Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Why does the Sun appear white at noon?

Answer»

The light is least scattered at noon.

2.

Both a spherical mirror and a thin spherical lens have a focal length of (-)15 cm. What type of mirror and lens are these?

Answer»

Both are concave. 

Alternative answer that should be given credit: Plano-concave lens

3.

The image formed by a concave mirror is observed to be real, inverted and larger than the object. Where is the object placed?

Answer»

Between the principal focus and the centre of curvature.

4.

Some work is done to move a charge Q from infinity to a point A in space. The potential of the point A is given as V. What is the work done to move this charge from infinity in terms of Q and V?

Answer»

The answer is: W=QV

5.

Two unequal resistances are connected in parallel. If you are not provided with any other parameters (eg. numerical values of I and R), what can be said about the voltage drop across the two resistors?

Answer»

Voltage-drop is same across both

6.

50 persons were examined through X-ray and observations were noted as under:Diameter of heart (in mm) : 120,121,122,123,124Number of patients: 5,8,12,9,6,10Find:(i) The mean diameter of heart,(ii) The median diameter of heart.

Answer»
Diameter of heart
(in mm)(xi)
Number of patients
(Frequecy) (fi)
fixicumulative frequency
(C.F.)
12056005
121896813
12212146425
1239110734
124674440
12510125050
n = \(\sum\)f= 50\(\sum\)fixi = 6133

\(\therefore\) Mean = \(\frac{\sum f_ix_i}{\sum f_i}\) = \(\frac{6133}{50}\) = 122.66

\(\frac{n}2=\frac{50}2=25\)

\(\therefore\) l = 122, c = 13, f = 12, h = 1

Medium = l + \(\cfrac{\frac{n}2-c}{f}\times h\) 

 = 122 + \(\frac{25-13}{12}\times 1\) 

 = 122 + \(\frac{12}{12}\times1\) 

 = 122 + 1 = 123

Hence, medium diameter of heart is 123 mm

7.

Name the part of a lens through which a ray of light passes without suffering any deviation.

Answer»

Optical centre.

8.

In the arrangement shown in figure there are two coils wound on a nonconducting cylindrical rod. Initially the key is not inserted in the circuit. Later the key is inserted and then removed shortly after.What are the two observations that can be noted from the galvanometer reading?

Answer»

There are momentary galvanometer deflections that die out shortly; the deflections are in opposite directions.

9.

Statement -1 in the following reaction : `C(s)+O_(2)(g)to CO_(2) (g), DeltaH=DeltaU-RT` Statement -2: `DeltaH` Is related to `DeltaU ` by the equation , `DeltaH=Delta+Deltan_(g)RT`A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - D
For reaction `C(s)+O_2(g)toCO_2(g),DeltaH=DeltaU`
10.

Assertion(A) : Heat of neutralisation of `HCl` and `NaOH` is same as that of `H_(2)SO_(4)` with `NaOH`. Reason(R ) : `HCl`, `H_(2)SO_(4)` and `NaOH` are all strong electrolytes.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - A
Heat of neutralisation of strong acid with strong base is contant `(-137 Kcal//mol^(-1))`
11.

A load impedance (200 + j0) ΩΩ is to be matched to a 50ΩΩ lossless transmission line by using a quarter wave line transformer (QWT). The characteristic impedance of the QWT required is

Answer»

For Quarter wave line transformer
\(Z^2_0\) = Zin . ZL
\(Z^2_0\) = 50 × 200
Z0=100 \( \Omega\)

12.

Statement-1: Diamonds are forever is generally quoted for diamond as rate of conversion of diamond to graphite at room condition is nearly zero. Statement-2 :At room condition, conversion of diamond into graphite is spontaneous.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - B
Thermodynamically it is favourable for diamond to turn into graphite, but it do not normally happen because there is high energy of activation for the process.
13.

Explain why are springs made of steel and not copper?

Answer»

A better spring will be one ,in which a large restoring force is developed on being deformed.This,in turn,depends upon the elasticity of the material of spring.As Young's Modulus of steel is greater than that of copper,steel is preferred to manufacture a spring.

14.

