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301.

The intensity of magnetic field is H and moment of magnet is M. The maximum potential energy isA. MHB. 2MHC. 3MHD. 4MH

Answer» Correct Answer - A
302.

The intensity of magnetic field is H and moment of magnet is M. The maximum potential energy isA. MBB. 2MBC. 3MBD. 4MB

Answer» Correct Answer - A
`U=MB(costheta_(0)-costheta)`
`=MB(costheta-cos 180)`
`=2MB`
303.

Assertion (A): Magnetic moment of an atom is due to both, the orbitla motion and spin motion of every electron. Reason (R ): A charged particle at rest producesA. Both `A` and `R` are true and `R` is the correct explanation of `A`.B. Both `A` and `R` are true and `R` is not correct explanation of `A`.C. `A` is true, But `R` is falseD. `A` is false, But `R` is true

Answer» Correct Answer - C
304.

For dimgnetic materials magnetic susceptibility isA. small and negativeB. small and positiveC. large and negativeD. large and positive

Answer» Correct Answer - A
305.

The difference in potential of two points lying on the axis a distance of 50 cm and 100 cm respectivelym from its centre isA. `9 xx10^(7) J//Am`B. `8xx 10^(-7) J//Am`C. `9 xx10^(-7) J//Am`D. `8xx 10^(7) J//Am`

Answer» Correct Answer - C
`V_(1)-V(2)=(mu_(0))/(4pi)M[(1)/(r_(1)^(2))-(1)/(r_(2)^(2))]=10^(-7)xx3[(1)/(0.25)-(1)/(1)]`
`9xx10^(-7) J//Am`
306.

Hysteresis loops for two magnetic matericals `A` and `B` are as given below: `(2016)` These materials are used to make magnets for electric generators, transformer core and electromagent core. Then, it is proper to useA. On substituting the value of `theta`B. A for electromagnets and `B` for electric generatorsC. A for transformers and `B` for electric generatorsD. `B` for electromagnets and transformers

Answer» Correct Answer - D
We need less retentivity and less coercivity and less coercivity for electronagents and transformers. Hence samll area of hysteresis loop.
307.

The magnetic moment of a length 10 cm amd pole strenth 4.0 Am will beA. `0.4 Am^(2)`B. `1.6 Am^(2)`C. `20 Am^(2)`D. `8.0 Am^(2)`

Answer» Correct Answer - A
308.

Can you bring two similar poles of two different magnetic close together easily? Why?

Answer»

No, because like poles repel each other, when two magnetic are brought close to each other.

309.

Why is it not possible to isolate a single magnetic pole?

Answer»

Magnetic poles always exist in pairs and cannot: exist independently. If a bar magnet is broken into two or more pieces, each of them will have a north pole and a south pole. Hence, it is impossible to obtain a piece of magnet with only one magnetic pole.

310.

What are artificial magnets ?

Answer»

Magnets that are made by humans from magnetic substances are called artificial magnets. They can be made in different shapes and sizes like bar magnet, horseshoe magnet, etc.

311.

A magnetic material of volume `30cm^(3)` is placed in a magnetic field of intensity `5` oversted. The manetic moment produced due it is `6 amp-m^(2)`. The value of magnetic induction will be.A. `0.2517` TeslaB. `0.025` TeslaC. `0.0025` TeslaD. `25` Tesla

Answer» Correct Answer - A
`H=50` ersted
`=5xx(10^(3))/(4pi) AM^(-1) , I=(M)/(V)=(6)/(30xx10^(-6))`
`B=mu_(0)(H+I)`
312.

A bar magnet suspended freely in uniform magnetic field is vibrating with a time period of `3` seconds. If the initial field strength is `2T`. Then the final field strength, for which time period becomes `4` seconds isA. `1.125`Tesla`B. `0.625`Tesla`C. `3.55` TeslaD. `0.75` Tesla

Answer» Correct Answer - A
`T=2pisqrt((I)/(MB))` and `T alpha (1)/(sqrtB)`
313.

