InterviewSolution
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InterviewSolution
| 1. |
Solve for x and y : 2(3x-y)=5xy, 2(x+3y)=5xy |
| Answer» 2(3x - y) = 5xy .(i)2(x + 3y) = 5xy ..(ii)Divide eqns. (i) and (ii) by xy,{tex}\\frac { 6 } { y } - \\frac { 2 } { x } = 5{/tex} ....(iii)and\xa0{tex}\\frac { 2 } { y } + \\frac { 6 } { x } = 5{/tex}\xa0.....(iv)Let\xa0{tex}\\frac { 1 } { y } = a \\text { and } \\frac { 1 } { x } = b{/tex}then equations (iii) and (iv) become6a - 2 b = 5 ......(v)2a -6b = 5 ...(vi)Multiplying eqn. (v) by 3 and then adding with eqn. (vi),18a - 6b + 2a - 6b = 15 + 520a = 20{tex}\\therefore {/tex}\xa0a=1Substituting this value of a in eqn. (v),{tex}b = \\frac { 1 } { 2 }{/tex}Now\xa0{tex}\\frac { 1 } { y } = a = 1{/tex}or, y=1and\xa0{tex}\\frac { 1 } { x } = b = \\frac { 1 } { 2 }{/tex}or, x=2Hence, x = 2, y = 1 | |