InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1301. |
Hence of 825 |
| Answer» What do you mean | |
| 1302. |
Exercise 3.1 2 and 3 answer detail |
| Answer» | |
| 1303. |
Find the two number whose sum is 27 and product is 182.??? |
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Answer» Mujhe pata hota to me puchti nahi shivam Let the first no. a then second no. is 27–=A/q a(27–a)=182 => a²–27a+182 = a²-13a–14a+182=> a(a-13)-14(a-13) => (a-१3)(a-14) . Then,a=13or 14 What is its answer |
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| 1304. |
The angles of a quadrilateral are in AP whose common difference is 10°. Find the angles. |
| Answer» (X)+(x+10)+(x+20)+(x+30)=3604x=300X=75(Thank me later ?) | |
| 1305. |
Find the 15th term from the end of the AP 3,5,7,9,....,201. |
| Answer» Given AP 3,5,7,9......197,199,201reversing the AP201,199,197,......9,7,5,3 First term=a=201 Common difference =d=a2-a1=199-201=215th term of AP=a+14da15=201+14(-2)=201-28=173 the required number is 173 | |
| 1306. |
Class 10. Ex 2.3 ques1 |
| Answer» It is given in this app | |
| 1307. |
If angleB and angleQ are acute angles that sinB=sinQ, then prove that AngleB=angleQ |
| Answer» | |
| 1308. |
Find the sum of first 17 terms of an Ap whose 4th and 9th term are -15 and -30 |
| Answer» Sum is -918 | |
| 1309. |
All formula chapter wise |
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Answer» (a-b)(a-b)=a+a_2ab+b+b (a+b)(a+b)=a+a+2ab+b+b |
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| 1310. |
Cos38* Cos52* - Sin38* Sin52* = 0 |
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Answer» \xa0cos 38* cos 52* - sin 38* sin 52*= cos 38* cos ( 90* - 38* ) - sin 38* sin ( 90* - 38 * )= cos 38* sin 38* - sin 38* cos 38*= 0 => cos 38* cos 52* - sin 38* sin 52*=> cos 38* cos ( 90* - 38* ) - sin 38* sin ( 90* - 38 * )=> cos 38* sin 38* - sin 38* cos 38*=> 0 |
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| 1311. |
2+4=124+6=306+3=211+9=? |
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| 1312. |
7.1 question number 6 |
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| 1313. |
Up to how much table should I know in 10 |
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Answer» 25 20 Ek bhi nhi Neenu ninnu premistunnanu Me me me me ekapai only u and me |
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| 1314. |
cos 45 / sec 30 cosec 30 |
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Answer» Are cos 45 ki value hoti h 1 and sec30 ki value hoti h 1/underroot 3 multiply by cossec 30 ki value C 1/√2×2/√3×2= 2√6/3 |
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| 1315. |
In ∆ abc, right angled at b, AB=5cm and angle ACB=30° then the lengths of the side BC is............ |
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Answer» In ∆ABC,Tan 30=AB/BC=>1/√3=5/BC=>BC=5√3cm.I hope this helps you ??. BC=5√3 cm |
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| 1316. |
Maths is so hard can help me |
| Answer» Ask ur doubt in this app and there are many students who can help u | |
| 1317. |
22\\7×24.5 |
| Answer» 77 | |
| 1318. |
Which term of the AP: 3, 8, 13, 18 … is 78? |
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Answer» A=3 d=5 Tn=78Formula :- a + (n-1)dPutting value,3 + (n-1)*5 = 78(n-1)*5 = 78-3(n-1)*5 = 75(n-1) = 75/5n-1) = 15n = 15+1 = n = 16 16 The given sequence is 3, 8, 13, 18, ....78.\'a\' = 3, \'d\' = 5, last term = 78, \'n\' = ?tn\u200b=a+(n−1)d⟹78=3+(n−1)5⟹78=3+5n−5⟹78=5n−2⟹5n=80orn=16.The 16th term is 78. |
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| 1319. |
P of x is equals to x square - 6 x + 9 |