The magnetic field due to the earth is closely equivalent to that due toA. A large magnet of length equal to the diameter of the earthB. A magnetic dipole placed at the centre of the earthC. A large coil carrying currentD. Neither of the above

Answer» Correct Answer - A
314.

The true dip at a place is `30^(@)` . What is the apparent dip when the dip circle is turned `60^(@)` out of the magnetic meridian ?

Answer» Correct Answer - `49.7 ^(@)`
315.

A dip circle is at right angles to the magnetic meridian. What will be the apparent dip ?A. `0^(@)`B. `30^(@)`C. `60^(@)`D. `90^(@)`

Answer» Correct Answer - D
316.

In two separate experiment the neutral point due to two small magnets are at a distance of r and 2r in broad side-on position. The ratio of their magnetic moments will beA. `4:1`B. `1:2`C. `2:1`D. `1:8`

Answer» Correct Answer - D
317.

What is a bar magnet?

Answer»

Bar magnet is a magnet in the shape of bar having two poles of equal and opposite pole strengths separated by certain distance (2l).

318.

A bar magnet is placed north-south with its north pole due north. The points of zero magnetic field will be in which direction from the centre of the magnet?A. North and southB. East and westC. North-east and south-westD. North-west and south-east

Answer» Correct Answer - B
319.

What are the rules concerning the lines of force?

Answer»

i. Magnetic lines of force originate from the north pole and end at the south pole. 

ii. The magnetic lines of force of a magnet or a solenoid form closed loops. This is in contrast to the case of an electric dipole, where the electric lines of force originate from the positive charge and end on the negative charge.

iii. The direction of the net magnetic field \(\vec{B}\) at a point is given by the tangent to the magnetic line of force at that point. 

iv. The number of lines of force crossing per unit area decides the magnitude of magnetic field \(\vec{B}\)

v. The magnetic lines of force do not intersect. This is because had they intersected, the direction of magnetic field would not be unique at that point.

320.

What are the magnetic lines of force?

Answer»

The magnetic field around a magnet is shown by lines going from one end of the magnet to the other. These lines are named as magnetic lines of force.

321.

Magnetic lines of induction in external space and inside the magnetic dipole respectively go fromA. S-pole to N-pole and N-pole to S-poleB. N-pole to S-pole and S-pol to N-poleC. S-pole to N-pole and S-pole to N-poleD. N-pole to S-pole and N-pole to S-pole

Answer» Correct Answer - B
322.

A magnetic dipole of moment M is placed in uniform magnetic field B so that angle betweem direction of M and B is `theta`,the torque acting on the magnetic dipole isA. MB `sintheta`B. MB`tantheta`C. MB `costheta`D. MB

Answer» Correct Answer - A
323.

Subceptibility is positive and small for aA. Paramagnetic substanceB. Ferromagnetic substanceC. Non magnetic substanceD. Diamagnetic substance

Answer» Correct Answer - A
324.

A magnetic field is produced by the two magnets as shown In the figure.The magnetic field is A. uniformB. Non uniform and N is a strong endC. Non uniform ansd S is a strong endD. Uniform and both N and S are equally strong.

Answer» Correct Answer - B
325.

When a material is used in a magnetic field B,a magnetic moment proportional to B but opposite in direction is induced.The metal isA. DiamagneticB. ParamagneticC. FerromagneticD. Antimagnetic

Answer» Correct Answer - A
326.

The group of the atomic magnets formed due to interaction are called asA. DomainsB. ResistancesC. InductancesD. None of these

Answer» Correct Answer - A
327.

Domain formation is the necessary feature ofA. Non magneticsB. DiamagneticsC. ParamagneticsD. Ferromagnetics

Answer» Correct Answer - D
328.

Domain formation is the necessary feature ofA. ferro magnetismB. paramagnetismC. diamagnetismD. electro magnetism

Answer» Correct Answer - A
329.

The magnetic force required to demagnetise the material isA. retentivityB. CoercivityC. energy lossD. hysterisis

Answer» Correct Answer - B
330.

