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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2301. |
Who is the founder of Zero |
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Answer» Aryabhatta Aryabhatta ha Mayans Aryabhatta Aryabhattt |
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| 2302. |
Why we multiply any number with 0 then answer is always be 0 why ? |
| Answer» The\xa0multiplication\xa0property of zero: Regardless of what the other\xa0number\xa0is,\xa0multiplying\xa0by zero\xa0always\xa0results in an\xa0answer\xa0of zero. ...\xa0Any\xa0two\xa0numbers\xa0whose sum is zero are additive inverses of one another. For example, if\xa0you\xa0add -5 to 5,\xa0you\xa0arrive at zero. So -5\xa0and\xa05 are additive inverses of one another. | |
| 2303. |
Xh |
| Answer» Don\'t post personal information, mobile numbers and other details.Don\'t use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.Ask specific question which are clear and concise.If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html | |
| 2304. |
The area of triangle with given tow sides 18 cm and 10 cm respectively and perimeter equal to 42 cm |
| Answer» Let the third side of triangle Be X cm. There for,Sum of all sides = perimeter18+10+X= 42X= 42-28X= 14cm (third side of triangle)No for finding area of triangle we will use heron s formulaFirst find the semi perimeter (s)S =(sum of all sides/2)S = (42/2)S = 21★\xa0Formula\xa0=\xa0√s(s–a)\xa0(s–b)\xa0(s–c)\xa0★➛\xa0√21\xa0(21\xa0–\xa018)\xa0(21\xa0–\xa010)\xa0(21\xa0–\xa014)➛\xa0√21\xa0(3)\xa0(11)\xa0(7)➛\xa0√3\xa0\xa07\xa0\xa03\xa0\xa011\xa0\xa07➛\xa03\xa0\xa07\xa0√11➛\xa021√11\xa0cm²Hence, the area of triangle is 21√11 cm². Option (d) is correct. | |
| 2305. |
Gkggjfjhfgh gkcjggj kee Kshatriyas hdhdjdgffn |
| Answer» Don\'t post personal information, mobile numbers and other details.Don\'t use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.Ask specific question which are clear and concise.If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html | |
| 2306. |
ABCD is a rhombus such that angle ACB = 40°, then angle ADB is -----(a) (b) (c) |
| Answer» 40° | |
| 2307. |
EXERCISE 13.8 2nd problem |
| Answer» 2. Find the amount of water displaced by a solid spherical ball of diameter(i) 28 cm (ii) 0.21 m(Assume π =22/7)Solution:(i) Diameter = 28 cmRadius, r = 28/2 cm = 14cmVolume of the solid spherical ball = (4/3) πr3Volume of the ball = (4/3)×(22/7)×143\xa0= 34496/3Hence, volume of the ball is 34496/3 cm3(ii) Diameter = 0.21 mRadius of the ball =0.21/2 m= 0.105 mVolume of the ball = (4/3 )πr3Volume of the ball = (4/3)× (22/7)×0.1053\xa0m3Hence, volume of the ball = 0.004851 m3 | |
| 2308. |
if angle adc = 23 degree find angle ABC |
| Answer» Make sure that Ur question is proper | |
| 2309. |
2/3×9/2×3/5 |
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Answer» 9/5 2/3×9/2×3/5= 9/5 |
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| 2310. |
i want 4.3,4.4 pleasei want to write |
| Answer» 1. Draw the graph of each of the following linear equations in two variables:(i) x+y = 4Solution:To draw a graph of linear equations in two variables, let us find out the points to plot.To find out the points, we have to find the values which x and y can have, satisfying the equation.Here,x+y = 4Substituting the values for x,When x = 0,x+y = 40+y = 4y = 4When x = 4,x+y = 44+y = 4y = 4–4y = 0\txy0440\tThe points to be plotted are (0, 4) and (4,0)For for click on the given link:EX 4.3:\xa0NCERT Solutions for Class 9 Maths Exercise 4.3 ...Ex 4.4 :\xa0NCERT Solutions for Class 9 Maths Exercise 4.4 ... | |
| 2311. |
Rational number between 3 and 5 |
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Answer» 30/10: 50/10 3.5 4 Infinite 3 and 5 |
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| 2312. |
Show that if the diagonals of quadrilateral bisect each other at right angles then it is a rhombus |
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Answer» It\'s is a right answer ? Sol: We have a quadrilateral ABCD such that the diagonals AC and BD bisect each other at right angles at O. AO = AO\xa0[Common] OB = OD\xa0[Given that O in the mid-point of BD]\xa0∠AOB = ∠AOD [Each = 90°] ΔAOB ≌ ΔAOD\xa0[SAS criteria]\xa0Their corresponding parts are equal.AB = AD\xa0...(1)Similarly, AB = BC\xa0...(2)BC = CD ...(3)CD = AD\xa0...(4)∴ From (1), (2), (3) and (4), we have AB = BC CD = DAThus, the quadrilateral ABCD is a rhombus. |
