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36001.

i want last year sample paper

Answer» Subject???
Which subject
36002.

Find the value:-a)sin60° cos30°+sin30° cos60°

Answer» √3÷2×√3÷2+1÷3×1÷2=3÷4+1÷4=3+1÷4=4÷4=1 ans
36003.

Root of x +y =7Root of y + x =11

Answer» X+y=7X=7-yIn eq2 we put the value xY+x=11Y+7-y=11Y=4X+y=7X+4=7X=3
36004.

Give me blue print

Answer»
36005.

Solve for x : 2x/x-3+1/2x+3+3x+9/(x-3)(2x+3)=0,xis not equal to 3,-3/2

Answer» Hshsgs
36006.

A two digit no. Is 4 times the sum of its digits.and twice the digits. Find the no.

Answer» Let the ten\'s place digit be y and unit\'s place be x.Therefore, number is 10y + x.According to given condition,10y + x = 4(x + y) and 10y + x = 2xy{tex}\\Rightarrow{/tex}\xa0x = 2y and 10y + x = 2xyPutting x = 2y in 10y + x = 2xy10y + 2y = 2.2y.y12y = 4y2\xa04y2\xa0- 12y = 0\xa0{tex}\\Rightarrow{/tex}\xa04y(y - 3) = 0{tex}\\Rightarrow{/tex}\xa0y - 3 = 0 or y = 3Hence, the ten\'s place digit is 3 and units digit is 6 (2y = x)Hence the required number is 36.
36007.

SinA - cos A

Answer» As we know, sin^2 A + cos^2 A = 1.................................................................Which could be written as,(Sin A - cos A )^2 + 2 sinA cos A = 1(SinA- cos A)^2 = 1 - 2sinA cosASinA - cos A = root ( 1- 2sinA cosA)
36008.

See me sample paper of Arthmetic progession and Quadratic equations

Answer»
36009.

Converse of basic proportional rheorem

Answer»
36010.

What is the common defference of an ap in which a21- a7 = 84

Answer» A21+A7 = a+20d+a+6d84=2a+26d42=a+13dD=42-a÷13
36011.

3326+5555-585

Answer» 8296
U can\'t do this ... of course ans is 8296
8296
8296
36012.

The sum of n,2n,3n term of an AP are S1,S2,S3 respectively . Prove that S3=3(S2_S1)

Answer» {tex}{S_1} = \\frac{n}{2}\\left[ {2a + (n - 1)d} \\right]{/tex}{tex}{S_2} = \\frac{{2n}}{2}\\left[ {2a + (2n - 1)d} \\right]{/tex}{tex}{S_3} = \\frac{{3n}}{2}\\left[ {2a + (3n - 1)d} \\right]{/tex}R.H.S = 3(S2 - S1){tex} = 3\\left[ {\\frac{{2n}}{2}(2a + (2n - 1)d - \\frac{n}{2}(2a + (n - 1)d)} \\right]{/tex}{tex} = 3\\left[ {\\frac{n}{2}\\left[ {4a + 4nd - 2d - 2a - nd + d} \\right]} \\right]{/tex}{tex} = 3\\left[ {\\frac{n}{2}(2a + 3nd - d)} \\right]{/tex}{tex} = \\frac{{3n}}{2}\\left[ {2a + (3n - 1)d} \\right] = {S_3}{/tex}
36013.

Latest sample by cbse

Answer» At the google
36014.

TanA/1-cotA + cotA/1-tanA = 1+ secA cosecA

Answer» You dont know answer solve it and get answer
36015.

What is the distance between the points A(sin0 - cos0, 0)and B(0,sin0+ cos0)?

Answer» AB= √{0-(sin0 - cos0)}^2 + {(sin0 + cos0) - 0}^2 = √(sin^2 0 + cos^2 0 -2sin0cos0 + sin^2 0 + cos^2 0 + 2sin0cos0 = √sin ^2 0 + cos^2 0 + sin^2 0 + cos^2 0 = √1+1 =√2
Root 2
36016.

What is probablity

Answer» Meassuring uncertainity is called as probability
the quality or state of being probable; the extent to which something is likely to happen or be the case.
36017.

What is probablity of getting 40mark in the maths paper

Answer» Total marks in maths=100P(getting 40 marks)= 40/100 2/5
36018.

Iines and angles of 7th CBSE exercise

Answer» Kuta
36019.

Is there any change syllabus of class 10 maths?

Answer» By my knowledge, no
36020.

A(x)square -bx+c Find Alfha - bata

Answer» (b+c)/a
36021.

If P(E)=0.05,what is the probability of \'not E\'

Answer» 0.95
P(Not E)= 1- P(E) = 1-0.05 = 0.95
36022.

Probalty

Answer»
36023.

(CotsquareA +cosecsquareA))

Answer» Its equal to one right......
36024.

the two opposite vertices of a square are - 12

Answer» What is ques. here
What is your question??
36025.

What is common difference

Answer» If the difference between any consecutive term of an AP is same or equal then the difference is known as common difference.
a2-a1
When common difference is same is called Ap
36026.

If sn=3n+5n² find 20th term

Answer» n=1 S1=A1=3(1)+5(1) A1=8Similarly S2=A1+A2=26A2=26-A1=18d=A2-A1=10Now,nth term=A1+(n-1)dSo 20th term=8+(20-1)10=8+190=198
n=20 Sn=3×20+5×400 =60+2000 =2060
36027.

