995 + Interview Questions in HYDROCARBONS IN GENERAL AWARENESS Page 2 InterviewSolution

51.	Addition of `HI` on the double bond of propene yield isopropyl iodide and not `n-` propyl iodide as the major product. This is because the addition proceeds throughA. A more stable free radicalB. A more stable carbanionC. A more stable carbonium ionD. None of the above being a concerted reaction
Answer» Correct Answer - c `HI rarr H^(+)+I^(-)` `CH_(3)-CH=CH_(2) + H^(+) to CH_(3) - underset({:(("Minor")),(1^(@)"Carboniumion"),(("Less stable")):})(CH_(2))-overset(+)(C )H_(2)+ CH_(3) +underset({:(("Minor")),(2^(@)"Carboniumion"),(("More stable")):})(overset(+)(C)H - CH_(3))` `CH_(3) underset(2^(@)"Carboniumion")(-overset(+)(C)H-CH_(3)) + I^(-) to underset({:("Isopropyl iodide"),("Major produce"):})underset(I)underset(\|)(CH_(3)-CH)-CH_(3)`

Discussion

52.	Acid catalysed hydration of alkene is an example forA. free radical substitutionB. nucleophilic substitutionC. nucleophilic additionD. electrophilic addition
Answer» Correct Answer - D Acid-catalysed hydration is an electrophilic addition reaction.

Discussion

53.	The compouhnd formed when alcoholic solution of ethylene dibromide is heated with granualted zinc isA. etheneB. ethyneC. ethaneD. bromoethane
Answer» Correct Answer - A `underset("Ethylene dibromide")({:(,CH_(2)Br),(,"\|"),(,CH_(2)Br):})+Zn underset("heat")overset("alcohol")to {:(CH_(2),),("\|\|",),(CH_(2),):}+ZnBr_(2)`

Discussion

54.	Propyl bromide on reaction with alcoholic KOH gives-A. Propane+EthaneB. PropeneC. ButaneD. Acetylene
Answer» Correct Answer - B

Discussion

55.	Ethylene dibromide on treating with alcoholic `KOH` givesA. `C_(2)H_(6)`B. `CH_(4)`C. `C_(2)H_(4)`D. `C_(2)H_(2)`
Answer» Correct Answer - D

Discussion

56.	In dehydrohalogenations the base (alcoholic KOH) abstacts-A. The halide ionB. The proton present on the carbon next to the carbon to which the halogen is attached.C. The proton present on the carbon to which the halogen is attached.D. The proton on the `alpha`-carbon
Answer» Correct Answer - B

Discussion

57.	Which of the following compound undergoes dehydrochlorination most easily when treated with alcoholic KOH-A. `CH_(3)-underset(CH_(3))underset(\|)(C)H-CH_(2)Cl`B. `CH_(3)-underset(Cl)underset(\|)(C)H-C_(2)H_(5)`C. `CH_(3)-CH_(2)-CH_(2)Cl`D. `(CH_(3))_(3)C-Cl`
Answer» Correct Answer - D

Discussion

58.	1 – chloropropane on treatment with alc. KOH produces :a. propane b. propene c. propyne d. propyl alcohol
Answer» Option : b. propene

Discussion

59.	Toluene, when treated with `(Br_(2))/(Fe)`, gives p-bromotoluene as the major product because the `-CH_(3)` group of toluene isA. is p-directingB. is m-directingC. activates the ring by herconjugationD. deactivates the ring
Answer» Correct Answer - A,C

Discussion

60.	When 2-butyne is treated with dil. `H_2SO_4//HgSO_4`, the product formed isA. butanol-1B. butanol-2C. 2-butanoneD. butanal
Answer» Correct Answer - C `underset"2-Butyne"(CH_3-C-=C-CH_3+H_2O) overset(H_2SO_4 // HgSO_4)to underset"2-Butanone"(CH_3COCH_2H_3)`

Discussion

61.	Statement-1. Propene reacts with HBr in presence of organic peroxide to give 1-bromopropane Statement-2. The reaction occurs through carbocation intermediateA. Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for Statement-1C. Statement- 1 is True, Statement-2 is FalseD. Statement-1 is False, Statement -2 is True
Answer» Correct Answer - C Correct statement-2. The reaction occurs through free radical intermediate

Discussion

62.	Propene reacts with HBr in the presence of peroxide to form …………
Answer» Propene reacts with HBr in the presence of peroxide to form 1 – Bromopropane.

