InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
Solve by factorisation: 5x²-3x-4 |
| Answer» 5x2 -(4x - 5x) - 45x2 - 4x+5x-4X(5x - 4) + 1(5x - 4)(5x - 4) ( x+1) | |
| 252. |
Can I have some tips for full concentration in maths |
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Answer» More than practice of mathematics by using phone and etc. And you will have to take interest in mathematics . Then you have full concentration in maths . But you need to do practice again and again . Not in 1 time . Ok First bath and then study Practice Have a cup of coffee |
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| 253. |
The probability of an sure event is ____ |
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Answer» 1 The probability of an sure event is 1. 1 0 1 |
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| 254. |
3.6 by elemation method only 1st beet 2 questions |
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| 255. |
Solve the following pair of linear equation by substitution method Q1 x+ y= 14 |
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Answer» Equation is incomplete.... Provide the other equation Where is one more eq. |
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| 256. |
6 prove that questions from triknomatry |
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| 257. |
I need examples of chapter 8 |
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| 258. |
Find the quadratic polynomial whose sum and product of zeros are 21/8 and 5/16 respectively |
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| 259. |
√5is irrational prove that |
| Answer» Let us assume that √5 is a rational number.Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/qOn squaring both the sides we get,⇒5=p²/q²⇒5q²=p² —————–(i)p²/5= q²So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational number | |
| 260. |
In the fig angle a is 90 deg ad perpinduclar bc bd 2 cm and CD 8 cm find ad |
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| 261. |
How to find zeroes of cubic polynomial |
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Answer» Bh https://youtu.be/s1SN5eD0xTA |
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| 262. |
Sec2a+ tan2a=1 find a |
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| 263. |
if a and b are the points -6,-7 and -1 , -5 respectively than what is distance 2ab |
| Answer» Root 29 | |
| 264. |
Ex 12.1 1 number question full solution |
| Answer» Go to you tube channel name is green board full perfect explainnation is there | |
| 265. |
Q no. 1 of ch 9 of class 10 |
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| 266. |
9 to the power n - 5 to the power n ends with what digit |
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| 267. |
root 3cos 13 degree +sun 13degree=2sin73 degree |
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| 268. |
Find the coordinats of the points which Davide the join (-1)and(4-5)in the ratio of 2:3 |
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| 269. |
A die is tossed twice. What is the probability of getting sum of numbers 12 ? |
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Answer» 1/36 1/36 1/36 No. of favourable outcomes= 1 i.e. (6,6)Total no. of outcomes =36P( sum of numbers 12) = 1/36 |
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| 270. |
If the 11^( th ) term of an A.P.is - 21 and the sum of first 7 terms is -49 find the A.P |
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Answer» 11th term=a+(11-1)d=(-21) a+10d=(-21) a=(-21-10d)Sum of first 7th term=7/2(2×a+(7-1)(d)=7(a+3d)=7(-21-10d+3d)=7(-21-7d)=49(-3-d)But,49(-3-d)=(-49) -3-d=(-1) d=(-2)a=-21-10(-2)=(-1)AP=(-1),(-3),(-5)....... 24 |
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| 271. |
Can someone explain the square method in chapter quadratic equation please |
