The sum of two natural number is 9 and the sum of their recipocal is 1

1.	The sum of two natural number is 9 and the sum of their recipocal is 1/2 ? Find the numbers
Answer» ANSWER⇒ Let one number be\xa0x, then other number will be\xa09−xAccording to the question,⇒ x1\u200b+9−x1\u200b=21\u200b⇒ x(9−x)9−x+x\u200b=21\u200b⇒ 9x−x29\u200b=21\u200b⇒ 2(9)=9x−x2⇒ 18−=9x−x2⇒ x2−9x+18=0⇒ x2−6x−3x+18=0⇒ x(x−6)−3(x−6)=0$⇒ (x−6)(x−3)=0⇒ x−6=0 and\xa0x−3=0∴ x=6\xa0and\xa0x=3⇒ One number is\xa06\xa0and other number is\xa03⇒ The sum of squares of the numbers\xa0=(6)2+(3)2=36+9=45

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