Discussion

63.	In the following reaction : `C_2H_2 underset(HgSO_4//H_2SO_4)overset(H_2O)to X hArr CH_3CHO` What is X ?A. `CH_3CH_2OH`B. `CH_3-O-CH_3`C. `CH_3CH_2CHO`D. `CH_2=CHOH`
Answer» Correct Answer - D `underset"Acetylene"(HC-=CH)underset(HgSO_4 // H_2SO_4)overset(H_2O)to underset"Vinyl alcohol (X)"(CH_2=CHOH) hArr underset"Acetaldehyde"(CH_3CHO)`

Discussion

64.	The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_3CH_2C-=C CH_2CH_3`B. `CH_3CH_2CH_2C-=C CH_2CH_2CH_3`C. `CH_3CH_2C-=CH`D. `CH_3CH=CHCH_3`
Answer» Correct Answer - C Only terminal alkynes react with Na in liquid `NH_3`. Thus, option (c ) is correct. `CH_3CH_2C-=CH overset(Na//liq. NH_3)to CH_3CH_2C-=C^(-) Na^+`

Discussion

65.	The hydrocarbon, which can react with sodium in liquid ammonia isA. `CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)`B. `CH_(3)CH_(2)C-=CH`C. `CH_(3)CH-=CHCH_(3)`D. `CH_(3)CH_(2)C-=C CH_(2)CH_(3)`
Answer» Correct Answer - B `underset("But-1-yne")(CH_(3)CH_(2)C)-=CH underset(Delta)overset(Na//Liq.NH_(3))rarrCH_(3)CH_(2)C-=CNa^(+)` Only terminal alkyne is responsible for reaction with Na in liquid ammonia.

Discussion

66.	Which pf the following posses the highest meltin point?A. ChlorobenzeneB. o-DichlorobenzeneC. m-DichlorobenzeneD. p-Dichlorobenzene
Answer» Correct Answer - D p-Dichlorobezene fits closely in the crystal lattice due to its symmetrical structure. Thereofre, it has highest melting point.

Discussion

67.	The thermal decomposition of alkanes in absence of air to give lower alkanes, alkenes and hydrogen is called …………. (A) vapour phase nitration (B) pyrolysis (C) polymerisation (D) combustion
Answer» Correct option is: (B) pyrolysis The thermal decomposition of alkanes in the absence of air to give lower alkanes, alkenes and Hydrogen is called pyrolysis Correct option is (B) pyrolysis

67.

The thermal decomposition of alkanes in absence of air to give lower alkanes, alkenes and hydrogen is called …………. (A) vapour phase nitration (B) pyrolysis (C) polymerisation (D) combustion

Answer»

Correct option is: (B) pyrolysis

The thermal decomposition of alkanes in the absence of air to give lower alkanes, alkenes and Hydrogen is called pyrolysis

Correct option is (B) pyrolysis

Discussion

68.	Propene reacts with `Cl_(20` at `500^(@)C` the products is formedA. `1-`chloro propene `-1`B. `2-`chloro propene `-1`C. `1,2-`dichloro propaneD. `3-`chloro propene `-1`
Answer» Correct Answer - d `CH_(3)-CH=CH_(2)overset(500^(@)C)underset(Cl_(2))rarrCH_(2)-CH=CH_(2)`

Discussion

69.	Hydroboratieon of 2-butyne followed by treatment with AcOHA. n-ButaneB. 1-ButyneC. trans-2-ButeneD. cis-2-butene
Answer» Correct Answer - D `CH_(3)-C-=C-CH_(3) +Sia_(2)BH to` `CH_(3)-CH-underset(Sia_(2))(C )-CH_(3) overset(CH_(3)COOH)to underset(cis)(CH_(3)CH=CHCH_(3))`

Discussion

70.	On chlorination, nitrobenzene will produce__________A. o-chloronitrobenzeneB. p-chloronitrobenzeneC. m-chloronitrobenzeneD. All of these
Answer» Correct Answer - C

