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1.

`K_(2)CrO_(4)` is converted to `K_(2)Cr_(2)O_(7)` byA. conc. `H_(2)SO_(4)`B. KOHC. `K_(2)CO_(3)`D. `KNO_(3)`

Answer» Correct Answer - A
In acid medium it gets converted to dichromate.
Discussion
2.

A compound `(A)` is used in paints instead of salts of lead. . Compound(A) is obtained when a white compound `(B)` is strongly heated . Compound `(B)` is insoluble in water but dissolves in sodium hydroxide forming a solution of compound `(C )` the compounds `(A)` on heating with coke gives a metal `(D)` and a gas `(E)` which burns with blue flame . `(B)` also dissolves in ammonium sulphate solution mixed with ammonium hydroxide. solution of compound `(A)` in dilute `HCl` gives a bluish white//white precipitate `(F)` with excess of `(F)` with excees of `K_(4)[Fe(CN)_(6)]` identify `(A)` to `(F)` and explain the reactions.A. Solution (F)B. Solution (H)C. A and B bothD. None of these

Answer» Correct Answer - A
`Fe^(2+)+K_(4)[Fe(CN)_(6)]rarr`White ppt
`Fe^(3+)+K_(4)[Fe(CN)_(6)]rarr` Blue colouration
`Fe^(2+)+K_(4)[Fe(CN)_(6)]rarr `Blue colouration
`Fe^(3+)+K_(3)[Fe(CN)_(6)]rarr ` Red - brown colouration
Discussion
3.

Number of salts among the following that will give metal on heating `Zn(NO_(3))_(2),AgNO_(3),Cu(NO_(3))_(2),Hg(NO_(3))_(2)`

Answer» Correct Answer - 2
`AgNO_(3)overset(Delta)(rarr)Ag+NO_(2)+(1)/(2)O_(2)`
`Hg(NO_(3))_(2)overset(Delta)(rarr)Hg+2NO_(2)+O_(2)`
`(i)underset((A))(Pb(NO_(3))_(2))+2NaClrarrunderset((B))(PbCl_(2))+1NaNO_(3)`
`(ii) PbCl_(2)+H_(2)S underset((C ))(PbS)+2HCl
`(iii) underset((B))(PbCl_(2))+2Nal rarr underset((D))(PbI_(2))+2NaCl`
`(iv) Pb(NO_(3))_(2) rarr PbO+2NO_(2)+(1)/(2)O_(2)`
Discussion
4.

Match the following `:`A. `{:("Compound",,"Characteristics",),((A)TiCl_(4),,(p)"Liquid at room temperature",):}`B. `{:("Compound",,"Characteristics",),((B)CaCl_(2),,(q)"Has the highest MP among the compounds given",):}`C. `{:("Compound",,"Characteristics",),((C)FeCl_(3),,(r)"Aqueous solution is acidic",):}`D. `{:("Compound",,"Characteristics",),((D) ZnCl_(2),,(s)"Undergoes hydrolysis",),(,,(t)"Solid at room temperature",):}`

Answer» Correct Answer - `Ararrp,r,s;Brarr q,t; C rarr r,s,t;Drarr r,s,t`
Conceptual
Discussion
5.

The oxidation state of chrominium in the final product formed in the reaction between `KI` and acidified potassium dichromate soluttion is

Answer» Correct Answer - A
`(a) Cr_(2)O_(7)^(2-)+6I^(_)+14H^(+)rarr3I_(2)+7H_(2)O+2Cr^(3+)` oxidation state of Cr is `3+`
Discussion
6.

`(NH_(4))_(2)Cr_(2)O_(7)overset(Delta)rarrN_(2)+4H_(2)O+X` ( Chromium compound), oxidation state of chromium that changes from `(NH_(4))_(2)Cr_(2)O_(7)` to X isA. 3B. 4C. 5D. -3

Answer» Correct Answer - D
`(NH_(4))_(2)overset(+VI)(Cr_(2)O^(7))overset(Delta)(rarr)overset(+III)(Cr_(2)O_(3)+N_(2)+4H_(2)O`
Discussion
7.

Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `MnO_(4)^(2-)+H^(+)rarr" "(p)` One of the products of transition element is paramagneticB. `Cu^(+)(aq)rarr" "(q)` Disproportionation reaction.C. `Cr_(2)O_(7)^(2-)(s)+H^(+)("conc.")+Cl^(-)(s)" "(r)` One of the products is liberated as coloured vapours.D. `Fe_(2)(SO_(4))_(3)+I^(-)rarr" "(s)` In one of the products central atom exhibits its highest oxidation state.

Answer» Correct Answer - A::B::C::D
`CuSO_(4),H_(2)SO_(4),KMnO_(4),K_(2)Cr_(2)O_(7),`
Bleaching powder, `Cl_(2),NaNO_(2)+HCl` gives `I_(2)`
Discussion
8.

Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `O_(2)^(-)rarrO_(2)+O_(2)^(2)" "(p)` redox reactionB. `CrO_(4)^(2-)+H^(+)rarr" "(q)` One of the products has trigonal planar structureC. `MnO_(4)^(-)+NO_(2)^(-)+H^(+)rarr" "(r )` dimeric bridged tetrahdedral metal ionD. `NO_(3)^(-)+H_(2)SO_(4)+Fe^(2+)rarr" "(s)` disproportionation

Answer» Correct Answer - `(A-p,p,s);(B-r);(C-p,q);(D-p)`
Conceptual
Discussion
9.

Zn reacts with cold and very dil `HNO_(3)` to giveA. `NH_(4)NO_(3)`B. `N_(2)O`C. `NO`D. `NO_(2)`

Answer» Correct Answer - A
`3Zn+8HNO_(3)("dil")rarr3Zn(NO_(3))_(2)+2NO+4H_(2)O`
Discussion
10.

`underset(("Purple"))(A)rarrunderset(("Green"))(B)+underset(("Black"))(C)+underset(("Gas"))(D)` B cannot be converted to A byA. `KOH`B. `CO_(2)` is formedC. `Cl_(2)`D. `O_(2)`

Answer» Correct Answer - A
KOH cannot oxidise `B rarr A`
Discussion
11.

In the following sequence in aqueous solution, the species X, Y and Z, respectively, are `S_(2)O_(3)^(2-) overset(Ag^(+))rarrunderset(("Clear solution"))X overset (Ag^(+))rarr underset(("White ppt."))Y overset("With time")rarr underset(("Black ppt."))Z`A. `[Ag(S_(2)O_(3))_(2)]^(3-),Ag_(2)S_(2)O_(3),Ag_(2)S`B. ` [Ag(S_(2)O_(3))_(3),Ag_(2)SO_(3),Ag_(2)S`C. `[Ag(SO_(3))_(2)]^(3-),Ag_(2)S_(2)O_(3),Ag`D. `[Ag(SO_(3))_(3)]^(3-),Ag_(2)SO_(4),Ag`

Answer» Correct Answer - A
`Ag^(+)+S_(2)O_(3)^(2-)rarrunderset((X))([Ag(S_(2)O_(3))_(2)]^(3-))overset(Ag^(+))(rarr)(darr)overset("Withtime")(rarr)underset("balck (Z))(Ag_(2)S)`
Discussion
12.

Chrome iron ore (x) was heated with dry `Na_(2)CO_(3)` in the presence of quick lime and air in a furnace. The mixture was extracted with water and filtered. The filtrate was yellow(A) which on adding conc. `H_(2)SO_(4)` turned to orange red. The solution was evaporated and cooled. The crystals of B were obtained. To the crystals in aqueous solution, `NH_(4)Cl` was added. On fractional crystallization, orange red crystals (C ) is formed. Compound (B) will beA. NaClB. `Na_(2)Cr_(2)O_(7)`C. `(NH_(4))_(2)Cr_(2)O_(7)`D. `NH_(4)Cl`

Answer» Correct Answer - B
`Na_(2)Cr_(2)O_(7)+2NH_(4)Clrarr(NH_(4))_(2)Cr_(2)O_(7)+2NaCl`
`(NH_(4))_(2)Cr_(2_)O_(7)` is less soluble than NaCl
Discussion
13.