In the given circuit (Fig), key `K` is switched on the at `t = 0`. The ratio of current `i` through the cell at `t = 0` to that at `t = oo` will be A. `3 : 1`B. `1 : 3`C. `1 : 2`D. `2 : 1`

Answer» At `t=0`, the branch containing `L` will offer infinite resistance while the branch containing the capacitor will be effectively a short circuit. Hence, `(R )_(L=0)=R` and `(i)_(t=0)=(epsilon)/(R )`. Similarly at `t=oo`, `L` will offer zero resistance whereas `c` will be an open circuit. Hence effective resistance `=R+(6xx3R)/(6+3)=3R` and `(i)_(t=oo)=(epsilon)/(3R)`
`:.` The required ratio `=(epsilon)/(R )xx(3R)/(epsilon)=3 : 1`
15.

Calculate the dipole moment for a dipole having equal charges 2C and 2C separated with a distance of 2cm

Answer»

Explanation: The dipole moment of charge 2C and distance 2cm will be,
M = Q x d. Thus, M = 2 x 0.02 = 0.04 C-m.

16.

Name four tests carried out in a complete electrical installation

Answer»

Following tests shall be carried out: Wiring continuity test, Insulation resistance test, Earth continuity test, Earth resistivity test, Performance test, and any other tests as instructed by the Supervising Engineer.

17.

Statement-1 :When a gas at high pressure expands against vacuum, the magnitude of work done is maximum. Statement-2 :Work is a path functionA. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - D
Work done against vacuum is zero. It is free expansion
18.

Statement-1: Due to adiabatic free expansion temperature of real gas may increase. Statement-2 : In adiabatic free expansion, temperature is always constant irrespective of real or ideal gasA. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - C
In case of temperature is more than inversion temperature on adiabatic free expansion temperature of real gas increases.
19.

For a steady state closed system(a) Q + W > 0(b) Q + W < 0(c) Q + W = 0(d) None of the mentioned

Answer» Correct option is (c) Q + W = 0

To explain: For a steady state closed system, U+25B3E = 0.
20.

The usual temperature of a gas or liquid is(a) Dry bulb temperature(b) Wet bulb temperature(c) Standard temperature(d) None of the mentioned

Answer» Right answer is (a) Dry bulb temperature

For explanation: The usual temperature of a gas or liquid is dry bulb temperature.
21.

`4` identical balls of radius `R` and mass `m` are lying a gravity free space. The balls are in contact and there centres are forming vertices of a square of side `2R` in horizontal plane. One identical ball travelling vertically with a speed `v` hits the four balls symmetrically. The collision is perfectly elastic. The centre of the `4` stationery ball are at (`R`, `R`, `0`), (`R`, `-R`, `0`) and (`-R`, `-R`,`0`) initially. The speed of ball which was intitially travelling with speed `v` just after collision is A. `(v)/(3)`B. `(21v)/(11)`C. `v`D. `2v`

Answer» `V-(4v)/(3)=V_(2)`
`V_(2)=-V//3`
22.

`4` identical balls of radius `R` and mass `m` are lying a gravity free space. The balls are in contact and there centres are forming vertices of a square of side `2R` in horizontal plane. One identical ball travelling vertically with a speed `v` hits the four balls symmetrically. The collision is perfectly elastic. The centre of the `4` stationery ball are at (`R`, `R`, `0`), (`R`, `-R`, `0`) and (`-R`, `-R`,`0`) initially. The speed of ball `1` after collision is : A. `(sqrt(2))/(3)v`B. `(v)/(sqrt(2))`C. `(6)/(11)sqrt((2)/(3))`D. none of these

Answer» `mv=(4mv_(1))/(sqrt(2))+mv_(2)`……(`1`)
`1=(v_(1)=(v_(2))/(sqrt(2)))/(v//sqrt(2))`.....(`2`)
`v_(1)=(sqrt(2)v)/(3)`
23.

A particle of mass `1kg` is projected at an angle of `theta=pi//4` from horizontal with a muzzle velocity of `20 m//s`. A long slender rod of mass `5kg` and length `30 m` is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of `60m` from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (`g=10m//s^(2)`) If the rod tilts to an angle `theta` after collision, then A. `theta=0^(@)`B. `theta=cos^(-1)(40//42)`C. `theta=cos^(-1)(41//42)`D. `theta=cos^(-1)(27//28)`

Answer» Hint : First find the point where collision occurs using equation of trajectory. Then use conservation of angular momentum. After collision energy conservation is valid.
24.

