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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2351. |
Cf:ty cnfm ygtvyv |
| Answer» Buyf, ggsvbj jnftujm | |
| 2352. |
if surface area of a sphere is 748pie cm² .find its radius. |
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Answer» Find six rational numbers between 3and 4 Given , surface area of sphere = 784πwe know that , surface area of sphere = 4πr²so , 4πr²= 784π4r²=784r²=196r= √196r = radius = 14 units |
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| 2353. |
The equation 2x+3y =12 has |
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Answer» Put x = 0 2(0) + 3y = 12 0 + 3y = 12 3y =12 y = 12÷3y = 4x=0 , y=4(0,4) Put x=1 2( 1) + 3y=12 2 +3y = 12 3y= 12 -2 3y = 10 y = 10upon 3 x =0 , y = 10 upon 3 (0,10 upon 3) two equation in one variable ???????? 2(3)+3(2)=12. (12=12) |
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| 2354. |
Find the total surface area of a cone whose radius is 2runits and slant height is 2l units. |
| Answer» givenslant height = 2lradius = 2rtotal surface area of the cone = 2π*radius(radius+slant height)=2π*2r[2r+2l]= 4πr 2(r+l)= 8πr (r +l) sq units | |
| 2355. |
if px x square -2√2x+1then (2√2) is equal to |
| Answer» | |
| 2356. |
Gje he o Isuzu Karsh |
| Answer» Send me all worksheet | |
| 2357. |
Simplify and write the answer in standard form.1/8+ 5/12+ 2/7+ 7/12+ 9/7+ -5/16 |
| Answer» First take LCM of all Fractions8,12,7,12,16That will be 2×2×2×2×2×7=16×14 =224Then see that 224 comes on which number in each of denominator(i.e. 8,12,7,12,16).Then multiply the number on which 224 comes in denominator by numerator.Then add all and at last simplify it and hence, your answer comes. | |
| 2358. |
Exercise 4.2 3rd qestion explained ans |
| Answer» A. 0-2(2)=4 0-4=4 -4=4 B. 2-2(0)=4 2=4C. 4-2(0)=4 4=4 => This is the solution of equation x-2y=4E. 1-2(1)=4 1-3=4 2=4 | |
| 2359. |
Find the value of x and yx + √y = 28√x + y = 14 |
| Answer» X=0. Y=14 | |
| 2360. |
Follow BODMAS rule 9(x+7)-6=9-2(x+9) |
| Answer» \xa09(x+7)-6=9-2(x+9)9x + 63 = 9 -2x - 189x + 2x = 9 - 18 - 637x = -9-637x = - 72x = -72/7x = - 10.28 | |
| 2361. |
The volume of a cone is 18480cm^3 if the height of the cone is 40 cm find the radius of its base |
| Answer» Let the radius of the cone be\xa0r\xa0cm.h=40\xa0cmVolume,V=18480\xa0cm331\u200b×22/7×r2×40=18480r2=441r=21\xa0cm | |
| 2362. |
Factorise 84-2n-2n sq |
| Answer» 84-2n-2n²=\xa02(42-n-n²)\xa0/* Taking\xa02\xa0common */= 2( 42\xa0-\xa07n\xa0+\xa06n\xa0-\xa0n²) /* splitting the middle term */= 2[7(6-n)+n(6-n)]=\xa02(6-n)(7+n)Therefore,.2,\xa0(6-n)\xa0and\xa0(7+n)\xa0are\xa0factors\xa0of\xa0given\xa0quadratic\xa0expression. | |
| 2363. |
Costruct a triangle ABC, in which angle B =60 degree ,angle = 45 degree and AB+BC+CA =10 cm |
| Answer» Steps of Construction:1.Draw a line segment PQ = 11 cm.( = AB + BC + CA).2.At P construct an angle of 60° and at Q, an angle of 45°.3.Bisect these angles. Let the bisectors of these angles intersect at a point A.4.Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.5.Join AB and AC (see Fig. 11.9). Then, ABC is the required triangle. | |
| 2364. |
Prove that all the angle of quadriteteral are 360 degrees |
| Answer» If we draw one diagonal to quadrilateral we will get two triangles i.e.\xa0△ABC\xa0and\xa0△ACD\xa0and we know that sum of the angles of a triangle is\xa0180oSum of angles of quadrilateral ABCD=sum of angles of\xa0△ABC\xa0+ sum of the angles\xa0△ACD=\xa0180o+180o=\xa0360o | |
| 2365. |
Ad is an altitude of an isosceles triangle ABC in which AD=AC .Show that AD bisects BC |
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| 2366. |
How to calculate the line parallel to y=mx+b |
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| 2367. |
Find the volume of sphere whose surface area is 154 cm 2 |
| Answer» Answer-Let r cm be the radius of sphere. Surface area of the sphere = 4πr2\xa0⇒\xa0154 = 4πr2 ⇒\xa04 x 22/7 x r2 = 154r2\xa0=\xa0154 x 7/4 x 22 = 72/22 ⇒ r = 7/2 Volume of sphere =\xa04/3πr3= 4/3 x 22/7 x 7/2 x 7/2 x 7/2 cm3= 539/3 cm3\xa0= 179.2/3 cm3 | |
