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Find the area of ahadded region abcd is a square of the side 14cm and APD and bpc are semicircles

Answer» Area of the shaded region= Area of the square ABCD - (Area of semicircle APD + Area of semicirde\xa0BPC){tex}= 14 \\times 14 - \\left[ \\frac { 1 } { 2 } \\pi \\left( \\frac { 14 } { 2 } \\right) ^ { 2 } + \\frac { 1 } { 2 } \\pi \\left( \\frac { 14 } { 2 } \\right) ^ { 2 } \\right]{/tex}{tex}= 196 - \\pi ( 7 ) ^ { 2 } = 196 - \\frac { 22 } { 7 } ( 7 ) ^ { 2 }{/tex}{tex}= 196 - 154 = 42 \\mathrm { cm } ^ { 2 }{/tex}


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