| Answer» p(x) = x2 -6x + 9p(x)=x2 -3x -3x+ 9p(x) = x(x -3) - 3(x-3)= (x-3)(x-3) | |
| 1320. |
Find the number of terms in the following AP: 7, 13, 19…., 205 |
| Answer» \xa07,13,19........,205Consider,tn\xa0= 205tn\xa0= a + (n - 1) d = 205 where a = 7 and d = 13 - 7 = 67 + (n - 1)\xa0× 6 = 2056(n - 1) = 198n - 1 = 33n = 34Hence, the number of terms in the given sequence are 34. | |
| 1321. |
Is syallbus will reduce or not |
| Answer» (a+b)(a+b) | |
| 1322. |
If pth term of an AP is q and qth term is p than prove that its (p+q)th term is zero. |
| Answer» \xa0Let a is the first term of AP and d is the common differencepth\xa0term = a + (p-1) d = q .................(1)qth\xa0term = a + (q-1) d = p .................(2)\xa0By subtracting eqn(2) from eqn(1), we get d = -1\xa0if we subsititue d = -1 in eqn.(1), we get a = p+q-1\xa0nth\xa0term = a+(n-1)d = (p+q-1) + (n-1)(-1) = p+q-n\xa0(p+q)th\xa0term = a+(p+q-1)d = (p+q-1)+(p+q-1)(-1) = 0 | |
| 1323. |
If cosa=3/5, find the value of sina-1/tana/2tana |
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Answer» Sin a - 1 = -1/5 2tan a = 8/3 Tan a = 4/3 |
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| 1324. |
Prove that 1/2 is irrational |
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Answer» Thanks 1/2 is not an irrational number To prove 1/√2 is irrationalLet us assume that\xa0√2 is irrational\xa01/√2 = p/q\xa0(where p and q are co prime)q/p =\xa0√2q =\xa0√2psquaring both sidesq² = 2p² .....................(1)By theorem\xa0q is divisible by 2∴ q = 2c ( where c is an integer)\xa0putting the value of q in equitation 12p² = q² = 2c² =4c²p² =4c² /2 = 2c²p²/2 = c²\xa0by theorem p is also divisible by 2But p and q are coprimeThis is a contradiction which has arisen due to our wrong assumption∴1/√2 is irrational |
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| 1325. |
Express 0.127͞ as fraction |
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| 1326. |
All integers between 100 and 550 which are not divisible by 9 |
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| 1327. |
The mode of the data is 65 and sum of frequencies is 50 find x and y |
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| 1328. |
Ex 1.1 calss 10 4 th question |
| Answer» Abhi 1.1 pe hi ho meri poori math हो gyi | |
| 1329. |
Prove that 3+2√5 is irrational number? |
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Answer» Jindagi bhar first chapter par atke rehna Let 3+2√5 be rational number.So,3+2√5=a/b(a and b are co-prime)A/q 3+2√5=a/b =>2√5=a/b-3 =>√5=(a-3b)/2b.a,b,3 and 2 are integers.So,(a-3b)/2b is rational.But,(a-3b)/2b=√5. (√5 is irrational).Hence, our assumption is wrong.So,3+2√5 is irrational... I hope this helps you.?? 3 + 2√5 = a/ b2√5 =a/b -3√5 =a-3b/2b√5 is rational.This contradicta the fact that √5 is irrational.So our supposition is incorrect. |
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| 1330. |
How to solve the Completeing the square mathod |
| Answer» Youtube kis kaam aayega | |
| 1331. |
If p, q r s are in ap then r -q is |
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Answer» Common difference Common difference |
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| 1332. |
Use euclid\'s division algorithm to find the hcf of 135and 225 |
| Answer» Step1-On dividing 225 by 135,we get 1as quotient and 90 as remainder.From Euclid lemma,225=135×1+90Step 2-On dividing 130 by 90 ,we get 1as quotient and 45 as remaider.From Euclid lemma,130=90×1+45Step3-On dividing 90 by 45,we get 2 as quotient and 0 as remainder.From Euclid lemma,90=45×2+0HCF(225,134)=45.I hope this helps you.?? | |
| 1333. |
Solve for x and y. 152x-378y=-74 ; 378x+152y=-604 |
| Answer» H | |
