InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 35001. |
What is the formula of area of minor segment |
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Answer» Area of sector-area of triangle made by sector AREA of corresponding sector- AREA of triangle Area of major sector= area of circle - area of minor sector. |
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| 35002. |
Board exams ki date sheet kab aayegi? |
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Answer» Yes brother... Pakka I think board exams start will be on 15 feb. |
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| 35003. |
What should be the main aim and the main books as the board exams are appearing soon? |
| Answer» | |
| 35004. |
Find two no. Whose sum is 1 and product is 12. |
| Answer» -3and4 | |
| 35005. |
Find the 25th term of the AP -5,-5\\2,0,5\\2.... |
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Answer» An=a+(n-1)dAn=-5+(25-1)×5\\2An=-5+24×2.5An=-5+60An=55 55 |
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| 35006. |
In what ratio |
| Answer» | |
| 35007. |
(1+sin)^2 |
| Answer» | |
| 35008. |
What is the shertest method to learn the trigonometric identity |
| Answer» To start it immidiately | |
| 35009. |
(cosec -cot) ²=sec+1/sec-1 |
| Answer» | |
| 35010. |
1+6+11+16+......+x=148Find x if they are in ap |
| Answer» a= 1d=6-1 =5Sn=148148 = n/2 [2a +(n-1)d]Now putting the values of a and d148= n/2[1+(n -1 )5]148=n/2[1+5n-5]396=5n^2 -4n5^n - 4n - 396Then solve this by the formula discriminate D=b^2 - 4acx= -b+&-√D/2a.......Thanku... | |
| 35011. |
4x+3y=175x-2y=4 in substitution method |
| Answer» y=5/11x=8 | |
| 35012. |
Example of 13chapter of ncrt |
| Answer» | |
| 35013. |
TanA+tanB/cotA+cotB=tanAtanB |
| Answer» | |
| 35014. |
Find the length of tangent whose radius is 5cm and distance10cm from centre |
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Answer» √75 5√3cm |
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| 35015. |
The nth term of an APis an=2n+1 find its sum |
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Answer» 2n +n Sum of how many terms????? |
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| 35016. |
Solve using EDL 15,45,10 |
| Answer» HCF -5 | |
| 35017. |
How to prepare chapter 13 |
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Answer» Only do and understand NCERT question for board exam it is easy than class 9th By learning all formula because we also facing this same problem Hello Neha Ican be your close friend please ? By solving all the questions of that chapter |
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| 35018. |
Find the area of the quadrant of circle whose circumference is 616 cm |
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Answer» 2πr=616,thenArea of quadrant=1/4πrsq 2πr=616,2×22/7×r=616,r=616×7/2×22,14×7=98,area=πrsq=22/7×98×98= 30184 2pir = area of sectors 2×22/7×r=61644/7×r=616r= 616×7/44 = 4x7= 28.Area of quadrant= 90/360×22/7×28×28 =22×28=616 ans. |
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| 35019. |
Check the total surface area of a solid hemisphere is 462 CM square find its volume |
| Answer» Is it 1436.755 cm^3 | |
| 35020. |
In a family of three children\'s find the probability of having at least one boy |
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Answer» 1/3 2/3 |
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| 35021. |
(1+ cotø-cosecø) (1+ tanø+secø)=2 |
| Answer» See ncert sollution | |
| 35022. |
If x+b is a factor of zeros of the polynomial axsquare +2(bx +5x+10find b |
| Answer» | |
| 35023. |
Find the value of k for which the system of equation 3x-y+8=0and 6x-ky+16=0 has no solution |
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Answer» K=2,also not equal to 2 2 |
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| 35024. |
Patters |
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| 35025. |
Cos2 67-sin2+tan2 45 |
| Answer» | |
| 35026. |
Waht is euclid |
| Answer» Euclid, sometimes given the name Euclid of Alexandria to distinguish him from Euclides of Megara, was a Greek mathematician, often referred to as the "founder of geometry" or the "father of geometry". He was active in Alexandria during the reign of Ptolemy | |
| 35027. |
An equilateral triangle ABC prove that 16 AD SQUARE = 13BC SQUARE |
| Answer» In equilateral {tex}\\triangle{/tex}ABC. 4BD = BCConstruction: Draw AE\xa0{tex}\\perp{/tex} BC.\xa0{tex}\\therefore{/tex} BE = {tex}\\frac{1}{2}{/tex}BC.In right {tex}\\triangle{/tex}AED, AD2 = DE2 + AE2\xa0{tex}\\Rightarrow{/tex} AE2 = AD2 - DE2 ..(i)In right {tex}\\triangle{/tex}AEB, AB2 = AE2 + BE2{tex}\\Rightarrow{/tex}\xa0AB2 = AD2 - DE2 + BE2 [using (i)]{tex}\\Rightarrow{/tex}\xa0AB2 + DE2 - BE2 = AD2{tex}\\Rightarrow{/tex}\xa0AB2 + (BE - BD)2 - BE2 = AD2{tex}\\Rightarrow{/tex}\xa0AB2\xa0+ BE2\xa0+ BD2\xa0- 2BE.BD - BE2\xa0= AD2{tex}\\Rightarrow{/tex}\xa0AB2 + ({tex}\\frac{1}{2}{/tex}BC)2 - {tex}2 \\times \\frac{1}{2}{/tex}BC{tex}\\times \\frac{1}{4}{/tex}BC = AD2{tex}\\Rightarrow{/tex}\xa0AB2\xa0+\xa0{tex}\\frac{1}{16}{/tex}BC2\xa0-\xa0{tex}\\frac{1}{4}{/tex}BC2\xa0= AD2{tex}\\Rightarrow{/tex}\xa0BC2\xa0- {tex}\\frac{3}{16}{/tex}BC2\xa0= AD2\xa0[{tex}\\because{/tex} AB = BC]{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { 13 \\mathrm { BC } ^ { 2 } } { 16 }{/tex} = AD2{tex}\\Rightarrow{/tex}\xa013BC2\xa0= 16AD2 | |
