Find the number of terms in the following AP: 7, 13, 19…., 205

1.	Find the number of terms in the following AP: 7, 13, 19…., 205
Answer» \xa07,13,19........,205Consider,tn\xa0= 205tn\xa0= a + (n - 1) d = 205 where a = 7 and d = 13 - 7 = 67 + (n - 1)\xa0× 6 = 2056(n - 1) = 198n - 1 = 33n = 34Hence, the number of terms in the given sequence are 34.

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