

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
551. |
To prepare a pure sample of n-hexane, using sodium metal as one reactant, the other reactant or reactants will be:A. ethyl bromide and n-butyl chlorideB. methyl bromide and n-pentyl bromideC. n-propyl chlorideD. ethyl bromide and n-butyl bromide |
Answer» Correct Answer - C | |
552. |
Choose the correct reagent used in the conversion. A. `p-Br_(2),q-"alc. "KOH, r-NaOH,s-Al_(2)O_(3)`B. `p-HB r , "alc. "KOH, r-CaC_(2), s-KMnO_(4)`C. `p-HBr,q-"alc. "KOH,r-NaNH_(2),s-"red hot iron tube"`D. `p-Br_(2),q-"alc. "KOH, r-NaNH_(2),s-"red hot iron tube"` |
Answer» Correct Answer - D | |
553. |
At room temperature , the eclipsed and staggered forms of ethane cannot be isolated becauseA. they interconvert rapidlyB. both the conformers are equally stableC. the energy difference between the conformers is largeD. there is a large energy barrier of rotation about the `sigma`-bond |
Answer» Correct Answer - A | |
554. |
Nucleophiles and electrophiles are reaction intermediates having electron rich and electron deficient centres respectively. Hence, they tend to attack electron deficient and electron rich centres respectively. Classify the following species as electrophiles and nucleophiles. (i)`H_3CO^-` , (ii)`H_3C-oversetoverset(O)(||)C-O^-` , (iii)`oversetdot(Cl)` , (iv)`Cl_2C` , (v) `(H_3C)_3C^+` , (vi)`Br^-` , (vii)`H_3COH` , (viii)`R-NH-R` |
Answer» Nucleophiles are electron-rich species . They may be neutral or negatively charge , i.e., (i)`H_3CO^-` , (ii)`H_3C-oversetoverset(O)(||)C-O^-` , (vi)`Br^-` , (vii)`H_3C-underset(ddot)overset(ddot) O-H`, (viii)`R-oversetddot(NH)-R` Electrophiles are electron-deficient species. They may be neutral or positively charged, i.e., (iii)`oversetddot(Cl)` , (iv)`Cl_2C` : , (v)`(H_3C)_3C^+` |
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555. |
Benzene is obtained by fractional distillation ofA. Heavy oilB. anthracene oilC. Middle oilD. Light oil |
Answer» Correct Answer - D Benzene is obtained by the fractional distillation of light oil. |
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556. |
The IUPAC name if the compound having the formula `(CH_(3)_(3)-C-CH=CH_(2)` isA. 1,1-Dimethyl-3-buteneB. 1,1,1-Trimethyl-3-propeneC. 3,3-Dimetyl-1-buteneD. 3,3,3-Triemthyl1,1-propene. |
Answer» Correct Answer - C `overset(4)(CH_(3))-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(overset(3)C)-overset(2)(CH)=overset(1)(CH_(2))` |
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557. |
Which among the following represents the correct reaction of general combusition?A. `C_(x)H_(y)+(x+(Y)/(4))O_(2)rarrxCO_(2)+(Y)/(2)H_(2)O`B. `C_(x)H_(y)+(2x+(y)/(4))O_(2)rarrxCO_(2)+(Y)/(2)H_(2)O`C. `C_(x)H_(y)+(x+(Y)/(2))O_(2)rarrsCO_(2)+(Y)/(2)H_(2)O`D. `C_(x)Y_(y)+(x+(Y)/(4))O_(2)rarrxCO_(2)+(Y)/(4)H_(2)O` |
Answer» Correct Answer - A | |
558. |
Carbide which react with water to give propyne isA. `CaC_(2)`B. `Mg_(2)C_(3)`C. `SiC`D. `Al_(4)C_(3)` |
Answer» Correct Answer - b `Mg_(2)C_(2)+4H_(2)O rarrCH_(3)C-=CH+2Mg(OH)_(2)` |
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559. |
Why do the C-C bonds rather than C-H bonds break during cracking of alkanes? |
Answer» Since the bond dissociation energy of C-C bonds (348kj /mol) is lower than bond dissociation energy of C-H bonds (414kj/mol), therefore, during cracking of alkanes, C-C bonds break more early than C-H bonds. |
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560. |
Which of the following is not a petroleum product?A. GasolineB. Cooking gasC. Bees waxD. All are petroleum producers |
Answer» Correct Answer - C | |
561. |
Whch of the following product is formed when acetylene is passed into a solution of curpours chloride in ammonium chloride?A. Vinyl acetyleneB. BenzeneC. CyclooctatetraeneD. Toulene |
Answer» Correct Answer - A Acetylene polymerises in `Cu_(2)Cl_(2)//NH_(4)Cl` solution `CH-=CH+H-C-=CH overset(Cu_(2)Cl_(2))to underset("Vinyl acetylene")(CH_(2)=H-C-=C)` |
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562. |
Which of the following can be obtained from napth?A. Parffin waxB. NapthaleneC. Petroleum etherD. All |