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| 2313. |
2x-3x |
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Answer» 2x - 3x = (-x) -x 2x-3x=-x -x |
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| 2314. |
Three angels of a quadrilateral abcd are equal is it a parallelogram why are why not |
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Answer» Yes all angles of parallelogram can be equal to each other Eg:Rectangle, Square They both are also parallelogram No, because parallelogram doesn\'t have all equal angles |
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| 2315. |
Factorise 125 x³+8y³+z³-30xyz |
| Answer» (5x)³+(2y)³+(z)³-30xyz=(5x+2y+z)[(5x)²+(2y)²+(z)²-(5x×2y)-=(2y×z)-(5x×z)]= (5x+2y+z)(25x²+4y²+z² -10xy - 2yz- 5xz) | |
| 2316. |
An isosceles right triangle has area 8cm square. The length of it\'s hypotenuse is? |
| Answer» The\xa0hypotenuse of a right triangle\xa0is always the side opposite the\xa0right\xa0angle. It is the longest side in a\xa0right triangle. The other two sides are called the opposite and adjacent sides. These sides are labeled in relation to an angle. In geometry, an\xa0isosceles triangle\xa0is a\xa0triangle\xa0that has two sides of equal\xa0length. Sometimes it is specified as having exactly two sides of equal\xa0length, and sometimes as having at least two sides of equal\xa0length, the latter version thus including the\xa0equilateral triangle\xa0as a special case. | |
| 2317. |
If P (a) =0 then a is called...... Of polynomial |
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Answer» Zero; as polynomial value of the question will be zero only?Hope you understood like if you Zero Zero |
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| 2318. |
What is square of 65 |
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Answer» 4225 The square of 65 is 4225 The square of 65 is 4225 The square of 65 is 4225 |
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| 2319. |
If diagonal of a cyclic qu |
| Answer» If the diagonals of a cyclic quadrilateral are diameters of the circle through the opposite vertices of the quadrilateral. Prove that the quadrilateral is a rectangle.AnswerHere, ABCD is a cyclic quadrilateral in which AC and BD are diameters .Since AC is a diameter.∴ ∠ABC =\xa0∠ADC = 90°[∵ angle of a semicircle = 90°]Also, BD is a diameter\xa0∴∠BAD =\xa0∠BCD\xa0= 90°[∵ angle of a semicircle\xa0= 90°]Now, all the angles of a cyclic quadrilateral ABCD are\xa090° each. Hence, ABCD is a rectangle. | |
| 2320. |
I want to ask 13.1 question 3.. please explain |
| Answer» Given: perimeter of rectangular wall=2(l+b)=250m (1)Now area of the four walls of the room=total cost to paint walls of the room ________________________________Cost to paint 1m² of the wall =15000 = 1500 m² (2)________ 10Therefore, area of the four walls = lateral surface area 2(bh+hl) = 2h(b+l) =1500 250×h = 1500 (from equation 1 & 2) h = 1500 ________ =6m 250 Hence, required height of the hall is 6m. | |
| 2321. |
If the non parallel sides of a trapezium are equal prove it is acyclix |
| Answer» Shut up man ??? | |
| 2322. |
The angles of quadrilateral are in the ratio 3:5:9:13. find all the angles of the quadrilateral. |
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Answer» which subham... Hello It\'s me shubham Let them x. Then all angle will be 3x,5x,9x and 13xSo, 3x +5x +9x+ 13x = 360 30x = 360 X = 12 degreeSo, required angles are 36,60,108 and 156 degreeThank you pls can anyone reply |
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| 2323. |
Is square root 5 is a rational number |
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Answer» No Let us assume that √5 is a rational number.So\xa0it t can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/qOn squaring both the sides we get,⇒5=p²/q²⇒5q²=p² —————–(i)p²/5= q²So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational number |
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| 2324. |
If x=8 ,find the value of x²+x-5 |
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Answer» Given :x=8x²+x-5(8)² + 8-564+8-572-567 67 Sorry by-mistake added x = 6 in place of x= 8. Let p(x)=x^2 +x-5Putting x=8 in p(x) = (8)^2+8-5= 64+8-5= 64+3 = 67 Put x = 8x²+x-5= (6)2 + 6 - 5= 36 + 1= 37\xa0\xa0 |
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| 2325. |
Prove that each angle of equilateral triangle is of 60 degre |
