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35901.

Is the together with maths beneficial for class 10?

Answer» Yes
Plz pkz ans
35902.

NCERT book class 10 pg:237, ex : 12.3 and 12, 13 questions

Answer» 12. 1st one 77by 8, 2nd one 49by 813. 228
35903.

What is the zeros of the polynomial

Answer» which polynomial?P(x)=?
Values which satisfy the polynomial
35904.

If sin theta +2cos theta=1Then prove that 2sin theta -cos theta =2

Answer» do yourself
35905.

Explain why 1,2,3,4,5 is a composite number?

Answer» Sorry your question is wrong 1,2,3,5 are not composite numbers...4 is the smallest composite number ..Composite numbers are those numbers which have three or more than three factor ...
35906.

if 4 cot theta = 5,show that: 5sin theta+3cos theta/5sin theta-2cos theta = 7/2

Answer» 5cot shiJsc628-3-2hsjdn8hwhFgwk
35907.

In the following AP, find the missing term in the boxes__ , 38 , __ __ __ ,-22

Answer» 53 ,23,8,-7 are the answers
35908.

The sum of first n term of AP is 5n-n^2 find the n^th term of this AP

Answer»
35909.

Cos under root x

Answer» √2
35910.

Find the Point on the x_axis which is equidistant from (2,-5) and (-2,9).

Answer» Let the point of x-axis be P(x, 0)Given A(2, -5) and B(-2, 9) are equidistant from PThat is PA = PBHence PA2\xa0= PB2 → (1)Distance between two points is\xa0{tex}\\sqrt{[(x_2\xa0- x_1)^2\xa0+\xa0(y_2\xa0- y_1)^2]}{/tex}PA =\xa0{tex}\\sqrt{[(2\xa0- x)^2\xa0+\xa0(-5\xa0- 0)^2]}{/tex}PA2\xa0= 4 - 4x +x2\xa0+ 25=\xa0x2\xa0- 4x + 29Similarly,\xa0PB2\xa0=\xa0x2\xa0+ 4x + 85Equation (1) becomesx2\xa0- 4x + 29 =\xa0x2\xa0+ 4x + 85- 8x = 56x = -7Hence the point on x-axis is (-7, 0)
35911.

Find the sum of all 11 terms of an AP whose middle most term is 30 ...

Answer»
35912.

X2 + ( a / a + b ) +(+a + b / a )x+1 =0

Answer» By factorization
35913.

√2+√2+√2+√2+√2??? = ???

Answer» Thank you rohan kumar and roht kumar
C2
2
Yhamini rply me
35914.

Find the coordinate of point which divide linesegment to (-2., 2)(2, 8)

Answer» Let P (x1, y1) Q(x2, y2) and R(x3, y3) be the points which divide the line segment AB into four equal parts.Then, P divides AB in the ratio 1 : 3 internally.{tex}x=\\frac{mx_2+nx_1}{m+n}{/tex}\xa0{tex}\\therefore x _ { 1 } = \\frac { ( 1 ) ( 2 ) + ( 3 ) ( - 2 ) } { 1 + 3 }{/tex}{tex}= \\frac { 2 - 6 } { 4 } = - \\frac { 4 } { 4 } = - 1{/tex}{tex}y=\\frac{my_2+ny_1}{m+n}{/tex}{tex}y _ { 1 } = \\frac { ( 1 ) ( 8 ) + ( 3 ) ( 2 ) } { 1 + 3 }{/tex}{tex}= \\frac { 8 + 6 } { 4 } = \\frac { 14 } { 4 } = \\frac { 7 } { 2 }{/tex}So,\xa0{tex}\\mathrm { P } \\rightarrow \\left( - 1 , \\frac { 7 } { 2 } \\right){/tex}Also, Q divides AB in the ratio 1 : 1 i.e.Q is the mid point of AB{tex}x _ { 2 } = \\frac { - 2 + 2 } { 2 } = 0{/tex}{tex}y _ { 2 } = \\frac { 2 + 8 } { 2 } = \\frac { 10 } { 2 } = 5{/tex}So,\xa0{tex}Q \\rightarrow ( 0,5 ){/tex}and, R divides AB in the ratio 3 : 1{tex}\\therefore x _ { 2 } = \\frac { ( 3 ) ( 2 ) + ( 1 ) ( - 2 ) } { 3 + 1 }{/tex}{tex}= \\frac { 6 - 2 } { 4 } = \\frac { 4 } { 4 } = 1{/tex}{tex}y _ { 3 } = \\frac { ( 3 ) ( 8 ) + ( 1 ) ( 2 ) } { 3 + 1 }{/tex}{tex}= \\frac { 24 + 2 } { 4 } = \\frac { 26 } { 4 } = \\frac { 13 } { 2 }{/tex}So,\xa0{tex}\\mathrm { R } \\rightarrow \\left( 1 , \\frac { 13 } { 2 } \\right){/tex}
35915.

3/8 in decimal form

Answer» I GOT THE ANSWER BUT I WAS CHECKING IT
0.375
35916.

If 3×9=9then 3×8=what

Answer» 8
8
35917.

(a cube - b cube) =

Answer» a cube -b cube =(a-b)(a sq+ b sq +2ab)
A square - B square + 2AB
A square + B square _ 2AB
35918.

All syntax of computer

Answer»
35919.

Here answer will give Root 32 And the finall answer is 4root 2

Answer»
35920.

Find the value of y for which the distance between the points P(2,-3) and Q(10,y) is 10 units .

Answer» -9 or 3
Put distance formula l know this answer but I do not write it on this
35921.

What is the root of 7

Answer» 2.64575
35922.