The waste solution from Kipps apparatus when evaporated and crystallized givesA. `ZnSO_(4)`B. `FeSO_(4)`C. ``Al_(2)(SO_(4))_(3)`D. `Na_(2)SO_(4)`

Answer» Correct Answer - B
`FeS+H_(2)SO_(4)rarrFeSO_(4)+H_(2)Suarr`
Discussion
14.

Match the following `:` Compound CharacteristicsA. Litharge`" "(p)PbO`B. Red lead`" "(q)PbO_(2)`C. Purple of Cassius`" "(r(NH_(4))_(2)[SnCl_(6)]`D. `{:("Butter of tin",,(s)"Au adsorbed over"Sn(OH)_(4)),(,,(t)"Anode plate in lead accumulator"):}`

Answer» Correct Answer - `A rarr p,t:,B rarr q:C rarr s:D rarr r`
Conceptual
Discussion
15.

The correct order of stability isA. `Pb^(4+)gtSn^(4+)`B. `Pb^(4+)gtPb^(2+)`C. `Sn^(2+)gtSn^(4+)`D. `Pb^(2+)gtSn^(2+)`

Answer» Correct Answer - D
Inert pair effect.
Discussion
16.

Transition metals usually from coloured complexes and d-d transitions `(t_(2g)hArre_(g))` are responsible for colour as the energy difference between `t_(2g)` and `e_(g)` lies in visible region. But all the coloured ions are not dut to d-d transition but charge transfer bands also play important roles. Charge transfer bands may be of two types. (i) ligand to metal (CTLM)`" "(ii)` metal to ligand (CTML). Charge transfer transition always produces intense colour as compared to d-d transition. `MnO_(4)^(-)` is dark purple coloured though Mn is in `(+VII)` oxidation state with `3d^(@)` configurationA. due to d-d transitionB. due to CTML spectraC. due to CTLM spectraD. None of these

Answer» Correct Answer - C
Conceptual
Discussion
17.

Photography is based on the nature of silver halides. Except AgF, the silver halides are photosensitive. These undergo decomposition in light and turn black due to formation of free silver. `2AgBroverset(light)to2Ag+Br_2` The photography films are prepared by adding `20%` aqueous solution of `AgNO_3` to `NH_4Br` solution containing gelatic. When such a film is exposed, emulsion gets affected and a latent image is formed on the film. When this exposed film or plate is dipped ina developer which contains a reducing agent, the part affected most during exposure are reduced to the maximum. The image becomes visible. It is called a negative. The remaining sensitive emulsion on the negative is removed by dissolving it in hypo solution (fixer). Fihnally, a positive of the nagative already prepared is made on silver bromide paper. Q. Silver bromide dissolves in hypo solution forming:A. `Ag_(2)S_(2)O_(3)`B. `Ag_(20S`C. `Na_(3)[Ag(S_(2)O_(3))_(2)]`D. `NaAgS_(2)O_(3)`

Answer» Correct Answer - C
Conceptual
Discussion
18.

Transition metals usually from coloured complexes and d-d transitions `(t_(2g)hArre_(g))` are responsible for colour as the energy difference between `t_(2g)` and `e_(g)` lies in visible region. But all the coloured ions are not dut to d-d transition but charge transfer bands also play important roles. Charge transfer bands may be of two types. (i) ligand to metal (CTLM)`" "(ii)` metal to ligand (CTML). Charge transfer transition always produces intense colour as compared to d-d transition. Select the correct statementA. In CTML, no net reduction - oxidation takes place because of the short life time of excited state.B. `Cu_(2)O` is a red coloured salt.C. Vermilon `(HgS)` is a red coloured compound.D. All of these

Answer» Correct Answer - D
Conceptual
Discussion
19.

Photography is based on the nature of silver halides. Except AgF, the silver halides are photosensitive. These undergo decomposition in light and turn black due to formation of free silver. `2AgBroverset(light)to2Ag+Br_2` The photography films are prepared by adding `20%` aqueous solution of `AgNO_3` to `NH_4Br` solution containing gelatic. When such a film is exposed, emulsion gets affected and a latent image is formed on the film. When this exposed film or plate is dipped ina developer which contains a reducing agent, the part affected most during exposure are reduced to the maximum. The image becomes visible. It is called a negative. The remaining sensitive emulsion on the negative is removed by dissolving it in hypo solution (fixer). Fihnally, a positive of the nagative already prepared is made on silver bromide paper. Q. Silver bromide dissolves in hypo solution forming:A. alkaline solution of pyrogallolB. alkaline solution of quinolC. either (A) or (B)D. neither (A) nor (B)

Answer» Correct Answer - C
Conceptual
Discussion
20.

