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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 35751. |
Find the point on the x-axis which is equidistant from (2,-5) and (-2,9) |
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Answer» X=8 chk your calculation Let the point of x-axis be P(x, 0)Given A(2, -5) and B(-2, 9) are equidistant from PThat is PA = PBHence PA2 = PB2 \xa0→ (1)Distance between two points is\xa0√[(x2 - x1)2 +\xa0(y2\xa0- y1)2]PA =\xa0√[(2\xa0- x)2\xa0+\xa0(-5\xa0- 0)2]PA2\xa0= 4 - 4x +x2 + 25 =\xa0x2 - 4x + 29Similarly,\xa0PB2\xa0=\xa0x2\xa0+ 4x + 85Equation (1) becomesx2\xa0- 4x + 29 =\xa0x2\xa0+ 4x + 85- 8x = 56x = -7Hence the point on x-axis is (-7, 0) |
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| 35752. |
Is 51 tearm of the AP 5,8,11 |
| Answer» Here the first term; a = 5Common difference; d = 11 - 8 = 8 - 5 = 3So, nth term is given by;tn = a + (n − 1)d = 5 + (n − 1) × 3Now to prove whether 51 is term of this A.P, taking tn = 5151 = 5 + (n − 1) × 3⇒ 51 = 5 + 3n − 3⇒ 3n = 51 + 3 − 5⇒ 3n = 49n = 49/33Now we know that number of terms can\'t be in fraction.So, 51 is not term of this A.P. | |
| 35753. |
5x-6x-2=o by quadratic formula |
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Answer» Ur ques is wrong...as it doesn\'t form any quadratic equation Bohot simple hai |
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| 35754. |
What is the square of (math) |
| Answer» ????? | |
| 35755. |
If sec A+ tan A= x.find secretary A |
| Answer» | |
| 35756. |
If sec A + tan A= x. Find sec A |
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Answer» X=1 By formula,secA +tanA=1 |
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| 35757. |
Factorise: *-45*+324 |
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| 35758. |
√34×√55 |
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Answer» 43.87 43.24567 |
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| 35759. |
Identification of sin cos tan |
| Answer» | |
| 35760. |
The area of the longest trangle the can be incribed a semi circle of radius r is |
| Answer» Hypotenuse | |
| 35761. |
if an AP, if the common difference (d) -4 and the seventh term A7 is 4 then find the first term |
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Answer» D = -4A7 =4 = AnAn = a+ (n-1)d4=a+(7-1)-44= a+(6)-44= a-24a=4+24a=28 a1= 28 |
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| 35762. |
4x+ py+8=0 |
| Answer» Given linear equation is 4x + py + 8 = 0 and 2x + 2y + 2 = 0.So, 4x + py + 8 = 0 ...(1)and 2x + 2y + 2 = 0 ...(2)a1 = 4, b1 = p, c1 = 8, a2= 2 , b2 = 2 and c2 = 2The condition of unique solution,\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } \\neq \\frac { b _ { 1 } } { b _ { 2 } }{/tex}Hence,{tex}\\frac { 4 } { 2 } \\neq \\frac { p } { 2 } \\text { or } \\frac { 2 } { 1 } \\neq \\frac { p } { 2 }{/tex}{tex}p \\neq 4{/tex}The value of p is other than 4 it may be 1,2,3, - 4 ,.... etc. | |
| 35763. |
Ch 8 8.2.ka example 8 |
| Answer» Sin(A-B)=1/2Sin30`=1/2So,A-B=30=eq1Cos(A+B)=1/2Cos60`=1/2So,A+B= 60=eq2Add eq 1 and 2,we getA-B=30 + A+B=60We get,A=45` and B=15` | |
| 35764. |
sin(A+B)=1 and Sin(A-B)=1/2 |
| Answer» sin(A+B)=1 , =› A+B= 90°...........(i)and sin(A-B)=1/2 , =› A-B=30°.............(ii)solving (i) and (ii) we get A=60, B=30 | |
| 35765. |
Under root of (1+x)+under root of (1-2) divided by under root of (1+x)+under root of (1-x).solve |
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| 35766. |
If sin A + cos A = root 2 cos A, find the value of cot A. |
| Answer» O Bhai copy le ke aa?? | |
| 35767. |
2+√3 is irrational number proove it |
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Answer» See example of chapter 1 Irrational |
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| 35768. |
How to find centroid of a triangle |
| Answer» X1 + x2 + x3 /3 = X & y1 + y2 + y3/3= Y of centroid | |