Answer» Correct Answer - C | |
563. |
Define the following terms with example.A. Wurtz Reaction. B. Chain Isomerism. C. Dihedral Angle. |
Answer» (a) Wurtz Reaction: When alkyl halides react with sodium metal in the presence of dry ether the product obtained is alkanes with more no. of carbon atoms. E.g. CH3 – Cl + 2Na +Cl – CH3 --------> 2NaCl + CH3 – CH3 (b) Chain Isomerism: The isomers which differ with respect to the nature of the carbon atom which may be either straight chain or branched chain. E.g. For C4H10 butane the two isomers obtained are CH3CH2CH2CH3 (c) Dihedral Angle:- The angle between the two non bonded hydrogen atoms of the two neighbouring carbon atoms in ethane is called Dihedral Angle. |
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564. |
Gasoline contains hydrocarbons in the rangeA. C-7 to C-12B. C-12 to C-15C. C-4 to C-6D. C-5 to C-8 |
Answer» Correct Answer - A Factual questions. |
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565. |
The homolytic fission of hydrocarbons in the rangeA. Free radicalsB. CarbocationsC. CarbanionsD. Carbenes |
Answer» Correct Answer - A Homolytic fission results in the formation of free radicals. |
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566. |
The principle constituents of petroleum areA. phenolsB. alcoholsC. hydrocarbonsD. unsaturated hydrocarbons only |
Answer» Correct Answer - C | |
567. |
What do you mean by cracking? |
Answer» The thermal decomposition of higher hydrocarbons into lower hydrocarbons in the presence or absence of a catalyst is called cracking. |
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568. |
What are the chief constituents of light oil fraction? |
Answer» Benzene, toluene and xylenes. |
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569. |
The substance which has been assigned octane number of -45 isA. n-octaneB. n-heptaneC. n-nonaneD. none of these |
Answer» Correct Answer - C | |
570. |
What type of hydrocarbons are present in high octane gasoline? |
Answer» Branched chain aliphatic and/or aromatic hydrocarbons. |
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571. |
Anti knocking character of gasoline can be improved by the addition ofA. lead sulphhateB. lead bromideC. tetraethyl leadD. diethyl cadium |
Answer» Correct Answer - C | |
572. |
1-Pentyne reacts with:A. SodiumB. sodamideC. Ammonical silver nitrateD. Ammonical cuprous chloride |
Answer» Correct Answer - A::B::C::D | |
573. |
Which among the following is deactivating group ?A. `-Cl`B. `-OR`C. `-NH_(2)`D. `-NHR` |
Answer» Correct Answer - a a |
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574. |
Which metal is used in wurtz reaction? |
Answer» Sodium is used in wurtz reaction. |
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575. |
The rotation of C – C single bond leads to different isomenc structure called as ……… |
Answer» The rotation of C – C single bond leads to different isomenc structure called as conformers. |
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576. |
Which catalyst is used in Friedel’s craft reaction? |
Answer» Anhydrous aluminium chloride. |
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577. |
Statement-I: Product of pyrolysis of Statement-II: C-H bond is weaker than C-D bond.A. If both statement-1 & statement-2 are true & the statement-II is a correct explanation of the statement-IB. If both statement-I & statement-II are true but statement-II si not a correct explanation of the statement-IC. If statement-I is true but the statement-II is false.D. If statement-I is false but the statement-II is true. |
Answer» Correct Answer - B Pyrolysis of ester is syn elimination so the bond energy of C-H and C-D is not the reason. |
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578. |
Which of the following gieves `CH_(4)` when treated with water ?A. Aluminium carbideB. Calcium carbideC. Silicon carbideD. Iron carbide |
Answer» Correct Answer - a `underset("Aluminium carbide")(Al_(4)C_(3)+6H_(2)O) rarrunderset("Methane")(3CH_(4)+2Al_(2)O_(3))` |
