InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2551. |
MathsTenth class |
| Answer» Get notes from here :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 2552. |
Area of major segment of r=14cm and angle is 90 |
| Answer» | |
| 2553. |
Find the value of \'a\' if x+a is a factor of the polynomial |
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| 2554. |
If sin theta =cos (theta - 6),find value of theta |
| Answer» Sin Q = cos (90-Q) , sinQ= sin (90-(Q-6)),=> Q=90-Q+6 => Q = 96 - Q => 2Q = 96 => Q = 48° | |
| 2555. |
IF THE QUADRATIC eqution px^2-2√5px+15=0 has two equal roots, than find the value of p |
| Answer» when roots equal;(b=-2×5^0.5×p; a=p; c=15)D=0》b^2-4ac=0》20p^2-60p=0》p^2-3p=0》p(p-3)=0》p=0 or p=3 | |
| 2556. |
Area of pyramid |
| Answer» A = lw +\xa0{tex} l \\sqrt { \\left( \\frac { w } { 2 } \\right) ^ { 2 } + h ^ { 2 } } + w \\sqrt { \\left( \\frac { l } { 2 } \\right) ^ { 2 } + h ^ { 2 } }{/tex}where,l = Base length,w = Base widthand h = Pyramid height | |
| 2557. |
What will be the area of square having diagonal 20cm |
| Answer» 200 cm² | |
| 2558. |
44+6944_33 |
| Answer» 124 | |
| 2559. |
find the value of k for which the system of equations kx -y=2 and 6x-2y=3 has a unique solution |
| Answer» K not equal to 3 | |
| 2560. |
, find the point on the x axis which is equidistant from (2, -5)and(-2, 9) |
| Answer» We know that a point on the x-axis is of the form (x, 0). So, let the point P(x, 0) be equidistant from A(2, –5) and B(–2, 9). ThenPA = PB{tex}\\Rightarrow{/tex} PA2 = PB2{tex}\\Rightarrow{/tex} (2 - x)2 + (-5 - 0)2 = (-2 - x)2 + (9 - 0)2{tex}\\Rightarrow{/tex} 4 + x2 - 4x + 25 = 4 + x2 + 4x + 81{tex}\\Rightarrow{/tex} - 4x + 25 = 4x + 81{tex}\\Rightarrow{/tex} 8x = -56{tex}\\Rightarrow \\;x = \\frac{{ - 56}}{8} = - 7{/tex}Hence, the required point is (-7, 0)Check:{tex}PA = \\sqrt {{{\\{ 2 - ( - 7)\\} }^2} + {{( - 5 - 0)}^2}}{/tex}{tex}= \\sqrt {81 + 25} = \\sqrt {106}{/tex}{tex}PB = \\sqrt {{{\\{ - 2 - ( - 7)\\} }^2} + {{(9 - 0)}^2}}{/tex}{tex}= \\sqrt {25 - 81} = \\sqrt {106}{/tex}{tex}\\because{/tex} PA = PB{tex}\\therefore{/tex} Our solution is chekcked. | |
| 2561. |
Write Trigno. Ratio of Sin A in terms of Cot A . |
| Answer» We have to express the trigonometric ratio\xa0sin A in terms of cot A.For sin A,By using identity {tex}cosec ^ { 2 } A - \\cot ^ { 2 } A = 1{/tex}{tex}\\Rightarrow cosec ^ { 2 } A = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\frac { 1 } { \\sin ^ { 2 } A } = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\sin ^ { 2 } A = \\frac { 1 } { 1 + \\cot ^ { 2 } A }{/tex}{tex} \\Rightarrow \\quad \\sin A = \\frac { 1 } { \\sqrt { 1 + \\cot ^ { 2 } A } }{/tex}\xa0 | |
| 2562. |
1/2+1/6+1/12+1/20+...........+1/10100 equal to what? |
| Answer» 100/101 | |
| 2563. |
Kya ncert pdne se top ho jaenge |
| Answer» Q nhi | |
| 2564. |
X sin3^ + y cos3^ = sin^ × cos ^ nd x sin^ = y cos ^ prove that x2 + y2 = 2 |
| Answer» | |
| 2565. |
Find the area of ahadded region abcd is a square of the side 14cm and APD and bpc are semicircles |
| Answer» Area of the shaded region= Area of the square ABCD - (Area of semicircle APD + Area of semicirde\xa0BPC){tex}= 14 \\times 14 - \\left[ \\frac { 1 } { 2 } \\pi \\left( \\frac { 14 } { 2 } \\right) ^ { 2 } + \\frac { 1 } { 2 } \\pi \\left( \\frac { 14 } { 2 } \\right) ^ { 2 } \\right]{/tex}{tex}= 196 - \\pi ( 7 ) ^ { 2 } = 196 - \\frac { 22 } { 7 } ( 7 ) ^ { 2 }{/tex}{tex}= 196 - 154 = 42 \\mathrm { cm } ^ { 2 }{/tex} | |
| 2566. |
5 |
| Answer» | |
| 2567. |
If cos this =8/17 find other five trigonometry ratios |
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Answer» 15 If cos =8/17 then cos =base /hyertenuceso we have base =8 and h=17 so find perpendicular by pithagerous theorem ad hence find all other ratios |
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| 2568. |
Ishita my friend good |
| Answer» | |
| 2569. |
Find the natural number from 101to 999 which are divisible by 2 and 5 |
| Answer» Natural numbers between 101 and 999 divisible by both 2 and 5, i.e., divisible by L.C.M of 2 and 5 i.e., 10, are 110, 120, 130 ,...., 990.so, this forms an AP 110,120....,990., where first term({tex}a{/tex})=110 and common difference({tex}d{/tex})=120-110=10, and last term({tex}l{/tex})=990Let {tex}l = {a_n} = a + (n - 1)d{/tex}Then,\xa0{tex}990 = 110 + (n - 1) \\times 10{/tex}{tex} \\Rightarrow n = 89{/tex} | |
