This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Replacement of Cl of chlorobenzene to give phenol requires drastic conditions. But chlorine of 2,4-dinitrochlorobenzene is readily replaced because(a). NO2 donates e- at meta position (b). NO2 withdraws e- from ortho/para positions (c). NO2 makes ring electron rich at ortho and para positions (d). NO2 withdraws e- from meta position. |
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Answer» (b). NO2 withdraws e- from ortho/para positions |
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| 2. |
Differentiate between roasting and calcination. |
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Answer» Roasting- Roasting is the process of converting an ore into its metallic oxide by heating strongly temperature insufficient to melt in excess of air. 4FeS2 + 11O2 → 2Fe2O3 + 8SO2 2Cu2S + 3O2 → 2Cu2O + 2SO2 2ZnS + 3O2 → 2ZnO + 2SO2; S + O → SO2↑ Calcination- Calcination is the process in which concentrated ore is heated strongly is the presence of a limited supply of air in a rever beratory furnance. By doing so moisture is removed and impurities escape as their volatile oxides. CaCO3 → CaO + CO2; Al2O3.2H2O → Al2O3 +2H2O 2Al(OH)3 → Al2O3 + 3H2O CuCO3Cu(OH)2 → 2CuO +H2O +CO2 |
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| 3. |
Phenolphthalein does not act as an indicator for the titration between:(a) KOH and H2SO4 (b) Ba(OH)2 and HCl(c) NaOH and acetic acid (d) Oxalic acid and KMnO4 |
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Answer» Correct option: (d) Oxalic acid and KMnO4 Explanation: Phenolphthalein is an acid-base indicator. |
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| 4. |
Why are Cd2+ salts white? |
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Answer» Cd2+ salt is white because Cd2+ ion has d-orbital which is completely filled (4d10) |
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| 5. |
Write the IUPAC name of [Pt(NH3)3Cl2]Cl2 |
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Answer» [Pt(NH3)3Cl2]Cl2 - Dieamine diechlorido platinum (IV) chloride |
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| 6. |
Blood is:(a) Strong acidic (b) Strongly basic(c) Neutral (d) Slightly basic |
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Answer» Correct option: (d) Slightly basic Explanation: Blood is alkaline having pH in between 7.0 to 7.4 |
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| 7. |
Calculate the [OH-] of a solution whose pH is 9.62. |
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Answer» pH + pOH = 14 pOH = 14 – pH = 14 – 9.62 = 4.38 pOH = 4.38 = – log10 [OH– ]; 4.38 = – log10 [OH– ] log10[ OH– ] = – 4.38 ; [OH–] = antilog (–4.38) = antilog (5 – 4.38 – 5) = antilog (0.62 – 5) = antilog (0.62) x 10–5 = 4.169 × 10–5 mol dm–3. |
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| 8. |
Explain the buffer of acidic buffer. |
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Answer» Consider acidic buffer mixture, CH3COOH ⇌ CH3COO- + H+; CH3COONa → CH3COO- + Na+ Here, acetic acid is a weak electrolyte, in its solution there exists equilibrium between it’s ions and molecules. Where as sodium acetate completely dissociates into it’s ions. Therefore, the buffer mixture contains large number of CH3COO- ions followed by Na+, H+, CH3COOH. Case (i) When an acid added to this solution: H+ ion of the acid combines with CH3COO- ion in buffer solution and makes equilibrium with acetic acid. CH3COO- + H+ ⇌ CH3COOH As a result, pH remains constant. Case (ii) When a base is added to this solution: OH- ion of the base combines with H+ ion in buffer solution forms water molecule. H++ OH- → H2O. As a result, pH remains constant. |
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| 9. |
The Henderson’s equation used to calculate the pOH of basic buffer is: |
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Answer» Correct option: (a) Explanation: This is Henderson equation for for basic buffer mixtures. |
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| 10. |
Represent the following compounds using Stock notation:Cu2O, SnCl4, MnO, Fe2O3, V2O5 |
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Answer» Cu2O - Cu2(l)O SnCl4 - Sn(IV)Cl4 MnO - Mn(II)O Fe2O3 - Fe2(III)O3 V2O5 - V2(V)O5 |
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| 11. |
Explain the following in terms of electron transfer concept: 1. Oxidation 2. Reduction 3. Oxidising agent 4. Reducing agent |
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Answer» 1. Oxidation: Loss of electron(s) by any species. 2. Reduction: Gain of electron(s) by any species. 3. Oxidising agent: Any species which accepts electrons). 4. Reducing agent: Any species which donates electron^). |