Discussion

71.	Benzene reacts with `I_2` in presence of which of the following to give iodobenzene ?A. `HNO_3`B. HIC. `SO_2`D. `H_2O`
Answer» Correct Answer - A Iodination occurs in presence of an oxidising agent `(HNO_3)`

Discussion

72.	Alkanes can be prepared from grignard reagents by reacting with-A. AlcoholsB. Primary aminesC. AlkynesD. all of them
Answer» Correct Answer - D

Discussion

73.	Which of the following hydrocarbon is liquid at room temperature?A. PentaneB. ButaneC. PropaneD. Ethane
Answer» Correct Answer - A Pentane is a liquid at room temperature.

Discussion

74.	Hydrocarbon which is liquid at room temperature isA. pentaneB. butaneC. propaneD. ethane
Answer» Correct Answer - A Lower alkanes (`C_(1)` to `C_(2)`) are gaseous at room temperature.

Discussion

75.	Liquid hydrocarbon can be converted to a mixture of gaswous hydrocarbon byA. CrackingB. Distillation under reduced pressureC. Hydrolysis of alkyl magnesium bromideD. Oxidation
Answer» Correct Answer - A On cracking a liquid hyrdrocarbon changes into a mixture of hydrocarbons.

Discussion

76.	The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_(3)CH_(2)C=C C_(2)CH_(3)`B. `CH_(3)CH_(2)CH_(2)C=C CH_(2)CH_(2)CH_(3)`C. `CH_(3)CH_(2)C=CH`D. `CH_(3)CH=CHCH_(3)`
Answer» Correct Answer - C Only terminal alkynes react with Na in `NH_(3)` Hence (C ) is correct `CH_(3)CH_(2)Cl-=OH overset(Na//liq NH_(3))to CH_(3)CH_(2)C-=overset(-)(CNa^(+))`

Discussion

77.	Which isomer of `C_(5)H_(12)` give four isomers of monoiodopentane?A. NeopentaneB. n-PentaneC. IsopentaneD. none of these
Answer» Correct Answer - C `CH_(3)-underset(CH_(3))underset(\|)(CH)-CH_(2)-CH_(3)` can give four isomers of mono iodo pentane which are `CH_(3)-underset(CH_(3))underset(\|)(CH)-CH_(2)-CH_(2)-I` `CH_(3)-underset(CH_(3))underset(\|)(CH)-overset(I)overset(\|)(CH)-CH_(2)` `CH_(3)-underset(CH_(3))underset(\|)overset(I)overset(\|)(CH)-CH_(2)-CH_(3)` ,`CH_(3)-underset(CH_(3)-I)underset(\|)(CH)-CH_(2)CH_(2)`

Discussion

78.	The hydrocarbon which is a liquid at room temperature is:A. butaneB. propaneC. decaneD. neopentane
Answer» Correct Answer - C Lower alkanes is gaseous in nature but as molecular weight increase physical state change in liquid.

Discussion

79.	The isomerisation of 1-butyne to 2-butyne can be achieved by treatment withA. hydrochloric acidB. ammoniacal silver nitrateC. ammoniacal cuprous chlorideD. ethanolic potassium hydroxide
Answer» Correct Answer - D `underset"(less stable)"underset"1-Butyne"(CH_3-CH_2-C-=CH)overset(Alc. KOHDelta)hArr underset"(more stable)"underset"2-Butyne"(CH_3-C-=C-CH_3)`

Discussion

80.	The thermal decomposition of alkanes in the absence of air is known as:A. OxidationB. CombustionC. HydrogenationD. Pyrolysis
Answer» Correct Answer - D

Discussion

81.	Methane can be prepared by:A. Wurtz reactionB. HydrogenationC. Decarboxylation of sodium acetate with soda limeD. Dehydrohalogenation
Answer» Correct Answer - C

Discussion

82.	Which of the following hydrocarbon is liquid at room temperature?A. EthaneB. PropaneC. HexaneD. Butane
Answer» Correct Answer - C Alkanes having `C_(1) "to" C_(4)` are gases and `C_(5)` to `C_(17)` are colourless, odouless liquids andfrom `C_(18)` onwards are colourless, odouless solids.