| 35769. |
What is the degree of zero polynomial???? |
| Answer» 1 | |
| 35770. |
If the ratio of a5 and a10 term is 2:5then find the ratio of a15 and a7 term |
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| 35771. |
13/2125 |
| Answer» 0.00611764705 | |
| 35772. |
1/a+b+x = 1/a +1/b +1/x |
| Answer» Given,{tex}\\frac { 1 } { ( a + b + x ) } = \\frac { 1 } { a } + \\frac { 1 } { b } + \\frac { 1 } { x }{/tex}{tex}\\Rightarrow \\quad \\frac { 1 } { ( a + b + x ) } - \\frac { 1 } { x } = \\frac { 1 } { a } + \\frac { 1 } { b } \\Rightarrow \\frac { x - ( a + b + x ) } { x ( a + b + x ) } = \\frac { b + a } { a b }{/tex}{tex}\\Rightarrow \\quad \\frac { - ( a + b ) } { x ( a + b + x ) } = \\frac { ( a + b ) } { a b }{/tex}On dividing both sides by (a+b){tex}\\Rightarrow \\quad \\frac { - 1 } { x ( a + b + x ) } = \\frac { 1 } { a b }{/tex}Now cross multiply{tex}\\Rightarrow{/tex}\xa0x(a + b + x) = -ab\xa0{tex}\\Rightarrow{/tex}\xa0x2 + ax + bx + ab = 0{tex}\\Rightarrow{/tex}\xa0x(x +a) + b(x +a) = 0{tex}\\Rightarrow{/tex}\xa0(x\xa0+ a) (x + b) = 0{tex}\\Rightarrow{/tex}\xa0x + a = 0 or x + b = 0{tex}\\Rightarrow{/tex}\xa0x = -a or x = -b.Therefore, -a and -b\xa0are the roots of the equation. | |
| 35773. |
Marked price |
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| 35774. |
Write a rational no. Between √2 and √3 . plzz answer my question |
| Answer» √2 = 1.414√3= 1.732So, a rational number between those two would be 1.5 (3/2). But there are several more, in fact, infinite number of rational numbers between √2 and √3. | |
| 35775. |
2 ki power x+3 =2 ki power x+5 +12 find value of x |
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| 35776. |
Why is pi taken as 22/7 |
| Answer» Pi is actually the ratio of the circumference of the circle to its diameter. On actual measurement, it has been found to be 3.14592635...,i.e., irrational. For the ease of calculation, it is considered 22/7 which is a rational number. | |
| 35777. |
5x-4y+8=07x+6-9=0Find the velu of x and y |
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| 35778. |
If -1and 2 are two zeroes of the polynomial 2x^3-x^2-5x-2,find the third zero |
| Answer» Given polynomial is p(x) = 2x3\xa0- x2- 5x - 2\xa0and -1 and 2 are zeroes of polynomial.{tex}\\therefore{/tex}\xa0{x - (-1)} (x - 2)= ( x + 1) (x - 2) = x2 - 2x + x - 2 = x2- x - 2 is a factor of p(x)For other zeroes, 2x\xa0+ 1 = 0{tex}\\Rightarrow x = \\frac { - 1 } { 2 }{/tex}{tex}\\therefore{/tex}\xa0Other zero = {tex}\\frac { - 1 } { 2 }{/tex} | |
| 35779. |
formula of Ap chaptar |
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Answer» wasa nahi bata sakta ho see in book.... |
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| 35780. |
(tan+2)(2tan+1)=5tan+sec2 |
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| 35781. |
An integer is chosen at random between 1and 100. Find the probability that it is divisible by 8 |
| Answer» Total number is 98Divisible by 8 are 8,16,24,32,40,48,56,64,72,80,88,96So 12 numbers are divisibleSo probability of divisible numbers = 12/98 = 6/49 | |
| 35782. |
Ch 4 ex 4.3 qu 1 |
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| 35783. |
Solve for x and y : 2(3x-y)=5xy, 2(x+3y)=5xy |
| Answer» 2(3x - y) = 5xy .(i)2(x + 3y) = 5xy ..(ii)Divide eqns. (i) and (ii) by xy,{tex}\\frac { 6 } { y } - \\frac { 2 } { x } = 5{/tex} ....(iii)and\xa0{tex}\\frac { 2 } { y } + \\frac { 6 } { x } = 5{/tex}\xa0.....(iv)Let\xa0{tex}\\frac { 1 } { y } = a \\text { and } \\frac { 1 } { x } = b{/tex}then equations (iii) and (iv) become6a - 2 b = 5 ......(v)2a -6b = 5 ...(vi)Multiplying eqn. (v) by 3 and then adding with eqn. (vi),18a - 6b + 2a - 6b = 15 + 520a = 20{tex}\\therefore {/tex}\xa0a=1Substituting this value of a in eqn. (v),{tex}b = \\frac { 1 } { 2 }{/tex}Now\xa0{tex}\\frac { 1 } { y } = a = 1{/tex}or, y=1and\xa0{tex}\\frac { 1 } { x } = b = \\frac { 1 } { 2 }{/tex}or, x=2Hence, x = 2, y = 1 | |