What is the molecular mass of an ideal gas with pressure 1 atm, and density 10 g/L at temperature 27^oC?(a) 84.5 g(b) 135.1 g(c) 186.8 g(d) 246.3 g

Answer» Right option is (d) 246.3 g

For explanation: M = dRT/P = 10*0.0821*300/1 = 246.3 g.
25.

A particle of mass `1kg` is projected at an angle of `theta=pi//4` from horizontal with a muzzle velocity of `20 m//s`. A long slender rod of mass `5kg` and length `30 m` is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of `60m` from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (`g=10m//s^(2)`) If projectile is fired horizontally, it will A. hit the rod between `O` and `A` (except mid point)B. hit the rod at its mid pointC. hit the rod at `A`D. not hit the rod at all

Answer» Hint : First find the point where collision occurs using equation of trajectory. Then use conservation of angular momentum. After collision energy conservation is valid.
26.

What is the specific gravity of CO2 at 27^oC and pressure 1 atm with respect to air of with density 1 g/L?(a) 1.23(b) 1.55(c) 1.78(d) 1.96

Answer» Right choice is (c) 1.78

The explanation: Density of CO2 = PM/RT = 1*44/(0.0821*300) = 1.78 g/L, => Specific gravity = 1.78/1 = 1.78.
27.

Point 5 represents?(a) Dew point temperature(b) Dry bulb temperature(c) Wet bulb temperature(d) None of the mentioned

Answer» Correct answer is (b) Dry bulb temperature

The best explanation: Point 5 represents the dry bulb temperature.
28.

What is the compressibility of ideal gases?(a) 1(b) 2(c) 3(d) 4

Answer» The correct answer is (a) 1

The explanation is: Compressibility = PV/nRT, but for ideal gases PV = nRT, => Compressibility = 1.
29.

Which of the following is true about compressibility of real gases?(a) Z = 1(b) Z < 1(c) Z > 1(d) Both Z < 1 and Z > 1

Answer» The correct choice is (d) Both Z < 1 and Z > 1

The best I can explain: For any value of compressibility except 1, the gas is real.
30.

What is the specific gravity of CO at 27^oC and pressure 5 atm with respect to air (molecular wt. = 29 g) at 27^oC and pressure 10 atm?(a) 0.48(b) 0.56(c) 0.64(d) 0.72

Answer» Right option is (a) 0.48

Best explanation: Density of CO = 5*28/(0.0821*300) = 5.68 g/L, density of air = 10*29/(0.0821*300) = 11.77 g/L, => specific gravity = 5.68/11.77 = 0.48.
31.

25 J of work is done by a steady state system, what is the heat supplied to the system?(a) – 25 J(b) 25 J(c) 20 J(d) – 20 J

Answer» Right option is (b) 25 J

The explanation is: 0 = – 15 + Q.
32.

At what temperature, does SO2 with compressibility 2 has pressure 5 atm and molar volume 10 mole/s?(a) 300.5 K(b) 304.5 K(c) 310 K(d) 312.5 K

Answer» Correct answer is (b) 304.5 K

The best explanation: T = PV/zR = 5*10/(2*0.0821) = 304.5 K.
33.

What is thrust

Answer»

Thrust is the amount of push a rocket engine provides to the rocket. Propulsion works when matter (something you can touch-like a gas or a liquid) is pushed out the back of a spacecraft. The amount of thrust or push in a spacecraft is related to how much matter is leaving the engine and at what speed the matter is leaving, minus resistance.

34.

What is the pressure of CO2 gas with compressibility z = 0.8, if the ideal gas pressure of CO2 is 10 Pa, all other variables are same?(a) 5(b) 8(c) 10(d) 14

Answer» Right option is (b) 8

For explanation I would say: Pressure of CO2 = 0.8*10 = 8 Pa.
35.

What is the compressibility factor for an ideal gas?(a) 1(b) 2(c) 3(d) Depends on the gas

Answer» The correct answer is (a) 1

The best explanation: Compressibility of an ideal gas is always 1.
36.

