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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 34951. |
tansquare theta-sin square theta is equal to tansquare theta.sinsquare theta |
| Answer» Tan^2=sin^2/cos^2Acc to question..Lhs= sin^2/cos^2-sin^2 = (sin^2-sin^2×cos^2)÷cos^2 Taking sin^2 as common, we get = Sin^2(1-cos^2)÷cos^2 =Sin^2× sin^2/cos^2 Since sin theta÷ cos theta=tan theta, we get Sin^2theta× tan^2 theta Hence proved | |
| 34952. |
Solve the equation 7x-2y/xy=5 , 8x+7y/xy=15 |
| Answer» | |
| 34953. |
How to learn trigonometry table |
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Answer» Pandit bhola Prasad hari hari bol Papa Beedi Piyoge Haan Haan Beta???? Pakistan Bhookha Piyasaa Hindustan Hara Bhara???? Pandit badri prasad har har bole ???PBPHHB. |
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| 34954. |
How to learn ratio table |
| Answer» By palm hand rule | |
| 34955. |
Find the area of minor sector and major sector whose central Angle is120 and radius is 10.5 |
| Answer» Area of minor sector is 115.49 cm^2Area of major sector is 231 cm^2 | |
| 34956. |
If the common difference of an AP is -6 then find (a16-a12) |
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Answer» -24 Answer |
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| 34957. |
The graph of ax+by+c= 0 when a= 0 and b≠ 0 is parallel to which axis |
| Answer» | |
| 34958. |
Write a solution for the linear equation in two variables x+ 2y= 4 |
| Answer» Infinite number of solutions | |
| 34959. |
If n1and n2 are two odd prime numbers such that n1>n2, then write the nature of n1²-n2². |
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Answer» Odd negative number The no. Will be positive and even The no. will be positive |
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| 34960. |
3+1 |
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Answer» 4 4 |
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| 34961. |
Sum of nth term |
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Answer» Sn=n/2(a+l) Sn=n/2{2a+(n-1)d} |
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| 34962. |
Use Euclid alogrithm find hcf of 240,6552 |
| Answer» HCF= 24 | |
| 34963. |
If nth term of an ap is (2n+1) what is the sum of first three terms |
| Answer» 15 is the answer | |
| 34964. |
How can solv. Rd sharma ex.15.1 q2 |
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Answer» Dimak se You type the question |
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| 34965. |
How to find the zeros of a cubic polynomial |
| Answer» Put a question related to this after that you can undertand clearly | |
| 34966. |
The perimeter of a sector of a circle of radius 8 cm is 25m, what is area of sector? |
| Answer» | |
| 34967. |
Write the other trigonometric rations of A in terms of secA. So how can we do this for cosec A? |
| Answer» As you get od sin A just reverse it | |
| 34968. |
Using Euclid division Show that the square of any positive integers is either of the form 3m or 3m |
| Answer» Let \'a\'as any positive integer.So,b=3,r=0,1,2a=bq+r,now,R=0,. a=3 put all the values and you can solve it easily | |
| 34969. |
What is the formula of (a+b)2? |
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Answer» a^2 +b^2 +2ab a² + b² + 2ab a^2+b^2+2ab |
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| 34970. |
X^3-2x^2+2x-2 |
| Answer» | |
| 34971. |
Construt a triangle of 130 which sides are 2cm |
| Answer» Ab aapko hm kaise bataye ,aap hi hame bana k dikha dena es app pr. Jab aapko a jaye phone pr banana.??? | |
| 34972. |
Sir /madam I have problems in trigonometry identities |
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Answer» 1 baar man laga ke padh lo .............. Sab kuch clear ho jayega............try......... All the best.....? Kis type ki problem |
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| 34973. |
Find the difference between between the following pair of point (2,3) ;(4,1) |
| Answer» 2√4 | |
| 34974. |
Math hindi me nahi [email\xa0protected] |
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Answer» Ji nahi you can\'t study maths in hindi may be ......I think it is in government school may be.... Matlab |
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| 34975. |
What is probability? |
| Answer» Probability is the measure of the likelyhood that an event will ocur . | |
| 34976. |
Can I have a full list of all formulas in all chapters of maths |
| Answer» Search in NCERT book | |
| 34977. |
What is equivalance class |
| Answer» | |
| 34978. |
Is there is to set question paper |
| Answer» | |
| 34979. |
If tan+sin=mTan-sin=nShow (M2-n2)=4√mn |