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| 12. |
TRATAKA is: A. Purifies lungs B. Improves respiratory function C. Removes acidity D. None of the above |
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Answer» Correct answer is D. None of the above |
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| 13. |
Consider the following reactions at equilibrium and determine which of the indicated changes will cause the reaction to proceed to the right.(1) CO(g) + 3H2(g) ⇋ CH4(g) + H2O(g) (add CH4)(2) N2(g) + 3H2(g) ⇋ 2NH3(g) (remove NH3)(3) H2(g) + F2(g) ⇋ 2HF(g) (add F2)(4) BaO(s) + SO3(g) ⇋ BaSO4(s) (add BaO)(a) 2, 3 (b) 1, 4 (c) 2, 4 (d) 2, 3, 4 |
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Answer» Correct option (a) 2, 3 |
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| 14. |
Find the oxidation number of Cr in [Cr(NH3)4Cl2]+ |
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Answer» Here the [Cr(NH3) 4Cl2]+ has a positive charge. So, Oxidation number of Cr in [Cr(NH3) 4Cl2]^+ is +3 |
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| 15. |
Write the IUPAC name of [Cr(NH3)4Cl2]+ |
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Answer» [Cr(NH3)4Cl2]+ Tetra-amine-diechlorido chromium (III) ion. |
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| 16. |
The oxidation state of Cr in [Cr ((NH3)4Cl2]+ isa). +3 b). +2 c). +1 d). 0 |
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Answer» The oxidation state of Cr in [Cr ((NH3)4Cl2]+ is +3 |
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| 17. |
In figure (1) below oxygen molecules represented by unshaded spheres, and chlorine molecules, represented by shaded spheres, are in separate compartments. Figure(2) shows the equilibrium state of the system after the stopcock separating the two compartments is opened. Assuming that oxygen and the chlorine behave as ideal gases, what are the signs (+, -, or 0) of ΔH, ΔS, and ΔG for this process?(a) ΔH = +, ΔS = -, ΔG = +(b) ΔH = 0, ΔS = +, ΔG = -(c) ΔH = 0, ΔS = -, ΔG = +(d) ΔH = -, ΔS = +, ΔG = - |
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Answer» Correct option (b) ΔH = 0, ΔS = +, ΔG = - |
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| 18. |
One mole of the complex compound gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with two moles of AgNO3 solution to yield two moles of AgCl (s). The structure of the complex is : a). [Co(NH3)5Cl]Cl2 b). [Co(NH3)5Cl2]2NH3 c). [Co(NH3)4Cl2]Cl. NH3 d). [Co(NH3)4Cl]Cl2. NH3 |
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Answer» a). [Co(NH3)5Cl]Cl2 |
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| 19. |
In which of the following, the number of carbon atoms does not remain same when carboxylic acid is obtained by oxidation? a). CH3COCH3 b). CCl3CH2CHO c). CH3CH2CH2OH d). CH3CH2CHO |
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Answer» a). CH3COCH3 |
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| 20. |
Read the passage given below and answer the following questions All those organic compounds in which a metal atom is directly linked to the carbon Atom is called organometallic compounds like CH3COOAg, CH3COONa, C2H5ONa are not organometallic compounds because the metal Atom is linked to oxygen Atom and not to carbon atom. Alkyl magnesium halides are commonly known as Grignard’s reagent . They are highly reactive compounds they react with all of those compounds which can donate a proton then they form hydrocarbons. The hydrocarbon form depends upon the alkyl group of Grignard’s reagent. Grignard’s reagent reacts with water or moisture oxygen and carbon dioxide therefore it is prepared and used in absence of Air moisture under inert atmosphere. In Grignard's reagent added carbon magnesium bond is covalent but highly polar. The carbon atom pulls electrons from electropositive magnesium. Thus the magnesium halogen bond is essentially Ionic.i. ASSERTION – Grignard reagent should be prepared under anhydrous conditions.REASON- Grignard’s reagent reacts with moisture to form alkane a). Both assertion and reason are true, and reason is the correct explanation of assertion. b). Both assertion and reason are true, but reason is not the correct explanation of assertion. c). Assertion is true but reason is false. d). Both assertion and reason are false.ii. ASSERTION - Sodium acetate is on organometallic compound REASON- The C-Na bond is ionic a). Both assertion and reason are true, and reason is the correct explanation of assertion. b). Both assertion and reason are true, but reason is not the correct explanation