A system in which the volume is invariant during a process is(a) Adiabatic system(b) Isobaric system(c) Isochoric system(d) Isothermal system

Answer» The correct answer is (c) Isochoric system

Explanation: A system in which the volume is invariant during a process is an Isochoric system.
37.

What is the compressibility factor of water with density 1 g/liter at 27^oC and 1 atm?(a) 0.25(b) 0.59(c) 0.73(d) 0.91

Answer» Correct choice is (c) 0.73

To explain I would say: z = PM/dRT = 1*18/(1*0.0821*300) = 0.73.
38.

90 g glucose is filled in a container at 10 atm, if the volume of container is 2 liter, what is the temperature of glucose (z = 1.5)?(a) 25.4^oC(b) 51.7^oC(c) 76.9^oC(d) 103.5^oC

Answer» Right choice is (b) 51.7^oC

Explanation: T = PV/znR = 10*2/(1.5*0.5*0.0821) = 324.8 K = 51.7^oC.
39.

What type of cooling coil is used in beverage cooler?

Answer»

Forced circulation type cooling

40.

What is the volume of 21 g of propane (z = 1.9) at 1 atm and 27^oC?(a) 23.4 liter(b) 37.5 liter(c) 42.1 liter(d) 59.6 liter

Answer» Correct choice is (a) 23.4 liter

Explanation: V = 1.9*0.5*0.0821*300/1 = 23.4 liter.
41.

What is the compressibility of neon (molar mass = 20) with density 20 g/liter at 27^oC and 100 atm?(a) 2.1(b) 3.5(c) 4(d) 6.8

Answer» Correct answer is (c) 4

The explanation is: z = PM/dRT = 100*20/(20*0.0821*300) = 4.
42.

What is the compressibility factor of a liquid of molar mass 90 g and density 10 g/liter at 27^oC and 2 atm?(a) 0.14(b) 0.39(c) 0.51(d) 0.73

Answer» Right answer is (d) 0.73

Explanation: z = PM/dRT = 2*90/(10*0.0821*300) = 0.73.
43.

What is the compressibility of methane with density 10 g/liter at 27^oC and 500 atm?(a) 32.5(b) 34.8(c) 39.6(d) 44.1

Answer» Right choice is (a) 32.5

The best explanation: z = PM/dRT = 500*16/(10*0.0821*300) = 32.5.
44.

What is the function of duct in air conditioning system?

Answer»

For the distribution of Air.

45.

In an ideal solution(a) All of the molecules have same intra-molecular force(b) All of the molecules may have same intra-molecular force(c) All of the molecules do not have same intra-molecular force(d) None of the mentioned

Answer» The correct option is (a) All of the molecules have same intra-molecular force

Easy explanation: In an ideal solution all of the molecules have same intra-molecular force.
46.

Name the instrument used to measure wind speed?

Answer»

Anemometer is use to measure the speed of wind and its direction.

47.

What is weathering?

Answer»

The process if disintegration and decomposition of rocks is known as “Weathering”.

48.

1 mole of cyclohexane (z = 1.2) is filled in a container at 27^oC and 4 atm, what is the volume of container?(a) 3.8 liter(b) 4.4 liter(c) 5.6 liter(d) 7.4 liter

Answer» The correct answer is (d) 7.4 liter

Explanation: V = 1.2*1*0.0821*300/4 = 7.4 liter.
49.

PQ is a solenoid. A magnetic needle is placed near the end ‘Q’ of the solenoid as shown in the figure. The solenoid acts as a bar magnet when current flows through it.(a) When the circuit is switched on, which pole of the magnetic needle is attracted towards Q ? (b) How did you arrive at this conclusion ? (c) Write any two methods to increase the magnetic strength of a current carrying solenoid ?

Answer»

(a) South pole. 

(b) When compass is brought near the solenoid (acting as a bar magnet), its magnetic field of lines interact with that of the solenoid, like poles repel each other. 

(c) (i) Increases the number of turns in a solenoid 

(ii) Increases the current through the solenoid.

50.

Which of the following is not the unit of R?(a) Atm.liter/K.mole(b) Pa.m^3/K(c) N.Kg.m^3/K.mole(d) None of the mentioned

Answer» Correct answer is (c) N.Kg.m^3/K.mole

Explanation: N.Kg.m/K.mole is the unit of R.