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Answer» All angles of equilateral triangle is equal x+x+ x= 180 3x = 180 x= 180/3= 60 Not sufficient By angle sum property we know that the sum of all the angles of a triangle is 180o We know that all the sides of a triangle are equal. i.e all the angles of an equilateral triangle are equal. Let each angle be x. x+x+x=180 60o 3x = 180 ⇒x = 60 Hence the answer. By angle sum property we know that the sum of all the angles of a triangle is 180oWe know that all the sides of a triangle are equal.i.e all the angles of an equilateral triangle are equal.Let each angle be x.x+x+x=18060o3x = 180⇒x = 60Hence the answer. |
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| 2326. |
Write an integer |
| Answer» In Maths,\xa0integers\xa0are the numbers which can be positive, negative or zero, but cannot be a fraction.\xa0The examples of integers are, 1, 2, 5,8, -9, -12, etc. The symbol of integers is “Z“. | |
| 2327. |
Find the remainder when x^3+3x^2+3x+1 is divided by x-1 |
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Answer» A n s w e rApply remainder theorem=> x -\xa01 =0=> x = 1Replace x by 1 we get=> x3\xa0+ 3x2\xa0+ 3x + 1=>(1)3\xa0+ 3(1)2\xa0+ 3(1) + 1=> 1 + 3 + 3 + 1=> 8Remainder is 8 14 |
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| 2328. |
Factorise 4x²+9y²+16z²+12xy+24yz+16xz |
| Answer» \xa04x²+9y²+16z²+12xy + 24yz +16xz= (2x)²+(3y)²+(4z)²+2(2)(3)xy +2(3)(4)yz + 2(2x)(4z)= (2x + 3y +4z)(2x + 3y + 4z)=\xa0(2x + 3y + 4z)2 | |
| 2329. |
How to learn 1 chapter of math with concept and formulas |
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Answer» That\'s why I can\'t solve again and again One more answer I ask only this one question Because I want to learn whole syllabus of mathematics Because tommorow is my paper I try that Baar baar solve Karo tab achhe se aayenga |
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| 2330. |
Give equation of two lines passing through (2,14) how many more such lines are there and why? |
| Answer» Since the given solution is\xa0(2,14)∴x=2\xa0and\xa0y=14Then, one equation is\xa0x+y=2+14=16x+y=16And, second equation is\xa0x−y=2−14=−12x−y=−12And, third equation is\xa0y=7x7x−y=0So, we can find infinite equations because through one point infinite lines can pass. | |
| 2331. |
How to make algles |
| Answer» 2+2 | |
| 2332. |
Chapter 13 of mathematics Who can tell well in full detail and make easiest chapter for me |
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Answer» chapter :- 13 Surface area and volume You want formula of chapter 13 named menstruation ????? Say Is anyone tell |
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| 2333. |
3y + 4 = 0 |
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Answer» 3y=-4Y=-4/3 This is easy peasy?????????? 3y + 4 = 03y = - 4y = - 4/ 3 3y + 4 = 03y = - 4y= -4/3 |
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| 2334. |
12x2-7x+1 |
| Answer» 12x^2-7x+1=012x^2-4x-3x+1=04x(3x-1)-1(3x-1)=0(4x-1)(3x-1)=0x=1/4, x=1/3 | |
| 2335. |
The diagonal of a dash are equal and bisect each other at 90 degree |
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Answer» Square The diagonals of a square are equal and bisect each other at right angles.Detailed proofLet ABCD be a square. Let the diagonals AC and BD intersect each other at a point O. To provethat the diagonals of a square are equal and bisect each other at right angles, we have toprove AC = BD, OA = OC, OB = OD, and ∠AOB = 90º.In ΔABC and ΔDCB,AB = DC (Sides of a square are equal to each other)∠ABC = ∠DCB (All interior angles are of 90)BC = CB (Common side)So, ΔABC ≅ ΔDCB (By SAS congruency)Hence, AC = DB (By CPCT)Hence, the diagonals of a square are equal in length.In ΔAOB and ΔCOD,∠AOB = ∠COD (Vertically opposite angles)∠ABO = ∠CDO (Alternate interior angles)AB = CD (Sides of a square are always equal)So, ΔAOB ≅ ΔCOD (By AAS congruence rule)Hence, AO = CO and OB = OD (By CPCT)Hence, the diagonals of a square bisect each other.In ΔAOB and ΔCOB,As we had proved that diagonals bisect each other, therefore,AO = COAB = CB (Sides of a square are equal)BO = BO (Common)So, ΔAOB ≅ ΔCOB (By SSS congruency)Hence, ∠AOB = ∠COB (By CPCT)However, ∠AOB + ∠COB = 1800 (Linear pair)2∠AOB = 1800∠AOB = 900Hence, the diagonals of a square bisect each other at right angles. |
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| 2336. |
What is the degree of constant polynamials 19 |