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579. |
Four structures are given in options (a) to (d) . Examine them and select the aromatic structures .A. B. C. D. |
Answer» Correct Answer - A::C Cyclopropenyl cation (a) has completely delocalized `2pi`-electrons. Therefore , in accordance with Huckel rule, it is aromatic. Cyclooctatetraene is not planar and also it has `8pi`-electrons. Therefore, in accordance with Huckel rule , it is not aromatic. (c )Diphenyl has two benzene rings each one of which is planar and has 6 `pi`-electrons . Therefore, like benzene, it is also aromatic. (d)Cyclopropenyl anion although planar has only 4 `pi`-electron. Therefore, in accordance with Huckel rule, it is not aromatic. |
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580. |
Four structures are given in options (i) to (iv). Examine them and select the aromatic structures. |
Answer» The correct answer is (i), (iii) |
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581. |
Define Aromatic Compounds. |
Answer» The Compounds which gives pleasant smell. | |
582. |
Four structures are given in options (a) to (d). Examine them and select the aromatic structures(a)(b)(c)(d) |
Answer» a and c, in both these options, rings are planar and follow (4n+ 2) pi electron rule. |
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583. |
Write IUPAC names of the following compounds :(i) (CH3)3CCH2C(CH3)3(ii) (CH3)2 C(C2H5)2(iii) tetra – tert-butylmethane |
Answer» (i) 2,2,4,4-tetramethylpentane (ii) 3, 3-Dimethylpentane (iii) 3,3-Di-tert-butyl -2, 2, 4, 4 - tetramethylpentane |
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584. |
n-propyl bromide on treatment with ethanolic potassium hydroxide producesA. propanol-1B. propeneC. propanol-2D. ethyl propyl ether |
Answer» Correct Answer - B `underset("n-propyl bromide")(CH_(3)CH_(2)CH_(2)Br)underset(Alc.KOH)rarrunderset("Propene")(CH_(3)CH=CH_(2))` |
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585. |
Write IUPAC names of the following:(i) (CH3)3CCH2C(CH3)(ii) (CH3)2C(C2H5)2(iii) Tetra – tert – butyl methane |
Answer» (i) 2, 2, 4, 4-Tetramethylpentane (ii) 3, 3-Dimethylpentane (iii) 2, 2, 4, 4-Tetramethyl-3, 3-di (2-methylpropyl) pentane |
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586. |
How will you demonstrate that double bonds of benzene are somewhat different from that of olefins? |
Answer» The double bonds of olefins decolorize bromine water and discharge the pink colour of Bayer's reagent while those of benzene not. |
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587. |
How will you separate propene from propyne? |
Answer» By passing the mixture through ammonical silver nitrate solution when propyne reacts while propene passes over. |
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588. |
How will you demonstrate that double bonds of benzene are somewhat different from that of olefins? |
Answer» The double bonds of olefins decolorize bromine water and discharge the pink colour of Bayer‘s reagent while those of benzene not. |
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589. |
What is Grignard reagent? |
Answer» Alkyl magnesium halides | |
590. |
When acetylene is treated with `HBr` the pruduct isA. `CICH=CHAsCl_(2)`B. `CH_(2)=CHAsCl_(2)`C. `CH_(2)=CAsCl_(3)`D. `AsCl_(3)` |
Answer» Correct Answer - A | |
591. |
Will the main product in the above reaction show geometrical isomerism? |
Answer» No, the major product, i.e., 2-methylbut-2-ene does not show geometrical (or cis-trans) isomerism. |
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592. |
Which one of these will react with sodium metal-A. EthyneB. EtheneC. EthaneD. Ether |
Answer» Correct Answer - A `CH-=CH+NatoCH-=C^(-)Na^(+)+1//2H_(2)uarr` ltBrgt Ethylene is more acidic there ethene, ethane and ether. |
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593. |
Amongst the given options, the compound in which all the atoms are in one plane in all the possible conformations (if any ), is (are)A. B. C. `H_2C=C=O`D. `H_2C=C=CH_2` |
