(2)` and then again to R. The bead is in equilibrium at position D and starts moving downward. Find the ratio of normal reaction on the bead to the cetrifugal force at the bottom most position. A. 2B. `(1)/(2)`C. `1,0`D. `(1)/(3)` |
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Answer» In position D spring is in equilibrium. ltbr. `N+mg-F=0`. . . (1) in bottom most position. `N+f-mg=(mv^(2))/(2)`. . . .(2) [since spring is elongated] where F=kx and `x=(3R)/(4)-(R)/(2)=(R)/(4)`in position D and `x=R-(3R)/(4)=(R)/(4)` in bottom position From 1 and 2 `N+(N+mg)-mg=(mv^(2))/(r)` `2N=(mv^(2))/(r)` `(N)/(mv^(2)//r)=(1)/(2)` |
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| 30. |
If equation `int (dt)/(sqrt(3a - 2t^(2))) = a^(x) sin ^(-1) ((r^(2))/(a^(2)) - 1)`, the value of x isA. ZeroB. 1C. 2D. `-1` |
| Answer» LHS is dimensionless So [x]=`[m^(@)L^(@)T^(@)]` | |
| 31. |
A particle `P` is moving with a constant speed of `6 m//s` in a direction `2 hati-hatj+2hatk`. When `t=0, P` is at a point whose position vectors is `3hati+4hatj-7hatk`. Find the position vector of the particle `P` after `4` seconds.A. `18hati-4hatj-23 hatk`B. `19hati-4hatj-23 hatk`C. `19 hati+4hatj-23hatk`D. `19hati-4hatj+23 hatk` |
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Answer» Correct Answer - B `vec(V)=6(2 hat(i)-hat(j)-2 hat(k))/(3)` `vec(r)=vec(r)_(0)+vec(v)t=3 hat(i)+4 hat(j)-7 hat(k)+4 xx2` `(2 hat(i)-hat(j)-2 hat(k))rArr vec(r)=19 hat(i)-4 hat(j)=23 hat(k)`. |
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| 32. |
Three co-planar vectors (`x-y` plane ) having magnitude `3sqrt(2),6,10` are shown in the figure. Find the componenent of resultant of three vectors along the `x` axis as shown. .A. `7`B. `-10`C. `9`D. `-7` |
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Answer» Correct Answer - D `3 sqrt(2) cos 45^(@) - 10=-7`. |
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| 33. |
Ratio of the ranges of the bullets fired from a gun `(` of constant muzzle speed `)` at angle `theta, 2 theta &4 theta` is found in the ratio `x:2:2`, then the value of `x` will be `(` Assume same muzzle speed of bullets `)`A. `1`B. `2`C. `sqrt(3)`D. `2/(sqrt(3))` |
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Answer» Correct Answer - D Range is same for `2 theta` and `4 theta` `:. 2 theta + 4 theta = 90^(@) rArr theta = 15^(@)` `:.` Range of ranges will be `sin 30^(@) : sin 60^(@) : sin 120^(@)`. |
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| 34. |
Ratio of the ranges of the bullets fired from a gun `(` of constant muzzle speed `)` at angle `theta, 2 theta &4 theta` is found in the ratio `x:2:2`, then the value of `x` will be `(` Assume same muzzle speed of bullets `)`A. 1B. 2C. `sqrt(3)`D. none of these |
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Answer» Correct Answer - D Range is same for `2 theta` and `4 theta`. `:. 4 theta+4 theta=90^(@)rArrtheta 15^(@)` `:. ` Ratio of ranges will be sin `30^(@): sin60^(@):sin120^(@)`. `(1)/(2):(sqrt(3))/(2):(sqrt(3))/(2)rArr(2)/(sqrt(3)):2:2` |
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| 35. |
Common indicator organism of water pollution isA. Escherichia coilB. Vibrio choleraeC. Salmonella typhiD. Entamoeba hisiolytica |
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Answer» Correct Answer - A (A) Common indicator organism of water pollution is Escherichia coli. |
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| 36. |
A lake with an inflow of domestic sewage rich in organic waste may result inA. Drying up due to algal bloomB. Increased fish production due to higher nutrient availabilityC. Death of fish due to oxygen depictionD. Increased food web organisation |
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Answer» Correct Answer - C (C) A lake receiving domestic sewage shows death of fish due to oxygen depletion. |
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| 37. |
What is the importance of flowering pattern of Strobilanthus kunthiana? |
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Answer» It flowers once in 12 years. |
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| 38. |
`C_(4)` pathway is advantageous over `C_(3)` pathway in plants as itA. occurs in reIatively low `CO_(2)` concentrationB. uses more amount of waterC. occurs in relatively low `O_(2)` concentrationD. is less efficient in energy utilisation |
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Answer» Correct Answer - A A plant with the `C_(4)` pathway is advantageous over a plant with a `C_(3)` pathway as the former can occur in low `CO_(2)` concentrations. When the weather is hot and arid, the leaves close their stomata to reduce water loss. This closure results in low `CO_(2)` concentrations and thus, leading to both loss of RuBP and inhibition of Calvin-Benson cycle. |
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| 39. |
For each of the sensory pathways A–E, select the most appropriate option from the list below. 1. Third order sensory pathway from thalamus to the post central gyrus. 2. The tracts carrying proprioception impulses in first order sensory neurones to the nucleus gracilis and cuneatus. 3. A tract in the brainstem carrying sensory impulses to the thalamus.4. A tract containing the second order sensory neurones carrying pain and temperature sensation. 5. A tract containing the ascending second order neurones carrying touch and pressure sensation. A. Lateral spino-thalamic tract. B. Thalamic radiation. C. Medial (ventral) spino-thalamic tract. D. Dorsal columns. E. Medial lemniscus. |