| 35784. |
( x+1)²+(x-1)²=3x-3 |
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| 35785. |
HOW TO SOLVE CO ORDINATE GEOMETERY DISTANCE FORMULA QUESTIONS |
| Answer» By using the distance formula | |
| 35786. |
Fugg |
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| 35787. |
Is the point p(x,y) is equidistant pointA(5,1)B(_-1,5)prove that 3x=2y |
| Answer» \xa0The distances of P (x, y) from A (5,1) and B (-1,5) are equal, then we have to prove that 3x = 2y.PA = PB{tex}\\therefore{/tex}\xa0PA2\xa0= PB2By distance formula,(5 - x)2\xa0+ (1 - y)2= (-1 - x)2\xa0+ (5 - y)2{tex}\\Rightarrow{/tex}25 - 10x + x2\xa0+ 1 - 2y + y2\xa0= 1 + 2x + x2\xa0+ 25 - 10y + y2{tex}\\Rightarrow{/tex}\xa0-10x - 2y = 2x - 10y{tex}\\Rightarrow{/tex}\xa08y = 12x{tex}\\Rightarrow{/tex}4(2y)= 4(3x){tex}\\Rightarrow{/tex}3x = 2yHence Proved. | |
| 35788. |
32+32(-32) |
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Answer» -992 by BODMAS -992 |
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| 35789. |
find the quadratic polynomial, the sum and product of whose zeros are root 2 and -12 respectively. |
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Answer» let ,alpha and bita are zeroesso,alpha+bita= 2 and alpha•bita=-12f(x)= xsquare-(alpha+bita)x+alpha•bita =x² -2x+(-12) =x²-2x-12 required polynomial= x²-2x-12 Kya Aaisha tumhe itna bhi nahi aata.Ans. Braket me X ka square phir _ braket me sum of zeroes braket close phir × X phir + product of zeroes braket close |
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| 35790. |
44⁴44+5555 |
| Answer» 49999 | |
| 35791. |
What is the formula of a3+b3 |
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Answer» I am sorry a3+b3=a3+b3+3a2b+3ab2 (a+b)^3 - 3ab (a+b) (a+b)3 -3(ab)(a+b) (a+b)(a2+b2-ab) a3+b3+3ab(a+b). |
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| 35792. |
When x3+2x2 + kx +3 is divided by ( x-3) then the remainder is 21 |
| Answer» Let p(x) ={tex} x^3 + 2x^2 + kx + 3{/tex}Now, x - 3 = 0\xa0{tex}\\Rightarrow{/tex}\xa0x = 3By the remainder theorem, we know that when p(x) is divided by (x - 3), the remainder is p(3).Now, p(3) = (3)3\xa0+ 2(3)2\xa0+ k(3) + 3= 27 + 2(9) + 3k + 3= 30 + 18 + 3k\xa0= 48 + 3kBut, remainder = 21\xa0{tex}\\Rightarrow{/tex}\xa048 + 3k = 21{tex}\\Rightarrow{/tex} 3k = 21 - 48{tex}\\Rightarrow{/tex}\xa03k = -27{tex}\\Rightarrow{/tex} k = {tex}\\frac{-27}3{/tex}{tex}\\Rightarrow{/tex} k = -9So, the value of k is -9. | |
| 35793. |
7sin2tita +3cos2tita =4then proved that tantita =1/root2 |
| Answer» Hii | |
| 35794. |
HCF of 29 and 56 |
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Answer» 1 1 |
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| 35795. |
Find the zeros of the polynomial if two zeros are |
| Answer» Where is the full question bro | |
| 35796. |
If x+a is factor of 2xsquare+2ax+5x +10 then find A |
| Answer» Here the given polynomial f(x)=2x2 + 2ax + 5x +10If x+a is a factor of f(x) then x+a=0 or x = -a{tex}\\Rightarrow{/tex}f(-a) = 0{tex}\\Rightarrow{/tex}2(-a)2 + 2a.(-a) + 5(-a) + 10 =0{tex}\\Rightarrow{/tex}2a2 - 2a2 -5a +10 =0{tex}\\Rightarrow{/tex}-5a = -10{tex}\\Rightarrow{/tex}a=2. | |
| 35797. |
what is Rational Number? |
| Answer» A number which is in the form of p/q, where p and q are integer and q is not equal to 0 is called Rational Number. | |
| 35798. |
Prove that product of three consecutive positive integers is divisible by 6 |
| Answer» 6q+1 | |
| 35799. |
The quadrtic polynomial whose equation are 2 and 3 |
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Answer» X² -2x+3 What we do in this question? |
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| 35800. |
If a and B are the zeros of the polynomial such that a+b=-6 and ab=5 then find tha polynomial |
| Answer» x^2+6x+5 | |