Explore topic-wise InterviewSolutions in Current Affairs.

Path of energy flow in an ecosystem is  Producers → Herbivores→ Carnivores →Decomposers

(d) All of them

(a) High purity (>99.95%) dihydrogen is obtained by electrolysing warm aqueous barium hydroxide . solution between nickel electrodes.

(b) This is due to high H-H bond enthalpy. 

(c) 1. In oxy-hydrogen torches. 

2. Liquid hydrogen is used as a fuel in rockets.

Protium (¹₁H), Deuterium (²₁H) and Tritium(^{​​​​​​​3}₁H)

(c) 1 cm³ of the solution liberates 30 cm³ of O₂ at STP

In acidic medium H₂O₂ reduces MnO₄^- to Mn²⁺ .

2MnO₄^- + 6H⁺ + 5H₂O₂→ 2Mn²⁺ + 8H₂O + 5O₂  

In basic medium H₂O₂ reduces l₂ to l^- . 

l₂ +H₂O₂+ 2OH^- → 2l^- + 2H₂O + O₂

The common gp present in both aldehyde and ketone is divolent carbonyl gp i.e.< C = 0.

Both Acetaldehyde & Acetone give iodoform Test. Both reacts with I₂ and NaOH to give yellow PPt of Iodoform m.

CH₃CHO(Acetaldehyde) + 3I₂ + 4NaOH → HCl₃↓(Yellow ppt) + 3NaI + 3H₂O

CH₃COCH₃(Acetone) + 3I₂ + 4NaOH → HCl₃↓(Yellow ppt) + 3NaI + HCOONa + 3H₂O

where bothe Acetaldehyde and acetone differ with Tollen's reagent.

Acetaldehyde reacts with Ammoniated AgNO₃ soln reduced Ag metal which is called silver mirror. So this reaction is used for the test of Aldehyde gp & known as silver mirror.

CH₃CHO + Ag₂O → CH₃COOH + 2Ag↓ Silver mirro

However, Acetone does not gives any reaction with Tollens reagent.

1. Adsorption

2. These are complex inorganic salts like sodium- aluminium silicate NaAlSiO₄ which can exchange cations such as Ca²⁺ and Mg²⁺ ions in hard water for Na⁺ ions. e.g. Zeolite.

In some of the transition metal hydrides, hydrogen is absorbed as H-atoms. Due to the inclusion of H- atoms, the metal lattice expands and thus becomes less stable. Therefore, when such metallic hydride is heated, it decomposes to release hydrogen gas and very finely divided metal. The hydrogen evolved in this manner can be used as a fuel. Thus, transition metals or their alloys can act as sponge and can be used to store and transport hydrogen to be used as a fuel.

1. Heavy water (D₂O). 

2. Cation exchange resins contain large organic molecule with -SO₃H group and are water insoluble. Ion exchange resin (RSO₃H) is changed to RNa by treating with NaCl. The resin exchanges Na⁺ ions with Ca²⁺ and Mg²⁺ ions present in hard water to make the water soft.

1. D₂O. Used as moderator in nuclear reactors. 

2. To prevent its decomposition. 

3. Calgon is chemically sodium hexametaphosphate (Na₆P₆O₁₈). It is used to remove Ca²⁺ and Mg²⁺ ions of hard water by converting them into soluble complexes. 

M²⁺ + Na₄P₆O^2-₁₈ → [Na₂MP₆O₁₈]^2- + 2Na⁺ (M = Mg,Ca)

Hydrogen atom has only one electron and thus, to achieve stable inert gas configuration of helium, it shares its single electron with electron of another hydrogen atom to form a stable diatomic molecule. The stability of H₂ is further confirmed by the fact, that formation of one mole of gaseous H₂ molecules results in the release of 435.8 kJ of energy. 

H(g) + H(g) H₂ (g); ∆H = – 435.8 kJ mol^-1

1. a) look 

b) have 

c) but 

d) under 

2. a) The 

b) greatest 

c) in

d) until 

3. a) was 

b) on 

c) a 

d) the 

4. a) for 

b) and 

c) at 

d) The 

5. a) oldest 

b) was using 

c) in d) carry 

6. a) frogs 

b) a 

c) them 

d) begun 

e) make

i) I don’t have much money with me. 

ii) Her speech was absolutely excellent. 

iii) Diet and exercise are equally important. 

iv) Can I come too? 

v) He learnt to play the violin at an early age. 

vi) The thief got in through the window. 

vii) Do you want to have some more tea? 

viii) There’s hardly anytime left. 

ix) John was very keen to help. 

x) We are fighting against terrorism. 

xi) I’ve already eaten my lunch. 

xii) The doctor will see you again next week, meanwhile use these medicines regularly. 

xiii) The ceremony lasted two hours anti we had to stand throughout the ceremony. 

xiv) The government is not wholly to be blamed for the raising of prices.