Discussion

83.	Water destroys Grignard reagents. Why?
Answer» CH₃MgX + HOH → CH₄ – Mg(OH)X. Water would protonate the grignard reagent and destroy the gngnard reagent, because the grignard carbon atom is highly nucleophilic. This would form a hydrocarbon. Therefore to make a grignard solution, only ether is the best solvent and water or alcohol are not used for that purpose.

83.

Water destroys Grignard reagents. Why?

Answer»

CH₃MgX + HOH → CH₄ – Mg(OH)X.

Water would protonate the grignard reagent and destroy the gngnard reagent, because the grignard carbon atom is highly nucleophilic. This would form a hydrocarbon. Therefore to make a grignard solution, only ether is the best solvent and water or alcohol are not used for that purpose.

Discussion

84.	The chlorination of an alkane involves:A. Cl free radicalsB. `Cl^(+)` speciesC. `Cl^(-)` speciesD. `CH_(4)` free radicals
Answer» Correct Answer - A

Discussion

85.	Isomerisation in alkane may be brought about by using-A. `Al_(2)O_(3)`B. `Fe_(2)O_(3)`C. `AlCl_(3)` and `HCl`D. Concentrated `H_(2)SO_(4)`
Answer» Correct Answer - C

Discussion

86.	An alkane is most likely to react with:A. A Free radicalB. An alkaliC. An electrophileD. A nucleophile
Answer» Correct Answer - A

Discussion

87.	Write down the combustion reaction of propane whose ΔH° = -2220 kJ
Answer» C₃H₈(g)(propane) + 5O₂ \(\longrightarrow\) 3CO₂(g) + 4H₂O(g)(carbon dioxide) ΔHº = -2220 kJ

Discussion

88.	Chlorination of methane does not occur in dark becauseA. methane can form free radicals in presence of sunlight ohnlyB. to get chlorine free radicals from `Cl_(2)` molecules energy is required. It cannot happen in darkC. substitution reaction can take place only in sunlight and not in darkD. termination step cannot take place in dark, it requires sunlight.
Answer» Correct Answer - B Chlorination of methane is free radical substitution. To get chlorine free radical energy is required which is provided by sunlight to initiate the reaction. `Cl_(2) overset(h upsilon)to Cl^()+Cl^()`

Discussion

89.	Is it possible to prepare methane by Kolbe’s electrolytic method.
Answer» Kolbe’s electrolytic method is suitable for the preparation of symmetrical alkanes, that is alkanes containing even number of carbon atoms. Methane has only one carbon, hence it cannot be prepared by Kolbe’s electrolytic method.

Discussion

90.	Ethane is subjected to comnustion process. The hydrid state of carbon during the combusion changes fromA. `sp^(2) "to" sp^(3)`B. `sp^(3)` to spC. sp tp `sp^(3)`D. unpredictable
Answer» Correct Answer - B `underset(sp^(3) "hybridiasation")(H_(3)C-CH_(3)+(7)/(2)O_(2))to underset(sp^(3) "hybridiasation")(2O=C=+3H_(2)O)`

Discussion

91.	Which of the following is not an oxidation product of alkane?A. AlcoholB. AldehydeC. Carboxylic acidD. Ether
Answer» Correct Answer - D Refer to Comprehensive Review.

Discussion

92.	It we see the reaction of methane with halogen, the rate determining step for chlorination is, endothermic reaction of the chlorine atom with methane to form methyl radical and a molecule of HCl. So free radical is the intermediate of the reaction. Formation of free radical depends upon the energy required to break a bond between a hydrogen atom and a carbon atom. Chlorination of propane and Bromination of propane. when compared it is found that bromination is more selective than chlorination. The probability factor for `3^(@),2^(@),1^(@)H` atom is `5.0:3.8:1.0` at `25^(@)C` for chlorination. When the given compound is subjected to chlorination and Bromination, what are the major product. A and B respectively? A. B. C. D.
Answer» Correct Answer - C