Match the compounds in column I with the products obtained on heating them in column II `:` A. `FeSO_(4)" "(PSO_(2)`B. `CuSO_(4)" "(Q)SO_(3)`C. `AgNO_(3)" "(R ) O_(2)`D. `{:(Zn(SO_(3))_(2),,(S)NO,,),(,,(T)NO_(2),,):}`

Answer» Correct Answer - `A-P,Q;B-Q;C-R,T;D-R,T`
Conceptual
Discussion
21.

The black colored compounds areA. `Fe_(2)O_(3)`B. `FeO`C. `Cu_(2)O`D. `CuO`

Answer» Correct Answer - B::D
`Fe_(2)O_(3)` and `Cu_(2)O` are red color.
Discussion
22.

Which of the following compounds are red in color ?A. `Ag_(2)CrO_(4)`B. `CrO_(2)Cl_(2)`C. `K_(2)Cr_(2)O_(7)`D. `Cu_(2)O`

Answer» Correct Answer - A,B,C,D
All have red color.
Discussion
23.

Which of the following ions will give a coloured precipitate with lead nitrate solutionA. `S^(2-)`B. `CrO_(4)^(2-)`C. `I^(-)`D. `SO_(4)^(2-)`

Answer» Correct Answer - A,B,C
`PbSO_(4)` is white
Discussion
24.

The color of B isA. BrownB. YellowC. BlackD. Blue

Answer» Correct Answer - A
`Cu_(2)[Fe(CN)_(6)]darr`
Discussion
25.

Match the following `:`A. `{:("Compound",,"Characteristics",),((A) PbO_(2),,(p)"Red pigment",):}`B. `{:("Compound",,"Characteristics",),((B) Pb_(3)O_(4),,(q)"Reducing agent",):}`C. `{:("Compound",,"Characteristics",),((C) SnCl_(2),,(r)"Oxidizing agent",):}`D. `{:("Compound",,"Characteristics",),((D) SnCl_(4),,(s)"Soluble in benzene",),(,,(t)"Mordant",):}`

Answer» Correct Answer - `Ararrr;,Brarrp,r:Crarrq:Drarrs,t`
Conceptual
Discussion
26.

ZnO shows yellow colour on heating due toA. d-d transitionB. charge transfer spectraC. higher polarization caused by ionD. presence of F- center.

Answer» Correct Answer - D
due to F- centers ZnO shows varies colours in different temperature
Discussion
27.

Which of the following respond to chromyl chloride testA. `SnCl_(2)`B. `NaCl`C. `PbCl_(2)`D. `AgCl`

Answer» Correct Answer - B
Chronyl chloride test for only free chloride ions `(Cl^(-))`
Discussion
28.

The compound formed during goldent yellow spangle test isA. `PbCl_(2)`B. `PbCrO_(4)`C. `PbS`D. `PbI_(2)`

Answer» Correct Answer - D
KI was added to `Pb^(2+)` solution and the solution was boiled and cooled. Golden yellow spangles appear.
Discussion
29.

When ferrous oxalate is heated in the absence of air, the compound obtained isA. FeB. FeOC. `Fe_(2)O_(3)`D. `Fe_(3)O_(4)`

Answer» Correct Answer - B
`Fe(C_(2)O_(4))underset(Delta)(rarr) FeO+CO+CO_(2)`
Discussion
30.

Which one of the following is used in eye lotions?A. `AgNO_(3)`B. `CuSO_(4)`C. `ZnSO_(4)`D. `FeSO_(4)`

Answer» Correct Answer - C
`4Zn+10HNO_(3)("v. dil")rarr4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`
Discussion
31.