| 35028. |
-1+1/4+3/2+....3969 find the no of term |
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Answer» 5n²-13n-31752=0 find the number of term in each of the following -1+1/4+3/2+...=3969 3696 is not the term of that AP |
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| 35029. |
2 x is equal to 5 + x |
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Answer» X=5 or X-5=0 or -X+5=0 2x=5+x X=5that\'s it |
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| 35030. |
Prove that (sinA+cosA) ^2(secA-cosA) = 1/tanA+cotA |
| Answer» Bw | |
| 35031. |
Find the area of quadrant of a circle whose circumference is 22cm |
| Answer» It\'s radius is 7/2cm and hence by using sector formula u can have your area of quadrant | |
| 35032. |
root is an irrational number |
| Answer» Yes | |
| 35033. |
If (a2+b2)x2+2(ab+bd)x+c2+d2=0 has no real roots then prove that ad not equal to bc |
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| 35034. |
2x+y-6=04×-2y-4=0 |
| Answer» 2x-y+2=0 | |
| 35035. |
If two never consecutive |
| Answer» | |
| 35036. |
How many. marks are There for chapter 11 |
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Answer» 10 to 15 marks Maths Geometry Construction is only NCERT read it make 13 marks to 15 marks Which subject In which subject |
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| 35037. |
When do use assumed mean method? |
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Answer» Easy to solve question To make the question easy |
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| 35038. |
Prove that 7 root 2 upon 3 is an irrational |
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Answer» It ks irrational Yes |
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| 35039. |
Write any two solutions 5x+2y=23 |
| Answer» X=1 & Y=9 also X=3 & Y=4 | |
| 35040. |
How we draw bisector on a line |
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Answer» Open your rounder to more than half of the given line segment. Then take the opened length as the radius and draw arc (mention only arc) up and down the line segment. Do the same from the other point of segment too. You\'ll find that these intersect at a point up and down. Join both the intersecting points. This is the perpendicular bisector of the line segment. We draw perpendicular bisector of line |
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| 35041. |
Without forming a triangle ,How we can say cos0°=1 ?? |
| Answer» | |
| 35042. |
Cos (90° -A) sin ( 90°-A) /tan (90°-A)=sinA |
| Answer» {tex} LHS = \\frac{{\\cos \\left( {90^\\circ - A} \\right)\\sin \\left( {90^\\circ - A} \\right)}}{{\\tan \\left( {90^\\circ - A} \\right)}}{/tex}{tex} = \\frac{{\\sin A \\times \\cos A}}{{\\cot A}}{/tex}\xa0{tex}\\left[ \\begin{gathered} \\cos \\left( {90^\\circ - \\theta } \\right) = \\sin \\theta \\hfill \\\\ \\sin \\left( {90^\\circ - \\theta } \\right) = \\cos \\theta \\hfill \\\\ \\end{gathered} \\right]{/tex}{tex} = \\frac{{\\sin A \\times \\cos A}}{{\\frac{{\\cos A}}{{\\sin A}}}}{/tex}{tex}= \\sin A \\times \\cos A \\times \\frac{{\\sin A}}{{\\cos A}}{/tex}{tex}= sin^2A = RHS{/tex} | |
| 35043. |
Express 140as a product of its prime factor |
| Answer» 2×2×5×7 | |
| 35044. |
Prove that √ tan A .tan B +tan B.tan A/sinA.secB )- sin^2 A/cos ^2 B. =tan A |
| Answer» | |
| 35045. |
If the HCF of 65 and 117 can be written as 65 - 117 find the value of m |
| Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:HCF =65m - 11713=65m - 11765m = 130m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2 | |
| 35046. |
12+2 |
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Answer» 14 aap kyon se class ma ho 1st ma kya?? 14 answer ...par Aapne 1 standard ka sawal kyun pucha ... so easy question ... 14 |
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| 35047. |
If tanx + cotx = 2 then find tan^7x + cot^7x |
| Answer» 14 | |
| 35048. |
Lessaon 1 |
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Answer» Aap ne leh kya likha ha samaj nahe aya raha Which subject |
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| 35049. |
What is the main points in chapter8 exercise 8.4 who can I do |
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Answer» Ok 8.4 proof qoition |
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| 35050. |
Ncert page no.37 exercise 2.3 Q.no 5 |
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Answer» Are, ans bhi milega All the parts we do If the polynomial x to the power 4 - 6 x cube + 16 X square - 25 x + 10 is divided by another polynomial x square - 2 X + K then remainder comes out to be X + a find K and a Write the question Kyo book nhi h kya bhai Bhai question liq ka doh plzzzz |
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