Discussion

93.	It we see the reaction of methane with halogen, the rate determining step for chlorination is, endothermic reaction of the chlorine atom with methane to form methyl radical and a molecule of HCl. So free radical is the intermediate of the reaction. Formation of free radical depends upon the energy required to break a bond between a hydrogen atom and a carbon atom. Chlorination of propane and Bromination of propane. when compared it is found that bromination is more selective than chlorination. The probability factor for `3^(@),2^(@),1^(@)H` atom is `5.0:3.8:1.0` at `25^(@)C` for chlorination. Isobutane when reacts with chlorine in presence of ultra violet radiations yield 2 products primary hydrogen substituted and `3^(@)` hydrogen substituted Find their % in product mixtureA. 64% 36%B. 72% 28%C. 36% 64%D. 30% 70%
Answer» Correct Answer - A

Discussion

94.	Assertion: Sodium acetate on Kolbe’s electrolysis gives methane.Reason: Methyl free radical is formed at cathode.(a) A is correct, R is correct and R is a correct explanation of A.(b)A is not correct,R is correct and R is not a explanation for A.(c)Both A and R are wrong.(d)R is correct reason but A is wrong.
Answer» (a) A is correct, R is correct and R is a correct explanation of A.

Discussion

95.	During chlorination of methane to methyl chloride, the propagation step is represented byA. B. C. D.
Answer» Correct Answer - C The process (A) refers to initiation, (C ) refers to propagation and (B), (D) refers to termination

Discussion

96.	Which of the following is correct potential energy diagram for the given chain propagation step ? `CH_(30-H+F^(.) rarr overset(.)(C)H_(3)+H-F Delta H^(@)=-134 Kj//mol`A. B. C. D.
Answer» Correct Answer - c Initial and final energy difference will be `-134kJ // mol`.

Discussion

97.	Which one of the following does not dissolve in conc. `H_(2)SO_(4)`?A. `CH_(2)=CH_(2)`B. `CH-C-=C-CH_(3)`C. `CH_(3)CH_(2)C-=CH`D. `CH-=CH`
Answer» Correct Answer - D

Discussion

98.	Give the mechanism of chlorination of methane.
Answer» It is a free radical chain reaction. 1. Chain initiation: Chlorine molecule undergoes hemolytic fission in the presence of diffused sunlight to form chlorine free radicals. Cl₂ → 2Cl 2. Chain propagation: The chlorine free radical abstracts a hydrogen atom from a methane molecule to form methyl free radical. CH₄ + Cl → CH3 . + HCl Methyl radical combine with another Cl₂ molecule forming chloromethane. 3. Chain termination: It stops when two radicals combine to form a stable covalent molecule. CH₃ + Cl → CH₃Cl CH₃ + CH₃ → CH₃-CH₃ Cl + Cl → Cl₂

98.

Give the mechanism of chlorination of methane.

Answer»

It is a free radical chain reaction.

1. Chain initiation: Chlorine molecule undergoes hemolytic fission in the presence of diffused sunlight to form chlorine free radicals.

Cl₂ → 2Cl

2. Chain propagation: The chlorine free radical abstracts a hydrogen atom from a methane molecule to form methyl free radical.

CH₄ + Cl → CH3 . + HCl

Methyl radical combine with another Cl₂ molecule forming chloromethane.

3. Chain termination: It stops when two radicals combine to form a stable covalent molecule.

CH₃ + Cl → CH₃Cl

CH₃ + CH₃ → CH₃-CH₃

Cl + Cl → Cl₂

Discussion

99.	Combustion of which of the following compounds ( in the presence of excess of oxygen) does not result in the change in the hybrid state of cabon atom?A. `CH_(4)`B. `CH_(2)=CH_(2)`C. `CH_(3)-CH_(3)`D. HC=CH
Answer» Correct Answer - D `underset("Acetylene")(HC-=CH+5//2O_(2))to underset("Carbon dioxide")(2O=C=O+H_(2)O)` In acetylene each C atom is sp-hybridised. Similarly in carbon dioxide, C-atom is sp-hybridrised