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Answer» I hope you understand. In completing the square method ,,,,For example = 2x² - 5x + 3 = 0 ,, so we need to remove coefficient 2 from x².,,Then ,, 2 ( x² - 5x/2 + 3/2 ) = 0 /2 = 0,,= x² - 5x/2 + 3/2 = 0 ,,,,Second step - x² - 5x/2 = - 3/2 ,,Third step - x² - 5x/2 + [ 5/2 ]² - [5/2 ]² = - 3/2 ,,,,use the formula of( a - b )².Forth step -[ x² - 5/4 ]² - [5/2]² = - 3/2,,,,=[ x - 5/4 ]² = - 3/2 +[ 5/2]²,,= [ x - 5/4]² = - 3/2 + 25/4,,,,= [ x - 5/4 ]² = - 24 + 25 / 16 =( [ x² - 5x/2]² = 1/16),,,,root of 16 is 4 then,,,,= x - 5/4 = ± root 1/4,,,,= Firstly take positive integer. + 1/4 . Then negative. - 1/4.x = 1/4 + 5/4 = 1 + 5 / 4 = 6/4 = 3/2 ,,= X = 2. = X = 2 . = x = - 1/4 + 5/4 = - 1 + 5 /4 = 4/4 = 1. = X = 1.[Answer is X =1 and X = 2 ],,Hence proved ,, It is not important because this method is deleted in syllabusThank you,,Shubham Saxena |
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| 272. |
In chapter = 14 ,, ( Statistics) ,, which method is deleted. Answer me?? |
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Answer» Ok thanks sahil Step deviations methad |
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| 273. |
How to find median through ogive? |
| Answer» Draw a perpendicular line where both ogives intersect each other. | |
| 274. |
Seca(1-sina) (Seca+tana) =1 |
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| 275. |
Bro in exercise 8.4 of ncert book How we know that which identity take place in that question??? |
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Answer» How Only practice You will know by yourself by looking at the fig. Just learn the formulas as you learn (a+b)² and then apply the formulas the same way you can do |
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| 276. |
Hcf 222 and 5554 |
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Answer» 2 Not possible |
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| 277. |
Find the sum of first 100 positive integer ?? |
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Answer» Thanks souvig you are good ,,Welldone This is for answering 151 Sorry,,your answer is wrong Answer is = formula ,,Sn = n/2 [ 2a + ( n-1) d] ,, = 100/2 [ 2 × 1 + ( 100-1 ) 1,,50 [ 2 + 99 × 1 ] ,,50 [ 101 ] ,, = 5050 . Ans,,,, hope you understand. a=1d=1l=100Summation = 100/2(101) =5050 151 |
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| 278. |
5.3 |
| Answer» Wt | |
| 279. |
If the equation 9x^2+6kx+4=0 has equal roots then the roots are both equal to |
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Answer» I think that there is an error in ur questionI think that we have to find the value of\'k\' not the roots... Btw the value of \'k\' is 2. In asexual reproduction involves only single parent |
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| 280. |
x2-2(a+2)x+(a+1)(a+3)=0 |
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| 281. |
the line segment joining the points (3 -1) and (-6 5) is trisected find the points of trisection |
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Answer» Sorry, the above answer is wrong. The line should be divided in the ratio 1:2 .The formula is the same. The answer should be (0,1). As the line segment is trisected, therefore, it is divided in the ratio 1:3.Following the section formula --- {1(-6)+3*3} /1+3 , {1*5+3(-1)}/1+3. are the points of trisection.Therefore, the points of trisection are : (3/4 , 1/2) |
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| 282. |
In triangle ABC & PQR, if DB=DQ and AB/PQ=BC/QR=1/2 then what is the value of PR/QR |
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| 283. |
If tan A = tan B where A and B are acute angle prove that A +B = 90 |
| Answer» TanA =tanATanA=tan(90-B) A=90-BA+B=90 | |
| 284. |
In-text questions |
| Answer» ?Which Chapter? | |
| 285. |
In text quitions |
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Answer» ?Which Chapter? In text questions |