Ex-6.2

Answer»
36028.

How much 8 chapter weight age is there

Answer» How much water in the brain
36029.

Do optional exercises come in board examination?

Answer» Yes offcource they just make us to belive that they wont give but every time they will give 2 problems every time in board exam
No it is for practice
Yes
Yes chances are there
No
36030.

Ex 7 A question 6 new book of rs aggarwal

Answer» I know answer
36031.

if the the sum of the 1st n terms of an ap iS given by sn=5n² + 3n. find its nth term

Answer» S1=5×1×1+3×1 =8a1=8S2=5×2×2+3×2 =26a1+a2=268+a2=26a2=18d=a2-a1 =18-8d =10an=a+(n-1)d =8+(n-1)10 =8+10n-10 an=10n-2
36032.

Cos square theta into cos square theta

Answer» Cos raised to power 4 theta
7itim
36033.

Mid term of -273

Answer» 139
36034.

4u-v=14uv3u-2u=16uvWhere u and v not=0.

Answer»
36035.

Prove that sinA-cosA+1÷sinA+cisA-1=1÷secA-tanA

Answer»
36036.

Prove n is a rational number

Answer»
36037.

X/2 -y/9=6X/7+y/3=5

Answer» Hello
36038.

3^1/2×SinX=CosX

Answer»
36039.

Ihghv

Answer»
36040.

How to prove root 2,3

Answer»
36041.

Maths lab manual activities second how to draw the graph of the equation 3 X square- 3 x-5

Answer»
36042.

(-250)+56(-56)

Answer» -3386
250
36043.

Cos(22/7/4-x) cos22/7/4-y) - sin(22/7/4-x)sin(22/7/4-y) =sin(x+y)

Answer» We have L.H.S=. {tex}\\cos \\left( {\\frac{\\pi }{4} - x} \\right)\\cos \\left( {\\frac{\\pi }{4} - y} \\right)\\sin \\left( {\\frac{\\pi }{4} - x} \\right){/tex}{tex}\\sin \\left( {\\frac{x}{4} - y} \\right){/tex}{tex} = \\cos \\left[ {\\frac{\\pi }{4} - x + \\frac{\\pi }{4} - y} \\right]{/tex}[ {tex}\\because {/tex}cos (A+ B) = cos A cos B - sin A sin B]{tex} = \\cos \\left[ {\\frac{\\pi }{2} - (x + y)} \\right]{/tex}= sin (x + y) = R.H.S
36044.

Cbse class 7

Answer»
36045.

What is the value of sin squared theta plus one by one plus 10 squared theta

Answer» 1
36046.

Prove that:-1+cosA+sinA/1+cosA-sinA=1+sinA/cosA

Answer»
36047.

Which term of the AP..3,8,13,18,.........is 78

Answer» 16
16
15
36048.

The sum of 3 terms of an ap is 24 and their product is 240 find the 3 terms of the AP

Answer» \u200b\u200b\u200b\u200b\u200b\u200blet the terms of\xa0a.p.= a-d, a,a+d,\xa0now, according to question\xa0a-d+a+a+d=243a =24a=24/3= 8again according to question\xa0(a-d)(a)(a+d)= 240(a2 - d2)(a)= 240now putting the value of a(8^2 -d^2)×8 =24064-d^2=240/8= 3064-30 = d^2d = root34so the terms = 8-root34, 8, 8+ root34
I don\'t know
36049.

how to know divisible of 13

Answer»
36050.

If p,q are prime positive integers prove √p+√q is irrational

Answer» Suppose that {tex} \\sqrt { p } + \\sqrt { q }{/tex} is a rational number equal to {tex} \\frac { a } { b }{/tex}, where a and b are integers having no common factor.Now,\xa0{tex} \\sqrt { p } + \\sqrt { q } = \\frac { a } { b }{/tex}{tex} \\Rightarrow \\sqrt { p } = \\frac { a } { b } - \\sqrt { q }{/tex} (squaring both side){tex} \\Rightarrow \\quad ( \\sqrt { p } ) ^ { 2 } = \\left( \\frac { a } { b } - \\sqrt { q } \\right) ^ { 2 }{/tex}{tex} \\Rightarrow \\quad p = \\frac { a ^ { 2 } } { b ^ { 2 } } - 2 \\left( \\frac { a } { b } \\right) \\sqrt { q } + q{/tex}{tex} \\Rightarrow \\quad 2 \\left( \\frac { a } { b } \\right) \\sqrt { q } = \\frac { a ^ { 2 } } { b ^ { 2 } } + q - p{/tex}{tex} \\Rightarrow \\quad 2 \\frac { a } { b } \\sqrt { q } = \\frac { a ^ { 2 } + b ^ { 2 } ( q - p ) } { b ^ { 2 } }{/tex}{tex} \\Rightarrow \\quad \\sqrt { q } = \\frac { a ^ { 2 } + b ^ { 2 } ( q - p ) } { 2 a b }{/tex}{tex} \\Rightarrow \\sqrt { q }{/tex}\xa0is a rational number. (because sum of two rational numbers is always rational)This is a contradiction as\xa0{tex} \\sqrt { q }{/tex}\xa0is an irrational number.Hence,\xa0{tex} \\sqrt { p } + \\sqrt { q }{/tex}\xa0is an irrational number.