| 2368. |
What is the square root of 12 |
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Answer» 2√3 2√3 144 2√3 or 3.46 Approximately 3.46 |
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| 2369. |
2x + 9 = 6 |
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Answer» 2x+9=62x=6-92x=-3X=-3/2 -3/2 x = -3/2 -3/2 2x + 9 = 62x = 6 - 92x = -3x = -3/2 |
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| 2370. |
Evaluate 1. (102)3 2. 140×96 3. (X+4) (x+10) |
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Answer» Thanks Question 1. 102x3=306 2. 140x96=13440 3. (x+4)(x+10) =x+x of 4+10 = 2x of 14 = 28x answer. Let us rewrite\xa0(102)3\xa0as\xa0(100+2)3Now using the identity\xa0(a+b)3=a3+b3+3ab(a+b), we get(100+2)3=1003+23+[(3×100×2)(100+2)]=1000000+8+(600×102)=1000000+8+61200=1061208Hence,\xa0(102)3=1061208 |
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| 2371. |
Q-12. Prove that angles opposite to equal sides of an isosceles triangle are equal. |
| Answer» Given:\xa0In the isosceles ∆XYZ, XY = XZ.To prove\xa0∠XYZ = ∠XZY.Construction:\xa0Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.Proof:\tStatement1. In ∆XYM and ∆XZM,(i) XY = XZ(ii) XM = XM(iii) ∠YXM = ∠ZXM\xa02. ∆XYM ≅ ∆XZM3. ∠XYZ = ∠XZY. (Proved)Reason1.(i) Given.(ii) Common side.(iii) XM bisects ∠YXZ.\xa02. By SAS criterion.3. CPCTC.\t | |
| 2372. |
Q-10. Construct an angle of 105°. |
| Answer» Step of Construction:\xa0(i)\xa0After making 90° angle take L and N as centre and draw two arcs cutting each other at S.(ii)\xa0Join SO.Then,\xa0∠SOA = 105°. | |
| 2373. |
Q-7. In the given figure, ∆PQC and ∆PRC are such that QC = PR and PQ = CR,Prove that /PCQ=/CPR. |
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Answer» In triangle PQC and triangle PRC,Given - QC= PRPQ=CRTo prove:- angle PCQ= angle CPRProof:- In triangle PQCand triangle PRC:-QC=PR [GIVEN]PQ=CR [GIVEN]andPC=PC [COMMON]by SAS similarly criterion, triangle PQC is congruent to triangle PRC.therefore by C.P.C.Tangle PCQ =angle CPR PQ=PR (Given)∴∠PQR=PRQ (Angles opposite to equal sides)QC=RC (Given)△PQC≅△CPRBy\xa0SAS\xa0criteria |
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| 2374. |
Write a coeffeicient of x term of the following:1. π/4 x+x2 -1 |
| Answer» π/4 | |
| 2375. |
What is statistic. |
| Answer» Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data. In applying statistics to a scientific, industrial, or social problem, it is conventional to begin with a statistical population or a statistical model to be studied.\xa0Statistics\xa0is a form of mathematical analysis that uses quantified models, representations and synopses for a given set of experimental data or real-life studies.\xa0Statistics\xa0studies methodologies to gather, review, analyze and draw conclusions from data. | |
| 2376. |
Find p(0),p(1),p(2),for each of the following polynomials: |
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Answer» Hhiia The question you are asking is not clear or incomplete. Where are the polynomials in your question?You can add more details like chapter name or book name.Ask specific question which are clear and concise.Ask properly stated queries for the answer. |
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| 2377. |
(87)×34 |
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Answer» 2958 87×34= 2958 2958 |
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| 2378. |
Prove that a cyclic parallelogram is a ractangle |
| Answer» If nobody anwer your question search in google | |
| 2379. |
a^4-a |
| Answer» a³ answer. | |
| 2380. |
CBSE anyone give me cut syllabus of maths |
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Answer» Go to the official website of cbse/kvs Introduction to Euclid\'s Geometry.Area of Parallelogram and Triangle. |
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| 2381. |
Simplify (31/3)4 |
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Answer» 41.33333333....... 41.34 (31×4)/3124/341.34 124/3 41.333333334 |