| 2570. |
23+78 |
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Answer» 108 Simple 101 |
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| 2571. |
The perimeter of a sector of acircle of radius 5.7 is27.2.find the area of sector |
| Answer» Let O be the centre of the circlewhose radius is 5.7 cm.Let OAB be the sector withperimeter 27.2 cm, Then,{tex}\\mathrm { OA } + \\mathrm { OB } + \\operatorname { arcACB } = 27.2{/tex}{tex}\\Rightarrow 5.7 + 5.7 + \\operatorname { arc } A C B = 27.2{/tex}{tex}\\Rightarrow 11.4 + \\operatorname { arc } A C B = 27.2{/tex}{tex}\\Rightarrow \\operatorname { arc } A C B = 27.2 - 11.4 = 15.8 \\mathrm { cm }{/tex}{tex}\\Rightarrow \\frac { \\theta } { 360 } \\times 2 \\pi r = 15.8{/tex}{tex}\\Rightarrow \\frac { \\theta } { 360 } \\times 2 \\times \\frac { 22 } { 7 } \\times 5.7 = 15.8{/tex}{tex}\\Rightarrow \\theta = \\frac { 15.8 \\times 360 \\times 7 } { 2 \\times 22 \\times 5.7 }{/tex}{tex}\\therefore {/tex}\xa0Area of the sector =\xa0{tex}\\frac { \\theta } { 360 } \\times \\pi r ^ { 2 }{/tex}{tex}= \\frac { 15.8 \\times 360 \\times 7 } { 2 \\times 22 \\times 5.7 \\times 360 } \\times \\frac { 22 } { 7 } \\times ( 5.7 ) ^ { 2 }{/tex}= 45.03 cm2 | |
| 2572. |
Chapter |
| Answer» | |
| 2573. |
2×3root -1 |
| Answer» 2×3√-12×-1=-2because cube root of -1 is -1 so,2×-1=-2 ans. is -2 | |
| 2574. |
Find the distance between the points A(a,b),B(-a,-b). |
| Answer» 4ab | |
| 2575. |
Hlo frnds |
| Answer» | |
| 2576. |
Are two triangles with equal corresponding sides always similar |
| Answer» Yed | |
| 2577. |
Which channel is best for study maths in u tube |
| Answer» Self study is best for all subjects .dont waste your time on any channels .take help from ur frnd and school teacher | |
| 2578. |
a letter is chosen at random from the word rainbow .find the probability that it is a vowel |
| Answer» 3/7=0.42 | |
| 2579. |
show that root 3 is not a rational number |
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| 2580. |
Euclids |
| Answer» | |
| 2581. |
Hello guys ??????????????? |
| Answer» | |
| 2582. |
Sahil app bahut achhe ho |
| Answer» | |
| 2583. |
I want ki aap mujhe boldo ki you hate me |
| Answer» | |
| 2584. |
Kisi ko maths 10 Ka board exam 2018 pta h |
| Answer» Check The Sample Paper Of Arihant All In One | |
| 2585. |
2=11proof mr skte ho logical method se |
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| 2586. |
Hlo guys how are u? |
| Answer» | |
| 2587. |
Kya janina hai puchho |
| Answer» | |
| 2588. |
Mix ho Matlab |
| Answer» | |
| 2589. |
Ergh |
| Answer» | |
| 2590. |
Sahil happy foolish day |
| Answer» | |
| 2591. |
SinA=xSecA=yFind the value of cot A |
| Answer» | |
| 2592. |
In the given fugure Traingle AMB~Traingle CMD. Find DM in term of a,b,c. |
| Answer» According to question it is given that\xa0{tex}\\triangle \\mathrm { AMB } \\sim\\triangle \\mathrm { CMD }{/tex}{tex}\\therefore \\frac { \\mathrm { AM } } { \\mathrm { CM } } = \\frac { \\mathrm { MB } } { \\mathrm { MD } }{/tex}[ By proportionality theorem ]\xa0{tex}\\Rightarrow \\frac { y} { z} = \\frac { x } { MD } \\\\ \\Rightarrow MD = \\frac { x z } { y }{/tex} | |
| 2593. |
Sahil answer na |
| Answer» | |
| 2594. |
Kisake picche |
| Answer» | |
| 2595. |
What is a divided into tangent of a line. |
| Answer» | |
| 2596. |
Kisase puchha rhe ho |
| Answer» | |
| 2597. |
How to find cf |
| Answer» | |
| 2598. |
Sahil mujhe kuch samajha nhi aa raha hai thik se bolona |
| Answer» | |
| 2599. |
Prove 5−2×√3 is an rational number |
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Answer» Okkk In this first we will assume it a rational number.then we will assume a/b are co-prime numbers.theb we will put it equal to a/b . Then we take 5 towards RHS and 2 also towards RHS and then we can easily prove √3 a irrational number .And then we will use the property of irrational number that The product of a rational number and irrational number is irrational number then another property of irrational number that The subtraction of a irrational number from a rational number is a irrational number.HENCE PROVED. Kya hoa answer dai dao Plzzzz give answer I know the ans...but its too long |
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| 2600. |
Me aapko TV me kaise dekhunge sahit |
| Answer» | |