of assertion. c). Assertion is true but reason is false. d). Both assertion and reason are false.iii. ASSERTION- In presence of ether ethyl chloride reacts with, magnesium to form ethyl magnesium chloride REASON- Ether contains acidic protons a). Both assertion and reason are true, and reason is the correct explanation of assertion. b). Both assertion and reason are true, but reason is not the correct explanation of assertion. c). Assertion is true but reason is false. d). Both assertion and reason are falseiv. ASSERTION- The reaction between Grignard's reagent with alcohol give rise aldehydes. REASON - Alcohol contain acidic - H atom (a). Both assertion and reason are true, and reason is the correct explanation of assertion. (b). Both assertion and reason are true, but reason is not the correct explanation of assertion. (c). Assertion is true but reason is false. (d). Both assertion and reason are falsev. ASSERTION- Organo metallic compounds are those which have one or more Carbon metal bond. REASON - Metallic carbonyls are organometallic compounds having both π and σ bonds a). Both assertion and reason are true, and reason is the correct explanation of assertion. b). Both assertion and reason are true, but reason is not the correct explanation of assertion. c). Assertion is true but reason is false. d). Both assertion and reason are false |
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Answer» (i). a (ii). d (iii). c (iv). c (v). a |
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| 21. |
Read the passage given below and answer the following questionsPresence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e.,µ = \(\sqrt{n(n+2)}\) Where n = number of unpaired electrons and = magnetic moment (in Bohr magneton, B.M.). If n = 1, then = 1.73 B.M.i. Among the transition metal ion given below, the one with lowest moment is :a). 3d7 b). 3d9 c). 3d2 d). 3d3ii. Which one of the following transition metal ions is paramagnetic? a). Ag2+ b). Zn2+ c). Cu2+ d). Au+iii. The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it is: a). 2 b). 3 c). 4 d). 5iv. The value of 'spin only' magnetic moment or one o the following configuration is 2.84 BM. The correct one is: a). d4 (in strong ligand field) b). d4 (in weak ligand field) c). d3 (in weak as well as strong fields) d). d5 (in strong ligand field) |
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Answer» (i). b (ii). c (iii). b (iv). a |
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| 22. |
What is the definition of an adult in a household? |
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Answer» Adult means a person who has completed 18 years of age. |
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| 23. |
The speed of sound in a mixture of `n_1=2` moles of He , `n_2=2` moles of `H_2` at temperature `T=972/5 K` is `etaxx10m//s`.Find `eta`.(Take `R=25/3J` /mole-K) |
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Answer» `v=sqrt((gammaRT)/M)` `M=(4xx2+2xx2)/4=3g` `gamma=1+2/f=1+(2xx(2+2))/(2xx3+2xx5)=3/2` `therefore v=sqrt(3/2xx25/3xx1000/3xx972/5)=900 m//s` |
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| 24. |
i). A reaction is first order in A and 2nd order in B. a). Write the differential law b). How is rate affected then consideration of B is tripled? c). How is rate effected when concentration of both A and B is doubled? (ii). in reference to Freundlich's adsorption Isotherm write the expression for adsorption of gases on solid in form of an equation. What is the nature of plot log\(\Big(\frac{x}{m}\Big)\) vs log C for the adsorption of solutes from solutions. |
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Answer» (i) It is given that a reaction is first order in A and second order in B. (a) The differential rate equation is as follows: Rate =k[A][B]2 (b) On increasing the concentration of B three times, rate becomes 9 times. (d[B])2 = 32 = 9 (c) When the concentrations of both A and B are doubled, rate becomes 8 times. d[A](d[B])2 = 2×22 = 8 (ii) The Freundlich's adsorption Isotherm is written as x/m = Kp1/n It is also written as Log x/m=log K+1/n log P where, x = mass of adsorbate m = mass of adsorbent p = Equilibrium pressure of adsorbate K = Constant For the adsorption of solutes from solution the nature of plot of log\(\Big(\frac{x}{m}\Big)\) vs log C is linear. |
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| 25. |
Which of the following statements is not correct for a nucleophile ?(a) Nucleophiles attack at low electron density sites(b) Nucleophiles are not electron seeking(c) Nucleophile is a Lewis acid(d) Ammonia is a nucleophile |