What is the unit of magnetic intensity, H? 

Answer»

The unit of magnetic intensity, H is Am-1.

331.

Define magnetic intensity. 

Answer»

The degree to which a magnetic field can magnetise a material is represented in terms of magnetic intensity. 

Magnetic intensity of a material is the ratio of external magnetic field to the permeability of free space. 

Magnetic intensity of a material, H =B00, where B0 - external magnetic field, μ0 - permeability of free space.  

332.

The dimensions of magnetic field intensity in M, L, T and C is given as(A) MT-2 C-1(B) MLT-1 C-1(C) MT-2 C-2(D) MT-1 C-1

Answer»

The answer is (D) MT-1 C-1 

333.

The magnetic moment has dimensions of(A) [LA](B) [L2A](C) |LT-1A|(D) [L2T-1A]

Answer»

The answer is (B) [L2A]

334.

Domain formation is the necessary feature of(A) Diamagnetism.(B) Paramagnetism(C) Ferromagnetism(D) all of theses

Answer»

The answer is (C) Ferromagnetism

335.

Relative permeability and permeability of a material are er and pr respectively. Which of the following values of these quantities are allowed for a diamagnetic material?(A) ∈r = 1.5, µr = 1.5(B) ∈r = 0.5, µr = 1.5(C) ∈r = 1.5, µr = 0.5(D) ∈r = 0.5, µr = 0.5 .

Answer»

The answer is (C) ∈r = 1.5, µr = 0.5

336.

What is magnetic declination?

Answer»

Declination at the place is the angle between true geographic north direction and the north shown by the magnetic compass needle. 

337.

Define neutral point in magnetic field of a bar magnet ? 

Answer»

It is a point near the magnet where the magnetic field due to the magnet is equal and opposite to the horizontal component of magnetic field. The resultant magnetic field at the neutral point is zero.  

338.

What are elements of earth’s magnetic field? Mention them. 

Answer»

They are: 

(1) Magnetic declination (θ) at that place. 

(2) Magnetic inclination (I) dip at that place. 

(3) Horizontal comp of earths magnetic field (BH) at that place. 

339.

Where on earth's surface the value of vertical component of magnetic field is zero ?

Answer»

At magnetic equator 

340.

What is magnetic dip or inclination? 

Answer»

Magnetic dip at a place is the angle between the earth’s total magnetic field at a place and horizontal drawn in magnetic meridian.

341.

What is the relation between horizontal component of earth’s field HE, vertical component of earth’s field ZE and inclination, I?

Answer»

ZE = BEsinI or HE = BEcosI or tanI = ZE/HE

342.

What is the relation between magnetic relative permeability and permeability of the medium? 

Answer»

μ = μ0μr. μ is the permeability of medium, μ0 is permeability of free space, and μr is relative permeability of the medium. 

343.

What is the unit of magnetisation? 

Answer»

The unit of magnetisation is Am-1.

344.

Describe the magnetisation (M), magnetic intensity (H), magnetic susceptibility (χ) and permeability (µ, µo and µr).  

Answer»

We know that a circulating electron in an atom has a magnetic moment. In a bulk material, these moments add up vectorially and they can give a net magnetic moment which is non-zero. We define magnetisation M of a sample to be equal to its net magnetic moment per unit volume: 

M = mnet/V 

M is a vector with dimensions L A and is measured in a units of Am-1. Consider a long solenoid of n turns per unit length and carrying a current I. The magnetic field in the interior of the solenoid was shown to be given by 

B0 = μ0 nI 

If the interior of the solenoid is filled with a material with non-zero magnetisation, the field inside the solenoid will be greater than B0. The net B field in the interior of the solenoid may be expressed as 

B = B0 + Bm 

where Bm is the field contributed by the material core. It turns out that this additional field Bm is proportional to the magnetisation M of the material and is expressed as 