Discussion

100.	Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) isA. `CH-=CH`B. `CH_2=CH_2`C. `CH_3-CH_3`D. `CH_4`
Answer» Correct Answer - D (i)Since hydrocarbon (A) reacts with `Br_2` by substitution by form an alkyl bromide , therefore , hydrocarbon (A) must be either `CH_4` or `CH_3CH_3` and the alkyl bromide it forms must be either `CH_3Br` or `CH_3CH_2Br` `CH_4+Br_2 overset"hv"to CH_3Br+HBr` `CH_3-CH_3+Br_2 overset"hv"to CH_3CH_2Br + HBr` (ii) Since `CH_2=CH_2` and `CH-=CH` give addition reactions on treatment with `Br_2` , therefore , hydrocarbon (A) cannot be `CH_2=CH_2` or `CH-=CH`. (iii)Since alkyl bromide on Wurtz reaction gives a hydrocarbon containing less than four carbon atoms, therefore, alkyl halide must be `CH_3Br` and the hydrocarbon formed must be ethane. `2CH_3Br + 2Na underset"(Wurtz reaction)"oversetDeltato underset"Ethane"(CH_3-CH_3)+ 2NaBr`

Discussion

Explore topic-wise InterviewSolutions in .

Addition of `HI` on the double bond of propene yield isopropyl iodide and not `n-` propyl iodide as the major product. This is because the addition proceeds throughA. A more stable free radicalB. A more stable carbanionC. A more stable carbonium ionD. None of the above being a concerted reaction

Acid catalysed hydration of alkene is an example forA. free radical substitutionB. nucleophilic substitutionC. nucleophilic additionD. electrophilic addition

The compouhnd formed when alcoholic solution of ethylene dibromide is heated with granualted zinc isA. etheneB. ethyneC. ethaneD. bromoethane

Propyl bromide on reaction with alcoholic KOH gives-A. Propane+EthaneB. PropeneC. ButaneD. Acetylene

Ethylene dibromide on treating with alcoholic `KOH` givesA. `C_(2)H_(6)`B. `CH_(4)`C. `C_(2)H_(4)`D. `C_(2)H_(2)`

In dehydrohalogenations the base (alcoholic KOH) abstacts-A. The halide ionB. The proton present on the carbon next to the carbon to which the halogen is attached.C. The proton present on the carbon to which the halogen is attached.D. The proton on the `alpha`-carbon

Which of the following compound undergoes dehydrochlorination most easily when treated with alcoholic KOH-A. `CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)Cl`B. `CH_(3)-underset(Cl)underset(|)(C)H-C_(2)H_(5)`C. `CH_(3)-CH_(2)-CH_(2)Cl`D. `(CH_(3))_(3)C-Cl`

1 – chloropropane on treatment with alc. KOH produces :a. propane b. propene c. propyne d. propyl alcohol

Toluene, when treated with `(Br_(2))/(Fe)`, gives p-bromotoluene as the major product because the `-CH_(3)` group of toluene isA. is p-directingB. is m-directingC. activates the ring by herconjugationD. deactivates the ring

When 2-butyne is treated with dil. `H_2SO_4//HgSO_4`, the product formed isA. butanol-1B. butanol-2C. 2-butanoneD. butanal

Propene reacts with HBr in the presence of peroxide to form …………

In the following reaction : `C_2H_2 underset(HgSO_4//H_2SO_4)overset(H_2O)to X hArr CH_3CHO` What is X ?A. `CH_3CH_2OH`B. `CH_3-O-CH_3`C. `CH_3CH_2CHO`D. `CH_2=CHOH`

The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_3CH_2C-=C CH_2CH_3`B. `CH_3CH_2CH_2C-=C CH_2CH_2CH_3`C. `CH_3CH_2C-=CH`D. `CH_3CH=CHCH_3`

The hydrocarbon, which can react with sodium in liquid ammonia isA. `CH_(3)CH_(2)CH_(2)C-=C CH_(2)CH_(2)CH_(3)`B. `CH_(3)CH_(2)C-=CH`C. `CH_(3)CH-=CHCH_(3)`D. `CH_(3)CH_(2)C-=C CH_(2)CH_(3)`

Which pf the following posses the highest meltin point?A. ChlorobenzeneB. o-DichlorobenzeneC. m-DichlorobenzeneD. p-Dichlorobenzene

The thermal decomposition of alkanes in absence of air to give lower alkanes, alkenes and hydrogen is called …………. (A) vapour phase nitration (B) pyrolysis (C) polymerisation (D) combustion

Propene reacts with `Cl_(20` at `500^(@)C` the products is formedA. `1-`chloro propene `-1`B. `2-`chloro propene `-1`C. `1,2-`dichloro propaneD. `3-`chloro propene `-1`

