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InterviewSolution
| 1. |
Triangle chapter exercise 6.3 question no 9 |
| Answer» In\xa0s ABC and AMP, we have,ABC =\xa0AMP =\xa0\xa0[Given]BAC =\xa0MAP [Common angles]\xa0By AA-criterion of similarity, we haveABC\xa0\xa0AMP(ii)\xa0We have\xa0ABC\xa0\xa0AMP [As prove above]\xa0 | |