-1 is the valency of hydrogen in hydride ion.

Lithium, Sodium, Potassium and Rubedium.

²₁H (deuterium)

1.By the reaction of granulated zinc with dilute HCl. 

Zn + 2HCl → ZnCl₂ + H₂ 

2. By the reaction of zinc with aqueous alkali.

 Zn + 2NaOH → Na₂ZnO₂ + H₂

Water gas shift reaction

b) Compact Disk Read Only Memory

CDROM stands for Compact Disk Read Only Memory.

c) wide shot

A long shot is also called as wide shot.

Correct answer is D. Indo-Tibetan Border Police

a) Library Classification

A technique, which helps in the proper organisation and arrangement of documents and information in a systematic manner, so that the user can use sources of information effectively, is called Library Classification.

1. Water can be easily reduced to dihydrogen by highly electropositive metals like Na. Here, Na is oxidised to NaOH. 

2H₂O(I) + 2Na(s) → 2NaOH(aq) + H₂ (g)

2. With F₂ , water is oxidised to O₂ . Here, F₂ is reduced to F^-. 

2F₂ (g) + 2H₂O((l) → 4H⁺(aq) + 4F^-(aq) + O₂ (g)

Nuclear spin isomers

1. Na 

2. Metal hydrides 

3. -1

H₂O₂ is Diamagnetic.

Oculusion on pd

1. Hydrogen 

2. Platinum 

3. Hydrogen

Job analysis is a type of controlling technique where a job is evaluated for determining the internal efficiency of the job. It defines the internal worth of the job.

1. A sample of water said to be hard water if it does not give lather with soap. Heavy water is the oxide of deuterium (D₂O). 

2. Temporary hardness is due to the presence of bicarbonate of calcium or magnesium. It can be removed by boiling. Permanent hardness is due to the presence of chlorides and sulphates of calcium and magnesium. It is not removed by boiling.

Hydrogen reacts with metals or non metals to form binary compounds known as hydrides.

Hydrides are mainly classified into the following 3 types: 

1. Ionic or salt like hydrides

These are stoichiometric compounds of dihydrogen formed with most of the s-block elements which are highly electropositive in character. These are crystalline, non-volatile and non-conducting in solid state. But their melts conduct electricity and on electrolysis liberate dihydrogen gas at anode. They react violently with water producing dihydrogen gas. 

e.g. NaH, KH.

2. Covalent hydrides or Molecular hydrides

These are formed by the action between dihydrogen and non metals (p-block elements). Covalent hydrides are classified into electron-deficient (e.g. B₂H₆), electron-precise (e.g. CH₄) and electron-rich hydrides (e.g. NH₃).

3. Metallic or Non-stoichiometric or Interstitial hydrides 

These are formed by the reaction of dihydrogen with many d-block and f-block elements. These hydrides conduct heat and electricity. They are almost always nonstoichiometric, being deficient in hydrogen,

e.g. LaH_2.87 ,YbH_2.55 ,VH_0.56 etc.

Among the following elements which does not make a hydride is Co.

Correct answer is A. Chin lift method 

Correct answer is D. @

1212686+68×69786+67677= 6,025,811

Interstitial compounds are those which are formed when small atoms like H, C (Or) N are trapped inside the crystal.

The correct answer is the Self Help Group.

• Self Help Group(SHG)
  • It is an informal association of people who choose to come together to find ways to improve their living conditions.
  • A Self Help Group is a financial intermediary committee usually composed of 10 to 25 local women between the ages of 18 and 40.
  • Most Self-Help Groups are in India, though they can be found in other countries, especially in South Asia and Southeast Asia.
  • SHG is generally a group of people who work on daily wages who form a loose grouping or union.
  • Many SHGs are linked with banks for the delivery of micro-credit.
  • Self-Help Groups are started by non-governmental organizations(NGOs) that generally have broad anti-poverty agendas.
  • The Government of India launched Swarn Jayanti Gram Swarozgar Yojana to promote self-employment in rural areas through the formation and skilling of SHGs in 1999.

Find Out which is not suitable? The products marketed in commodity exchange are Rice.

Charge through a cross section of a conductar is given by θ = 5t² - 3 t coulomb. 

The average currenl through the conductar in the interval t₁ = 2s to t₂ = 45.

change at the given instants

θ = 5t² - 3t

At  t₁ = 25

θ₁ = 5(2)² - 6 = 14 c

At t₂ = 45

θ₂ = 5 (4)² - 12

θ₂ = 68 c

Average current 

I \(=\frac{Δ\theta}{Δt}\)

\(=\frac{68-14}{4-2}\)

\(=\frac{54}{2}\)

I = 27 ampere