Hydroboratieon of 2-butyne followed by treatment with AcOHA. n-ButaneB. 1-ButyneC. trans-2-ButeneD. cis-2-butene

On chlorination, nitrobenzene will produce__________A. o-chloronitrobenzeneB. p-chloronitrobenzeneC. m-chloronitrobenzeneD. All of these

Benzene reacts with `I_2` in presence of which of the following to give iodobenzene ?A. `HNO_3`B. HIC. `SO_2`D. `H_2O`

Alkanes can be prepared from grignard reagents by reacting with-A. AlcoholsB. Primary aminesC. AlkynesD. all of them

Which of the following hydrocarbon is liquid at room temperature?A. PentaneB. ButaneC. PropaneD. Ethane

Hydrocarbon which is liquid at room temperature isA. pentaneB. butaneC. propaneD. ethane

Liquid hydrocarbon can be converted to a mixture of gaswous hydrocarbon byA. CrackingB. Distillation under reduced pressureC. Hydrolysis of alkyl magnesium bromideD. Oxidation

The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_(3)CH_(2)C=C C_(2)CH_(3)`B. `CH_(3)CH_(2)CH_(2)C=C CH_(2)CH_(2)CH_(3)`C. `CH_(3)CH_(2)C=CH`D. `CH_(3)CH=CHCH_(3)`

Which isomer of `C_(5)H_(12)` give four isomers of monoiodopentane?A. NeopentaneB. n-PentaneC. IsopentaneD. none of these

The hydrocarbon which is a liquid at room temperature is:A. butaneB. propaneC. decaneD. neopentane

The isomerisation of 1-butyne to 2-butyne can be achieved by treatment withA. hydrochloric acidB. ammoniacal silver nitrateC. ammoniacal cuprous chlorideD. ethanolic potassium hydroxide

The thermal decomposition of alkanes in the absence of air is known as:A. OxidationB. CombustionC. HydrogenationD. Pyrolysis

Methane can be prepared by:A. Wurtz reactionB. HydrogenationC. Decarboxylation of sodium acetate with soda limeD. Dehydrohalogenation

Which of the following hydrocarbon is liquid at room temperature?A. EthaneB. PropaneC. HexaneD. Butane

Water destroys Grignard reagents. Why?

The chlorination of an alkane involves:A. Cl free radicalsB. `Cl^(+)` speciesC. `Cl^(-)` speciesD. `CH_(4)` free radicals

Isomerisation in alkane may be brought about by using-A. `Al_(2)O_(3)`B. `Fe_(2)O_(3)`C. `AlCl_(3)` and `HCl`D. Concentrated `H_(2)SO_(4)`

An alkane is most likely to react with:A. A Free radicalB. An alkaliC. An electrophileD. A nucleophile

Write down the combustion reaction of propane whose ΔH° = -2220 kJ

Is it possible to prepare methane by Kolbe’s electrolytic method.

Ethane is subjected to comnustion process. The hydrid state of carbon during the combusion changes fromA. `sp^(2) "to" sp^(3)`B. `sp^(3)` to spC. sp tp `sp^(3)`D. unpredictable

Which of the following is not an oxidation product of alkane?A. AlcoholB. AldehydeC. Carboxylic acidD. Ether

During chlorination of methane to methyl chloride, the propagation step is represented byA. B. C. D.

Which of the following is correct potential energy diagram for the given chain propagation step ? `CH_(30-H+F^(.) rarr overset(.)(C)H_(3)+H-F Delta H^(@)=-134 Kj//mol`A. B. C. D.

Which one of the following does not dissolve in conc. `H_(2)SO_(4)`?A. `CH_(2)=CH_(2)`B. `CH-C-=C-CH_(3)`C. `CH_(3)CH_(2)C-=CH`D. `CH-=CH`

Give the mechanism of chlorination of methane.

Combustion of which of the following compounds ( in the presence of excess of oxygen) does not result in the change in the hybrid state of cabon atom?A. `CH_(4)`B. `CH_(2)=CH_(2)`C. `CH_(3)-CH_(3)`D. HC=CH

Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) isA. `CH-=CH`B. `CH_2=CH_2`C. `CH_3-CH_3`D. `CH_4`