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Answer» Correct option (c) Nucleophile is a Lewis acid Explanation: Reason : Nucleophiles are electron rich species so act as Lewis base. |
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| 26. |
Correct IUPAC name of the following compound is(a) Pentanetrioic acid(b) Propane-1,2,3-tricarboxylic acid(c) 2-carboxypentanedioic acid(d) Propanetrioic acid |
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Answer» Correct option (b) Propane-1,2,3-tricarboxylic acid |
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| 27. |
What is the procedure to register oneself for employment? |
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Answer» Household having adult members desirous of seeking unskilled wage employment in MGNREGA may apply for registration. The application for registration may be given on prescribed form or plain paper to the local Gram Panchayat. To allow maximum opportunities to families that may migrate, registration shall also be opened throughout the year at the GP office. |
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| 28. |
How is Household defined in MGNREGA? |
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Answer» “Household” means the members of a family related to each other by blood, marriage or adoption and normally residing together and sharing meals or holding a common ration card. |
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| 29. |
Which one of the following pairs of solution is not an acidic buffer ?(a) H2CO3 and Na2CO3(b) H3PO4 and Na3PO4(c) HClO4 and NaClO4 (d) CH3COOH and CH3COONa |
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Answer» Correct option (c) HClO4 and NaClO4 HClO4 and NaClO4 cannot act as an acidic buffer as HClO4 is strong Acid |
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| 30. |
Observe the figure, identify the part "X". |
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Answer» Bronchioles. |
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| 31. |
Name the system that you observed in the picture. |
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Answer» Lymphatic system of human body. |
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| 32. |
Observe the following paragraph and answer the questions.According to Weismann prediction, every organism undergoes two kinds of cell divisions. In mitosis, there is no change in chromosomal number (2n) and in Meiosis, chromosomal number is reduced to half (n).(1) What does 'n' and '2n' indicate ? (2) In which cells, Meiosis takes place ? (3) What happens if chromosomal number is not reduced in Meiosis ? (4) Which type of cell division occurs in the sperm cells ? |
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Answer» (1) 'n' indicates haploid state and '2n' indicates diploid state of chromosomes. (2) Meiosis occurs in sex cells during the information of gametes. (3) The chromosomal number will not be constant in successive generations. (4) Meiosis. |
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| 33. |
Platythelmenthes : Flame cells, Arthropods : ? |
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Answer» Green glands or Malpighian tubules. |
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| 34. |
I carry the messages towards the Central Nervous System from Sense organs. Who am I ? |
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Answer» Sensory neuron. |
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| 35. |
Which of the following group represent the scientists those associated with evolution.A. Walther Flemming, F.W. Went, Gallen, LavoisierB. Charles Darwin, Lamark, A.R. Wallace, Charles Lyell |
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Answer» Group -B →Charles Darwin, Lamark, A.R. Wallace, Charles Lyell |
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| 36. |
Observe the figure and answer the following questions. (1) To which life process, the above shown picture is associated with ? (2) Name the labelled parts A and B in the given picture. (3) Name the reaction that takes place in A. (4) Name the part in the given picture through which oxygen is liberated. |
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Answer» (1) Photosynthesis (2) A - Stroma ; B - Granum (3) Dark reaction (4) In granum during light reaction. |
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| 37. |
Expand "ASHA". |
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Answer» Accredited Social Health Activist. |
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| 38. |
What is degree of unsaturation of following compound(a) 14 (b) 10 (c) 12 (d) 8 |
