4x+ py+8=0

1.	4x+ py+8=0
Answer» Given linear equation is 4x + py + 8 = 0 and 2x + 2y + 2 = 0.So, 4x + py + 8 = 0 ...(1)and 2x + 2y + 2 = 0 ...(2)a1 = 4, b1 = p, c1 = 8, a2= 2 , b2 = 2 and c2 = 2The condition of unique solution,\xa0{tex}\\frac { a _ { 1 } } { a _ { 2 } } \\neq \\frac { b _ { 1 } } { b _ { 2 } }{/tex}Hence,{tex}\\frac { 4 } { 2 } \\neq \\frac { p } { 2 } \\text { or } \\frac { 2 } { 1 } \\neq \\frac { p } { 2 }{/tex}{tex}p \\neq 4{/tex}The value of p is other than 4 it may be 1,2,3, - 4 ,.... etc.

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