In solid `CuSO_(4).5H_(2)O`A. `Cu^(2+)` ion is coordinate bonded to four water moleculesB. One `H_(2)O` molecule is `H-` bondedC. It has four types of bonds, Ionic, covalent, coordinate and H- bondD. Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`

Answer» Correct Answer - A,B,C
Discussion
32.

An aqueous solution of an anhydrous white solid A on addition of KCN solution gives a white precipitate B. Addition of excess of KCN to the precipitate dissolves if forming C.A. `K_(2)[Cr(CN)_(4)`B. `K_(3)[Cu(CN)_(4)]`C. `CuCN`D. `Cu(CN)_(2)`

Answer» Correct Answer - B
Discussion
33.

Pb and Sn are extracted from their chief ore by `:`A. Carbon reduction and self reductionB. Self reduction and carbon reductionC. Electrolysis and self reductionD. Self reduction and electrolysis

Answer» Correct Answer - B
`2Pbsoverset(3O_(2))(rarr)2PbOoverset(PbS)(rarr)3Pb+SO_(2)("self reduction")`
`SnO_(2)+2CrarrSn+2CO`
Discussion
34.

Amount of oxalic acid present in a solution can be determined by its titration with `KMnO_(4)` solution in the presence of `H_(2)SO_(4)`. The titration gives unsatisfactory result when carried out in the presence of HCl because HClA. gets oxidised by oxalic acid to chlorineB. furnished `H^(+)` ions in addition to those from oxalic acidC. reduces permanganate to `Mn^(2+)`D. Oxidation oxalic acid to carbon dioxide and water

Answer» Correct Answer - C
(c ) The titration of oxalic acid with `KMnO_(4)` is presence of HCl gives unsatisfactory result because of the fact that `KMnO_(4)` can also oxidise HCl along with oxalic acid. HCl on oxidation gives `Cl_(2)` and HCl reduces `KMnO_(4)` to `Mn^(2+)` thus the correct answer is `(c )`
Discussion
35.

When `KMnO_(4)` solution is added to oxalic acid solution , the decolourisation is slow in the beginning but becomes instantaneous after some time becauseA. `CO_(2)` is formed as the productB. Reaction is exothermicC. `MnO_(4)^(-)` catalyses the reactionD. `Mn^(2+)` acts as autocatalyst

Answer» Correct Answer - D
Discussion
36.

(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound `(C )`. `(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D). (iv) A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same coloure at that of (C). (v) A solution of (A) on treatment with a solution of barium chloride gave a white precipitate of compound (F) Which was insoluble in conc. `HNO_(3)` and conc. HCl. Consider the following statement `:` `(I) ` Anions of both (B) and (C ) are diamagnetic and have tetradhedral geometray. `(II)` Anions of both (B) and ( C) are paramagnetic and have tetrahedral geometry. (III) Anions of (B) is paramagnetic and that of (C ) is diamagnetic but both have same tetrahedral geometry. `(IV)` Green coloured compound (B) in a neutral of acidic medium disproportionates to give (C ) and (D). Of these select the correct one from the code given `:`A. I and III onlyB. II and III onlyC. II and IV onlyD. III and IV only

Answer» Correct Answer - D
Conceptual
Discussion
37.

`(i)` A powdered substance `(A)` on treatment with fusion mixture gives a green coloured compound (B). `(ii)` The solution of `(B)` in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound (C ). `(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D). `(iv)` A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound `(E)` which was of the same colour at that of `(C )`. `(v)` A solutionof ( A) on treatment with a solution of barium chloride gas a white precipitate of compound (F) which was insoluble in conc. `HNO_(3)` and conc. HCl. The oxidation state of central metal ions of (A) , (B) and (C) compounds are respectively.A. `+II,+VI` and `+VII`B. `+II,+VI` and `+VI`C. `+II,+VII` and `+VII`D. `+VI,+VII` and `+VII`

Answer» Correct Answer - A
Conceptual
Discussion
38.