| Answer» Given, {tex}\\tan \\theta + \\sin \\theta = m{/tex} and {tex}\\tan \\theta - \\sin \\theta = n{/tex}L.H.S =\xa0{tex}m^{2}-n^{2}{/tex}{tex}=(tan\\theta+sin\\theta)^{2}-(tan\\theta-sin\\theta)^{2}{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-[tan^{2}\\theta+sin^{2}\\theta-2tan\\theta sin\\theta]{/tex}{tex}=tan^{2}\\theta+sin^{2}\\theta+2tan\\theta sin\\theta-tan^{2}\\theta-sin^{2}\\theta+2tan\\theta sin\\theta{/tex}{tex}=4tan\\theta sin\\theta{/tex}R.H.S = 4{tex}\\sqrt{mn}{/tex}{tex}=4\\sqrt{(tan\\theta+sin\\theta)(tan\\theta-sin\\theta)}{/tex}{tex}=4\\sqrt{tan^{2}\\theta-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta}{cos^{2}\\theta}-sin^{2}\\theta}{/tex}{tex}=4\\sqrt{\\frac{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{cos^{2}\\theta}}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta-sin^{2}\\theta cos^{2}\\theta}{/tex}{tex}=\\frac{4}{cos\\theta}\\sqrt{sin^{2}\\theta (1-cos^{2}\\theta)}{/tex}{tex}=\\frac{4}{cos\\theta} \\times sin\\theta \\times \\sqrt{sin^{2}\\theta}{/tex}{tex}=4tan\\theta sin\\theta{/tex}Hence, L.H.S = R.H.S | |
| 34980. |
Sample paper latest |
| Answer» Check out the cbse website or u can get it from mycbseguide at sample question paper section. | |
| 34981. |
How much paper will come from ncret |
| Answer» Everything will be from ncert but the questions will be molded | |
| 34982. |
If the area of two similar triangles are equal them prove that they are congruent |
| Answer» Let the two triangles be.∆abc.&∆pQR .thus we have... AnglA=angleP.& Angle B=angle.Q.Now..given both triangles have equal area.Ar.∆ABC÷Ar.PQR=1\\2 BC×AD(let AD BE THE HEIGHT.)÷1\\2×QR×PS(LET PS BE THE HEIGHT.=BC\\QR=1BC=QR.THUS WE AHAVE BC=QRANGLE.A=ANGLE.PAND.ANGLE B=ANLGE Q.SO.∆ABC IS CONGRUENT TO ∆ PQR.BY.ASA PROPERTY | |
| 34983. |
Relation between mean , mediam and mode |
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Answer» Nice joke yar That is emperial formula Are you want to prove this All among are use to study data in statistics 3median =mode +2mean All are related to mathematics??? |
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| 34984. |
Chapter 17 |
| Answer» Of which subject | |
| 34985. |
Quadratic formula...... |
| Answer» ax2 +bx +c | |
| 34986. |
If the point A(0,2) is equidistance from the points B(3,p) and c(p,5),find p |
| Answer» P=1 | |
| 34987. |
2x +4x+5 |
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Answer» 6x +5 X=-5/6. Can i know where u r from |
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| 34988. |
The circumference of circle increased by 50percent find percentage increase in area |
| Answer» Circumference = 2 πr where r is radius of circleso area of circle = πr2Circumference is proportional to radius.When circumference is increased by 50% the radius will also increased by 50%.So new radius = 150 r /100 = 1.5 rSo new area = (1.5 r)2\xa0× πso increased in area = (1.5 r)2\xa0× π – πr2= π (2.25 r2\xa0– r2)= 1.25 πr2% increase in area = increase in area\xa0× 100\xa0original area = 1.25 πr2 × 100= 125 % | |
| 34989. |
If the sum of the zeroes of the quadratic polynomial 3x^2 −kx+ 6 is 3, then the value of K is: |
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Answer» 9 Alpha+beta =-b/a .sum of zeroes is given.putting the value of alpha+beta as 3= -(k)/3.on solving you will get the value of k as 9 This question is wrong The ques. Is If the sum of the square of the zeroes of quadratic _______ |
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| 34990. |
Guys kya maths ke 2 paper h iss year means standard level or higher level plz reply. |
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Answer» The cbse has not confirmed whether it will happen or not but 95% chances say that this can\'t occur this year No,it is from next year Sure btana May be |
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| 34991. |
Is class 10th board exam 2019 is in February or March |
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Answer» For vocational subject it is in February but for main subjects in March Start in feb last week |
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| 34992. |
Prove that 3+2/5 is irrational |
| Answer» Assume that 3+2/5 is rational no. Let a and b be the CO prime no. And 3+2/5=a/b2/5=a/b-3/5=a-3b/2b. eqn1But /5 is irrational no. eqn2And a-3b/2b is rational no. :From eqn1 2 33+2/5 is irrational no. Our assumption was wrong Hence proved | |
| 34993. |
The nth term of an AP is an 2n+1 find its sum |
| Answer» Here, an = 2n + 1Put n = 1, 2. Then,a1 = 2(1) + 1 = 3{tex}\\therefore {/tex}\xa0a2 = 2(2) + 1 = 5a = 3d = a2 - a1 = 5 - 3 = 2{tex}\\therefore {/tex}\xa0Sum of first n-terms of the AP = Sn{tex} = \\frac{n}{2}\\left[ {2a + (n - 1)d} \\right]{/tex}{tex} = \\frac{n}{2}\\left[ {2(3) + (n - 1)2} \\right]{/tex}= n (3 + n - 1)= n (n + 2) | |
| 34994. |
Write all the formulas related to the chapter trigonometry?please☹️? |
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Answer» These are main SinA+CosA=11+tan^A=Sec^A1+Cot^A=Cosec^A |
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| 34995. |
Define sector of a circle |
| Answer» Sector of a circle is the region enclosed by an arc of a circle and its two bounding radii is called.. | |
| 34996. |
Find HCF 3cube✖5 & 3square ✖5square |
| Answer» 3sq. ✖5=9 ✖5=45 | |
| 34997. |
269+638-739/8673 |
| Answer» Baby i love you | |
| 34998. |
The 11th term of an AP(5a-x),6a,(7a-x),.... |
| Answer» here A= 5a-x d=a+x11th term=A+(11-1)*d=5a-x+10*(a+x)= 15 a + 9x Ans.\xa0 | |
| 34999. |
Prove that sum root 2 and root is irrationsl |
| Answer» | |
| 35000. |
For any positive integer n,prove that n×n×n-n is divisible by 6 |
| Answer» 2 | |