Answer» Correct Answer - B::C Along C-C single bond, numerous conformations are possible in 1,3-butadiene (a) . In some of these conformations , all the atoms may not lie in the same plane. In `CH_2=C=CH_2` (d), due to sp-hybridization of the central carbon, H-atoms on the terminal `CH_2` groups lie in perpendicular planes . However, in `CH_2=C=O` (c ), due to replacement of `CH_2` by O the two H-atoms on the `sp^2`-hybridized `CH_2` group lie in the same plane in which the two carbon and the oxygen atoms lie. In compound (b), due to linear structure of H-C`-=`C- portion of the molecule , the three H-atoms on -HC =`CH_2` portion always lie in the same plane. Thus, options (b) and (c ) are correct. |
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594. |
Consider the following reaction the major alkene product is `(CH_(3))_(3)C CH_(2)-underset(Br)underset(|)(C(CH_(3))_(2)overset(base)to` the major alkene product is -A. `(CH_(3))_(3)C CH=C(CH_(3))_(2)`B. `(CH_(3))_(3)C CH_(2)overset(CH_(3))overset(|)(C)=CH_(2)`C. `(CH_(3))_(2)C=overset(CH_(3))overset(|)(C)-CH(CH_(3))_(2)`D. `CH_(2)=overset(CH_(3))overset(|)(C)-overset(CH_(3))overset(|)(C)HCH(CH_(3))_(2)` |
Answer» Correct Answer - A More stable alkene will formed |
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595. |
Which of the following compound can be prepared from acetylene by carbonylation ?A. `CH_(3)-COOC_(2)H_(5)`B. `CH_(2)=CH-COOH`C. `CH_(3)CH_(2)-COOH`D. `CH_(3)-CH_(2)-COOCH_(3)` |
Answer» Correct Answer - b The compound which can be prepared from acetylene by carbonylation is `CH_(2)=CH-COOH` `underset(acetyl en e)(H-C-=C-H)+CO+H_(2)O overset(BF_(3))underset(Ni(CO)_(4))rarr underset(acrylic acid)(CH_(2)=CH-COOH)` |
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596. |
Acetylene is prepared in the industry by the action of water on …………. (A) calcium carbonate (B) calcium carbide (C) mercuric chloride (D) calcium oxide |
Answer» Correct option is: (B) calcium carbide \(\underset {Calcium\, Carbide}{CaC_2 + H_2O} \rightarrow HC \equiv \underset {Acetylene} {CH + Ca (OH)_2} \) (B) calcium carbide |
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597. |
From which one of the following both ethylene and acetylene could be prepared in a single step reaction ?A. `CH_3CH_2OH`B. `Br-CH_2-CH_2-Br`C. `CH_3CH_2Br`D. `Br-CH_2-CH_2-OH` |
Answer» Correct Answer - B `BrCH_2-CH_2Br underset((-ZnBr_2))overset(Zn//CH_3OH, Delta)to CH_2=CH_2` `BrCH_2-CH_2Br overset(NaNH_2 "in liq."NH_3)to HC-=CH` |
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598. |
Which of the following is not an endothermic reaction ?A. Combustion of propaneB. Ethane to etheneC. DehydrogenationD. Change of chloring molecule into chlorine atoms. |
Answer» Correct Answer - a The enthalpy of combustion, `i.e. Delta H` is always negative. It means combustion is an exothermic reaction. |
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599. |
Pick out the alkane while differs from the other members of the group.A. 2,2-dimethylpropaneB. pentaneC. 3-methylbutaneD. 2,2-dimethylbutane |
Answer» Correct Answer - D (a),(b) and (c ) are all isomers but (d) is not . |
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600. |
Benzenesulphonic acid when heated with steam gives benzene but nitrobenzene does not. Why so ? |
Answer» Sulphonation is a reversible reaction. When heated with excess of conc. `H_2SO_4`, the reaction moves in the forward direction giving benzenesulphonic acid and `H_2O`. However, when benzenesulphonic acid is heated with excess of steam , the reaction moves in the backward direction giving benzene and `H_2SO_4`. `underset"Benzene"(C_6H_6)+H_2SO_4 overset"Heat"to underset"Benzenesulphonic acid"(C_6H_5SO_3H)+H_2O` `underset"Benzenesulphonic acid"(C_6H_5SO_3H)+underset"Steam"(H_2O) overset"Heat"to underset"Benzene"(C_6H_6)+ H_2SO_4` In contrast, nitration is an irreversible reaction. Therefore, when nitrobenzene is heated with steam, backward reaction does not occur and hence nitrobenzene is recovered . `underset"Benzene"(C_6H_6)+underset"Conc."(HNO_3) overset(Conc. H_2SO_4)to underset"Nitrobenzene"(C_6H_5NO_2)+H_2O` |
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