`(i)` A powdered substance `(A)` on treatment with fusion mixture gives a green coloured compound (B). `(ii)` The solution of `(B)` in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound (C ). `(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D). `(iv)` A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound `(E)` which was of the same colour at that of `(C )`. `(v)` A solutionof ( A) on treatment with a solution of barium chloride gas a white precipitate of compound (F) which was insoluble in conc. `HNO_(3)` and conc. HCl. Consider the following statements `:` `(I)` An ions of both `(B)` and `(C )` are diamagnetic and have tetradhedral geometry. `(II)` Anions of both (B) and (C ) are paramagnetic and have tetrahedral geometry. `(C )` is diamagnetic but both have same tetrahedral geometry. (IV) Green coloured compound (B) in a neutral or acidic medium disproportionates to give (C ) and (D). Of these select the correct one from the codes given `:`A. I and III onlyB. II and III onlyC. II and IV onlyD. III and IV only

Answer» Correct Answer - D
Conceptual
Discussion
39.

(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound `(C )`. `(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D). (iv) A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same coloure at that of (C). (v) A solution of (A) on treatment with a solution of barium chloride gave a white precipitate of compound (F) Which was insoluble in conc. `HNO_(3)` and conc. HCl. The oxidation state of central metal ions of (A), (B) and (C ) compounds are respectively `:`A. `+II,+VI` and `+VII`B. `+II,+VI` and `+VI`C. `+II,+VII` and `+VII`D. `+VI,+VII` and `+VII`

Answer» Correct Answer - A
Conceptual
Discussion
40.

On addition of small amoung of `KMnO_(4)` to concentrated `H_(2)SO_(4)`, a green oily compound is obtained which is highly explosive in nature. Identify the compound from the following.A. `Mn_(2)O_(7)`B. `MnO_(2)`C. `MnSO_(4)`D. `Mn_(2)O_(3)`

Answer» Correct Answer - A
`KMnO_(4)+underset(("Conc."))(H_(2)SO_(4))rarrMn_(2)O_(7)`
Discussion
41.

`MnO_(4)^(-)` is of intense pink colour, though `Mn` is in`(+7)` oxidation state.It is due to:A. oxygen gives colour to itB. charge transfer when Mn gives its electron to oxygenC. charge transfer when oxygen gives its electron to Mn making it `Mn(+VI)` hence colouredD. None is correct.

Answer» Correct Answer - C
Mn is in `+7` o.s. having no unpaired `e^(-)` Pink coloure of `MnO_(4)^(-)` is due to charge transfer.
Discussion
42.

When `MnO_(2)` is fused with `KOH,` a coloured compound is formed, the product and its colour is:A. `K_(2)MnO_(4)`, greenB. `Mn_(2)O_(3)`, brownC. `Mn_(2)O_(4)`, blackD. `KMnO_(4)`,Purple

Answer» Correct Answer - A
`2MnO_(2)+4KOH+O_(2)rarr2K_(2)MnO_(4)+H_(2)O`
Discussion
43.

`CuFeS_(2)+O_(2)("excess")overset(Delta)(rarr)X`(hydrated salt is blue)+Y(s)(Unbalanced Equation)`:` Which is correct choice for (X) and (Y) ?A. (Y) on heating liberates `SO_(3)` onlyB. (X) forms bluish white ppt. with sodium hydroxide which redissolves in excess of sodium hydroxide.C. (Y) on reaction with potassium ferricyanide gives brown ppt.D.

Answer» Correct Answer - A
`CuFeS_(2)+4O_(2)overset(Delta)(rarr)CuSO_(4)(s)+FeSO_(4)(s)`
`(A) CuSO_(4)+4KIrarrCu_(2)I_(2)+I_(2)+2K_(2)SO_(4)`
`(B)2FeSO_(2)overset(Delta)(rarr)Fe_(2)O_(3)+SO_(2)+2SO_(3)`
`(C ) CuSO_(4)+2NaOH rarr Na_(2)SO_(4)+Cu(OH)_(2)darr("insoluble in excess NaOH")`
`(D) Fe^(2+)+2K_(3)[Fe(CN)_(6)]rarrFe_(3)[Fe9CN)_(6)]_(2)("deep vlue")`
Discussion
44.

Which of the following on heating with `K_(2)Cr_(2)O_(7)` and conc. `H_(2)SO_(4)` with organge red color vapours ?A. NaClB. `ZnCl_(2)`C. `Hg_(2)Cl_(2)`D. `AgCl`

Answer» Correct Answer - A,B
`Hg_(2)Cl_(2)` is covalent and AgCl is insoluble in water 1 and so cannot give chromyl chloride test.
Discussion
45.