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Answer» Correct option (a) 14 Four rings and 10 double bond present |
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| 39. |
Identify the scientist with the help of this paragraph.He formulated and proposed a widely used chemical formula for photosynthesis in the year 1931. His opinion was "for each molecule of carbohydrate formed, one molecule of water and one molecule of oxygen is produced". |
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Answer» C.B. Van Neil. |
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| 40. |
What is the significance of door to door survey in identification of eligible household under MGNREGA? |
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Answer» Door to door survey helps to identify eligible households who have been missed out and wish to be registered under the Act. It should be undertaken by each GP every year and need to be ensured that this survey is held at that time of the year when people have not migrated to other areas in search of employment or for other reasons. |
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| 41. |
Who can apply for Job Card Registration? |
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Answer» A household having adult members desirous of seeking unskilled employment in MGNREGA may apply for registration. |
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| 42. |
What is the frequency of Job Card registration? |
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Answer» Throughout the Year |
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| 43. |
For how many years is the registration for Job Card valid? |
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Answer» The registration is valid for five years and may be renewed/re-validated following process prescribed for renewal/revalidation as and when required. |
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| 44. |
Which of the following statement is/are true for carbide (i) Silicon & Boron carbides are covalent(ii) Silicon & Boron carbides are hydrolysed(iii) Calcium & Barium carbide on hydrolysis give ethyne (acetylene)(iv) Berrylium carbide resembles to Aluminium carbide as both give methane on hydrolysis(a) (i) and (ii)(b) (i), (ii) and (iii)(c) (i), (iii) and (iv)(d) all are true |
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Answer» Correct option (c) (i), (iii) and (iv) |
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| 45. |
Who should apply for Job Card on behalf of a Household? |
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Answer» Any adult member can apply on behalf of Household. |
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| 46. |
What are the issues the Gram Panchayat need to verify when application was made for Job Card? |
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Answer» The Gram Panchayat need to verify: - Whether the household is really an entity as stated in the application - Applicant households are local residents in the GP concerned - Applicants are adult members of the household The process of verification shall be completed not later than a fortnight after the receipt of the application. |
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| 47. |
Can all adult members of a household register for Job Card? |
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Answer» Adult members of a household willing to do unskilled manual work can register themselves to obtain a job card under MGNREGA. |
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| 48. |
Is there any pre-printed form for providing details while registering for Job Card? |
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Answer» The State Government may make a printed form available as per format prescribed in the relavant Annexures of the MGNREGA Operational Guidelines 2013. However, a printed form should not be insisted upon. |
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| 49. |
Which has highest ionic mobility in aqueous solution?(a) Bc2- (b) Mg2- (c) Ba2- (d) Sr2- |
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Answer» Correct option is (c) Ba2- Due to the high heat of hydration of small cations, ionic mobility for the small cations is low. Order of ionic mobility is Be2+< Mg2+< Sr2+ < Ba2+ |
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| 50. |
In hydrogen atom, the energy of second shell `e^(Θ`A. `-5.44xx10^(-19)J`B. `-5.44xx10^(-19)KJ`C. `-5.44xx10^(19)Cal`D. `-5.44xx10^(-19)erg` |
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Answer» Correct Answer - A `E_(2)`= -3.4 eV ` -3.4xx1.6xx10^(-19)`J `= -5.44xx10^(-19)`J |
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