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| 286. |
Triangle chapter exercise 6.3 question no 9 |
| Answer» In\xa0s ABC and AMP, we have,ABC =\xa0AMP =\xa0\xa0[Given]BAC =\xa0MAP [Common angles]\xa0By AA-criterion of similarity, we haveABC\xa0\xa0AMP(ii)\xa0We have\xa0ABC\xa0\xa0AMP [As prove above]\xa0 | |
| 287. |
9832541514 is my no .please study with me in what\'s app during this lockdown because i feel bored |
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| 288. |
Kx+3y-(K-3)=012x+Ky-K=0 |
| Answer» So whatWhat we have to do Tell full question | |
| 289. |
Root 2x+root3y..0Root3x_root8y...0 |
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| 290. |
An ap 5,12,19 has 50 terms..... and last terms is |
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Answer» [ An = A + ( n - 1 ) D ],, A1 - A2 = 12 - 5 = 7 ,, A50 = 5 +( 50 - 1 ) 7 ,,= 5 + 49 × 7 = 343 + 5 = 348 .. hence proved .. thank you “348”. HoPe It HeLpS yOu?? a = 5 , d = a2 - a1 = 12 - 5 = 7 , n = 50 , an = ? Solve : a50 = a + (n - 1)d = 5 + (50-1)7 = 5 + (49)7 = 5 + 343 a50=348 A= 5 ,common difference =a2-a1. => 12 - 5 = 7. So the 50 terms is a50= 5+(50-1)7. a50=348 |
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| 291. |
1+cotA×cotA÷1+cosecA=cosecA |
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| 292. |
The sum of two natural number is 9 and the sum of their recipocal is 1/2 ? Find the numbers |
| Answer» ANSWER⇒ Let one number be\xa0x, then other number will be\xa09−xAccording to the question,⇒ x1\u200b+9−x1\u200b=21\u200b⇒ x(9−x)9−x+x\u200b=21\u200b⇒ 9x−x29\u200b=21\u200b⇒ 2(9)=9x−x2⇒ 18−=9x−x2⇒ x2−9x+18=0⇒ x2−6x−3x+18=0⇒ x(x−6)−3(x−6)=0$⇒ (x−6)(x−3)=0⇒ x−6=0 and\xa0x−3=0∴ x=6\xa0and\xa0x=3⇒ One number is\xa06\xa0and other number is\xa03⇒ The sum of squares of the numbers\xa0=(6)2+(3)2=36+9=45 | |
| 293. |
In an equilateral triangle ABC,AD is perpendicular to BC and AD²=P.BC² then find value of p |
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Answer» Since AD is height so AD=(√3)a/2 And BC is side of equilateral triangle? so BC=aNow, AD²=p×BC²(√3a/2)² =p×a²3a²/4 =p×a²P=3/4 P=3/4 |
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| 294. |
A tower stand vertically |
| Answer» Generate right angle | |
| 295. |
Solve for x: x+1/x=5 |
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Answer» x+1/x =5x+1=5×xx+1=5x1=5x-x4x=1x=1/4 x+1/x=5(x2+ 1)/x = 5x2 + 1 = 5xx2 - 5x + 1 = 0Then solve bu using formula methodx = - b\xa0±\xa0√b2 - 4ac/ 2a |
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| 296. |
Find (X + 2)( X + 1) = (X + 4 )(x + 3) is a quadratic equation |
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Answer» (X+2)(x+1) = (x+4)(x+3)X(x+1)+2(x+1) = X(x+3)+4(x+3)X2 + x + 2x + 2 = X2 + 3x + 4x + 12X2 + 3x + 2 = X2 + 7x + 12 X2 + 3x + 2 - X2 - 7x - 12 = 0 4x - 10 = 0 .Hence , It is not a quadratic equation. (X + 2)( X + 1) = (X + 4 )(x + 3)\xa0x ( x + 1) + 2 ( x + 1) = x ( x+ 3) + 4 ( x+ 3)x2 + x + 2x + 1 = x2 + 3x + 4x + 12x2 + 3x + 1 = x2 + 7x + 123x + 1 = 7x + 127x - 3x = 1 - 124x = -11 is not a quadratic equation |
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| 297. |
If the sum of first 8 terms of an AP is 50 and that of 17 terms is 289,find the sum of n terms |
| Answer» In this question , you know that S8 = 8/2 ( 2a + (8-1)d )You will get an equation from this and from S17 as well By combining these two equation by elimination or by any other method you will find d and after that you have to put the value of d in Sn = n/2 ( 2a + (n-1)d ) and at last you will get the answer ( the answer can also be a quadratic equation ) . | |
| 298. |
2x) +5x= |
| Answer» 7x | |
| 299. |
2/sintheta +costheta*sintheta |
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| 300. |
In a triangle prove that the sum of two angle is greater than the third angle |
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