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35801.

How to slove problems of to prove LHS=RHS easily in trigonometry

Answer» Firstly solve LHS aand if you find difficulty then solve RHS then any time your LHS =RHS
Multiply both LHS and RHS to 0
Convert all your tan .. etc into sin or cos Then any ques can be solved
when we solved LHS first If you want to Solve RHS so you can solved it
When we solved RHS first
35802.

HCF OF 25920 &11730 USING FACTORISATION MATHOD

Answer»
35803.

Convert into p/q form 43.123456789123.....

Answer» It is non-terminating decimals.
U
(43123456789-43)/999999999 =43123456746/999999999
35804.

465:&487

Answer» A=x4y4 ,b= x3y
35805.

A=x4 y4,b=x3y

Answer»
35806.

Factorisation method with eg

Answer»
35807.

Prove that tangents are perpendicular to radius

Answer» You will get a chord in a circle and in that circle you should join airline radius to and from centre you make a right angle triangle and slowly slowly use food near the near the joint. Of hypotenuse to the radius and using that radius is perpendicular to the
??
35808.

Sy

Answer»
35809.

What is ore

Answer» Minerals in which high percentage of metals are found is known as ore.
Ore mean rock or earth from which metal can be taken
35810.

REAL NUM

Answer» RAEGF
35811.

Show that the points A(3,0) ,B(8,2) ,C(-1,4),D(-2,-1)are the vertices of rhombus. Find its area.

Answer» Ok john
35812.

How I get more marks in exqmination

Answer» By consistence practice
By studying properly and following a regular time table, in which you have to give a specific timeline for all subjects and follow them regularly. And do not refer to any guide or help book ? just refer your textbooks.
By Hardwork
by answring correctly
By referring the textbook
35813.

Prove that root 3 irrational.

Answer» Let root 3 is a rational no.Therefore root 3 = P/q (where q# 0)Squaring both side 3 =p^2/ q^23q^2 = p^2Because p^2 divided by 3Therefore P also divided by 3 Now, P = 3mSquaring both side (p)^2 = (3m)^2 3q^2 = 9m^2q^2 =9/3 =3q^2= 3m^2Because q^2 divided by 3Therefore q also divided by 3Therefore p and q have at least 3 as a common factor.So our assumption root 3 is a rational no. is incorrect.
We have assume √3 is rational Therefore √3 =p/q and p and q are co primes p not equal to 0 Therefore p = √3q Squaring on both sides p^2 = 3q^2 Theorem : let p be a prime number ,it divides a^2 than p divides a, where a is a positive integer 3 divides q ^2 .3 divides q Let p = 3x (3x)^2 =3q ^2 9x^2 = 3 q ^2 3x^2 = q ^2 Theorem : let p be a prime number ,it p divides a^2 than p divides a where a is a positive integer 3 divides q^2 3 divides q That mean p and q has 2 common factorWhich is a contradicts the fact a and b Therefore √3 is irrational
Root 3 is a rational numberWhere a and b are positive integer and has on common number(Root 3) =a÷b 3a=b3 divodes aPut a= 3m in eq 13.b2 =9m b2= 3m 3divides bSo root3 has common numberWhich is contradicationSo root3 is an irrational number
35814.

Chapter 6 Me sabse important theorems and questions kaun se hai

Answer» And theorem 6.5 is most most imp.....
Pythagoras and BPT and converse of both
Pythagoras theorem
Pythogrous theorm and BPT both are very important.
Basic proposnality theoram
35815.

If cos (A+B)=0 and cot (A-B) =3 Find the value of -1. secA *tanB- cot A.tanB

Answer» bruh! recheck your question
what haha
Haha
35816.

A vehicle run 4 km in 1 litre of petrol . How much it runs in 10 litre of petrol?

Answer» 40km
40 KM
40 KM
40
40
35817.

Prove that sin+cos is never be less than 2

Answer»
35818.

(8,1),(k,-4),(2,-5)...find the value of "k". Coordinate geometry

Answer» First we have to put the value of area of triangle1/2[ x1 ( y2 -y3) + x2( y3 - y1) +x3 (y1 - y2) ] So, now we have put the values=1/2[8(-4+5)+k(-5-1) +2(1+4)]=1/2(8-6k+10)=1/2(18-6k) =1/2*2(9-3k) => -3k = -9=> k =3 Hence the value of k is 3
35819.

If sinA + cosB =2,then find sinB

Answer»
35820.