Anhydrous ferric chloride is prepared byA. heating hydrated ferric chloride at a high temperature in a stream of airB. heating metallic iron in a stream of dry chlorine gasC. reaction of metallica iron with hydrochloric acidD. reaction of metallic iron with nitric acid

Answer» Correct Answer - B
`(b) 2Fe+3Cl_(2)("dry")rarr2FeCl_(3)(" anhydrous")`
Discussion
46.

Anhydrous ferric chloride is prepared byA. heating hydrated ferric chloride at a high temperature in a stream of airB. heating metallic iron in a stream of dry chlorine gasC. reaction of ferric oxide with HCl(aq)D. reaction of metallic iron with HCl(aq)

Answer» Correct Answer - B
`(B) 2Fe+3Cl_(2)rarr2FeCl_(3)("anhydrous"),(A),(C ),(D)` do not give anhydrous `FeCl_(3)` but hydrated `FeCl_(3)`
Discussion
47.

`KMnO_(4)` on treatment with conc. `H_(2)SO_(4)` forms a compound (X) which decomposes explosively on heating forming (Y). The (X) and (Y) are respectively `:`A. `Mn_(2)O_(7),MnO_(2)`B. `Mn_(2)O_(7),Mn_(2)O_(3)`C. `MnSO_(4),Mn_(2)O_(3)`D. `Mn_(2)O_(3),MnO_(2)`

Answer» Correct Answer - A
`2KMnO_(4)+3H_(2)SO_(4)rarr2KHSO_(4)+(MnO_(3))_(2)SO_(4)+2H_(2)O`
`(MnO_(3))_(2)SO_(4)+H_(2)OrarrMn_(2)O_(7)+H_(2)SO_(4)`
`Mn_(2)O_(7)overset(Delta)(rarr)2MnO_(2)+3O_(2)`
Discussion
48.

`KMnO_(4)` acts as an oxidising agent in acidic medium. The number of moles of `KMnO_(4)` that will be needed to react with one mole of sulphide ions in acidic solution isA. `(2)/(5)`B. `(3)/(5)`C. `(4)/(5)`D. `(1)/(5)`

Answer» Correct Answer - A
`(2)/(5)` moles of `KMnO_(4)` required
Discussion
49.

In the oxidation reactions of `KMnO_(4)` , in acidic medium, only `H_(2)SO_(4)` is used to product acidic medium but not HCl(or ) `HNO_(3)` becauseA. HCl reacts with `KMnO_(4)` and produces `Cl_(2)`, `HNO_(3)` itself is oxidizing agent.B. `HNO_(3)` reacts with `KMnO_(4)` and produces `Cl_(2)`, HCl itself acts as oxidizing agent.C. Both `HNO_(3)` and HCl liberates `Cl_(2)` from `KMnO_(4)`D. Both `HNO_(3)` and HCl liberates `O_(2)` from `KMnO_(4)`

Answer» Correct Answer - A
HCl reacts with `KMnO_(4)` and produce `Cl_(2) . HNO_(3)` acts as oxidising agent.
Discussion
50.

A metal M and its compound can give the following observable changes in a consequence of reactions `Munderset(HNO_(3))overset("dilute")(rarr)["Colourless Solutions"]underset(NaOH)overset("aqueous")(rarr)["White Precipitate"]underset("NaOH(aq)")overset("excess")(rarr)["Colourless Solutions"]overset(H_(2)S)(rarr)["White Precipitate"]`A. MgB. PbC. ZnD. Sn

Answer» Correct Answer - C
`underset((M))(Zn)overset(dlHNO_(3))(rarr)underset("Colourless solution")(Zn(NO_(3))_(2))underset("NaOH")overset(Aq)(rarr)underset("White ppt")(Zn(OH)_(2))`
`underset("NaOH")overset("Excess")(rarr)underset("Soluble")(Na_(2)[Zn(OH)_(4)])overset(H_(2)S)(rarr)underset("Whiteppt")(Zns`
Discussion