Hye ! Friends what do you think in boards for subject maths questions from maths exemepler also cone

Answer» And by adding the marks of statistics ,probablity, and polynomials it is around 40-60 marks
I also have seen last year boards paper many of the question were of NCERT so by solving only NCERT question we can get good % in exam .
I have seen many years of board papers they are mostly NCERT and NCERT exemplar questions but now but they are not the same as it.
NCERT is a base of cbse. The question will be complicated than ncert.
100 % ncert because board can not give questions out of ncert . Ncert is government book guys so practice ncert book or exampler
70% Ncert 30% Other
35923.

In an ap if the common difference is -4 and the seventh term is 4 then find the first term

Answer» First term is 28a+6(-4)= 4a=4+24a=28
35924.

Write the HCF of smallest composite number and smallest prime numbers.

Answer» Hey , this is the qus of last year 10 board
The smallest composite number is 4The smallest prime number = 2To find HCF between 2 and 4, we write2 = 2 × 14 = 2 × 2HCF = 2
35925.

elaborate the herons formula

Answer» Square nhi mil raha keyboard par
35926.

Thalls theorum

Answer» Thales theorem us also kniwn as basic propotionality theorem.
If a line is drawn parallel to one side of triangle ,it intersect other two sides in distinct points and other two sides divided in the same ratio
35927.

How to find the zeroes of 4u2+8u and verify the relation between the zeroes and coefficient

Answer» Take 4u common and then do it 4u(u + 2)= 0 4u= 0, u+2=0So u = 0 , -2
35928.

If alpha and bita are zeroes of quadratic polynomial x2-6x+a. Find the a if 3 alpha +2bita=20

Answer» Plz find the value of alpha or bita in first polynomial after that solve equation first or second
35929.

7+2(a + 1) - 3a =5a

Answer» 7+2a+2-3a=5a 9-a=5a 9=5a+a 9=6a 9/6=a 3/2=a 1.5=a
35930.

Prove that√2 irriotional

Answer» Spelling
????
it is irrational: spellig?
35931.

A number divided by 53 gives 33 as questan and 19 as remainder . Find the number

Answer» 1768
Ara oooh you tube pa thak la
1834
35932.

How to find a root number

Answer»
35933.

40+40

Answer» 80
35934.

Find mean by step deviation methods

Answer»
35935.

Prove? root 3 is irrational number?

Answer» To prove whether\xa0{tex}\\sqrt{3}{/tex} is rational or irrational, we find the square root of\xa0{tex}\\sqrt{3}{/tex}\xa0by long division method.{tex}\\therefore{/tex}\xa0{tex}\\sqrt{3}{/tex}\xa0= 1.732050807We observe that the decimal representation of{tex}\\sqrt{3}{/tex}\xa0is neither terminating nor repeating. Hence,\xa0{tex}\\sqrt{3}{/tex} is an irrational number.
35936.

Define focal length and focus of concave mirror

Answer» Principal focus of a concave mirror is a point where light rays parallel to principle axis converge.The distance between pole of mirror to point of principle focus is focal length of mirror.Focal length of spherical mirror is half of its radius of curvature.
35937.

Chapter four

Answer»
35938.

396 kg of cement is packed equally in 18 bags . How many bags are required to pack 550 kg of cement?

Answer» 18 divided by 396 and multiplied by 550
25
35939.

If tfogisupGnkohopptsvbnccgjjopcirrhfoecwjoerfsbddgjgdbwfdemZqqhenq

Answer» I did not understand the question
Ques glat hai
35940.

-5+(-8)+(-11)+....+(-230)

Answer» –5 + (–8) + (–11) + …. + (–230)This is an AP.Here, a = –5d = –8 –(–5) = –8 + 5 = –3l = –230Let the number of terms of the AP be nWe know thatl = a + (n - 1)d{tex} \\Rightarrow {/tex}\xa0-230 = -5 + (n - 1) (-3){tex} \\Rightarrow {/tex}\xa0(n - 1) (-3) = -230 + 5{tex} \\Rightarrow {/tex}\xa0(n - 1) (-3) = -225{tex} \\Rightarrow n - 1 = \\frac{{ - 225}}{{ - 3}} = 75{/tex}{tex} \\Rightarrow {/tex}\xa0n = 75 + 1{tex} \\Rightarrow {/tex}\xa0n = 76Again, we know that{tex}{S_n} = \\frac{n}{2}(a + l){/tex}{tex} \\Rightarrow {S_{76}} = \\frac{{76}}{2}\\left[ {( - 5) + ( - 230)} \\right]{/tex}{tex} \\Rightarrow {/tex}\xa0S76 = 38(-235){tex} \\Rightarrow {/tex}\xa0S76 = -8930Hence, the required sum is -8930.
35941.

What is the value of $ in rupees

Answer» Mmar ke juta yyad dharaeb 71rupia pahele dai bhail baye aur na padha pepar banru
1 USD = 70.76 INR
35942.

Solve for x : x to the power 4 -26 x square plus 25 is equal to zero.

Answer» No x=0
x=4
35943.

Sir give me this year syllabus of maths sa1 gorverment school

Answer» 1 to 7 and 14 ,15 will also come
Half yearly syllabus Ch1…2…3…4…5…6…7 ch will come
35944.

12.2 q6 in detail

Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html
35945.

(cosecA-cotA)=1-cosA/1+cos

Answer» I think you have written wrong question I guess the question is :- (cosecA - cotA)^2 = 1-cosA/1+cosA
35946.

3(sinA+cosA)4 +6(cosA+cosecA)2 =(1+secA×cosecA)

Answer»
35947.

Sas proportion

Answer»
35948.

All concept of trigonometric ratios

Answer»
35949.

a^2x^2- b^2 =0 , solve by factorization method

Answer»
35950.

Easy method of factorisation method for verbal sums

Answer»