| 1334. |
The circumference of a circle exceeds it\'s diameter by16.8 cm.find the circumference of the circle |
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| 1335. |
(x + 1) –x ² =0 has 11 real root2 real root 4 real root |
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Answer» D=b^2-4ac=1^2-4(-1)(1)=1+4=5.D>0.Hence it has two real and unequal roots. Class 10 ka questions1.1 2 real root |
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| 1336. |
If sum of first k terms of an AP is 2k^2-3k, then what is its second term? |
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Answer» Sum of first k term=2k^2-3kSum of first(k-1) term=2(k-1)^2-3(k-1)=>2(k^2+1-2k)-3k+3=>2k^2+2-4k-3k+3=>2k^2+5-7k..K th term=2k^2-3k-2k^2-5+7k=>4k-5..2nd term of AP=4×2-5=3. Please solve fast? |
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| 1337. |
If 5 tan thita =4 show that 5 sin thita - 3cos thita /5 sin thita +3cos thita = 1/6 |
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| 1338. |
Have a doubt Ask me of maths chapter trigonometry |
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Answer» 1+cos x/1-cos xRationalise1+cos x/1-cos x *1+cos x/1+cos x(1+cos x)^2/1^2-cos^2x(1/sin x+ cos x/sin x)(Cosec x+ cot x) =RHS Prove that 1+cos x/1-cos x=(cosec x+cot x) |
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| 1339. |
Exercise 4.3 question 1. 3rd part |
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Answer» Thanks ☺️☺️ 4x^ +4√3x +3 = 4x^ + 4√3x = -3 = 4x^/4 +4√3x/4 = -3/4= X^ + √3x = -3/4= X^ + √3x + 3/4 = -3/4+3/4=X^+√3x+3/4 =0= (X+√3/2)^=0= (x+√3/2)(x+√3/2) = 0If x+√3/2=0,then x=-√3/2If x+√3/2=0,then x=-√3/2 |
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| 1340. |
1+2+4×3÷1=3÷46=3666×5÷9+4456 |
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| 1341. |
How we give nameof similar triangle |
| Answer» What | |
| 1342. |
Express 140 as product of prime factors |
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Answer» 2*2*5*7 2*2*5*7 2×2×5×7 7 into 2 into 5 into 2 |
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| 1343. |
To verify that given sequence is an airthmetic progession by paper cutting and pasteing |
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| 1344. |
Find value of k in kx2 - 2(2k-1)x + 4 |
| Answer» 2_3× 4 | |
| 1345. |
What\'s is l in Ap series |
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Answer» Let term of AP is denoted as l Thankyou☺️ Last term (l) |
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| 1346. |
The sum of three numbers in A P is 24 and their product is 440 finde the numbers |
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Answer» a+ d +a+a-d = 24. 3a=24a= 8(a+d)a(a-d)=440a(a^2-d^2)=4408(8^2-d^2) =44064- d^2=55d^2=9d= 3Required no.= 11, 8 and 5. 5,8,11 or 11,8,5 Next, (a+d)a(a–d)=440 => (64–d²)8=440 => d²=9 d=3. Let the no. be (a+d),a,(a–d)। । A/q a+d+a+(a–d)=24 => 3a=24 => a=8. |
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| 1347. |
Ex 1.4 q2 class 10 |
| Answer» Answer are given in this app | |
| 1348. |
Plzz tell the answers of ex 1.4 q2 |
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Answer» You have to just write the first question\'s in the form of 2^m5^n Answers are given in this app Plzz tell the answer quickly |
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| 1349. |
LCM three digits Questions |
| Answer» | |
| 1350. |
How many marks of questions of NCERT are asked in maths clas 10 paper? |
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Answer» Why are you answering if you don\'t know yhe answer?? 1,2,3,4 |
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