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Answer» 0 0 A n s w e r : 0Degree of constant polynomial is always Zero\xa0As it doesn’t have any variable, because in actual degree of the polynomial is nothing but the highest power of variable x in it. |
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| 2337. |
Chapter 7 ma ex 7.3 ma q1 |
| Answer» In the above question, it is given that ΔABC and ΔDBC are two isosceles triangles.(i) ΔABD and ΔACD are similar by SSS congruency because:AD = AD (It is the common arm)AB = AC (Since ΔABC is isosceles)BD = CD (Since ΔDBC is isosceles)∴ ΔABD ΔACD.(ii) ΔABP and ΔACP are similar as:AP = AP (It is the common side)PAB = PAC (by CPCT since ΔABD ΔACD)AB = AC (Since ΔABC is isosceles)So, ΔABP ΔACP by SAS congruency condition.(iii) PAB = PAC by CPCT as ΔABD ΔACD.AP bisects A. — (i)Also, ΔBPD and ΔCPD are similar by SSS congruency asPD = PD (It is the common side)BD = CD (Since ΔDBC is isosceles.)BP = CP (by CPCT as ΔABP ΔACP)So, ΔBPD ΔCPD.Thus, BDP = CDP by CPCT. — (ii)Now by comparing (i) and (ii) it can be said that AP bisects A as well as D.(iv) BPD = CPD (by CPCT as ΔBPD ΔCPD)and BP = CP — (i)also,BPD +CPD = 180° (Since BC is a straight line.)⇒ 2BPD = 180°⇒ BPD = 90° —(ii)Now, from equations (i) and (ii), it can be said thatAP is the perpendicular bisector of BC. | |
| 2338. |
(a^2+b^2)= |
| Answer» (a+b)(a-b) | |
| 2339. |
Sardi ka answer se kya relation h sir ek to aapki Antoinette aur bhav kha rhe ho |
| Answer» ?????? | |
| 2340. |
Mean of ten observations is 56 each observations increased by 3what is the new mean |
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Answer» 59 What thing were 59 |
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| 2341. |
Represent 9.3 on number line... |
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Answer» ANSWERSteps:1) Draw a line segment AB of length 9.3 units.2) Extend the line by 1 unit more such that BC=1 unit .3) Find the midpoint of AC.4) Draw a line BD perpendicular to AB and let it intersect the semicircle at point D.5) Draw an arc DE such that BE=BD.Therefore, BE= Root 9.3 units |
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| 2342. |
If each side of a triangle is increased by 5 times then it\'s area will increase by |
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Answer» 5 5 times. |
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| 2343. |
What is the equation of line passing through the origin? |
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Answer» Thanks a lot ☺️ y=mx, m is the gradiant |
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| 2344. |
31x -19X +8 |
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Answer» 31x-19x +8= 12x + 8= 4(3x + 2) Hope it helps you.. 31x -19X +8= 12x + 8= 4(3x + 2) |
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| 2345. |
Find the surface area of Sphere whose diameter is 16 cm |
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Answer» 804.57 A\xa0=4πr2d=2rSolving forAA = π\xa0d2 =\xa0π·162\xa0≈804.24772 cm² |
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| 2346. |
(a+6b)^2 |
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Answer» a²+12ab+36b² (a + 6b)2 = a2 + (6b)2 + 2 (a)(6b)= a2 + 36b2 + 12ab |
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| 2347. |
Draw the graph of x + 2y = 7 |
| Answer» | |
| 2348. |
290 min =how many hours |
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Answer» 4 hours 50 minutes 4h 50 min 4.833333333333333 hours 60 min = 1 hour290 min = 4 hour 50 min |
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| 2349. |
Factorise 3x²+x-2 |
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Answer» (x+2)(3x-2) (x+1)(3x-2) 3x²+x-2= 3x²+3x- 2x -2= 3x(3 x + 2) - 2 ( x + 2)= (3x - 2) ( x + 2) 3x^2+x-23x^2-3x-2-23x^2+3x-2x-23x(x+1)-2(x+1)=(3x-2)(x+1) |
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| 2350. |
Prove that ✌two different circles ⭕ cannot intersect each other at more than two 2⃣ points. |
| Answer» Let us consider that 2 distinct circles intersect at more than 2 points.∴These points are non-collinear points.As 3 non-collinear points determine one and only one circle∴There should be only one circle.(i.e. those circles are supposed to superimpose each other)But, the superimposition of 2 circles of different radii is impossible, i.e. concentric circles would be derived instead.This contradicts our assumption. Therefore, our assumption is wrong.Hence, 2 circles cannot intersect each other at more than 2 points. | |