InterviewSolution
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InterviewSolution
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The sum of three numbers in A P is 24 and their product is 440 finde the numbers |
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Answer» a+ d +a+a-d = 24. 3a=24a= 8(a+d)a(a-d)=440a(a^2-d^2)=4408(8^2-d^2) =44064- d^2=55d^2=9d= 3Required no.= 11, 8 and 5. 5,8,11 or 11,8,5 Next, (a+d)a(a–d)=440 => (64–d²)8=440 => d²=9 d=3. Let the no. be (a+d),a,(a–d)। । A/q a+d+a+(a–d)=24 => 3a=24 => a=8. |
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