Bm = μ0

where μ0 is the same constant (permittivity of vacuum) that appears in Biot-Savart law. It is convenient to introduce another vector field H, called the magnetic intensity, which is defined by H = B/µ- M 

where H has the same dimensions as M and is measured in units of Am-1. Thus, the total magnetic field B is written as 

B = μ0 (H + M) 

If we partition the contribution to the total magnetic field inside the sample into two parts: one, due to external factors such as the current in the solenoid. This is represented by H. The other is due to the specific nature of the magnetic material, namely M. The latter quantity can be influenced by external factors. This influence is mathematically expressed as 

M = χ H 

where χ, a dimensionless quantity, is appropriately called the magnetic susceptibility. It is a measure of how a magnetic material responds to an external field. lists χ for some elements. It is small and positive for materials, which are called paramagnetic. It is small and negative for materials, which are termed diamagnetic. In the latter case M and H are opposite in direction. we obtain, 

B = μ0 (1 + χ H) = μ0 μr H = μ H 

where μr = 1 + χ, is a dimensionless quantity called the relative magnetic permeability of the substance. It is the analog of the dielectric constant in electrostatics. The magnetic permeability of the substance is m and it has the same dimensions and units as μ0

μ = μ0 μr = μ0 (1 + χ ) 

The three quantities χ, μr and μ are interrelated and only one of them is independent. Given one, the other two may be easily determined.  

345.

What are the Common information about Magnetism ?

Answer»

Some of the commonly known ideas regarding magnetism are: 

(i) The earth behaves as a magnet with the magnetic field pointing approximately from the geographic south to the geographic north. 

(ii) When a bar magnet is freely suspended, it points in the north-south direction. The tip which points to the geographic north is called the north pole and the tip which points to the geographic south is called the south pole of the magnet. 

(iii) There is a repulsive force when north poles (or south poles) of two magnets are brought close together. Conversely, there is an attractive force between the north pole of one magnet and the south pole of the other. 

(iv) We cannot isolate the north, or south pole of a magnet. If a bar magnet is broken into two halves, we get two similar bar magnets with somewhat weaker properties. Unlike electric charges, isolated magnetic north and south poles known as magnetic monopoles do not exist. 

(v) It is possible to make magnets out of iron and its alloys. 

346.

Calculate the work done in rotating a magnet of magnetic moment `3*0JT^-1` through an angle of `60^@` from its position along a magnetic field of strength `0*34xx10^-4T`.

Answer» Correct Answer - `5.1 xx 10^(-5) J`
347.

The work done in rotating a magnet of magnetic moment `2A-m^(2)` in a magnetic field to opposite direction to the magnetic field, isA. ZeroB. `2xx10^(–2) J`C. `10^(–2 )J `D. 10 J

Answer» Correct Answer - B
348.

The work done in rotating the magnet form the direction of uniform field to the opposite direction to the field is`W`. The work done in rotating the magnet form the field direction to half the maximum couple position isA. `2W`B. `(sqrt3W)/(2)`C. `(W)/(4)(2-sqrt3)`D. `(W)/(2)(1-sqrt3)`

Answer» Correct Answer - C
`W=MB[costheta_(1)-costheta_(2)]`
349.

A magnetic field strength `(H) 3xx10^(3) Am^(-1)` produces a magnetic field of induction `(B)` of `12piT` in an iron rod. Find the relative permeability of iron ?

Answer» `mu=(B)/(H)=(12pi)/(3xx10^(3))=4pixx10^(-3)`
`therefore mu_(r)=(mu)/(mu_(0))(4pixx10^(-3))/(4pixx10^(-7))=10^(4)`
350.

The magnetic moment of a magnet of mass `75 gm` is `9xx10^(-7) A-m^(2)`. If the density of the material of magnet is `7.5xx10^(3) kg m^(-3)`, then find intensity of magnetisation is

Answer» `I=(M)/(V)` Where volume, `V=( "mass"(m))/("density"(rho))`
`=(Mxxrho)/(m)=(9xx10^(-7)xx7.5xx10^(3))/(75xx10^(-3))=0.09A//m`