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| 2382. |
if two complete monetary angles |
| Answer» Ask the questions properly | |
| 2383. |
if X= 0.125, find the value of (1/X)1/3 |
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Answer» Please aap help kr dein But vo mujhe nhi aarha Math ke Mujhe apna holiday home work krna hai X=5 |
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| 2384. |
Express 8.0025 in the form |
| Answer» Are u askig to express it in fractional form?Then here is ur ans..80025/10000U just have to exclude the decimal and in denominator have to write zeros according to how many digits are thr aftr decimal..Then convert it into its simplest form..3201/400 | |
| 2385. |
A triangle can not have more than....... Right angle |
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Answer» 1right angle 1 One 1 One |
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| 2386. |
Express 8.025 in the form of P/Q |
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Answer» 8025/1000 It can be written as 8025/1000 8025/1000321/100 |
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| 2387. |
The area of triangle 150 cm square side are in ratio 345 what perimeter |
| Answer» 1 is the perimeter | |
| 2388. |
represent 3+√2.6 on number line |
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Answer» . We are required to theexpression 3 + root 2.6 on thenumber line.Since, we know,3+ √2.6 = 3 + √2.6 3+1.61 4.61So, it is required to representthe number 4.61 on the numberline.As we know,The number 4.61 lies betweenthe numbers 4.6 and 4.7. |
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| 2389. |
Line segment joining the centre to any point on the circle is a radius of the circle true or false |
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Answer» True True True True True |
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| 2390. |
Dilpreet Singh 9E |
| Answer» | |
| 2391. |
What is the Degree of Zero polynomial ? |
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Answer» Not defined 0 Degree of zero polynomial is not defined Degree of zero polynomial is not defined 0 |
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| 2392. |
Simply the follwing by rationalising denominte |
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| 2393. |
Equilateral angle |
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Answer» A triangle with all sides equal and each angle is equal to 60°.So, 60°+60°+60°= 180°. A triangle which has equal sides and equal angles. Equal sides Each angle will be equal to 60 degreeSo,60+60+60=180 Tites |
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| 2394. |
Compare the |
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Answer» Hi chirag, Line segment actually has end points like if i say here is a line segmet pq then it has its end points p--------q.. u cannot extend it further.. whereas line doesnt has end points u can extend it to infinty or whatever lenght u want.. or in other words line segment will most probably have a finite lenght or measurement.. whereas line will not.. Line line Hoti hai or line segment line ki line Hoti hai??? What is the difference between line and line segment |
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| 2395. |
factories 6x3-5x2-13x+12 |
| Answer» | |
| 2396. |
If the digonal of a parallelogram are equal tjen show that its rectangle |
| Answer» In ?️ DAB and ?️ CBA AD=BC ( opp. Sides of llgm) AB=BA( common) DB=CA( Given) ?️ DAB ~= ?️ CBA (SSS Rule)BY C.P.C.T- Angle DAB=Angle CBA=x x +x=180 2x=180 x=180÷2 X=90So,ABCD is a Rectangle. | |
| 2397. |
7 .8 |
| Answer» Please ask question with complete information. | |
| 2398. |
Puncuate prospero eas a duck of millan in the kingdom of nepal |
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| 2399. |
Evaluate 16 3/4 |
| Answer» 16*3/4•4*3•12 | |
| 2400. |
The coordinates of two points are A(4,5) and B(-3,6), then find (abscissa of A) - (abscissa of B) |
| Answer» The abscissa of A is 4 andabscissa of B is -3 Thus, 4-(-3) = 7 | |