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Answer» A. Option 4 A tract containing the second order sensory neurones carrying pain and temperature sensation. These tracts carry pain and temperature impulses from receptors on the opposite side of the body to the thalamus. B. Option 1 Third order sensory pathway from thalamus to the postcentral gyrus. In the postcentral gyrus the sensory impulses generate conscious sensation. C. Option 5 A tract containing the ascending second order neurones carrying touch and pressure sensation. These tracts carry touch and pressure impulses from the opposite side of the body to the thalamus. D. Option 2 The tracts carrying proprioception impulses in first order sensory neurones to the nucleus gracilis and cuneatus. These tracts carry impulses from muscle spindles and other receptors on the same side of the body that ascend in first order sensory neurones to the gracile and cuneate nuclei. From there second order neurones cross to the opposite side of the body in the sensory decussation to join the medial lemniscus and ascend to the thalamus. E. Option 3 A tract in the brainstem carrying sensory impulses to the thalamus. This is the common sensory pathway in the brainstem carrying all sensory impulses to the thalamus. |
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| 40. |
A mutant plant is unable to produce materials or precursors that form Casparians trip. This plant would beA. unable to transport water from roots to the leavesB. able to exert greater root pressure than the normal plantC. unable to transport food from leaves to rootsD. unable to control amount of water and solute it absorbs |
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Answer» Correct Answer - C Presence of Casparian strips in plants controls the amount of water and solute it absorbs. Thus, a plant that cannot produce Casparian strips effectively will be unable to control the amount of water and solute in plants. |
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| 41. |
Cell A has osmotic potential of -18 bars and pressure potential of 8 bars, whereas, cell B has osmotic potential of -14 bars and pressure potential 2 bars. The direction of flow of water will beA. from cell B to cell AB. from cell A to BC. no flow of waterD. in both the directions |
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Answer» Correct Answer - A The water potential is the chemical potential of the water, which is equivalent to diffusion pressure deficit with negative sign. Therefore, water potential (`Psi_(A)`) of cell A is `Psi_(A)=Psi_(S)+Psi_(P)=-20+5=-15` bars `Psi_(B)=Psi_(S)+Psi_(P)=18+2=-2` bars Since, water moves from higher water potential to lower potential, the flow of water will be from cell B (-2 bars) to cell A (-15 bars). |
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| 42. |
If someone is "gung ho", they are _____. A) stupid B) childish C) enthusiastic |
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Answer» Correct option is C) enthusiastic |
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| 43. |
"Great guns" means _____. A) slow and precise B) big and heavy C) fast and hard |
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Answer» Correct option is C) fast and hard |
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| 44. |
We won _____ two goals _____ nil. A) by / to B) with / by C) with / to D) by / in |
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Answer» Correct option is A) by / to |
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| 45. |
Which of the vitamins affects the blood clotting?(a) Vitamin A (b) Vitamin B (c) Vitamin K (d) Vitamin D |
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Answer» Vitamin K affects the blood clotting. |
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| 46. |
How are you? - I am WELL, thank you. A) ill B) greedy C) fine D) O.K. E) ready |
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Answer» Correct option is A) ill |
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| 47. |
This box is very light. The man can EASILY lift it. A) hardly B) hurriedly C) slowly D) earnestly E) badly |
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Answer» Correct option is A) hardly |
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| 48. |
My brother learned _____ the same time as me, but I passed first. A) at B) in C) on D) is |
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Answer» Correct option is A) at |
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| 49. |
Exposure _____ radiation may result _____ sickness and even death. A) to / in B) with / in C) of / with D) to / from |
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Answer» Correct option is A) to / in |
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| 50. |
German is _____ English in some ways, but it is more difficult _____ English. A) like / then B) as / that C) like / than D) like / like |
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Answer» Correct option is C) like / than |
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