Solved for x √3xsquare -2√2 x -2√3 =0

Answer» {tex}\\sqrt { 3 } x ^ { 2 } - 2 \\sqrt { 2 } x - 2 \\sqrt { 3 } = 0{/tex}{tex}\\sqrt { 3 } x ^ { 2 } - 3 \\sqrt { 2 } x + \\sqrt { 2 } x - 2 \\sqrt { 3 } = 0{/tex}{tex}\\sqrt { 3 } x [ x - \\sqrt { 6 } ] + \\sqrt { 2 } [ x - \\sqrt { 6 } ] = 0{/tex}or,\xa0{tex}( x - \\sqrt { 6 } ) ( \\sqrt { 3 } x + \\sqrt { 2 } ) = 0{/tex}or,\xa0{tex}x = \\sqrt { 6 } , - \\sqrt { \\frac { 2 } { 3 } }{/tex}
35821.

Express sin theta in terms of tan theta. Fast

Answer» We know that tan =sin/cos divide sin by cos
35822.

Ggduj

Answer»
35823.

9.1 qestion number 4

Answer»
35824.

Express sin theta in terms of tan theta ? Gast

Answer»
35825.

How to do squring both sides

Answer» For example u have underoot: 2=p than putting( squaring both sides) and u have 2= p 2
35826.

If √3cot2A-4cotA+√3=0.find cot2A+tan2A

Answer»
35827.

In an ap if the common difference -4 and these 17 term A7 is 4 then find the first term

Answer» d=-4a+16d=4Put d =-4 a+16*-4=4a+64=4a=4-64a=-60
35828.

Cos 45/sec30+cosec30

Answer»
35829.

2x + 3y = 53x + 5y = 10

Answer» Y=5 ,x=-5
35830.

Find demension of the prayer hall discuss in section in4.1

Answer»
35831.

Root 3 plus 2root3 solve it

Answer» I am also favour in third one
3root3
3√3
2 root 6
35832.

Empirical relationship between mean, median and mode

Answer» Mode=3median-2mean
35833.

You give me modern test paper

Answer»
35834.

A metallic cube of edge 1 cm ia drawn into a wire of diameter 4mm, the find the length of the wire.

Answer»
35835.

Find the integers between 50 to500 which are divisible by 7

Answer» n=57
35836.

Why is trigometric value in ratio

Answer»
35837.

find the area of triangle whose vertices are (1,-1),(-3,5) and(2,-7)

Answer»
35838.

Find the value of P if the quadratic equation Psquare ×Xsquare -12x +P +7=0has the root 3/2

Answer»
35839.

Find the HCF of 96 and 404 by the prime factorisation method . Hence find their LCM

Answer» First factorize 96 and 404 separately and then find their common factor .The HCF will come 2 and the LCM will come 2424
Po
35840.

Ch 5

Answer» What chapter 5 give questions ??
35841.

Prove that sin(2n+1) A.sinA=sin2(n+1)A sin2nA

Answer»
35842.

Express sin theta in terms of tan theta

Answer» How?
The question is wrong the tan theta convert into the sin theta and it is sin theta /cos theta
35843.

If asinA + bcosA = c then prove that acosA-bsinA = √a2+b2-c2

Answer» 1
1
1
35844.

888,888,888,888

Answer» 23,123,123,123
35845.

If an is equal to 6n —3 find a, div and s20

Answer»
35846.

What\'s ( a + b )³. Reply fast please

Answer» a3+ b3 + 3ab (a+b)
a³+b³+3a²b+3ab²
a3+b3+3ab(a+b)
35847.

Prove that√ 3 is irrational

Answer» Check the n.c.e.r.t chapter no. 1
Its answer is there in RS Aggarwal
35848.

2÷4

Answer» OMG !!!? Are u really in class 10 ?
2
Are you really in class 10 or your younger one had do it.You are lowing the position of cpass 10. Really ...... I am feeling very shy on seeing this.
Did you do first time this type of questions
Are u seriously in class 10th???
35849.

Give an example of a flower which contains both stamens and carpels?

Answer» It\'s Hibiscus?
Science
35850.

If x= cosecA + cosA and y= cosecA- cosA then prove that (2÷x+y)^2 + (x-y÷2)^2 -1 =0

Answer» x = cosec A + cos A and y = cosec A - cos AThus, we havex + y =\xa0cosec A + cos A + cosec A - cos A = 2 cosec Ax - y =\xa0cosec A + cos A - cosec A + cos A = 2 cos\xa0AL.H.S =\xa0{tex}\\left( \\frac { 2 } { x + y } \\right) ^ { 2 } + \\left( \\frac { x - y } { 2 } \\right) ^ { 2 } - 1{/tex}{tex}= \\left( \\frac { 2 } { 2 \\cos e c A } \\right) ^ { 2 } + \\left( \\frac { 2 \\cos A } { 2 } \\right) ^ { 2 } - 1{/tex}{tex}= \\left( \\frac { 1 } { \\text{cosec} A } \\right) ^ { 2 } + ( \\cos A ) ^ { 2 } - 1{/tex}= (sin A)2\xa0+ (cos A)2\xa0- 1= sin2A + cos2A - 1= 1 - 1= 0= R.H.S